Basic Probability Rules
Apply addition and multiplication rules, and understand complements and mutually exclusive events.
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🎲 Basic Probability Rules
Fundamental Definitions
Sample Space ()
- Set of all possible outcomes
- Example: rolling die →
Event ()
- Subset of sample space
- Example: "roll even"
Probability
- P(A) = \frac{\text{# favorable outcomes}}{\text{# total outcomes}} (assuming equally likely)
- Ranges from 0 (impossible) to 1 (certain)
The Complement Rule
Definition: is the complement (event does NOT occur)
Example: If , then
Use case: Sometimes easier to calculate directly
Mutually Exclusive Events
Definition: Events cannot occur simultaneously;
Example: Single die roll → "even" and "odd" are mutually exclusive
Implication: If and mutually exclusive, then
Addition Rule for Mutually Exclusive Events
Example:
General Addition Rule (for Any Events)
Subtract to avoid double-counting
Example:
- , ,
Worked Example
Scenario: Polling 1000 voters
- 600 support tax increase
- 400 oppose tax increase
- 100 of supporters also want education reform
What's the probability a voter supports tax increase OR education reform?
Need —not given! Use Venn diagram or two-way table.
Common Mistakes
- Using addition rule for non-mutually-exclusive events without subtracting overlap
- Confusing "and" () with "or" ()
- Forgetting to subtract in general rule
Decision Rule
Are events mutually exclusive? → Use Can they overlap? → Use
AP Exam Tip
Draw Venn diagrams or two-way tables for clarity. The general addition rule always works—apply it first when unsure.
📚 Practice Problems
1Problem 1easy
❓ Question:
At a concert, P(rain) = 0.3. What is P(no rain)?
💡 Show Solution
P(no rain) = 1 - P(rain) = 1 - 0.3 = 0.7. The complement rule states that an event and its complement partition the sample space with probability 1.
2Problem 2medium
❓ Question:
In a class of 100 students, 60 play soccer, 40 play basketball, and 15 play both. What is P(soccer OR basketball)?
💡 Show Solution
Using the inclusion-exclusion principle: P(A ∪ B) = P(A) + P(B) - P(A ∩ B). P(soccer ∪ basketball) = 60/100 + 40/100 - 15/100 = 85/100 = 0.85. The union includes all who play at least one sport; subtract the overlap to avoid double-counting.
3Problem 3hard
❓ Question:
A lottery ticket wins with probability 0.001. If you buy 5 independent tickets, what is the probability of winning at least one prize?
💡 Show Solution
P(at least one win) = 1 - P(no wins) = 1 - P(all 5 lose). P(lose one ticket) = 1 - 0.001 = 0.999. P(all 5 lose) = (0.999)⁵ ≈ 0.9950. P(at least one win) = 1 - 0.9950 ≈ 0.0050 = 0.50%. Using complement is simpler than summing P(X=1) + P(X=2) + ... + P(X=5).
⚠️ Common Mistakes: Basic Probability Rules
Avoid these 3 frequent errors
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