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🎯⭐ INTERACTIVE LESSON

Polynomials and Factoring

Learn step-by-step with interactive practice!

Polynomials and Factoring - Complete Interactive Lesson

Part 1: Polynomial Basics

Polynomials & Factoring

Part 1 of 7 — Polynomial Basics

What is a Polynomial?

A polynomial is an expression with one or more terms: anxn+an−1xn−1+⋯+a1x+a0a_nx^n + a_{n-1}x^{n-1} + \cdots + a_1x + a_0

  • Degree: highest power of xx (e.g., 3x4+2x−13x^4 + 2x - 1 has degree 4)
  • Leading coefficient: coefficient of the highest-degree term
  • Constant term: the term with no variable (a0a_0)

Adding & Subtracting Polynomials

Combine like terms (same variable and exponent):

(3x2+5x−2)+(x2−3x+7)=4x2+2x+5(3x^2 + 5x - 2) + (x^2 - 3x + 7) = 4x^2 + 2x + 5

(3x2+5x−2)−(x2−3x+7)=3x2+5x−2−x2+3x−7=2x2+8x−9(3x^2 + 5x - 2) - (x^2 - 3x + 7) = 3x^2 + 5x - 2 - x^2 + 3x - 7 = 2x^2 + 8x - 9

Subtraction trap: distribute the negative sign to ALL terms in the second polynomial!

Multiplying Polynomials

Use distribution (FOIL for binomials):

(2x+3)(x−4)=2x2−8x+3x−12=2x2−5x−12(2x + 3)(x - 4) = 2x^2 - 8x + 3x - 12 = 2x^2 - 5x - 12


Worked Example 1 — Multiplying Three Factors

Expand (x+1)(x−3)(x+2)(x + 1)(x - 3)(x + 2).

StepWork
First two factors(x+1)(x−3)=x2−2x−3(x+1)(x-3) = x^2 - 2x - 3
Multiply by third(x2−2x−3)(x+2)(x^2 - 2x - 3)(x + 2)
Distribute xxx3−2x2−3xx^3 - 2x^2 - 3x
Distribute 222x2−4x−62x^2 - 4x - 6
Combinex3−2x2+2x2−3x−4x−6=x3−7x−6x^3 - 2x^2 + 2x^2 - 3x - 4x - 6 = x^3 - 7x - 6

Worked Example 2 — Subtraction Trap

Simplify (5x3−x2+4)−(3x3+2x2−x+1)(5x^3 - x^2 + 4) - (3x^3 + 2x^2 - x + 1).

StepWork
Distribute negative5x3−x2+4−3x3−2x2+x−15x^3 - x^2 + 4 - 3x^3 - 2x^2 + x - 1
Combine x3x^32x32x^3
Combine x2x^2−3x2-3x^2
Combine xxxx
Combine constants33
Result2x3−3x2+x+32x^3 - 3x^2 + x + 3

Polynomial Operations 🎯

Special Products to Memorize

PatternExpansion
(a+b)2(a + b)^2a2+2ab+b2a^2 + 2ab + b^2
(a−b)2(a - b)^2a2−2ab+b2a^2 - 2ab + b^2
(a+b)(a−b)(a + b)(a - b)a2−b2a^2 - b^2
(a+b)3(a + b)^3a3+3a2b+3ab2+b3a^3 + 3a^2b + 3ab^2 + b^3

Worked Example 3 — Using Special Products

Expand (3x−2)2(3x - 2)^2.

StepWork
Apply (a−b)2(a - b)^2(3x)2−2(3x)(2)+(2)2(3x)^2 - 2(3x)(2) + (2)^2
Simplify9x2−12x+49x^2 - 12x + 4

⚠️ Common mistake: (3x−2)2≠9x2−4(3x - 2)^2 \neq 9x^2 - 4. You must include the middle term!

Degree of a Product

The degree of a product equals the sum of the degrees.

(2x3+1)(x2−5x)→degree 3+2=5(2x^3 + 1)(x^2 - 5x) \to \text{degree } 3 + 2 = 5

Special Products & Degree 🎯

Identify the Property 🔍

For each expression, identify what type of operation or pattern it represents.

Key Takeaways — Part 1

ConceptKey Point
DegreeHighest exponent (not first term!)
SubtractionDistribute negative to ALL terms
(a+b)2(a+b)^2a2+2ab+b2a^2 + 2ab + b^2 (don't forget middle term)
(a+b)(a−b)(a+b)(a-b)a2−b2a^2 - b^2
Degree of productSum of degrees
  • Combine like terms as the final step after every operation
  • FOIL is just distribution for two binomials — use full distribution for larger products
  • Special products save time and reduce errors on the SAT

Part 2: Factoring Techniques

Polynomials & Factoring

Part 2 of 7 — Factoring Techniques

GCF Factoring

Always look for a Greatest Common Factor first:

6x3+9x2=3x2(2x+3)6x^3 + 9x^2 = 3x^2(2x + 3)

Difference of Squares

a2−b2=(a+b)(a−b)a^2 - b^2 = (a + b)(a - b)

Example: x2−49=(x+7)(x−7)x^2 - 49 = (x + 7)(x - 7)

Tricky example: 4x2−25=(2x)2−52=(2x+5)(2x−5)4x^2 - 25 = (2x)^2 - 5^2 = (2x + 5)(2x - 5)

Perfect Square Trinomials

a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a + b)^2 a2−2ab+b2=(a−b)2a^2 - 2ab + b^2 = (a - b)^2

How to recognize: first and last terms are perfect squares, middle term is ±2×first×last\pm 2 \times \sqrt{\text{first}} \times \sqrt{\text{last}}.

x2+10x+25=(x+5)2x^2 + 10x + 25 = (x + 5)^2 because 2(x)(5)=10x2(x)(5) = 10x ✓

Sum/Difference of Cubes (Rare on SAT)

a3+b3=(a+b)(a2−ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2) a3−b3=(a−b)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2)


Worked Example 1 — Multi-Step Factoring

Factor completely: 2x3−18x2x^3 - 18x.

StepWork
GCF2x(x2−9)2x(x^2 - 9)
Difference of squares2x(x+3)(x−3)2x(x + 3)(x - 3)

Worked Example 2 — Recognizing Perfect Squares

Is 9x2−30x+259x^2 - 30x + 25 a perfect square trinomial?

CheckResult
First term: (3x)2(3x)^2?Yes ✓
Last term: 525^2?Yes ✓
Middle: 2(3x)(5)=30x2(3x)(5) = 30x?Yes ✓
Factor(3x−5)2(3x - 5)^2

Factoring Patterns 🎯

Factoring Trinomials: ax2+bx+cax^2 + bx + c

When a=1a = 1: Find two numbers that multiply to cc and add to bb.

x2+7x+12x^2 + 7x + 12: numbers that multiply to 1212 and add to 77? → 33 and 44.

=(x+3)(x+4)= (x + 3)(x + 4)

When a≠1a \neq 1: Use the AC method.

Worked Example 3 — AC Method

Factor 6x2+11x−106x^2 + 11x - 10.

StepWork
a⋅ca \cdot c6×(−10)=−606 \times (-10) = -60
Find pair: product −60-60, sum 11111515 and −4-4
Rewrite middle6x2+15x−4x−106x^2 + 15x - 4x - 10
Group(6x2+15x)+(−4x−10)(6x^2 + 15x) + (-4x - 10)
Factor groups3x(2x+5)−2(2x+5)3x(2x + 5) - 2(2x + 5)
Extract common(3x−2)(2x+5)(3x - 2)(2x + 5)

Worked Example 4 — Signs Guide

If c>0c > 0, b>0b > 0Both factors positive(x+?)(x+?)(x + ?)(x + ?)
If c>0c > 0, b<0b < 0Both factors negative(x−?)(x−?)(x - ?)(x - ?)
If c<0c < 0One positive, one negative(x+?)(x−?)(x + ?)(x - ?)

Trinomial Factoring 🎯

What Factoring Method? 🔍

Choose the best factoring technique for each expression.

Key Takeaways — Part 2

MethodWhen to UseExample
GCFAlways check first6x3+9x2=3x2(2x+3)6x^3 + 9x^2 = 3x^2(2x+3)
Diff. of squaresa2−b2a^2 - b^2x2−49=(x+7)(x−7)x^2 - 49 = (x+7)(x-7)
Perfect squarea2±2ab+b2a^2 \pm 2ab + b^2x2+10x+25=(x+5)2x^2 + 10x + 25 = (x+5)^2
Trinomial (a=1a=1)Find pair: product cc, sum bbx2+7x+12=(x+3)(x+4)x^2 + 7x + 12 = (x+3)(x+4)
AC method (a≠1a \neq 1)Product acac, sum bb, then group6x2+11x−106x^2 + 11x - 10
  • "Factor completely" = keep going until nothing else factors
  • a2+b2a^2 + b^2 does NOT factor over the reals
  • Signs of bb and cc tell you the signs of the factor pair

Part 3: Special Products

Polynomials & Factoring

Part 3 of 7 — Polynomial Division

Long Division

Divide x3+2x2−5x+6x^3 + 2x^2 - 5x + 6 by x−1x - 1:

  1. x3÷x=x2x^3 \div x = x^2. Multiply: x2(x−1)=x3−x2x^2(x-1) = x^3 - x^2. Subtract: 3x2−5x3x^2 - 5x
  2. 3x2÷x=3x3x^2 \div x = 3x. Multiply: 3x(x−1)=3x2−3x3x(x-1) = 3x^2 - 3x. Subtract: −2x+6-2x + 6
  3. −2x÷x=−2-2x \div x = -2. Multiply: −2(x−1)=−2x+2-2(x-1) = -2x + 2. Subtract: 44

Result: x2+3x−2x^2 + 3x - 2 remainder 44.

Synthetic Division (Faster!)

For dividing by (x−c)(x - c): write the coefficients, bring down, multiply, add.

Dividing x3+2x2−5x+6x^3 + 2x^2 - 5x + 6 by (x−1)(x - 1):

12-56
1↓13-2
13-24

Result: x2+3x−2x^2 + 3x - 2 with remainder 44.

The Remainder Theorem

The remainder when f(x)f(x) is divided by (x−c)(x - c) equals f(c)f(c).

Check: f(1)=1+2−5+6=4f(1) = 1 + 2 - 5 + 6 = 4 ✓


Worked Example 1 — Missing Term Trap

Divide x3−8x^3 - 8 by (x−2)(x - 2).

StepWork
Include 0 placeholdersCoefficients: 1,0,0,−81, 0, 0, -8
Synthetic with c=2c = 2Bring down 1 → 1⋅2=21 \cdot 2 = 2 → 0+2=20 + 2 = 2 → 2⋅2=42 \cdot 2 = 4 → 0+4=40 + 4 = 4 → 4⋅2=84 \cdot 2 = 8 → −8+8=0-8 + 8 = 0
Resultx2+2x+4x^2 + 2x + 4, remainder 00

So x3−8=(x−2)(x2+2x+4)x^3 - 8 = (x - 2)(x^2 + 2x + 4) — this is the difference of cubes formula!

Worked Example 2 — Using Remainder Theorem Strategically

Is (x+2)(x + 2) a factor of 2x3+x2−7x+22x^3 + x^2 - 7x + 2?

StepWork
(x+2)=(x−(−2))(x + 2) = (x - (-2)), so c=−2c = -2
Evaluate f(−2)f(-2)2(−8)+(4)−7(−2)+22(-8) + (4) - 7(-2) + 2
Simplify−16+4+14+2=4-16 + 4 + 14 + 2 = 4
Remainder4≠04 \neq 0, so NO — not a factor

Polynomial Division 🎯

Writing the Result of Division

f(x)d(x)=q(x)+rd(x)\frac{f(x)}{d(x)} = q(x) + \frac{r}{d(x)}

Example: x2+3x+5x+1=x+2+3x+1\frac{x^2 + 3x + 5}{x + 1} = x + 2 + \frac{3}{x + 1}

This form appears on the SAT! They may ask "what is the remainder" or "rewrite the expression."

Worked Example 3

Rewrite x2−4x+7x−1\frac{x^2 - 4x + 7}{x - 1} in quotient-remainder form.

StepWork
Dividef(1)=1−4+7=4f(1) = 1 - 4 + 7 = 4 → remainder is 44
Synthetic: c=1c = 1Coefficients 1,−4,71, -4, 7 → result 1,−31, -3 remainder 44
Write resultx−3+4x−1x - 3 + \frac{4}{x - 1}

SAT Shortcut: Remainder without Division

To find just the remainder of f(x)÷(x−c)f(x) \div (x - c), simply compute f(c)f(c). No division needed!

Division Applications 🎯

Remainder Theorem Quick Check 🔍

Find the remainder without doing long division.

Key Takeaways — Part 3

ToolPurposeSpeed
Long divisionAny divisorSlow
Synthetic divisionDivisor (x−c)(x - c) onlyFast
Remainder TheoremFind remainder onlyFastest
Factor TheoremCheck if factorFastest
  • Remainder Theorem: f(x)÷(x−c)f(x) \div (x-c) → remainder =f(c)= f(c)
  • Factor Theorem: (x−c)(x - c) is a factor iff f(c)=0f(c) = 0
  • Include 00 coefficients for missing terms (e.g., x3−8x^3 - 8 → 1,0,0,−81, 0, 0, -8)
  • Division result: f(x)=d(x)⋅q(x)+rf(x) = d(x) \cdot q(x) + r

Part 4: Polynomial Division

Polynomials & Factoring

Part 4 of 7 — Zeros, Roots, and the Factor Theorem

Zeros = Roots = x-intercepts

These terms all mean the same thing: the values of xx where f(x)=0f(x) = 0.

If f(x)=(x−2)(x+5)(x−1)f(x) = (x - 2)(x + 5)(x - 1), the zeros are x=2,−5,1x = 2, -5, 1.

Multiplicity

The multiplicity of a zero is how many times its factor appears.

f(x)=(x−3)2(x+1)f(x) = (x - 3)^2(x + 1):

  • x=3x = 3 has multiplicity 2 (graph touches x-axis and bounces)
  • x=−1x = -1 has multiplicity 1 (graph crosses x-axis)

End Behavior

DegreeLeading Coeff.Left EndRight End
EvenPositive↑↑
EvenNegative↓↓
OddPositive↓↑
OddNegative↑↓

SAT Connection

The SAT asks: "How many x-intercepts does the graph of f(x)=x3−4xf(x) = x^3 - 4x have?"

Factor: x(x2−4)=x(x−2)(x+2)x(x^2 - 4) = x(x-2)(x+2). Three distinct factors → 3 x-intercepts.


Worked Example 1 — Building a Polynomial from Zeros

Find a polynomial with zeros at x=−1,2,5x = -1, 2, 5 and leading coefficient 33.

StepWork
Write factors(x+1)(x−2)(x−5)(x + 1)(x - 2)(x - 5)
Apply leading coeff.3(x+1)(x−2)(x−5)3(x + 1)(x - 2)(x - 5)

Worked Example 2 — Finding aa from a Point

f(x)=a(x−1)(x+3)f(x) = a(x - 1)(x + 3) passes through (2,10)(2, 10). Find aa.

StepWork
Substitute (2,10)(2, 10)10=a(2−1)(2+3)10 = a(2 - 1)(2 + 3)
Simplify10=a(1)(5)=5a10 = a(1)(5) = 5a
Solvea=2a = 2
Answerf(x)=2(x−1)(x+3)f(x) = 2(x - 1)(x + 3)

Zeros & End Behavior 🎯

Multiplicity and Graph Behavior

MultiplicityGraph at that zeroExample
1 (odd)Crosses x-axisf(x)=x−2f(x) = x - 2 at x=2x = 2
2 (even)Touches and bouncesf(x)=(x−2)2f(x) = (x - 2)^2 at x=2x = 2
3 (odd)Crosses with inflectionf(x)=(x−2)3f(x) = (x - 2)^3 at x=2x = 2

Worked Example 3 — Degree from Graph

A graph crosses the x-axis at x=−3x = -3 and x=4x = 4, and bounces at x=1x = 1. Both ends point downward. What is the minimum degree?

ZeroMin. multiplicity
x=−3x = -3 (crosses)1
x=1x = 1 (bounces)2
x=4x = 4 (crosses)1
Min. degree1+2+1=41 + 2 + 1 = 4

Both ends down → even degree, negative leading coefficient ✓ (degree 4 is even).

Worked Example 4 — Number of Real Zeros

f(x)=x4−5x2+4f(x) = x^4 - 5x^2 + 4. How many x-intercepts?

StepWork
Let u=x2u = x^2u2−5u+4=(u−1)(u−4)u^2 - 5u + 4 = (u-1)(u-4)
Back-substitute(x2−1)(x2−4)=(x+1)(x−1)(x+2)(x−2)(x^2-1)(x^2-4) = (x+1)(x-1)(x+2)(x-2)
Count4 distinct x-intercepts

Graph Analysis 🎯

Match the Graph Feature 🔍

What does each piece of information tell you?

Key Takeaways — Part 4

ConceptKey Rule
Zeros from factors(x−r)(x - r) → zero at x=rx = r
Even multiplicityGraph bounces at zero
Odd multiplicityGraph crosses at zero
End behaviorDegree (even/odd) + sign of leading coeff.
Max turning pointsDegree minus 1
Build polynomialf(x)=a(x−r1)(x−r2)⋯f(x) = a(x - r_1)(x - r_2)\cdots
  • Given zeros + one point → find aa by substitution
  • Number of real zeros ≤ degree of polynomial
  • The SAT often shows a graph and asks for the equation — read zeros + end behavior first

Part 5: Zeros & Roots

Polynomials & Factoring

Part 5 of 7 — Rational Expressions

Simplifying Rational Expressions

A rational expression is a fraction with polynomials:

x2−9x2+5x+6=(x+3)(x−3)(x+2)(x+3)=x−3x+2(x≠−3)\frac{x^2 - 9}{x^2 + 5x + 6} = \frac{(x+3)(x-3)}{(x+2)(x+3)} = \frac{x - 3}{x + 2} \quad (x \neq -3)

Steps: Factor numerator and denominator, then cancel common factors.

Multiplying & Dividing

Multiply: Factor, cancel, then multiply what remains.

x2−4x+1⋅x+1x−2=(x+2)(x−2)x+1⋅x+1x−2=x+2\frac{x^2 - 4}{x + 1} \cdot \frac{x + 1}{x - 2} = \frac{(x+2)(x-2)}{x+1} \cdot \frac{x+1}{x-2} = x + 2

Divide: Flip the second fraction and multiply.

Adding & Subtracting

Find a common denominator:

2x+1+3x−1=2(x−1)+3(x+1)(x+1)(x−1)=5x+1x2−1\frac{2}{x+1} + \frac{3}{x-1} = \frac{2(x-1) + 3(x+1)}{(x+1)(x-1)} = \frac{5x + 1}{x^2 - 1}

Undefined Values (Domain Restrictions)

A rational expression is undefined when the denominator equals zero. The SAT asks: "What value of xx makes the expression undefined?"


Worked Example 1 — Multi-step Simplification

Simplify 2x2−8x2−x−2\frac{2x^2 - 8}{x^2 - x - 2}.

StepWork
Factor numerator2(x2−4)=2(x+2)(x−2)2(x^2 - 4) = 2(x+2)(x-2)
Factor denominator(x−2)(x+1)(x-2)(x+1)
Cancel (x−2)(x-2)2(x+2)x+1\frac{2(x+2)}{x+1}, x≠2x \neq 2

Worked Example 2 — Subtracting with LCD

xx+3−2x−1\frac{x}{x+3} - \frac{2}{x-1}

StepWork
LCD(x+3)(x−1)(x+3)(x-1)
Rewritex(x−1)−2(x+3)(x+3)(x−1)\frac{x(x-1) - 2(x+3)}{(x+3)(x-1)}
Expandx2−x−2x−6(x+3)(x−1)=x2−3x−6(x+3)(x−1)\frac{x^2 - x - 2x - 6}{(x+3)(x-1)} = \frac{x^2 - 3x - 6}{(x+3)(x-1)}

Rational Expressions 🎯

Complex Fractions

A complex fraction has a fraction in the numerator, denominator, or both:

1x+1y1x−1y\frac{\frac{1}{x} + \frac{1}{y}}{\frac{1}{x} - \frac{1}{y}}

Strategy: Multiply the top and bottom by the LCD of all the little fractions.

Worked Example 3 — Simplifying a Complex Fraction

Simplify 1x−131x+13\frac{\frac{1}{x} - \frac{1}{3}}{\frac{1}{x} + \frac{1}{3}}.

StepWork
LCD of inner fractions3x3x
Multiply top and bottom by 3x3x3x⋅1x−3x⋅133x⋅1x+3x⋅13\frac{3x \cdot \frac{1}{x} - 3x \cdot \frac{1}{3}}{3x \cdot \frac{1}{x} + 3x \cdot \frac{1}{3}}
Simplify3−x3+x\frac{3 - x}{3 + x}

Common SAT Trap — Canceling Terms vs. Factors

ExpressionCan you cancel?Why?
(x+2)(x−3)(x+2)\frac{(x+2)(x-3)}{(x+2)}✅ Yes(x+2)(x+2) is a factor of both
x+2x+5\frac{x + 2}{x + 5}❌ Noxx is a term, not a factor
x2+xx\frac{x^2 + x}{x}✅ YesFactor first: x(x+1)x=x+1\frac{x(x+1)}{x} = x + 1

Rule: You can only cancel common factors — never individual terms.

Advanced Rational Expressions 🎯

Simplification Check 🔍

Is each simplification valid?

Key Takeaways — Part 5

OperationProcedure
SimplifyFactor top & bottom → cancel common factors
MultiplyFactor all → cancel across → multiply
DivideFlip 2nd fraction → multiply
Add/SubtractFind LCD → combine numerators
Complex fractionMultiply top & bottom by LCD of inner fractions
Common TrapFix
Canceling terms (x+2x+5\frac{x+2}{x+5})Only cancel factors
Forgetting restrictionsState x≠x \neq (zeros of original denominator)
Sign errors in subtractionDistribute the minus to ALL terms
  • Matching numerators: when two rational expressions are equal, set the numerators equal and plug in convenient xx-values to find unknown constants

Part 6: Problem-Solving Workshop

Polynomials & Factoring

Part 6 of 7 — Polynomial Graphs and Transformations

Reading Polynomial Graphs

From a graph, you can determine:

  • Zeros: where the curve crosses/touches the x-axis
  • y-intercept: where the curve crosses the y-axis (the constant term)
  • Degree: count the number of turns + 1 (approximately)
  • Leading coefficient sign: from end behavior

Transformations

For f(x)=x3f(x) = x^3:

TransformationEquationEffect
Vertical shift up kkf(x)+kf(x) + kGraph moves up
Horizontal shift right hhf(x−h)f(x - h)Graph moves right
Vertical stretch by aaaf(x)af(x)Taller/narrower
Reflection over x-axis−f(x)-f(x)Flip upside down
Reflection over y-axisf(−x)f(-x)Flip left-right

SAT Graph Reading Strategy

When the SAT shows a polynomial graph and asks for the equation:

  1. Read the x-intercepts → write factors
  2. Check end behavior → determine sign of leading coefficient
  3. Check one more point (often the y-intercept) → determine the leading coefficient

Worked Example 1 — From Graph to Equation

A graph crosses at x=−1x = -1 and x=4x = 4, bounces at x=2x = 2, and passes through (0,−16)(0, -16). Find the equation.

StepWork
Write factorsa(x+1)(x−4)(x−2)2a(x + 1)(x - 4)(x - 2)^2
Use (0,−16)(0, -16)a(1)(−4)(4)=−16a=−16a(1)(-4)(4) = -16a = -16
Solvea=1a = 1
Answerf(x)=(x+1)(x−4)(x−2)2f(x) = (x+1)(x-4)(x-2)^2

Worked Example 2 — Transformation Chain

If f(x)=x3f(x) = x^3, describe the graph of g(x)=−2(x+1)3+5g(x) = -2(x + 1)^3 + 5.

TransformationRuleEffect
(x+1)3(x + 1)^3f(x−h)f(x - h) with h=−1h = -1Shift left 1
2(⋯ )2(\cdots)af(x)af(x) with a=2a = 2Vertical stretch by 2
−(⋯ )-(\cdots)−f(x)-f(x)Reflect over x-axis
+5+ 5f(x)+kf(x) + kShift up 5

The inflection point moves from (0,0)(0, 0) to (−1,5)(-1, 5).

Polynomial Graphs 🎯

Matching Equations to Graphs — Decision Framework

On the SAT, you'll often see four equation choices and one graph (or vice versa). Here's how to eliminate quickly:

CheckWhat it tells youHow to read it
End behaviorDegree (even/odd) + signBoth ends same = even; opposite = odd
x-interceptsFactors and their multiplicityCrosses = odd mult.; bounces = even
y-interceptConstant termPlug x=0x = 0 into each answer choice
Number of turnsApproximate degreeTurns ≤ degree − 1

Worked Example 3 — Elimination by y-intercept

Which polynomial has y-intercept −6-6 and zeros at x=1,2,3x = 1, 2, 3?

Optiony-int (plug x=0x = 0)Match?
(x−1)(x−2)(x−3)(x-1)(x-2)(x-3)(−1)(−2)(−3)=−6(-1)(-2)(-3) = -6✅
2(x−1)(x−2)(x−3)2(x-1)(x-2)(x-3)2(−6)=−122(-6) = -12❌
−(x−1)(x−2)(x−3)-(x-1)(x-2)(x-3)−(−6)=6-(-6) = 6❌

Answer: (x−1)(x−2)(x−3)(x-1)(x-2)(x-3) — no extra coefficient needed.

Inside vs. Outside — Transformation Direction

A common SAT trap: shifts inside the function go the opposite direction.

WrittenDirection
f(x−3)f(x - 3)Right 3
f(x+3)f(x + 3)Left 3
f(x)−3f(x) - 3Down 3
f(x)+3f(x) + 3Up 3

Memory trick: Inside is "opposite" — outside is "obvious."

Graphs & Transformations 🎯

Transformation Identifier 🔍

What transformation does each change represent?

Key Takeaways — Part 6

SkillStrategy
Graph → EquationRead zeros, end behavior, y-intercept
Equation → GraphPlot zeros, check multiplicity, draw end behavior
TransformationsInside = horizontal (opposite); outside = vertical
EliminationPlug x=0x = 0 into choices to match y-intercept
TransformationDirection Rule
f(x−h)f(x - h)Right hh (opposite sign)
f(x+h)f(x + h)Left hh (opposite sign)
f(x)+kf(x) + kUp kk (same sign)
af(x)af(x), a>1a > 1Vertical stretch
−f(x)-f(x)Reflect over x-axis
  • On the SAT, always check the y-intercept — it's the fastest way to narrow four answer choices down to one

Part 7: Review & Applications

Polynomials & Factoring

Part 7 of 7 — Review & Advanced SAT Problems

Factoring Decision Tree

  1. GCF? Always check first
  2. Two terms? → Difference of squares (a2−b2a^2 - b^2) or sum/difference of cubes
  3. Three terms? → Trinomial factoring or completing the square
  4. Four terms? → Factor by grouping

Factor by Grouping

x3+3x2+2x+6x^3 + 3x^2 + 2x + 6:

  • Group: (x3+3x2)+(2x+6)(x^3 + 3x^2) + (2x + 6)
  • Factor each group: x2(x+3)+2(x+3)x^2(x + 3) + 2(x + 3)
  • Factor the common binomial: (x2+2)(x+3)(x^2 + 2)(x + 3)

Special SAT Pattern: Disguised Quadratics

x4−5x2+4x^4 - 5x^2 + 4: let u=x2u = x^2:

u2−5u+4=(u−1)(u−4)=(x2−1)(x2−4)=(x+1)(x−1)(x+2)(x−2)u^2 - 5u + 4 = (u - 1)(u - 4) = (x^2 - 1)(x^2 - 4) = (x+1)(x-1)(x+2)(x-2)

This technique works whenever you see ax2n+bxn+cax^{2n} + bx^n + c.


Worked Example 1 — Multi-layer Factoring

Factor completely: 3x3−12x3x^3 - 12x.

StepWork
GCF first3x(x2−4)3x(x^2 - 4)
Diff. of squares3x(x+2)(x−2)3x(x + 2)(x - 2)

Always start with GCF — it reveals hidden patterns.

Worked Example 2 — Algebraic Identity on the SAT

If a−b=7a - b = 7 and a2−b2=35a^2 - b^2 = 35, find a+ba + b.

StepWork
Recognize identitya2−b2=(a+b)(a−b)a^2 - b^2 = (a+b)(a-b)
Substitute35=(a+b)(7)35 = (a+b)(7)
Solvea+b=5a + b = 5

Advanced Factoring 🎯

Putting It All Together — SAT Strategy

On the SAT, factoring isn't always labeled "factor this." It often appears disguised:

SAT Question TypeFactoring Skill Needed
"Simplify the expression"Factor and cancel
"How many solutions?"Factor, count zeros
"What is the value of...?"Factor to reveal identity
"Which is equivalent?"Factor and match
"Find the zeros"Factor and solve

Worked Example 3 — SAT-Style Identity Problem

If 9x2−6x+1=09x^2 - 6x + 1 = 0, what is the value of 3x−13x - 1?

StepWork
Recognize9x2−6x+1=(3x−1)29x^2 - 6x + 1 = (3x - 1)^2
Set equal to 0(3x−1)2=0(3x - 1)^2 = 0
Solve3x−1=03x - 1 = 0

Answer: 3x−1=03x - 1 = 0. No need to find xx at all!

Worked Example 4 — Disguised Difference of Squares

Compute 10032−99721003^2 - 997^2 without a calculator.

StepWork
Identitya2−b2=(a+b)(a−b)a^2 - b^2 = (a+b)(a-b)
Apply(1003+997)(1003−997)=(2000)(6)(1003 + 997)(1003 - 997) = (2000)(6)
Answer12,00012{,}000

SAT Factoring Patterns Cheat Sheet

PatternFormulaExample
Difference of squaresa2−b2=(a+b)(a−b)a^2 - b^2 = (a+b)(a-b)x2−9=(x+3)(x−3)x^2 - 9 = (x+3)(x-3)
Perfect square trinomiala2±2ab+b2=(a±b)2a^2 \pm 2ab + b^2 = (a \pm b)^2x2+6x+9=(x+3)2x^2 + 6x + 9 = (x+3)^2
Sum of cubesa3+b3=(a+b)(a2−ab+b2)a^3 + b^3 = (a+b)(a^2 - ab + b^2)x3+8=(x+2)(x2−2x+4)x^3 + 8 = (x+2)(x^2-2x+4)
Difference of cubesa3−b3=(a−b)(a2+ab+b2)a^3 - b^3 = (a-b)(a^2+ab+b^2)x3−27=(x−3)(x2+3x+9)x^3 - 27 = (x-3)(x^2+3x+9)

SAT-Level Challenge 🎯

Name That Factoring Pattern 🔍

Identify which factoring technique applies to each expression.

Key Takeaways — Part 7

TechniqueWhen to UseKey Move
GCFAlways firstFactor out common factor
Diff. of squaresa2−b2a^2 - b^2(a+b)(a−b)(a+b)(a-b)
Perfect squarea2±2ab+b2a^2 \pm 2ab + b^2(a±b)2(a \pm b)^2
Trinomialax2+bx+cax^2 + bx + cFind factors of acac that add to bb
Grouping4 termsPair, factor, extract binomial
Disguised quad.Even powers like x4,x6x^4, x^6Let u=xnu = x^n
Identities"Find a+ba+b" or "Find x2+1/x2x^2 + 1/x^2"Expand or factor known identity

Full Topic Summary — Polynomials & Factoring

PartCore Skill
1Polynomial basics, adding/multiplying, special products
2Factoring techniques: GCF, diff. of squares, trinomials
3Polynomial division: long division, synthetic, remainder theorem
4Zeros, multiplicity, end behavior, building from roots
5Rational expressions: simplify, add, multiply, restrictions
6Graphs, transformations, matching equation to graph
7Review: decision tree, identities, SAT strategy