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Test for independence using probability rules and understand its implications.
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Events and are independent if:
Knowing occurred doesn't change probability of
Two events have P(A) = 0.4, P(B) = 0.5, and P(A ā© B) = 0.2. Are A and B independent?
Check if P(A ā© B) = P(A) Ć P(B). P(A) Ć P(B) = 0.4 Ć 0.5 = 0.2. P(A ā© B) = 0.2 = 0.2. ā Yes, A and B are independent. Since the intersection equals the product, knowing B occurred tells us nothing about A.
A two-way table: 300 students surveyed. 180 exercise regularly, 200 have healthy BMI. 120 both exercise and have healthy BMI. Are exercising regularly and having healthy BMI independent?
Avoid these 3 frequent errors
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Equivalently (any of these):
When and independent:
Example: Flip two fair coins
Method: Check if
Example with data:
Check:
Since , not perfectly independent (likely due to sampling variation, but close)
Independent:
Dependent:
Scenario:
Are studying and passing independent?
Check:
Conclusion: Dependent (studying increases probability of passing)
Are events independent? ā Use Are events mutually exclusive? ā Use
"Are A and B independent?" requires checking the definition: does knowing B change the probability of A? If yes, dependent.
P(exercise) = 180/300 = 0.6. P(healthy BMI) = 200/300 = 0.667. P(both) = 120/300 = 0.4. P(exercise) Ć P(healthy BMI) = 0.6 Ć 0.667 = 0.4. Since P(exercise ā© healthy BMI) = 0.4 = 0.6 Ć 0.667, the events are independent. Exercise and BMI health are unrelated in this sample.
Consider rolling two fair dice. Let A = "first die shows 6" and B = "sum of both dice is 7." Are A and B independent? Justify with probabilities.
P(A) = 1/6 (first die is 6). P(B) = 6/36 = 1/6 (sums: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1). P(A ā© B) = 1/36 (both: first is 6 AND sum is 7, only outcome 6+1). P(A) Ć P(B) = (1/6) Ć (1/6) = 1/36. Since P(A ā© B) = P(A)P(B), A and B are independent. Rolling a 6 first doesn't change the odds of summing to 7.