Polynomials and Factoring

Factor polynomials, perform polynomial arithmetic, understand the relationship between factors and zeros, and use the Remainder Theorem.

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Polynomials and Factoring on the SAT

What Is a Polynomial?

A polynomial is an expression with variables and coefficients using only addition, subtraction, multiplication, and non-negative integer exponents.

P(x)=anxn+an1xn1++a1x+a0P(x) = a_nx^n + a_{n-1}x^{n-1} + \cdots + a_1x + a_0

  • Degree: The highest power of the variable
  • Leading coefficient: The coefficient of the highest-degree term
  • Constant term: The term with no variable (a0a_0)

Types of Polynomials

| Degree | Name | Example | |---|---|---| | 0 | Constant | 55 | | 1 | Linear | 3x+23x + 2 | | 2 | Quadratic | x24x+1x^2 - 4x + 1 | | 3 | Cubic | 2x3+x72x^3 + x - 7 | | 4 | Quartic | x43x2+1x^4 - 3x^2 + 1 |


Factoring Techniques

1. Greatest Common Factor (GCF)

6x3+9x2=3x2(2x+3)6x^3 + 9x^2 = 3x^2(2x + 3)

2. Difference of Squares

a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b) Example: x225=(x+5)(x5)x^2 - 25 = (x+5)(x-5)

3. Perfect Square Trinomials

a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a + b)^2 a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a - b)^2 Example: x2+10x+25=(x+5)2x^2 + 10x + 25 = (x+5)^2

4. Trinomial Factoring (x2+bx+cx^2 + bx + c)

Find two numbers that multiply to cc and add to bb. Example: x2+7x+12=(x+3)(x+4)x^2 + 7x + 12 = (x+3)(x+4)

5. Trinomial Factoring (ax2+bx+cax^2 + bx + c, a1a \neq 1)

Use the AC method or trial and error. Example: 2x2+7x+3=(2x+1)(x+3)2x^2 + 7x + 3 = (2x+1)(x+3)

6. Sum and Difference of Cubes

a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2) a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2)

7. Factor by Grouping

x3+3x2+2x+6=x2(x+3)+2(x+3)=(x2+2)(x+3)x^3 + 3x^2 + 2x + 6 = x^2(x+3) + 2(x+3) = (x^2+2)(x+3)


Polynomial Operations

Addition/Subtraction

Combine like terms (same variable, same exponent).

Multiplication

Use FOIL for binomials, or distribute each term. (2x+3)(x4)=2x28x+3x12=2x25x12(2x + 3)(x - 4) = 2x^2 - 8x + 3x - 12 = 2x^2 - 5x - 12

Division

Polynomial long division or synthetic division (for dividing by xcx - c).


Remainder Theorem

When polynomial P(x)P(x) is divided by (xc)(x - c), the remainder is P(c)P(c).

Example: If P(x)=x32x+1P(x) = x^3 - 2x + 1, the remainder when divided by (x3)(x - 3) is: P(3)=276+1=22P(3) = 27 - 6 + 1 = 22


Factor Theorem

(xc)(x - c) is a factor of P(x)P(x) if and only if P(c)=0P(c) = 0.

Example: Is (x2)(x - 2) a factor of x34x2+x+6x^3 - 4x^2 + x + 6? P(2)=816+2+6=0P(2) = 8 - 16 + 2 + 6 = 0 → Yes!


SAT Question Types

Type 1: Factor a Polynomial

"Factor x25x6x^2 - 5x - 6" → (x6)(x+1)(x-6)(x+1)

Type 2: Find Zeros from Factored Form

"If f(x)=(x2)(x+3)(x5)f(x) = (x-2)(x+3)(x-5), what are the zeros?" → x=2,3,5x = 2, -3, 5

Type 3: Polynomial Division

"What is the remainder when x3+2x5x^3 + 2x - 5 is divided by x1x - 1?" P(1)=1+25=2P(1) = 1 + 2 - 5 = -2 (use the Remainder Theorem!)

Type 4: Equivalent Expressions

"Which expression is equivalent to (x+2)3(x+2)^3?" =x3+3(x2)(2)+3(x)(4)+8=x3+6x2+12x+8= x^3 + 3(x^2)(2) + 3(x)(4) + 8 = x^3 + 6x^2 + 12x + 8


Common SAT Mistakes

  1. Sign errors when factoring — double-check by FOILing your answer
  2. Forgetting the GCF before trying other methods
  3. Confusing (x+3)2(x+3)^2 with x2+9x^2 + 9 — it's x2+6x+9x^2 + 6x + 9!
  4. Not using the Remainder Theorem — much faster than long division
  5. Dropping terms when subtracting polynomials — distribute the negative sign

📚 Practice Problems

1Problem 1easy

Question:

Factor completely: 3x2123x^2 - 12

💡 Show Solution

Step 1: Factor out the GCF first: 3x212=3(x24)3x^2 - 12 = 3(x^2 - 4)

Step 2: Recognize the difference of squares: 3(x24)=3(x+2)(x2)3(x^2 - 4) = 3(x + 2)(x - 2)

Answer: 3(x+2)(x2)3(x+2)(x-2)

Key: Always look for a GCF first!

2Problem 2medium

Question:

Factor: 2x2+7x+32x^2 + 7x + 3

💡 Show Solution

AC Method: ac=23=6a \cdot c = 2 \cdot 3 = 6. Find two numbers that multiply to 6 and add to 7: 6 and 1.

Rewrite middle term: 2x2+6x+x+32x^2 + 6x + x + 3

Factor by grouping: 2x(x+3)+1(x+3)2x(x + 3) + 1(x + 3) (2x+1)(x+3)(2x + 1)(x + 3)

Check: (2x+1)(x+3)=2x2+6x+x+3=2x2+7x+3(2x+1)(x+3) = 2x^2 + 6x + x + 3 = 2x^2 + 7x + 3

Answer: (2x+1)(x+3)(2x+1)(x+3)

3Problem 3medium

Question:

What is the remainder when P(x)=2x3x2+3x7P(x) = 2x^3 - x^2 + 3x - 7 is divided by (x2)(x - 2)?

💡 Show Solution

Use the Remainder Theorem: The remainder when P(x)P(x) is divided by (xc)(x - c) is P(c)P(c).

Here c=2c = 2: P(2)=2(2)3(2)2+3(2)7P(2) = 2(2)^3 - (2)^2 + 3(2) - 7 =2(8)4+67= 2(8) - 4 + 6 - 7 =164+67= 16 - 4 + 6 - 7 =11= 11

Answer: The remainder is 11.

SAT Tip: The Remainder Theorem saves enormous time compared to polynomial long division!

4Problem 4hard

Question:

If f(x)=x36x2+11x6f(x) = x^3 - 6x^2 + 11x - 6 and f(1)=0f(1) = 0, factor f(x)f(x) completely.

💡 Show Solution

Step 1: Since f(1)=0f(1) = 0, by the Factor Theorem, (x1)(x - 1) is a factor.

Step 2: Divide x36x2+11x6x^3 - 6x^2 + 11x - 6 by (x1)(x - 1) using synthetic division:

1161161 | 1 \quad -6 \quad 11 \quad -6 156\quad | \quad 1 \quad -5 \quad 6 1560\quad 1 \quad -5 \quad 6 \quad 0

Quotient: x25x+6x^2 - 5x + 6

Step 3: Factor the quadratic: x25x+6=(x2)(x3)x^2 - 5x + 6 = (x - 2)(x - 3)

Answer: f(x)=(x1)(x2)(x3)f(x) = (x-1)(x-2)(x-3)

The zeros are x=1,2,3x = 1, 2, 3.

5Problem 5expert

Question:

Which polynomial has zeros at x=1x = -1, x=2x = 2, and x=4x = 4, and passes through the point (0,16)(0, -16)?

💡 Show Solution

Step 1: Write the general form using the zeros: f(x)=a(x+1)(x2)(x4)f(x) = a(x + 1)(x - 2)(x - 4)

Step 2: Use the point (0,16)(0, -16) to find aa: f(0)=a(0+1)(02)(04)=a(1)(2)(4)=8af(0) = a(0 + 1)(0 - 2)(0 - 4) = a(1)(-2)(-4) = 8a 16=8a-16 = 8a a=2a = -2

Step 3: Write the final polynomial: f(x)=2(x+1)(x2)(x4)f(x) = -2(x+1)(x-2)(x-4)

Check: f(0)=2(1)(2)(4)=2(8)=16f(0) = -2(1)(-2)(-4) = -2(8) = -16

Answer: f(x)=2(x+1)(x2)(x4)f(x) = -2(x+1)(x-2)(x-4)

Expanded: f(x)=2x3+10x24x16f(x) = -2x^3 + 10x^2 - 4x - 16