Triangle Inequalities
Apply triangle inequality theorem
Triangle inequalities content
📚 Practice Problems
1Problem 1easy
❓ Question:
Can a triangle have sides of length 3, 7, and 12? Explain why or why not.
💡 Show Solution
Step 1: Recall the Triangle Inequality Theorem: The sum of any two sides of a triangle must be greater than the third side
Step 2: Check all three combinations: Test 1: 3 + 7 > 12? 10 > 12? NO ✗
Test 2: 3 + 12 > 7? 15 > 7? YES ✓
Test 3: 7 + 12 > 3? 19 > 3? YES ✓
Step 3: Analyze the results: Since 3 + 7 is NOT greater than 12, the Triangle Inequality is violated
Step 4: Conclusion: These three lengths cannot form a triangle The two shorter sides (3 and 7) aren't long enough to reach around the longest side (12)
Answer: No, these cannot form a triangle because 3 + 7 ≯ 12
2Problem 2easy
❓ Question:
Two sides of a triangle measure 5 and 8. What are the possible lengths for the third side?
💡 Show Solution
Step 1: Use Triangle Inequality Theorem: The third side must satisfy:
- 5 + 8 > third side
- 5 + third side > 8
- 8 + third side > 5
Step 2: Simplify each inequality: From first: third side < 13 From second: third side > 3 From third: third side > -3 (always true for positive lengths)
Step 3: Combine the restrictions: third side > 3 AND third side < 13 Therefore: 3 < third side < 13
Step 4: Interpret: The third side must be greater than 3 and less than 13
Step 5: Note the pattern: The third side must be between:
- The difference of the two known sides: |8 - 5| = 3
- The sum of the two known sides: 8 + 5 = 13
Answer: The third side must be greater than 3 and less than 13 (3 < x < 13)
3Problem 3medium
❓ Question:
In triangle ABC, AB = 10, BC = 6. What is the range of possible values for AC?
💡 Show Solution
Step 1: Apply Triangle Inequality: The third side must be between the difference and the sum of the two known sides
Step 2: Find the minimum (difference): Minimum = |10 - 6| = 4 AC must be greater than 4
Step 3: Find the maximum (sum): Maximum = 10 + 6 = 16 AC must be less than 16
Step 4: Express the range: 4 < AC < 16
Step 5: Verify with extreme cases: If AC = 4: sides would be 10, 6, 4 Check: 6 + 4 = 10 (not greater than) ✗ If AC = 4.1: 6 + 4.1 = 10.1 > 10 ✓
If AC = 16: sides would be 10, 6, 16 Check: 10 + 6 = 16 (not greater than) ✗ If AC = 15.9: 10 + 6 = 16 > 15.9 ✓
Answer: 4 < AC < 16
4Problem 4medium
❓ Question:
In triangle DEF, side DE = 2x, side EF = x + 5, and side DF = 12. If the triangle exists, what are the possible values of x?
💡 Show Solution
Step 1: Apply all three Triangle Inequalities:
- DE + EF > DF: (2x) + (x + 5) > 12
- DE + DF > EF: (2x) + 12 > (x + 5)
- EF + DF > DE: (x + 5) + 12 > (2x)
Step 2: Solve inequality 1: 2x + x + 5 > 12 3x + 5 > 12 3x > 7 x > 7/3 x > 2.33...
Step 3: Solve inequality 2: 2x + 12 > x + 5 x + 12 > 5 x > -7 (Always true for positive x)
Step 4: Solve inequality 3: x + 5 + 12 > 2x x + 17 > 2x 17 > x x < 17
Step 5: Combine all restrictions: x > 7/3 AND x < 17 Therefore: 7/3 < x < 17 Or: 2.33... < x < 17
Step 6: Also ensure all sides are positive: 2x > 0 → x > 0 x + 5 > 0 → x > -5 The binding constraint is x > 7/3
Answer: 7/3 < x < 17 (approximately 2.33 < x < 17)
5Problem 5hard
❓ Question:
Using the Hinge Theorem: In triangles ABC and DEF, AB = DE = 8, AC = DF = 10, and angle A = 60° while angle D = 45°. Which is longer: BC or EF?
💡 Show Solution
Step 1: Understand the Hinge Theorem (SAS Inequality): If two sides of one triangle are congruent to two sides of another triangle, but the included angle of the first is larger, then the third side of the first triangle is longer than the third side of the second triangle
Step 2: Identify the given information: Triangle ABC: sides AB = 8, AC = 10, included angle A = 60° Triangle DEF: sides DE = 8, DF = 10, included angle D = 45°
Step 3: Compare the included angles: Angle A = 60° Angle D = 45° Therefore: Angle A > Angle D
Step 4: Apply the Hinge Theorem: Since AB = DE, AC = DF, and angle A > angle D, then BC > EF
Step 5: Conceptual understanding: The larger included angle (60°) "pushes" the opposite side (BC) farther apart than the smaller angle (45°) pushes EF apart
Think of it like opening a door:
- Opening 60° creates a wider gap than opening 45°
Answer: BC > EF (BC is longer than EF)
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