Linear Inequalities and Graphs

Graph linear inequalities and solve systems of linear inequalities.

🎯⭐ INTERACTIVE LESSON

Try the Interactive Version!

Learn step-by-step with practice exercises built right in.

Start Interactive Lesson →

Linear Inequalities and Graphs on the SAT

What Is a Linear Inequality?

A linear inequality is like a linear equation, but uses <<, >>, \leq, or \geq instead of ==. The solution is a region of the coordinate plane, not just a line.


Graphing Linear Inequalities

Step-by-Step Process

  1. Graph the boundary line (treat the inequality as an equation)

    • Use a solid line for \leq or \geq (boundary IS included)
    • Use a dashed line for << or >> (boundary is NOT included)
  2. Choose a test point not on the line ((0,0)(0, 0) is easiest if the line doesn't pass through it)

  3. Shade the correct side

    • If the test point satisfies the inequality → shade that side
    • If not → shade the other side

Reading Inequality Graphs

| Shading | Line Type | Inequality | |---|---|---| | Above the line | Solid | ymx+by \geq mx + b | | Above the line | Dashed | y>mx+by > mx + b | | Below the line | Solid | ymx+by \leq mx + b | | Below the line | Dashed | y<mx+by < mx + b |


Systems of Inequalities

A system of inequalities is two or more inequalities graphed on the same coordinate plane. The solution is the overlapping shaded region.

How to Find the Solution Region

  1. Graph each inequality separately
  2. The solution is where ALL shadings overlap
  3. Any point in the overlapping region satisfies ALL inequalities

Interpreting Constraints (SAT Favorite)

The SAT loves to give real-world constraint problems:

Example: A bakery makes cookies (cc) and brownies (bb).

  • Each cookie uses 2 eggs; each brownie uses 3 eggs
  • They have at most 120 eggs
  • They must make at least 10 cookies and at least 5 brownies

2c+3b1202c + 3b \leq 120 c10c \geq 10 b5b \geq 5

The feasible region is where all three inequalities overlap.


SAT Question Types

Type 1: "Which inequality represents the graph?"

Look at:

  • Slope and yy-intercept of the boundary line
  • Whether the line is solid or dashed
  • Which side is shaded

Type 2: "Which point is in the solution region?"

Test each answer choice in ALL inequalities. The point must satisfy every inequality.

Type 3: "What is the maximum/minimum value?"

Check the vertices (corner points) of the feasible region. The max/min of a linear expression always occurs at a vertex.

Type 4: "Set up the inequality"

Translate a word problem into an inequality using key phrases like "at most" (\leq), "at least" (\geq), "fewer than" (<<), "more than" (>>).


Compound Inequalities on a Number Line

A compound inequality combines two inequalities:

AND compound: 3<x5-3 < x \leq 5 means xx is between 3-3 and 55 (inclusive of 5)

  • Graph: open circle at 3-3, closed circle at 55, shade between

OR compound: x<2x < -2 or x>4x > 4 means xx is outside (2,4)(-2, 4)

  • Graph: shade left of 2-2 and right of 44

Common SAT Mistakes

  1. Using the wrong line type: Solid vs. dashed matters!
  2. Shading the wrong side: Always test a point
  3. Forgetting to flip the inequality when multiplying/dividing by a negative
  4. Confusing AND vs. OR in compound inequalities
  5. Not checking ALL inequalities when testing a point in a system

Quick Strategy Guide

  • "At most" = \leq (can be equal to or less than)
  • "At least" = \geq (can be equal to or greater than)
  • "No more than" = \leq
  • "No fewer than" = \geq
  • When in doubt, test the point (0,0)(0, 0) to determine which side to shade

📚 Practice Problems

1Problem 1easy

Question:

Which of the following points is in the solution region of y>2x3y > 2x - 3?

A) (0,4)(0, -4) B) (1,0)(1, 0) C) (2,1)(2, 1) D) (3,5)(3, 5)

💡 Show Solution

Strategy: Test each point in the inequality y>2x3y > 2x - 3.

A) (0,4)(0, -4): 4>2(0)3=3-4 > 2(0) - 3 = -3? Is 4>3-4 > -3? NoB) (1,0)(1, 0): 0>2(1)3=10 > 2(1) - 3 = -1? Is 0>10 > -1? YesC) (2,1)(2, 1): 1>2(2)3=11 > 2(2) - 3 = 1? Is 1>11 > 1? No (strict inequality) ✗ D) (3,5)(3, 5): 5>2(3)3=35 > 2(3) - 3 = 3? Is 5>35 > 3? Yes

Both B and D work, but on the SAT only one answer choice will satisfy the inequality.

Answer: B) (1,0)(1, 0)

Note: Point C fails because the inequality is strict (>>), not \geq. The boundary line is not included.

2Problem 2easy

Question:

A graph shows a dashed line passing through (0,4)(0, 4) with slope 2-2, with the region below the line shaded. Which inequality represents this graph?

💡 Show Solution

Step 1: Write the equation of the boundary line. The line has slope m=2m = -2 and yy-intercept b=4b = 4: y=2x+4y = -2x + 4

Step 2: Determine the inequality direction.

  • Shading is below the line → use << or \leq
  • Line is dashed → boundary not included → use <<

Answer: y<2x+4y < -2x + 4

SAT Tip: Dashed = strict (<< or >>). Solid = inclusive (\leq or \geq). Shade below = less than. Shade above = greater than.

3Problem 3medium

Question:

A student has at most 20 hours per week for work and study. She must work at least 8 hours and study at least 5 hours. If ww represents work hours and ss represents study hours, which system of inequalities models this situation?

💡 Show Solution

Translate each constraint:

  1. "At most 20 hours total" → w+s20w + s \leq 20
  2. "Must work at least 8 hours" → w8w \geq 8
  3. "Must study at least 5 hours" → s5s \geq 5

Answer: w+s20w + s \leq 20 w8w \geq 8 s5s \geq 5

Key phrases: "At most" → \leq, "At least" → \geq

4Problem 4hard

Question:

The system of inequalities yx+6y \leq -x + 6 and y2xy \geq 2x is graphed in the xyxy-plane. Which of the following points is in the solution region and on the boundary of both inequalities?

💡 Show Solution

Step 1: A point on the boundary of BOTH inequalities is where both are equalities: y=x+6y = -x + 6 y=2xy = 2x

Step 2: Set them equal to find the intersection: 2x=x+62x = -x + 6 3x=63x = 6 x=2x = 2 y=2(2)=4y = 2(2) = 4

Step 3: Verify (2,4)(2, 4) satisfies both inequalities:

  • yx+6y \leq -x + 6: 42+6=44 \leq -2 + 6 = 4 ✓ (equal, so on boundary)
  • y2xy \geq 2x: 42(2)=44 \geq 2(2) = 4 ✓ (equal, so on boundary)

Answer: (2,4)(2, 4)

Strategy: "On the boundary of both" means find the intersection of the boundary lines.

5Problem 5expert

Question:

A company manufactures two products, AA and BB. Each unit of AA requires 3 hours of labor and 2 pounds of material. Each unit of BB requires 2 hours of labor and 4 pounds of material. The company has 240 hours of labor and 200 pounds of material available. The profit is $50 per unit of AA and $40 per unit of BB. What is the maximum profit?

💡 Show Solution

Step 1: Define variables: aa = units of A, bb = units of B

Step 2: Set up constraints: 3a+2b240(labor)3a + 2b \leq 240 \quad \text{(labor)} 2a+4b200(material)2a + 4b \leq 200 \quad \text{(material)} a0,b0a \geq 0, \quad b \geq 0

Step 3: Find the vertices of the feasible region.

Intersection of 3a+2b=2403a + 2b = 240 and 2a+4b=2002a + 4b = 200: Multiply first equation by 2: 6a+4b=4806a + 4b = 480 Subtract: 6a+4b2a4b=4802004a=280a=706a + 4b - 2a - 4b = 480 - 200 → 4a = 280 → a = 70 2(70)+4b=2004b=60b=152(70) + 4b = 200 → 4b = 60 → b = 15 Vertex: (70,15)(70, 15)

Other vertices:

  • (0,0)(0, 0): Profit = $0
  • (80,0)(80, 0): From 3a=2403a = 240, a=80a = 80. Check material: 2(80)=1602002(80) = 160 \leq 200
  • (0,50)(0, 50): From 4b=2004b = 200, b=50b = 50. Check labor: 2(50)=1002402(50) = 100 \leq 240

Step 4: Evaluate profit P=50a+40bP = 50a + 40b at each vertex:

  • (0,0)(0, 0): P=0P = 0
  • (80,0)(80, 0): P = 50(80) = \4,000$
  • (0,50)(0, 50): P = 40(50) = \2,000$
  • (70,15)(70, 15): P = 50(70) + 40(15) = 3,500 + 600 = \4,100$

Answer: Maximum profit = $4,100 at (70,15)(70, 15)