Phenols & Quinones
Phenol acidity, oxidation to quinones, redox biology, antioxidants, and Kolbe-Schmitt synthesis
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🌿 Phenols & Quinones
Phenols (ArOH) bridge alcohols and aromatic chemistry. Phenoxide stabilization by resonance into the ring makes phenols ~10⁶× more acidic than alcohols (pKa ≈ 10).
Substituent effects on phenol acidity — EWGs at the ortho/para positions stabilize the conjugate base (picric acid pKa ≈ 0.4); EDGs raise the pKa.
Reactions
- Williamson ether synthesis with alkyl halides
- Kolbe-Schmitt carboxylation (phenol → salicylic acid → aspirin)
- Bromination (no FeBr₃ needed; tribromophenol forms)
- Oxidation to quinones (1,4-benzoquinone)
Quinones in biology — coenzyme Q, vitamin K, plastoquinone. Reversible 2e⁻/2H⁺ redox couple underlies the electron-transport chain.
📚 Practice Problems
1Problem 1medium
❓ Question:
Rank the following compounds in order of increasing pKa: phenol, p-methylphenol (p-cresol), p-nitrophenol, p-methoxyphenol, picric acid (2,4,6-trinitrophenol). Justify each ordering with a one-sentence resonance/inductive argument.
💡 Show Solution
Increasing pKa (most acidic → least acidic): picric acid (~0.4) < p-nitrophenol (~7.2) < phenol (~10.0) < p-methylphenol (~10.3) < p-methoxyphenol (~10.2/10.3, ≈ p-cresol)
- Picric acid has 3 NO₂ groups whose resonance + inductive withdrawal stabilize the phenoxide tremendously.
- p-Nitrophenol — one para NO₂ accepts the negative charge by resonance (quinoid resonance form with O⁻ → N→O⁻).
- Phenol — baseline; phenoxide stabilized by aromatic delocalization.
- p-Methylphenol — the hyperconjugating CH₃ is weakly electron-donating, destabilizes the phenoxide.
- p-Methoxyphenol — OMe donates by resonance (lone pair into the ring), destabilizing phenoxide; nearly the same pKa as p-cresol because the inductive withdrawal of OMe partially offsets resonance donation.
2Problem 2hard
❓ Question:
Propose a synthesis of acetylsalicylic acid (aspirin) starting from phenol. Show the Kolbe-Schmitt step and the final acylation, and explain why bicarbonate (HCO₃⁻) is not used in place of CO₂ in step 1.
💡 Show Solution
Step 1 — Kolbe-Schmitt carboxylation:
- Treat phenol with NaOH → sodium phenoxide.
- Heat the dry phenoxide salt with CO₂ at ~125 °C and 100 atm.
- The phenoxide oxygen coordinates a Na⁺ that delivers CO₂ to the ortho position; protonation gives salicylic acid (2-hydroxybenzoic acid).
Step 2 — Acetylation of the phenolic OH:
- Acetic anhydride + catalytic H₂SO₄ converts the phenolic OH (more nucleophilic than the carboxylic acid OH) to the acetate ester → acetylsalicylic acid.
Why CO₂ rather than HCO₃⁻? Bicarbonate is a weak electrophile and a poor source of CO₂ for delivery to a phenoxide ring. The Kolbe-Schmitt requires the neutral, electrophilic CO₂ molecule, coordinated by the sodium counterion at high pressure to enforce ortho selectivity. Bicarbonate would either (a) protonate the phenoxide back to phenol or (b) fail to electrophilically attack the ring.
⚠️ Common Mistakes: Phenols & Quinones
Avoid these 3 frequent errors
🌍 Real-World Applications: Phenols & Quinones
See how this math is used in the real world
📝 Worked Example: Stoichiometry — Limiting Reagent
mol of reacts with mol of . How many grams of water are produced? Which is the limiting reagent? ()
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