Measures of Spread
Calculate and interpret range, IQR, variance, and standard deviation.
Try the Interactive Version!
Learn step-by-step with practice exercises built right in.
Measures of Spread
Range
Formula:
Properties:
- Simplest measure
- Uses only two values (min, max)
- Not resistant: one outlier inflates range
- Affected by sample size: larger samples tend to have larger range
Example: data 5, 8, 10, 12, 15 → range = 15 − 5 = 10
Interquartile Range (IQR)
Definitions:
- Q1 (first quartile): 25th percentile
- Q2 (second quartile): 50th percentile = median
- Q3 (third quartile): 75th percentile
Formula:
Interpretation: spread of middle 50% of data
Properties:
- Resistant: unaffected by outliers (only uses middle half)
- Paired with median to describe center and spread of skewed data
- Comparable across datasets
Finding Q1 and Q3:
- Order data
- Find median (divides into lower and upper halves)
- Q1 = median of lower half
- Q3 = median of upper half
Sample Variance (\(s^2\))
Formula:
Why n−1? (not n)
- Use n−1 for sample variance (estimating population)
- Corrects for underestimation (Bessel's correction)
- Use n only for population variance \(\sigma^2\)
Properties:
- Measures average squared deviation from mean
- Squared units (e.g., if data in inches, variance in square inches)
- Not resistant: affected by outliers
- Larger dataset → typically larger variance
Sample Standard Deviation (\(s\))
Formula:
Interpretation:
- Typical (rough average) distance of data points from mean
- Same units as original data
- In approximately normal data: roughly 68% within 1s, 95% within 2s, 99.7% within 3s
Properties:
- Not resistant: affected by outliers
- Paired with mean (for symmetric data)
- Larger s → more spread
Worked Example
Data: Test scores: 60, 70, 75, 80, 85, 90, 95
- n = 7, mean = \(\bar{x} = \frac{595}{7} = 85\)
IQR calculation:
- Lower half: 60, 70, 75 → Q1 = 70
- Upper half: 85, 90, 95 → Q3 = 90
- IQR = 90 − 70 = 20
Variance calculation:
Standard deviation:
Interpretation: Scores vary by about 13.54 points from the mean.
Computational Shortcut for \(s^2\)
Avoids computing \(\bar{x}\) explicitly; useful for calculators or spreadsheets.
Resistance to Outliers
Example: Dataset 5, 8, 10, 12, 15
- Range: 15 − 5 = 10
- IQR: Q1 = 8, Q3 = 12 → IQR = 4
- s ≈ 3.74
Add outlier 100:
- New range: 100 − 5 = 95 (increased 9×)
- New IQR: 8 to 12 (unchanged)
- New s ≈ 37.6 (increased 10×)
Conclusion: IQR is resistant; range and s are not.
Common Mistakes
- Dividing by n instead of n−1: use n−1 for sample variance
- Forgetting to square deviations: variance formula uses \((x_i - \bar{x})^2\)
- Confusing variance and std dev: std dev = \(\sqrt{\text{variance}}\)
- Misinterpreting s: s is not "maximum distance from mean"; it's typical distance
AP Exam Tip
When comparing spread:
- Symmetric data, no outliers: compare standard deviations
- Skewed data or outliers: compare IQR (resistant)
- Statement: "Distribution A (s = 5) is less spread than Distribution B (s = 8)."
Justify why you chose std dev vs. IQR based on shape of distributions.
📚 Practice Problems
1Problem 1easy
❓ Question:
A dataset has minimum value 10, Q1 = 25, median = 40, Q3 = 55, and maximum = 100. Calculate the range and interquartile range (IQR).
💡 Show Solution
Range = Maximum − Minimum = 100 − 10 = 90
Interquartile Range (IQR) = Q3 − Q1 = 55 − 25 = 30
The range includes all data but is affected by outliers. The IQR represents the spread of the middle 50% and is resistant to outliers — the extreme value of 100 doesn't pull it higher.
2Problem 2medium
❓ Question:
Two classes took the same exam. Class A has mean 75 with standard deviation 5. Class B has mean 75 with standard deviation 15. Both classes have the same average performance, but what does the difference in standard deviation tell you?
💡 Show Solution
Interpretation:
Even though both classes have the same mean (75), the standard deviation reveals different patterns:
Class A (SD = 5): Scores are tightly clustered around 75. Most students scored within about 5-10 points of the mean (roughly 70-80), showing consistent performance. Students are more similar to each other.
Class B (SD = 15): Scores are spread out over a wider range. Students deviate much more from 75 on average (roughly 60-90), showing more variability in performance. There's greater diversity—some students did much better, some much worse.
Conclusion: The standard deviation measures consistency. Class A has more uniform understanding, while Class B has greater range in mastery levels. The same average can hide very different distributions!
3Problem 3hard
❓ Question:
Explain why the IQR is considered resistant to outliers while the standard deviation is not. Use an example with a dataset that has an extreme outlier.
💡 Show Solution
Why IQR is resistant:
The IQR = Q3 − Q1 depends only on the 25th and 75th percentile positions. Even if one value becomes extremely large or small, it doesn't change Q1 or Q3 (as long as it's still outside those quartiles). The IQR ignores the extreme value entirely.
Why standard deviation is not:
Standard deviation measures average squared distance from the mean:
An extreme outlier creates a huge squared deviation, which dramatically increases .
Example: Dataset: 10, 12, 14, 16, 18
- Q1 = 12, Q3 = 16, IQR = 4
- Mean = 14, SD ≈ 3.16
Now add extreme outlier: 10, 12, 14, 16, 18, 500
- Q1 = 12, Q3 = 16, IQR = 4 (unchanged!)
- Mean = 93.33, SD ≈ 201 (exploded!)
Lesson: Use IQR and median when outliers are present; they're more reliable summaries.
⚠️ Common Mistakes: Measures of Spread
Avoid these 3 frequent errors
Practice with Flashcards
Rate this topic's cards with spaced repetition. Cards join your deck when you finish a topic's lesson and take its exit quiz.
Browse All Topics
Explore more AP Statistics topics