Factor polynomials, perform polynomial arithmetic, understand the relationship between factors and zeros, and use the Remainder Theorem.
How can I study Polynomials and Factoring effectively?โพ
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 13 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
Is this Polynomials and Factoring study guide free?โพ
Yes โ all study notes, flashcards, and practice problems for Polynomials and Factoring on Study Mondo are free to access. No account is needed.
What course covers Polynomials and Factoring?โพ
Polynomials and Factoring is part of the SAT Prep course on Study Mondo, specifically in the Passport to Advanced Math section. You can explore the full course for more related topics and practice resources.
Are there practice problems for Polynomials and Factoring?โพ
Yes, this page includes 13 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.
2
2
+
ab+
b2)
)
=
โ2x
I:
6โ x=6x
L:
6โ (โ2)=โ12
Combine:
x2โ2x+6xโ12=x2+4xโ12
Answer:x2+4xโ12
SAT Tip: Don't forget to combine like terms after FOIL-ing!
a2โb2=(a+b)(aโb)
Here: x2โ49=x2โ72
Factor:
=(x+7)(xโ7)
Answer:(x+7)(xโ7)
Check:(x+7)(xโ7)=x2โ7x+7xโ49=x2โ49 โ
SAT Tip: Difference of squares is common! Memorize a2โb2=(a+b)(aโb)
2
โ
9
4x2+9
4x2โ12x+9
4x2+12x+9
๐ก Show Solution
Solution:
Use square of a difference pattern:
(aโb)2=a2โ2ab+b2
Here: a=2x, b=3
(2x)2=4x2โ2(2x)(3)
Result:
4x2โ12x+9
Answer: C
Common trap: A is (2x+3)(2xโ3) (difference of squares, not square!)
SAT Tip:(aโb)2 has THREE terms, not two! Don't forget the middle term.
3x2โ12=3(x2โ4)
Step 2: Recognize the difference of squares:
3(x2โ4)=3(x+2)(xโ2)
Answer:3(x+2)(xโ2)
Key: Always look for a GCF first!
3x2โ12=3(x2โ4)
Step 2: Recognize the difference of squares:
3(x2โ4)=3(x+2)(xโ2)
Answer:3(x+2)(xโ2)
Key: Always look for a GCF first!
aโ c=2โ 3=6
6 and 1
Rewrite middle term:2x2+6x+x+3
Factor by grouping:2x(x+3)+1(x+3)(2x+1)(x+3)
Check:(2x+1)(x+3)=2x2+6x+x+3=2x2+7x+3 โ
Answer:(2x+1)(x+3)
aโ c=2โ 3=6
6 and 1
Rewrite middle term:2x2+6x+x+3
Factor by grouping:2x(x+3)+1(x+3)(2x+1)(x+3)
Check:(2x+1)(x+3)=2x2+6x+x+3=2x2+7x+3 โ
Answer:(2x+1)(x+3)
2
+
3xโ
7
(xโ2)
๐ก Show Solution
Use the Remainder Theorem: The remainder when P(x) is divided by (xโc) is P(c).
Here c=2:
P(2)=2(2)3โ(2)2+3(2)=2(8)โ4+6โ7=16โ4+6โ7=11
Answer: The remainder is 11.
SAT Tip: The Remainder Theorem saves enormous time compared to polynomial long division!
2
+
3xโ
7
(xโ2)
๐ก Show Solution
Use the Remainder Theorem: The remainder when P(x) is divided by (xโc) is P(c).
Here c=2:
P(2)=2(2)3โ(2)2+3(2)=2(8)โ4+6โ7=16โ4+6โ7=11
Answer: The remainder is 11.
SAT Tip: The Remainder Theorem saves enormous time compared to polynomial long division!
2
+
11xโ
6
f(1)=0
f(x)
๐ก Show Solution
Step 1: Since f(1)=0, by the Factor Theorem, (xโ1) is a factor.
Step 2: Divide x3โ6x2+11xโ6 by (xโ1) using synthetic division:
1โฃ1โ611โ6โฃ1โ56
Quotient: x2โ5x+6
Step 3: Factor the quadratic:
x2โ5x+6=(xโ2)(xโ3)
Answer:f(x)=(xโ1)(xโ2)(xโ3)
The zeros are x=1,2,3.
2
+
11xโ
6
f(1)=0
f(x)
๐ก Show Solution
Step 1: Since f(1)=0, by the Factor Theorem, (xโ1) is a factor.
Step 2: Divide x3โ6x2+11xโ6 by (xโ1) using synthetic division:
1โฃ1โ611โ6โฃ1โ56
Quotient: x2โ5x+6
Step 3: Factor the quadratic:
x2โ5x+6=(xโ2)(xโ3)
Answer:f(x)=(xโ1)(xโ2)(xโ3)
The zeros are x=1,2,3.
=
4
(0,โ16)
๐ก Show Solution
Step 1: Write the general form using the zeros:
f(x)=a(x+1)(xโ2)(xโ4)
Step 2: Use the point (0,โ16) to find a:
f(0)=
Step 3: Write the final polynomial:
f(x)=โ2(x+1)(xโ2)(xโ4)
Check:f(0)=โ2(1)(โ2)(โ4)=โ2(8)=โ16 โ
Answer:f(x)=โ2(x+1)(xโ2)(xโ4)
Expanded: f(x)=โ2x3+10x2โ4xโ
=
4
(0,โ16)
๐ก Show Solution
Step 1: Write the general form using the zeros:
f(x)=a(x+1)(xโ2)(xโ4)
Step 2: Use the point (0,โ16) to find a:
f(0)=
Step 3: Write the final polynomial:
f(x)=โ2(x+1)(xโ2)(xโ4)