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🎯⭐ INTERACTIVE LESSON

Triangle Inequalities

Learn step-by-step with interactive practice!

Triangle Inequalities - Complete Interactive Lesson

Part 1: The Triangle Inequality Theorem

📐 Triangle Inequalities

Part 1 of 5 — The Triangle Inequality Theorem


Topics in This Part

Section
Can These Sides Make a Triangle?
The Triangle Inequality Theorem
The One-Check Shortcut

🔑 Key Concept: Not every set of three lengths can close up into a triangle. If two sides are too short, they simply can't reach across the third. The Triangle Inequality Theorem tells you exactly when three lengths will form a triangle.

Can These Sides Make a Triangle?

Imagine two sticks hinged at one end. To form a triangle, their free ends must meet the third side. If the two sticks are too short, they fall short of reaching — no triangle.

  • Sides 33, 44, 55 → the two shorter sticks (3+4=73 + 4 = 7) easily reach across the side of length 55. ✓ Triangle
  • Sides 11, 22, 1010 → the two shorter sticks (1+2=31 + 2 = 3) can't span a gap of 1010. ✗ No triangle

The deciding factor is always whether the two shorter sides together are long enough to stretch across the longest side.

💡 Picture it: if you flatten the triangle completely, the two short sides lie along the long side. To make a real (non-flat) triangle, they must add up to strictly more than the long side.

The Triangle Inequality Theorem

🔑 Theorem: The sum of the lengths of any two sides of a triangle is greater than the length of the third side.

For a triangle with sides aa, bb, and cc, all three of these must hold:

a+b>ca+c>bb+c>aa + b > c \qquad a + c > b \qquad b + c > a

Example: Sides 77, 1010, 55

CheckSumvs. thirdPass?
7+10>57 + 10 > 51717>5> 5✓
7+5>107 + 5 > 101212>10> 10✓
10+5>710 + 5 > 71515>7> 7✓

All three pass, so 77, 1010, 55 form a triangle.

⚠️ The inequality is strict (>>, not ≥\geq). If a sum equals the third side, the three points lie on a straight line — a degenerate triangle with zero area, which we do not count as a real triangle.

Concept Check 🎯

The One-Check Shortcut

Checking all three inequalities works, but there's a faster way.

🔑 Shortcut: Add the two shortest sides. If that sum is greater than the longest side, the triangle is valid. You only need this one check.

Why? If the two shortest sides already beat the longest side, then any two sides (which can only be longer) will certainly beat the remaining one.

Example: Sides 66, 99, 44

The two shortest are 44 and 66. The longest is 99.

4+6=10>9  ⇒  valid triangle✓4 + 6 = 10 > 9 \;\Rightarrow\; \text{valid triangle} ✓

Example: Sides 33, 1111, 77

Two shortest: 33 and 77. Longest: 1111.

3+7=10≯11  ⇒  NOT a triangle✗3 + 7 = 10 \not> 11 \;\Rightarrow\; \text{NOT a triangle} ✗

Valid or Not? 🔽

Use the shortcut — add the two shortest sides and compare with the longest.

Apply the Shortcut 🧮

For each set of sides, add the two shortest sides, then decide.

1) Sides 77, 99, 44 — what is the sum of the two shortest sides? 2) Sides 33, 55, 99 — what is the sum of the two shortest sides?

Part 2: The Range of the Third Side

📐 Triangle Inequalities

Part 2 of 5 — The Range of the Third Side


🔑 The Question: If two sides of a triangle are aa and bb, how long can the third side xx be? Not anything — it's trapped between a smallest and largest value.

Boxing In the Third Side

Suppose two sides are aa and bb. Let the third side be xx. The triangle inequality gives us two useful bounds:

  • From a+b>xa + b > x: the third side must be less than the sum. So   x<a+b\;x < a + b.
  • From a+x>ba + x > b and b+x>ab + x > a: the third side must be more than the difference. So   x>∣a−b∣\;x > |a - b|.

Putting them together:

∣a−b∣<x<a+b|a - b| < x < a + b

🔑 Range Rule: The third side is bigger than the difference of the other two and smaller than their sum.

Example: Two sides are 77 and 1010

∣10−7∣<x<10+7|10 - 7| < x < 10 + 7 3<x<173 < x < 17

So the third side can be anything strictly between 33 and 1717.

Concept Check 🎯

Worked Example: Counting Whole-Number Possibilities

Two sides of a triangle are 44 and 99. How many whole-number values are possible for the third side?

Step 1 — Find the range. ∣9−4∣<x<9+4  ⇒  5<x<13|9 - 4| < x < 9 + 4 \;\Rightarrow\; 5 < x < 13

Step 2 — List the whole numbers strictly between 55 and 1313.

x=6,  7,  8,  9,  10,  11,  12x = 6,\; 7,\; 8,\; 9,\; 10,\; 11,\; 12

Step 3 — Count them. That's 7\mathbf{7} possible whole-number lengths.

⚠️ The endpoints 55 and 1313 are excluded — the inequality is strict, so x=5x = 5 and x=13x = 13 would give degenerate (flat) triangles.

💡 Shortcut for counting whole numbers strictly between two integers mm and nn (with m<nm < n): there are n−m−1n - m - 1 of them. Here 13−5−1=713 - 5 - 1 = 7. ✓

Find the Range 🧮

For each pair of sides, enter the smallest and largest strict bounds for the third side xx, where low<x<high\text{low} < x < \text{high}.

1) Sides 99 and 1414: low = ?= \,? , high = ?= \,? 2) Sides 1111 and 1111: low = ?= \,? , high = ?= \,?

Count the Possibilities 🧮

1) Two sides are 55 and 88. How many whole-number values are possible for the third side? 2) Two sides are 1010 and 1010. How many whole-number values are possible for the third side?

Part 3: Sides, Angles & Their Order

📐 Triangle Inequalities

Part 3 of 5 — Sides, Angles & Their Order


🔑 The Big Idea: Inside any triangle, the longest side and the largest angle are partners — they always sit opposite each other. The shortest side faces the smallest angle.

The Side–Angle Relationship

🔑 Theorem (Side–Angle Inequality): In any triangle, the larger angle is opposite the longer side, and the longer side is opposite the larger angle. The ordering of the sides exactly matches the ordering of the angles opposite them.

Think of an angle as how "wide open" a corner is. A wider corner forces the side across from it to stretch farther.

Example

In a triangle, suppose the angles are 50°50°, 60°60°, and 70°70°. Then the sides opposite them, from shortest to longest, are:

AngleSide opposite itRank
50°50° (smallest)shortest side1st
60°60° (middle)middle side2nd
70°70° (largest)longest side3rd

💡 "Big angle → big side across from it." Just match the order: smallest angle to shortest side, largest angle to longest side.

Reading a Labeled Triangle

A side is named by the two vertices at its ends; the angle "opposite" a side is the vertex not on that side.

In triangle ABCABC:

  • Side BCBC is opposite vertex AA (angle AA).
  • Side ACAC is opposite vertex BB (angle BB).
  • Side ABAB is opposite vertex CC (angle CC).

Example

In triangle ABCABC, ∠A=80°\angle A = 80°, ∠B=60°\angle B = 60°, ∠C=40°\angle C = 40°.

The largest angle is ∠A\angle A, so the longest side is the one opposite AA, namely BCBC.

The smallest angle is ∠C\angle C, so the shortest side is opposite CC, namely ABAB.

⚠️ A common slip is naming the side touching the big angle. The longest side is the one across from (opposite) the largest angle, not next to it.

Match Side to Angle 🔽

In triangle ABCABC, ∠A=75°\angle A = 75°, ∠B=65°\angle B = 65°, ∠C=40°\angle C = 40°.

Going the Other Way: Sides → Angles

The relationship works in both directions. If you know the sides, you can rank the angles.

Example: Sides AB=9AB = 9, BC=5BC = 5, CA=7CA = 7

Rank the sides shortest → longest: BC=5<CA=7<AB=9BC = 5 < CA = 7 < AB = 9.

The angle opposite each side follows the same order:

  • Opposite BCBC is ∠A\angle A → smallest angle.
  • Opposite CACA is ∠B\angle B → middle angle.
  • Opposite ABAB is ∠C\angle C → largest angle.

So ∠A<∠B<∠C\angle A < \angle B < \angle C.

💡 To rank angles from side lengths: find which side each angle is opposite, then the angles line up in the same order as those opposite sides.

Concept Check 🎯

Largest and Smallest 🧮

A triangle has angles 55°55°, 48°48°, and 77°77° (in degrees).

1) The longest side is opposite the angle measuring how many degrees? 2) The shortest side is opposite the angle measuring how many degrees?

Part 4: Exterior Angles & Ordering in Practice

📐 Triangle Inequalities

Part 4 of 5 — Exterior Angles & Ordering in Practice


🔑 Two more tools: the Exterior Angle Inequality (an exterior angle beats each far interior angle) and a reliable routine for ordering sides when you only know the angles — even when one angle is hidden.

The Exterior Angle Inequality

Extend one side of a triangle past a vertex; the angle formed outside is an exterior angle. The two interior angles not next to it are its remote interior angles.

🔑 Exterior Angle Inequality: An exterior angle of a triangle is greater than either of its two remote interior angles.

This is actually a consequence of the Exterior Angle Theorem, which says the exterior angle equals the sum of the two remote interior angles:

exterior=remote1+remote2\text{exterior} = \text{remote}_1 + \text{remote}_2

Since each remote angle is positive, the exterior angle must exceed each one individually.

Example

A triangle has remote interior angles of 45°45° and 70°70° for a given exterior angle.

exterior=45°+70°=115°\text{exterior} = 45° + 70° = 115°

And indeed 115°>45°115° > 45° and 115°>70°115° > 70°. ✓

💡 The exterior angle and the interior angle at the same vertex are supplementary (they add to 180°180°). Here the interior angle is 180°−115°=65°180° - 115° = 65°.

Exterior Angles 🧮

A triangle has interior angles AA, BB, and CC.

1) The remote interior angles for the exterior angle at CC are A=55°A = 55° and B=80°B = 80°. What is that exterior angle (in degrees)? 2) Using your answer, what is interior angle CC (in degrees)?

Ordering Sides When an Angle Is Missing

Often a problem gives two angles and asks you to order the sides. The trick: the three angles of a triangle always sum to 180°180°, so the missing angle is 180°180° minus the other two.

Example: Angles 40°40° and 75°75° are given

Find the third angle:

180°−40°−75°=65°180° - 40° - 75° = 65°

Now order the angles: 40°<65°<75°40° < 65° < 75°.

The sides opposite, from shortest to longest, follow that exact order:

  • shortest side opposite 40°40°,
  • middle side opposite 65°65°,
  • longest side opposite 75°75°.

⚠️ Don't forget to find the missing angle first. Comparing only the two given angles can hide which side is truly longest.

Order Everything 🔽

In triangle XYZXYZ, ∠X=35°\angle X = 35° and ∠Y=95°\angle Y = 95°.

Concept Check 🎯

Part 5: Mixed Practice & Mastery Check

📐 Triangle Inequalities

Part 5 of 5 — Mixed Practice & Mastery Check


You can now (1) test whether three lengths form a triangle, (2) find the range for a missing side, (3) match sides to angles, and (4) use exterior angles and ordering. Let's put it all together.

Quick Reference

GoalKey rule
Do a,b,ca,b,c form a triangle?sum of two shortest >> longest (strict)
Range of third side xx (sides a,ba,b)∣a−b∣<x<a+b\lvert a-b\rvert < x < a+b
Count whole-number sidesintegers strictly between the bounds
Longest sideopposite the largest angle
Shortest sideopposite the smallest angle
Exterior angle== sum of the two remote interiors

⚠️ Two habits that prevent most mistakes: use strict inequalities (>>, never ≥\geq), and always pair a side with the angle opposite it — never the angle beside it.

Mixed Practice 🎯

One More Range 🧮

Two sides of a triangle measure 1313 and 66.

1) Smallest strict bound for the third side xx (the low end):  ?\,? 2) Largest strict bound for the third side xx (the high end):  ?\,? 3) Number of whole-number values possible for xx:  ?\,?

Exit Quiz ✅

Answer all three to finish the lesson.