Estimating Limits from Tables

Learn to estimate limit values by examining tables of function values

Using Tables to Find Limits

One of the most intuitive ways to understand limits is by creating a table of values and observing the pattern.

The Strategy

To estimate limxaf(x)\lim_{x \to a} f(x):

  1. Choose values approaching from the left (x < a)
  2. Choose values approaching from the right (x > a)
  3. Calculate f(x) for each value
  4. Look for a pattern - what value are the outputs approaching?

Example Setup

Let's find limx2x24x2\lim_{x \to 2} \frac{x^2 - 4}{x - 2} using a table.

Note: We can't just plug in x = 2 because we'd get 00\frac{0}{0} (undefined!)

From the left (x < 2):

| x | f(x) = x24x2\frac{x^2 - 4}{x - 2} | |---|---| | 1.9 | (1.9)241.92=0.390.1=3.9\frac{(1.9)^2 - 4}{1.9 - 2} = \frac{-0.39}{-0.1} = 3.9 | | 1.99 | (1.99)241.992=0.03990.01=3.99\frac{(1.99)^2 - 4}{1.99 - 2} = \frac{-0.0399}{-0.01} = 3.99 | | 1.999 | (1.999)241.99923.999\frac{(1.999)^2 - 4}{1.999 - 2} \approx 3.999 |

From the right (x > 2):

| x | f(x) = x24x2\frac{x^2 - 4}{x - 2} | |---|---| | 2.1 | (2.1)242.12=0.410.1=4.1\frac{(2.1)^2 - 4}{2.1 - 2} = \frac{0.41}{0.1} = 4.1 | | 2.01 | (2.01)242.012=0.04010.01=4.01\frac{(2.01)^2 - 4}{2.01 - 2} = \frac{0.0401}{0.01} = 4.01 | | 2.001 | (2.001)242.00124.001\frac{(2.001)^2 - 4}{2.001 - 2} \approx 4.001 |

The Pattern

Both sides are approaching 4!

Therefore: limx2x24x2=4\lim_{x \to 2} \frac{x^2 - 4}{x - 2} = 4

Tips for Making Tables

  1. Start reasonably close - Use values like 0.1, 0.01 away from a
  2. Get progressively closer - Move to 0.01, 0.001, etc.
  3. Check both sides - Always examine left and right approaches
  4. Use a calculator - For complex functions, don't do it by hand
  5. Look for agreement - If both sides approach the same value, that's your limit!

When Tables Fail

Tables are estimates! They might be misleading if:

  • You don't get close enough to the point
  • The function oscillates wildly near the point
  • There's a very steep change right at the point

Tables are excellent for building intuition, but algebraic methods (coming in later lessons) are more precise.

📚 Practice Problems

1Problem 1medium

Question:

Use a table to estimate limx1x1x21\lim_{x \to 1} \frac{x - 1}{x^2 - 1}. Check values from both sides.

💡 Show Solution

Let's create a table approaching x = 1:

From the left (x < 1):

| x | x1x21\frac{x - 1}{x^2 - 1} | Decimal | |---|---|---| | 0.9 | 0.10.19\frac{-0.1}{-0.19} | 0.526 | | 0.99 | 0.010.0199\frac{-0.01}{-0.0199} | 0.503 | | 0.999 | 0.0010.001999\frac{-0.001}{-0.001999} | 0.500 |

From the right (x > 1):

| x | x1x21\frac{x - 1}{x^2 - 1} | Decimal | |---|---|---| | 1.1 | 0.10.21\frac{0.1}{0.21} | 0.476 | | 1.01 | 0.010.0201\frac{0.01}{0.0201} | 0.498 | | 1.001 | 0.0010.002001\frac{0.001}{0.002001} | 0.500 |

Both sides approach 0.5, so:

limx1x1x21=0.5=12\lim_{x \to 1} \frac{x - 1}{x^2 - 1} = 0.5 = \frac{1}{2}