Phenols & Quinones
Phenol acidity, oxidation to quinones, redox biology, antioxidants, and Kolbe-Schmitt synthesis
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๐ฟ Phenols & Quinones
Phenols (ArOH) bridge alcohols and aromatic chemistry. Phenoxide stabilization by resonance into the ring makes phenols ~10โถร more acidic than alcohols (pKa โ 10).
Substituent effects on phenol acidity โ EWGs at the ortho/para positions stabilize the conjugate base (picric acid pKa โ 0.4); EDGs raise the pKa.
Reactions
- Williamson ether synthesis with alkyl halides
- Kolbe-Schmitt carboxylation (phenol โ salicylic acid โ aspirin)
- Bromination (no FeBrโ needed; tribromophenol forms)
- Oxidation to quinones (1,4-benzoquinone)
Quinones in biology โ coenzyme Q, vitamin K, plastoquinone. Reversible 2eโป/2Hโบ redox couple underlies the electron-transport chain.
๐ Practice Problems
1Problem 1medium
โ Question:
Rank the following compounds in order of increasing pKa: phenol, p-methylphenol (p-cresol), p-nitrophenol, p-methoxyphenol, picric acid (2,4,6-trinitrophenol). Justify each ordering with a one-sentence resonance/inductive argument.
๐ก Show Solution
Increasing pKa (most acidic โ least acidic): picric acid (~0.4) < p-nitrophenol (~7.2) < phenol (~10.0) < p-methylphenol (~10.3) < p-methoxyphenol (~10.2/10.3, โ p-cresol)
- Picric acid has 3 NOโ groups whose resonance + inductive withdrawal stabilize the phenoxide tremendously.
- p-Nitrophenol โ one para NOโ accepts the negative charge by resonance (quinoid resonance form with Oโป โ NโOโป).
- Phenol โ baseline; phenoxide stabilized by aromatic delocalization.
- p-Methylphenol โ the hyperconjugating CHโ is weakly electron-donating, destabilizes the phenoxide.
- p-Methoxyphenol โ OMe donates by resonance (lone pair into the ring), destabilizing phenoxide; nearly the same pKa as p-cresol because the inductive withdrawal of OMe partially offsets resonance donation.
2Problem 2hard
โ Question:
Propose a synthesis of acetylsalicylic acid (aspirin) starting from phenol. Show the Kolbe-Schmitt step and the final acylation, and explain why bicarbonate (HCOโโป) is not used in place of COโ in step 1.
๐ก Show Solution
Step 1 โ Kolbe-Schmitt carboxylation:
- Treat phenol with NaOH โ sodium phenoxide.
- Heat the dry phenoxide salt with COโ at ~125 ยฐC and 100 atm.
- The phenoxide oxygen coordinates a Naโบ that delivers COโ to the ortho position; protonation gives salicylic acid (2-hydroxybenzoic acid).
Step 2 โ Acetylation of the phenolic OH:
- Acetic anhydride + catalytic HโSOโ converts the phenolic OH (more nucleophilic than the carboxylic acid OH) to the acetate ester โ acetylsalicylic acid.
Why COโ rather than HCOโโป? Bicarbonate is a weak electrophile and a poor source of COโ for delivery to a phenoxide ring. The Kolbe-Schmitt requires the neutral, electrophilic COโ molecule, coordinated by the sodium counterion at high pressure to enforce ortho selectivity. Bicarbonate would either (a) protonate the phenoxide back to phenol or (b) fail to electrophilically attack the ring.
โ ๏ธ Common Mistakes: Phenols & Quinones
Avoid these 3 frequent errors
๐ Real-World Applications: Phenols & Quinones
See how this math is used in the real world
๐ Worked Example: Stoichiometry โ Limiting Reagent
mol of reacts with mol of . How many grams of water are produced? Which is the limiting reagent? ()
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