Limits & Continuity (AP Calculus AB Unit 1)
Limit definition, evaluation, one-sided limits, squeeze theorem, and IVT
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Limits & Continuity — AP Calculus AB Unit 1
Limits are the foundation of every other idea in calculus. The derivative is a limit. The definite integral is a limit. Continuity, asymptotic behavior, and the major theorems (IVT, MVT, EVT, FTC) all rest on limit reasoning. Roughly 10–12 % of the AP Calculus AB exam is drawn directly from this unit, but the real weight is much larger because limits power Units 2–8 as well.
This page is the unit hub: it gives you the conceptual framing, the AP-style "must-know" skills, and a roadmap of all the granular sub-topics you can study below.
What you'll learn in this unit
- What a limit is — both intuitively (where the function is heading) and formally (the – definition AP uses informally).
- How to compute limits four ways: graphically, numerically (tables), algebraically (factoring, rationalizing, substitution, special trig limits), and via L'Hôpital's Rule (introduced formally in Unit 4 but previewed here for and forms).
- One-sided limits and what they tell you about jump discontinuities and vertical asymptotes.
- Limits at infinity — end behavior, horizontal asymptotes, and the rational-function rule of thumb.
- Infinite limits — vertical asymptotes from the inside out.
- Continuity at a point (three-part definition) and on an interval, and the three flavors of discontinuity (removable, jump, infinite).
- Big-picture theorems — Intermediate Value Theorem, Squeeze Theorem.
The big idea
A limit asks: "As gets arbitrarily close to , what value is getting arbitrarily close to?"
It does not ask what is. That's the trick: may be undefined, the wrong value, or anything else, and the limit can still exist. This separation between value at a point and behavior near a point is exactly what lets calculus describe instantaneous rates and exact areas.
Three things a limit can do at
- Equal a finite number. . The function approaches a single value from both sides.
- Equal (an "infinite limit"). The function blows up; this signals a vertical asymptote at .
- Fail to exist. Either the left- and right-hand limits disagree (jump), the function oscillates without settling, or disagrees on the two sides.
A limit exists (in the AP sense of "equals a number") only when both one-sided limits agree on a finite value. Any other behavior — jumps, oscillation, blow-ups — means the limit DNE.
Computing limits — the AP playbook
When asked to evaluate , follow this order:
- Try direct substitution. If is continuous at , . Done.
- If you get , look for algebraic simplification. Most common moves:
- Factor and cancel (e.g., for ).
- Rationalize (multiply by conjugate when there's a square root).
- Combine fractions in the numerator.
- Use a trig identity (e.g., ).
- Recognize special trig limits: and .
- For limits at infinity of rational functions, compare leading-term degrees:
- degree(num) < degree(den): limit = 0
- degree(num) = degree(den): limit = ratio of leading coefficients
- degree(num) > degree(den): limit is (no horizontal asymptote)
- If you still get an indeterminate form ( or ), use L'Hôpital's Rule: .
Continuity in one breath
A function is continuous at iff all three are true:
- is defined.
- exists.
- .
If any one fails, is discontinuous at . The flavor depends on which one:
| Discontinuity | What goes wrong | Fixable by redefining ? |
|---|---|---|
| Removable ("hole") | exists, but doesn't equal it (or doesn't exist) | Yes |
| Jump | Left and right limits exist but disagree | No |
| Infinite | ; vertical asymptote | No |
The Intermediate Value Theorem (IVT)
If is continuous on and is any value between and , then there is at least one with .
In AP problems, the IVT is the go-to justification for "show that has a solution on " or "show that takes the value 5 somewhere on ." Always state the continuity hypothesis explicitly when you cite the IVT — graders will not award the point if you don't.
The Squeeze Theorem
If near (except possibly at ) and , then .
Most-used template: showing that by sandwiching between and .
How this unit shows up on the AP exam
- Multiple choice (no calculator): Algebraic limit evaluations ( form, factoring, rationalizing). Continuity diagnostics from a piecewise definition. Limits-at-infinity / horizontal asymptotes.
- Multiple choice (calculator): Estimating limits from a table or graph; verifying a removable discontinuity numerically.
- Free response: A continuity argument citing IVT; setting up a piecewise function so it's continuous (solve for a parameter); using one-sided limits to characterize a vertical asymptote.
Common mistakes to avoid
- Computing instead of the limit. They are not the same thing — the limit ignores the value at .
- Saying "" means the limit exists. On the AP exam, an infinite "limit" means the limit does not exist in the formal sense. Use to describe the behavior, not to claim existence.
- Skipping the continuity hypothesis when citing IVT. No "continuous on " → no credit.
- Plugging into rational functions directly. Always compare degrees first.
- Forgetting the absolute-value subtlety. does not exist (left = , right = ).
Quick reference card
- Limit exists left limit = right limit = same finite number
- 3-part continuity: defined; exists; they're equal
- Discontinuity types: removable / jump / infinite
- Indeterminate forms to attack: , (then factor / rationalize / L'Hôpital)
- Special trig: ;
- Rational function at : compare leading-term degrees
- IVT requires continuity on a closed interval
Sub-topics in this unit
Use the cards below to drill into each granular skill. Start with the conceptual ones (what a limit is, notation, one-sided limits) and move into the algebraic-technique sections (factoring, rationalizing, indeterminate forms) before tackling continuity and limits at infinity. There's also an interactive lesson and entrance quiz at the top of this page that test the whole unit at once.
📚 Practice Problems
1Problem 1easy
❓ Question:
Evaluate .
💡 Show Solution
The function is a polynomial — continuous everywhere — so the limit equals the value:
.
2Problem 2easy
❓ Question:
Evaluate .
💡 Show Solution
Direct substitution gives , an indeterminate form. Factor the numerator:
for .
So .
Note that itself is undefined (the original function has a removable discontinuity at ), but the limit exists.
3Problem 3easy
❓ Question:
Given the piecewise function , find , , , and . Is continuous at ?
💡 Show Solution
Left limit: .
Right limit: .
Since both one-sided limits equal 3, .
(from the middle piece).
The limit exists and is defined, but . Continuity fails the third condition → is not continuous at . The discontinuity is removable (redefining would fix it).
4Problem 4medium
❓ Question:
Evaluate .
💡 Show Solution
Direct substitution gives . Multiply numerator and denominator by the conjugate :
.
Now plug in : .
5Problem 5medium
❓ Question:
Evaluate and .
💡 Show Solution
Rule of thumb (rational function at ): compare leading-term degrees.
(a) Top and bottom both have degree 2. Limit = ratio of leading coefficients = .
(b) Top has degree 1, bottom has degree 2. Bottom grows faster, so the ratio . (The line is a horizontal asymptote.)
6Problem 6medium
❓ Question:
Evaluate .
💡 Show Solution
Use the special trig limit .
Rewrite: .
As , , so .
.
7Problem 7medium
❓ Question:
Find all values of that make continuous at .
💡 Show Solution
Continuity at requires the two pieces to agree there:
Left value: .
Right limit: .
Set equal: .
8Problem 8hard
❓ Question:
Use the Intermediate Value Theorem to show that has a root in the interval .
💡 Show Solution
Step 1. is a polynomial → continuous on (and everywhere). The IVT continuity hypothesis is satisfied.
Step 2. Compute the endpoints:
Step 3. . So lies between and .
Step 4. By the IVT, there exists with . ∎
AP grading note: explicitly stating "continuous on " is required for full credit.
9Problem 9hard
❓ Question:
Evaluate .
💡 Show Solution
Direct substitution gives , indeterminate. Multiply by the conjugate:
.
Divide top and bottom by (with so ):
.
As , :
.
10Problem 10hard
❓ Question:
Use the Squeeze Theorem to evaluate .
💡 Show Solution
Step 1 — Bound the sine. For all , .
Step 2 — Multiply by (positive for ): .
Step 3 — Take limits of the outer functions: and .
Step 4 — Apply the Squeeze Theorem: , so the limit equals .
Note that alone has no limit at 0 (it oscillates wildly), but multiplying by damps the oscillation.
📋 AP Calculus AB — Exam Format Guide
| Section | Format | Questions | Time | Weight | Calculator |
|---|---|---|---|---|---|
| Multiple Choice (No Calculator) | MCQ | 30 | 60 min | 33.3% | 🚫 |
| Multiple Choice (Calculator) | MCQ | 15 | 45 min | 16.7% | ✅ |
| Free Response (Calculator) | FRQ | 2 | 30 min | 16.7% | ✅ |
| Free Response (No Calculator) | FRQ | 4 | 60 min | 33.3% | 🚫 |
📊 Scoring: 1-5
💡 Key Test-Day Tips
- ✓Show all work on FRQs
- ✓Use proper notation
- ✓Check units
- ✓Manage your time
⚠️ Common Mistakes: Limits & Continuity (AP Calculus AB Unit 1)
Avoid these 4 frequent errors
🌍 Real-World Applications: Limits & Continuity (AP Calculus AB Unit 1)
See how this math is used in the real world
📝 Worked Example: Related Rates — Expanding Circle
A stone is dropped into a still pond, creating a circular ripple. The radius of the ripple is increasing at a rate of cm/s. How fast is the area of the circle increasing when the radius is cm?
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