Skip to content Study Mondo Free study resources for students from Grade 4 through AP and test prep. 24 courses, 700+ topics.
Courses Features Company Stay Ahead in School Free weekly study tips, practice sets, and exam strategies. Join 10,000+ students.
ยฉ 2026 Study Mondo. Built for students.
APยฎ is a trademark registered by the College Board, which is not affiliated with, and does not endorse, this website.
Exponents and Radicals - Interactive Lesson | Study Mondo
Exponents and Radicals - Complete Interactive Lesson Part 1: Laws of Exponents Exponents & Radicals
Part 1 of 7 โ Exponent Rules
The Core Rules
Rule Formula Example Product a m โ
a n = a m + n a^m \cdot a^n = a^{m+n} a m โ
a n = a m + n x 3 โ
x 4 = x 7 x^3 \cdot x^4 = x^7 x 3 โ
x 4 = x 7 Quotient a m / a n = a m โ n a^m / a^n = a^{m-n} a m / a n = a m โ n x 5 / x 2 = x 3 Power ( a m ) n = a m n (a^m)^n = a^{mn} ( a m ) n = a mn ( x 3 ) 2 = x 6 (x^3)^2 = x^6 Zero a 0 = 1 a^0 = 1 a 0 = 1 (when a โ 0 a \neq 0 a ๎ = 0 )7 0 = 1 7^0 = 1 7 Negative a โ n = 1 / a n a^{-n} = 1/a^n a โ n = 1/ a n x โ 2 = 1 / x 2 x^{-2} = 1/x^2 x Distribution ( a b ) n = a n b n (ab)^n = a^n b^n ( ab ) n = a n b n ( 2 x ) 3 = 8 x 3 (2x)^3 = 8x^3
SAT Trap
( x + y ) 2 โ x 2 + y 2 (x + y)^2 \neq x^2 + y^2 ( x + y ) 2 ๎ = x 2 + y โ you MUST FOIL!
( x + y ) 2 = x 2 + 2 x y + y 2 (x + y)^2 = x^2 + 2xy + y^2 ( x + y ) 2 = x 2 + 2 x y + y
But ( x y ) 2 = x 2 y 2 (xy)^2 = x^2 y^2 ( x y ) 2 = x 2 y 2 โ โ distribution works for products, NOT sums.
Worked Example 1
Simplify ( 2 x 3 ) 2 โ
x 4 4 x 5 \frac{(2x^3)^2 \cdot x^4}{4x^5} 4 x 5 ( 2 x 3 ) .
Step Work Expand ( 2 x 3 ) 2 (2x^3)^2 ( 2 x 3 ) 2 = 4 x 6 = 4x^6 = 4 x
Worked Example 2
Rewrite 1 x โ 3 \frac{1}{x^{-3}} x โ 3 1 โ with positive exponents.
Step Work Negative exponent in denominator 1 x โ 3 = x 3 \frac{1}{x^{-3}} = x^3 x โ 3 1 โ = x
Negative Exponents in Fractions
A negative exponent "flips" a factor between numerator and denominator:
x โ 2 y โ 3 = y 3 x 2 \frac{x^{-2}}{y^{-3}} = \frac{y^3}{x^2} y โ 3 x โ 2 โ
Harder Exponent Problems ๐ฏ
Which Rule? ๐
Identify the exponent rule used in each simplification.
Key Takeaways โ Part 1
Operation What to Do with Exponents Multiply same base Add: a m โ
a n = a m + n a^m \cdot a^n = a^{m+n} a m โ
a n = a
Part 2: Negative & Zero Exponents Exponents & Radicals
Part 2 of 7 โ Radicals and Rational Exponents
Radical โ Exponent Conversion
a 1 / n = a n a m / n = a m n = ( a n ) m a^{1/n} = \sqrt[n]{a} \qquad a^{m/n} = \sqrt[n]{a^m} = (\sqrt[n]{a})^m a 1/ n = n
Part 3: Radicals & Roots Exponents & Radicals
Part 3 of 7 โ Scientific Notation & Large/Small Numbers
Scientific Notation: a ร 10 n a \times 10^n a ร 1 0 n
Where 1 โค โฃ a โฃ < 10 1 \leq |a| < 10 1 โค โฃ a โฃ < 10 and is an integer.
Part 4: Rational Exponents Exponents & Radicals
Part 4 of 7 โ Solving Equations with Exponents
Strategy 1: Make the Bases Match
If 2 3 x = 8 x + 1 2^{3x} = 8^{x+1} 2 3 x = 8 x + 1 :
Part 5: Simplifying Expressions Exponents & Radicals
Part 5 of 7 โ Radical Equations
Solving Radical Equations
Isolate the radical on one side
Square (or cube, etc.) both sides
Solve the resulting equation
CHECK for extraneous solutions!
Example: x + 3 = x โ 3 \sqrt{x + 3} = x - 3 x + 3 โ =
Part 6: Problem-Solving Workshop Exponents & Radicals
Part 6 of 7 โ Simplifying Complex Expressions
Combining Radicals
a n + b n = ( a + b ) n a\sqrt{n} + b\sqrt{n} = (a + b)\sqrt{n} a n โ + b (like terms!)
Part 7: Review & Applications Exponents & Radicals
Part 7 of 7 โ Review & SAT-Level Practice
Quick Reference Card
Operation Rule Example a m โ
a n a^m \cdot a^n a m โ
a n a m + n a^{m+n}
x^5 / x^2 = x^3 x 5 / x 2 = x 3
( x 3 ) 2 =
x 6
0
=
1
โ 2
=
1/ x 2
( 2 x ) 3 =
8 x 3
2
2
2
โ
x 4
โ
6
Multiply numerator 4 x 6 โ
x 4 = 4 x 10 4x^6 \cdot x^4 = 4x^{10} 4 x 6 โ
x 4 = 4 x 10
Divide 4 x 10 4 x 5 = x 5 \frac{4x^{10}}{4x^5} = x^5 4 x 5 4 x 10 โ = x 5
3
Think of it as 1 รท 1 x 3 = x 3 1 \div \frac{1}{x^3} = x^3 1 รท x 3 1 โ = x 3
=
x 2 y 3 โ
Worked Example 3 Simplify 3 a โ 2 b 3 6 a 4 b โ 1 \frac{3a^{-2}b^3}{6a^4b^{-1}} 6 a 4 b โ 1 3 a โ 2 b 3 โ .
Step Work Coefficients 3 / 6 = 1 / 2 3/6 = 1/2 3/6 = 1/2 a a a termsa โ 2 / a 4 = a โ 6 = 1 / a 6 a^{-2}/a^4 = a^{-6} = 1/a^6 a โ 2 / a 4 = a โ 6 = 1/ a 6 b b b termsb 3 / b โ 1 = b 3 โ ( โ 1 ) = b 4 b^3/b^{-1} = b^{3-(-1)} = b^4 b 3 / b โ 1 = b Final b 4 2 a 6 \frac{b^4}{2a^6} 2 a 6 b 4 โ
Common Base Conversions Number As a Power of 2 As a Power of 3 4 2 2 2^2 2 2 โ 8 2 3 2^3 2 3 โ 16 2 4 2^4 2 4 โ 9 โ 3 2 3^2 3 2 27 โ 3 3 3^3 3 3 81 โ 3 4 3^4 3 4
m
+
n
Divide same base Subtract: a m / a n = a m โ n a^m / a^n = a^{m-n} a m / a n = a m โ n
Power of a power Multiply: ( a m ) n = a m n (a^m)^n = a^{mn} ( a m ) n = a mn
Product to a power Distribute: ( a b ) n = a n b n (ab)^n = a^n b^n ( ab ) n = a n b n
Negative exponent Reciprocal: a โ n = 1 / a n a^{-n} = 1/a^n a โ n = 1/ a n
Zero exponent Always 1: a 0 = 1 a^0 = 1 a 0 = 1 (a โ 0 a \neq 0 a ๎ = 0 )
Exponents do NOT distribute over addition: ( a + b ) n โ a n + b n (a + b)^n \neq a^n + b^n ( a + b ) n ๎ = a n + b n
Convert to matching bases when comparing or solving equations
a
โ
a m / n
=
x 1 / 2 = x x^{1/2} = \sqrt{x} x 1/2 = x โ
x 2 / 3 = x 2 3 x^{2/3} = \sqrt[3]{x^2} x 2/3 = 3 x 2 โ
8 2 / 3 = ( 8 3 ) 2 = 2 2 = 4 8^{2/3} = (\sqrt[3]{8})^2 = 2^2 = 4 8 2/3 = ( 3 8
Simplifying Radicals 50 = 25 โ
2 = 5 2 \sqrt{50} = \sqrt{25 \cdot 2} = 5\sqrt{2} 50 โ = 25 โ
2 โ = 5 2 โ
Look for perfect square factors : 4, 9, 16, 25, 36, 49, 64, 81, 100...
Rationalizing the Denominator 3 5 = 3 5 โ
5 5 = 3 5 5 \frac{3}{\sqrt{5}} = \frac{3}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}} = \frac{3\sqrt{5}}{5} 5 โ 3 โ = 5 โ 3 โ โ
5 โ 5 5 3 5 โ โ
Worked Example 1 Evaluate 16 3 / 4 16^{3/4} 1 6 3/4 .
Step Work Root first (denominator = 4) 16 4 = 2 \sqrt[4]{16} = 2 4 16 โ = 2 Then power (numerator = 3) 2 3 = 8 2^3 = 8 2 3 = 8 Answer 16 3 / 4 = 8 16^{3/4} = 8 1 6 3/4 = 8
Worked Example 2 Rationalize 2 3 + 2 \frac{2}{3 + \sqrt{2}} 3 + 2 โ 2 โ .
Step Work Multiply by conjugate 2 3 + 2 โ
3 โ 2 3 โ 2 \frac{2}{3+\sqrt{2}} \cdot \frac{3-\sqrt{2}}{3-\sqrt{2}} 3 + 2 โ 2 โ โ
3 โ 2 โ 3 โ 2 Numerator 2 ( 3 โ 2 ) = 6 โ 2 2 2(3 - \sqrt{2}) = 6 - 2\sqrt{2} 2 ( 3 โ 2 โ ) = 6 โ 2 Denominator ( 3 ) 2 โ ( 2 ) 2 = 9 โ 2 = 7 (3)^2 - (\sqrt{2})^2 = 9 - 2 = 7 ( 3 ) 2 โ ( 2 โ ) Answer 6 โ 2 2 7 \frac{6 - 2\sqrt{2}}{7} 7 6 โ 2 2 โ โ
Radicals & Rational Exponents ๐ฏ
Converting Between Forms
The SAT often asks you to rewrite an expression. Know these equivalences:
Radical Form Exponent Form x \sqrt{x} x โ x 1 / 2 x^{1/2} x 1/2 x 3 \sqrt[3]{x} 3 x โ x 1 / 3 x^{1/3} x 1 x \frac{1}{\sqrt{x}} x โ 1 โ x x x\sqrt{x} x x โ x 3 / 2 x^{3/2} x 3/2 x 3 \sqrt{x^3} x 3 โ x 3 / 2 x^{3/2} x
Worked Example 3
Rewrite x 2 x 3 \frac{x^2}{\sqrt[3]{x}} 3 x โ using a single exponent.
Step Work Rewrite radical x 2 x 1 / 3 \frac{x^2}{x^{1/3}} x 1/3 x 2 โ Subtract exponents
Worked Example 4
Simplify x 4 y 6 \sqrt{x^4 y^6} x 4 y 6 โ .
Step Work Apply \sqrt{} โ to each x 4 โ
y 6 \sqrt{x^4} \cdot \sqrt{y^6}
Radical or Exponent? ๐
Convert each expression to the other form.
Key Takeaways โ Part 2
Concept Key Rule a m / n a^{m/n} a m / n Denominator = root, numerator = power Order Root first, then power (usually easier) Simplify radicals Extract perfect square/cube factors Rationalize Multiply by a a \frac{\sqrt{a}}{\sqrt{a}} a โ a โ โ or conjugate x โ
x x \cdot \sqrt{x} x โ
x โ = x 3 / 2 = x^{3/2} = x 1 x \frac{1}{\sqrt{x}} x โ 1 โ
n n n
Large: 4,500,000 = 4.5 ร 10 6 4{,}500{,}000 = 4.5 \times 10^6 4 , 500 , 000 = 4.5 ร 1 0 6
Small: 0.00032 = 3.2 ร 10 โ 4 0.00032 = 3.2 \times 10^{-4} 0.00032 = 3.2 ร 1 0 โ 4
Operations with Scientific Notation Multiply: ( 3 ร 10 4 ) ( 2 ร 10 5 ) = 6 ร 10 9 (3 \times 10^4)(2 \times 10^5) = 6 \times 10^9 ( 3 ร 1 0 4 ) ( 2 ร 1 0 5 ) = 6 ร 1 0 9
Divide: 8 ร 10 7 4 ร 10 3 = 2 ร 10 4 \frac{8 \times 10^7}{4 \times 10^3} = 2 \times 10^4 4 ร 1 0 3 8 ร 1 0 7 โ = 2 ร 1 0 4
Powers of 10 Shortcuts
Moving decimal right = smaller exponent
Moving decimal left = larger exponent
10 3 = 1,000 10^3 = 1{,}000 1 0 3 = 1 , 000 (3 zeros)
Worked Example 1 Multiply ( 4.2 ร 10 5 ) ( 3 ร 10 โ 2 ) (4.2 \times 10^5)(3 \times 10^{-2}) ( 4.2 ร 1 0 5 ) ( 3 ร 1 0 โ 2 ) .
Step Work Multiply coefficients 4.2 ร 3 = 12.6 4.2 \times 3 = 12.6 4.2 ร 3 = 12.6 Add exponents 10 5 + ( โ 2 ) = 10 3 10^{5 + (-2)} = 10^3 1 0 5 + ( โ 2 ) = 1 0 3 Result 12.6 ร 10 3 12.6 \times 10^3 12.6 ร 1 0 3 Adjust to proper form 1.26 ร 10 4 1.26 \times 10^4 1.26 ร 1 0 4
Worked Example 2 How many times larger is 6 ร 10 8 6 \times 10^8 6 ร 1 0 8 than 3 ร 10 5 3 \times 10^5 3 ร 1 0 5 ?
Step Work Divide 6 ร 10 8 3 ร 10 5 = 2 ร 10 3 \frac{6 \times 10^8}{3 \times 10^5} = 2 \times 10^3 3 ร 1 0 5 6 ร 1 0 8 โ = 2 ร 1 0 3 Answer 2,000 2{,}000 2 , 000 times larger
Adding/Subtracting in Scientific Notation
To add or subtract, the exponents must match first.
Worked Example 3
Add 3.5 ร 10 4 + 2.1 ร 10 3 3.5 \times 10^4 + 2.1 \times 10^3 3.5 ร 1 0 4 + 2.1 ร 1 0 3 .
Step Work Match exponents 2.1 ร 10 3 = 0.21 ร 10 4 2.1 \times 10^3 = 0.21 \times 10^4 2.1 ร 1 0 3 = 0.21 ร 1 0 4 Add 3.5 ร 10 4 + 0.21 ร 10 4 =
Worked Example 4
A cell has mass 8.3 ร 10 โ 12 8.3 \times 10^{-12} 8.3 ร 1 0 โ 12 grams. How many cells in 1 gram?
Step Work Divide 1 8.3 ร 10 โ 12 \frac{1}{8.3 \times 10^{-12}} 8.3 ร 1 0 โ 12 1 โ Simplify
SAT Tip: When comparing very large or very small numbers, look at the exponent first โ bigger exponent = bigger number (for positive coefficients).
Real-World Scientific Notation ๐ฏ
Convert and Compare ๐
Select the correct scientific notation or comparison.
Key Takeaways โ Part 3
Operation Rule Multiply Multiply coefficients, add exponents Divide Divide coefficients, subtract exponents Power Raise coefficient to power, multiply exponents Add/Subtract Match exponents first, then combine Compare Look at exponent first (higher = bigger)
Always adjust so coefficient is between 1 and 10
SAT context: distances, populations, atomic sizes โ the math stays the same
=
2 3
2 3 x = ( 2 3 ) x + 1 = 2 3 x + 3 2^{3x} = (2^3)^{x+1} = 2^{3x+3} 2 3 x = ( 2 3 ) x + 1 = 2 3 x + 3 Bases match โ 3 x = 3 x + 3 3x = 3x + 3 3 x = 3 x + 3 ? That gives 0 = 3 0 = 3 0 = 3 , so no solution .
Strategy 2: Use Logarithmic Thinking If 3 x = 15 3^x = 15 3 x = 15 , the SAT won't expect you to compute log โก 3 15 \log_3 15 log 3 โ 15 , but it might ask:
"Between which two integers is x x x ?" Since 3 2 = 9 3^2 = 9 3 2 = 9 and 3 3 = 27 3^3 = 27 3 3 = 27 , x x x is between 2 and 3.
Strategy 3: Exponential Equations from Context "A population doubles every 5 years. Starting at 1000, when will it reach 8000?"
1000 โ
2 t / 5 = 8000 1000 \cdot 2^{t/5} = 8000 1000 โ
2 t /5 = 8000 โ 2 t / 5 = 8 = 2 3 2^{t/5} = 8 = 2^3 2 t /5 = 8 = 2 3 โ t / 5 = 3 t/5 = 3 t /5 = 3 โ t = 15 t = 15 t = 15 years.
Worked Example 1 Solve 25 x โ 1 = 125 25^{x-1} = 125 2 5 x โ 1 = 125 .
Step Work Rewrite as powers of 5 5 2 ( x โ 1 ) = 5 3 5^{2(x-1)} = 5^3 5 2 ( x โ 1 ) = 5 3 Set exponents equal 2 ( x โ 1 ) = 3 2(x-1) = 3 2 ( x โ 1 ) = 3 Solve 2 x โ 2 = 3 2x - 2 = 3 2 x โ 2 = 3 โ x = 5 / 2 x = 5/2 x = 5/2
Worked Example 2 If 2 a = 5 2^a = 5 2 a = 5 , express 2 3 a 2^{3a} 2 3 a in terms of a number.
Step Work Use power rule 2 3 a = ( 2 a ) 3 2^{3a} = (2^a)^3 2 3 a = ( 2 a ) 3 Substitute = 5 3 = 125 = 5^3 = 125 = 5 3 = 125
Exponential Equations ๐ฏ
Exponential Growth and Decay
Model Formula Example Growth A = A 0 โ
r t / k A = A_0 \cdot r^{t/k} A = A 0 โ โ
r t / k Population doubling (r = 2 r = 2 r = 2 ) Decay A = A 0 โ
r t / k A = A_0 \cdot r^{t/k} A = A 0 โ โ
r t / k Radioactive half-life (r = 1 / 2 r = 1/2 ) Percent growth A = A 0 ( 1 + p ) t A = A_0(1 + p)^t A = A 0 โ ( 1 + p ) t 5% annual growth (p = 0.05 p = 0.05 p ) Percent decay A = A 0 ( 1 โ p ) t A = A_0(1 - p)^t A = A 0 โ ( 1 โ p ) t 3% depreciation (p = 0.03 p = 0.03 p )
Worked Example 3
A car worth $20,000 depreciates 15% per year. When is it worth $10,000?
Step Work Model 20000 ( 0.85 ) t = 10000 20000(0.85)^t = 10000 20000 ( 0.85 ) t = 10000 Simplify ( 0.85 ) t = 0.5 (0.85)^t = 0.5 ( 0.85 )
Worked Example 4
2 x โ
4 x + 1 = 8 3 2^x \cdot 4^{x+1} = 8^3 2 x โ
4 x + 1 = 8 3 . Find x x x .
Step Work Convert to base 2 2 x โ
2 2 ( x + 1 ) = 2 9 2^x \cdot 2^{2(x+1)} = 2^9 2 x โ
2 2 ( x + 1 ) = 2
Match the Base ๐
Rewrite each number as a power of 2 or 3.
Key Takeaways โ Part 4
Strategy When to Use Match bases Both sides can be written as same base "Between which integers" Can't match bases; evaluate at integer exponents 2 x + k = 2 x โ
2 k 2^{x+k} = 2^x \cdot 2^k 2 x + k = 2 x โ
2 k "If 2 x = n 2^x = n 2 x = n , find 2 x + k 2^{x+k} 2 x + k " Growth: ( 1 + r ) t (1 + r)^t ( 1 + r ) t Percent increase per period Decay: ( 1 โ r ) t (1 - r)^t ( 1 โ r ) t Percent decrease per period Half-life: ( 1 / 2 ) t / k (1/2)^{t/k} ( 1/2 ) t / k Quantity halves every k k k units
x โ
3
Square both sides: x + 3 = ( x โ 3 ) 2 = x 2 โ 6 x + 9 x + 3 = (x - 3)^2 = x^2 - 6x + 9 x + 3 = ( x โ 3 ) 2 = x 2 โ 6 x + 9
Rearrange: x 2 โ 7 x + 6 = 0 x^2 - 7x + 6 = 0 x 2 โ 7 x + 6 = 0 โ ( x โ 1 ) ( x โ 6 ) = 0 (x - 1)(x - 6) = 0 ( x โ 1 ) ( x โ 6 ) = 0
Check x = 1 x = 1 x = 1 : 4 = 1 โ 3 = โ 2 \sqrt{4} = 1 - 3 = -2 4 โ = 1 โ 3 = โ 2 ? No! 2 โ โ 2 2 \neq -2 2 ๎ = โ 2 โ Extraneous!
Check x = 6 x = 6 x = 6 : 9 = 6 โ 3 = 3 \sqrt{9} = 6 - 3 = 3 9 โ = 6 โ 3 = 3 ? Yes! โ
Why Extraneous Solutions Appear Squaring both sides can introduce false solutions because ( โ 3 ) 2 = 3 2 = 9 (-3)^2 = 3^2 = 9 ( โ 3 ) 2 = 3 2 = 9 . The squaring step "loses" the sign information.
Worked Example 1 Solve 5 x + 1 = x + 1 \sqrt{5x + 1} = x + 1 5 x + 1 โ = x + 1 .
Step Work Square both sides 5 x + 1 = ( x + 1 ) 2 = x 2 + 2 x + 1 5x + 1 = (x+1)^2 = x^2 + 2x + 1 5 x + 1 = ( x + 1 ) 2 = x 2 + 2 x + 1 Rearrange x 2 โ 3 x = 0 x^2 - 3x = 0 x 2 โ 3 x = 0 Factor x ( x โ 3 ) = 0 x(x - 3) = 0 x ( x โ 3 ) = 0 โ x = 0 x = 0 x = 0 or x = 3 x = 3 x = 3 Check x = 0 x = 0 x = 0 1 = 1 \sqrt{1} = 1 1 โ = 1 and โCheck x = 3 x = 3 x = 3 16 = 4 \sqrt{16} = 4 16 โ = 4 and โBoth valid! x = 0 x = 0 x = 0 and x = 3 x = 3 x = 3
Equations with Two Radicals
When there are two radicals, isolate one, square, then isolate the other and square again.
Worked Example 2
Solve x + 5 โ x = 1 \sqrt{x + 5} - \sqrt{x} = 1 x + 5 โ โ x โ = 1 .
Step Work Isolate one radical x + 5 = 1 + x \sqrt{x + 5} = 1 + \sqrt{x} x + 5 โ = 1 +
Cube Root Equations
No extraneous solutions with cube roots (cubing preserves sign).
Worked Example 3
Solve 2 x โ 1 3 = 3 \sqrt[3]{2x - 1} = 3 3 2 x โ 1 โ = 3 .
Step Work Cube both sides 2 x โ 1 = 27 2x - 1 = 27 2 x โ 1 = 27 Solve 2 x = 28 2x = 28 2 x = 28 โ x = 14 x = 14 x
SAT Tip: The SAT will specifically design problems to test whether you check for extraneous solutions. Always substitute back into the original equation.
Trickier Radical Equations ๐ฏ
Valid or Extraneous? ๐
For each solution, determine if it is valid.
Key Takeaways โ Part 5
Step Details 1. Isolate Get the radical alone on one side 2. Raise Square (or cube) both sides 3. Solve Standard algebra from here 4. Check Substitute back โ always!
x โฅ 0 \sqrt{x} \geq 0 x โ โฅ 0 always โ if the other side is negative, the solution is extraneous
Two radicals? Isolate one, square, isolate the other, square again
Cube roots: no extraneous solutions (cubing preserves sign)
n
โ
=
( a +
a โ
b = a b \sqrt{a} \cdot \sqrt{b} = \sqrt{ab} a โ โ
b โ = ab โ a b = a b \frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}} b โ a โ โ = b a โ โ Example: 3 2 + 5 2 โ 2 = 7 2 3\sqrt{2} + 5\sqrt{2} - \sqrt{2} = 7\sqrt{2} 3 2 โ + 5 2 โ โ 2 โ = 7 2 โ
But: 3 2 + 5 3 3\sqrt{2} + 5\sqrt{3} 3 2 โ + 5 3 โ cannot be simplified further.
Simplify Before Combining 12 + 27 = 2 3 + 3 3 = 5 3 \sqrt{12} + \sqrt{27} = 2\sqrt{3} + 3\sqrt{3} = 5\sqrt{3} 12 โ + 27 โ = 2 3 โ + 3 3 โ = 5 3 โ
Worked Example 1 Simplify 18 + 50 โ 8 \sqrt{18} + \sqrt{50} - \sqrt{8} 18 โ + 50 โ โ 8 โ .
Step Work Simplify each 18 = 3 2 \sqrt{18} = 3\sqrt{2} 18 โ = 3 2 โ , 50 = 5 2 \sqrt{50} = 5\sqrt{2} 50 โ = 5 2 , 8 = 2 2 \sqrt{8} = 2\sqrt{2} 8 โ = 2 2 Combine 3 2 + 5 2 โ 2 2 3\sqrt{2} + 5\sqrt{2} - 2\sqrt{2} 3 2 โ + 5 2 Result 6 2 6\sqrt{2} 6 2 โ
Worked Example 2 Simplify ( x 4 y 2 ) 3 / 2 \left(\frac{x^4}{y^2}\right)^{3/2} ( y 2 x 4 โ ) 3/2 .
Step Work Apply exponent to num. & denom. ( x 4 ) 3 / 2 ( y 2 ) 3 / 2 \frac{(x^4)^{3/2}}{(y^2)^{3/2}} ( y 2 ) 3/2 ( x 4 ) 3/2 โ Multiply exponents x 6 y 3 \frac{x^6}{y^3} y 3 x 6 โ
Simplifying Expressions ๐ฏ
Multiplying Radical Expressions
Use FOIL when multiplying binomials with radicals.
Worked Example 3
Expand ( 3 + 5 ) ( 3 โ 5 ) (3 + \sqrt{5})(3 - \sqrt{5}) ( 3 + 5 โ ) ( 3 โ 5 โ ) .
Step Work Difference of squares ( 3 ) 2 โ ( 5 ) 2 (3)^2 - (\sqrt{5})^2 ( 3 ) 2 โ ( 5
This is the conjugate pattern โ the radical disappears!
Worked Example 4
Expand ( 2 3 + 1 ) 2 (2\sqrt{3} + 1)^2 ( 2 3 โ + 1 ) 2 .
Step Work FOIL pattern ( 2 3 ) 2 + 2 ( 2 3 ) ( 1 ) + 1 2 (2\sqrt{3})^2 + 2(2\sqrt{3})(1) + 1^2 ( 2 3 โ )
Worked Example 5
Simplify x 2 / 3 โ
x โ 1 / 6 x 1 / 2 \frac{x^{2/3} \cdot x^{-1/6}}{x^{1/2}} x 1/2 x 2/3 โ
x .
Step Work Add exponents in numerator x 2 / 3 + ( โ 1 / 6 ) = x 4 / 6 โ 1 / 6 = x 3 / 6 = x 1 / 2 x^{2/3 + (-1/6)} = x^{4/6 - 1/6} = x^{3/6} = x^{1/2} x 2/3 + ( โ 1/6 ) = x
Complex Simplification ๐ฏ
Can These Be Combined? ๐
Determine whether each pair can be simplified into a single term.
Key Takeaways โ Part 6
Rule When It Works a n + b n = ( a + b ) n a\sqrt{n} + b\sqrt{n} = (a+b)\sqrt{n} a n โ + b n โ = ( a + b ) n โ Same radicand only a โ
b = a b \sqrt{a} \cdot \sqrt{b} = \sqrt{ab} a โ โ
b ( a + b ) ( a โ b ) = a 2 โ b (a + \sqrt{b})(a - \sqrt{b}) = a^2 - b ( a + b โ ) ( a โ Simplify first, then combine 12 + 27 = 2 3 + 3 3 \sqrt{12} + \sqrt{27} = 2\sqrt{3} + 3\sqrt{3} 12 โ + 27
Convert to exponent form for complex fraction simplification
Conjugate multiplication eliminates radicals in denominators
a + b โ a + b \sqrt{a} + \sqrt{b} \neq \sqrt{a + b} a โ + b โ radicals don't distribute over addition!
a m + n
x 3 โ
x 4 = x 7 x^3 \cdot x^4 = x^7 x 3 โ
x 4 = x 7
a m / a n a^m / a^n a m / a n a m โ n a^{m-n} a m โ n x 5 / x 2 = x 3 x^5 / x^2 = x^3 x 5 / x 2 = x 3
( a m ) n (a^m)^n ( a m ) n a m n a^{mn} a mn ( x 3 ) 2 = x 6 (x^3)^2 = x^6 ( x 3 ) 2 = x 6
a โ n a^{-n} a โ n 1 / a n 1/a^n 1/ a n x โ 2 = 1 / x 2 x^{-2} = 1/x^2 x โ 2 = 1/ x 2
a m / n a^{m/n} a m / n a m n \sqrt[n]{a^m} n a m โ 8 2 / 3 = 4 8^{2/3} = 4 8 2/3 = 4
a b \sqrt{ab} ab โ a โ
b \sqrt{a}\cdot\sqrt{b} a โ โ
b โ 12 = 2 3 \sqrt{12} = 2\sqrt{3} 12 โ = 2 3
Common SAT Exponent Traps
( x + y ) 2 โ x 2 + y 2 (x + y)^2 \neq x^2 + y^2 ( x + y ) 2 ๎ = x 2 + y 2 โ must FOIL
( โ x ) 2 = x 2 (-x)^2 = x^2 ( โ x ) 2 = x 2 but โ x 2 = โ ( x 2 ) -x^2 = -(x^2) โ x 2 = โ order of operations!
x 2 = โฃ x โฃ \sqrt{x^2} = |x| x 2 โ = โฃ x โฃ , not just x x x
a 0 = 1 a^0 = 1 a 0 = 1 for ALL nonzero a a a , including negatives: ( โ 5 ) 0 = 1 (-5)^0 = 1 ( โ 5 ) 0 = 1
Worked Example 1 โ Trap-Style Problem If ( โ 3 ) 4 โ 3 4 + ( โ 3 ) 3 + 3 3 = ? (-3)^4 - 3^4 + (-3)^3 + 3^3 = ? ( โ 3 ) 4 โ 3 4 + ( โ 3 ) 3 + 3 3 = ?
Step Work ( โ 3 ) 4 (-3)^4 ( โ 3 ) 4 81 81 81 (even power, positive)3 4 3^4 3 4 81 81 81 ( โ 3 ) 3 (-3)^3 ( โ 3 ) 3 โ 27 -27 โ 27 (odd power, negative)3 3 3^3 3 3 27 27 27 Combine 81 โ 81 + ( โ 27 ) + 27 = 0 81 - 81 + (-27) + 27 = 0 81 โ 81 + ( โ 27 ) + 27 = 0
Shortcut: Even powers make signs agree; odd powers make signs cancel.
Worked Example 2 โ Multi-Rule Problem If ( 2 x 3 ) 2 โ
x โ 4 4 x 2 = x n \frac{(2x^3)^2 \cdot x^{-4}}{4x^2} = x^n 4 x 2 ( 2 x 3 ) 2 โ
x โ 4 โ = x n , find n n n .
Step Work Expand numerator ( 2 x 3 ) 2 = 4 x 6 (2x^3)^2 = 4x^6 ( 2 x 3 ) 2 = 4 x 6 Multiply 4 x 6 โ
x โ 4 = 4 x 2 4x^6 \cdot x^{-4} = 4x^2 4 x 6 โ
x โ 4 = 4 x 2 Divide 4 x 2 4 x 2 = x 0 = 1 \frac{4x^2}{4x^2} = x^0 = 1 4 x 2 4 x 2 โ = Result n = 0 n = 0 n = 0
SAT Strategy: Rewrite Everything as Powers of Small Primes
Many SAT problems look complex but simplify once you rewrite bases as powers of 2, 3, or 5.
Worked Example 3
If 8 x = 32 8^x = 32 8 x = 32 , what is x x x ?
Step Work Rewrite as powers of 2 ( 2 3 ) x = 2 5 (2^3)^x = 2^5 ( 2 3 ) x = 2 5 Simplify 2 3 x = 2 5 2^{3x} = 2^5 2 3 x = 2 5 Set exponents equal 3 x = 5 3x = 5 3 x = 5 โ x = 5 / 3 x = 5/3 x = 5/3
Worked Example 4
Simplify 9 n + 1 3 2 n โ 1 \frac{9^{n+1}}{3^{2n-1}} 3 2 n โ 1 9 n + 1 โ .
Step Work Rewrite 9 = 3 2 9 = 3^2 9 = 3 2 ( 3 2 ) n + 1 3 2 n โ 1 = 3 2 n + 2 3 2 n โ 1 \frac{(3^2)^{n+1}}{3^{2n-1}} = \frac{3^{2n+2}}{3^{2n-1}}
Worked Example 5
If x 2 + 6 x + 9 = 7 \sqrt{x^2 + 6x + 9} = 7 x 2 + 6 x + 9 โ = 7 , find .
Step Work Recognize perfect square ( x + 3 ) 2 = 7 \sqrt{(x+3)^2} = 7 ( x + 3 ) 2 โ
Which Strategy? ๐
For each problem, choose the best first step.
Key Takeaways โ Full Topic Review
Category Key Rules Multiplying a m โ
a n = a m + n a^m \cdot a^n = a^{m+n} a m โ
a n = a m + n Dividing a m / a n = a m โ n a^m / a^n = a^{m-n} a m / a n = a m โ n Power of power ( a m ) n = a m n (a^m)^n = a^{mn} ( a m ) n = a mn Negative exponent a โ n = 1 / a n a^{-n} = 1/a^n a โ n = 1/ a n Rational exponent a m / n = a m n a^{m/n} = \sqrt[n]{a^m} a m / n = n a m Radical product a โ
b = a b \sqrt{a} \cdot \sqrt{b} = \sqrt{ab} a โ โ
b Radical equation Square both sides, check for extraneous Trap: sign ( โ x ) 2 โ โ x 2 (-x)^2 \neq -x^2 ( โ x ) 2 ๎ = โ x 2 Trap: addition ( x + y ) 2 โ x 2 + y 2 (x+y)^2 \neq x^2 + y^2 ( x + y ) 2 ๎ = x 2 + y Trap: square root $\sqrt{x^2} =
SAT Strategies:
Rewrite all bases as powers of small primes (2, 3, 5)
Convert between radical and exponent form freely
Check extraneous solutions after squaring
For ( โ 1 ) n (-1)^n ( โ 1 ) n : odd โ โ 1 -1 โ 1 , even โ 1 1 1
3 โ ( โ 1 )
=
b 4
โ
) 2
=
2 2 =
4
โ
โ
=
โ
โ
2
=
9 โ
2 =
7
1/3
x โ 1 / 2 x^{-1/2} x โ 1/2
3/2
x 2
โ
x 2 โ 1 / 3 = x 5 / 3 x^{2 - 1/3} = x^{5/3} x 2 โ 1/3 = x 5/3
x
4
โ
โ
3/2
= x โ 1 / 2 = x^{-1/2} = x โ 1/2
3.71 ร 10 4 3.5 \times 10^4 + 0.21 \times 10^4 = 3.71 \times 10^4 3.5 ร 1 0 4 + 0.21 ร 1 0 4 = 3.71 ร 1 0 4
1 8.3 ร 10 12 โ 0.12 ร 10 12 \frac{1}{8.3} \times 10^{12} \approx 0.12 \times 10^{12} 8.3 1 โ ร 1 0 12 โ 0.12 ร 1 0 12
Proper form โ 1.2 ร 10 11 \approx 1.2 \times 10^{11} โ 1.2 ร 1 0 11
r
=
1/2
=
0.05
=
0.03
t
=
0.5
Estimate 0.85 4 โ 0.52 0.85^4 \approx 0.52 0.8 5 4 โ 0.52 , 0.85 5 โ 0.44 0.85^5 \approx 0.44 0.8 5 5 โ 0.44
Answer Between 4 and 5 years
9
Simplify left side 2 x + 2 x + 2 = 2 9 2^{x + 2x + 2} = 2^9 2 x + 2 x + 2 = 2 9
Set exponents equal 3 x + 2 = 9 3x + 2 = 9 3 x + 2 = 9
0 + 1 = 1 0 + 1 = 1 0 + 1 = 1
3 + 1 = 4 3 + 1 = 4 3 + 1 = 4
Square both sides x + 5 = 1 + 2 x + x x + 5 = 1 + 2\sqrt{x} + x x + 5 = 1 + 2 x โ + x
Simplify 4 = 2 x 4 = 2\sqrt{x} 4 = 2 x โ โ x = 2 \sqrt{x} = 2 x โ = 2
Check 9 โ 4 = 3 โ 2 = 1 \sqrt{9} - \sqrt{4} = 3 - 2 = 1 9 โ โ 4 โ = 3 โ 2 = 1 โ
=
14
No check needed Cubing doesn't introduce extraneous solutions
โ
โ
โ
โ
โ
) 2
Simplify 9 โ 5 = 4 9 - 5 = 4 9 โ 5 = 4
2
+
1 2
Simplify 12 + 4 3 + 1 12 + 4\sqrt{3} + 1 12 + 4 3 โ + 1
Result 13 + 4 3 13 + 4\sqrt{3} 13 + 4 3 โ
โ 1/6
โ
4/6 โ 1/6
=
x 3/6 =
x 1/2
Subtract denominator x 1 / 2 โ 1 / 2 = x 0 = 1 x^{1/2 - 1/2} = x^0 = 1 x 1/2 โ 1/2 = x 0 = 1
โ
=
Always (for non-negative a , b a, b a , b )
b
โ
)
=
a 2 โ
b
โ
=
โ
๎ =
โ
โ ( x 2 )
x
0
=
1
3 2 n โ 1
( 3 2 ) n + 1
โ
=
3 2 n โ 1 3 2 n + 2 โ
Subtract exponents 3 ( 2 n + 2 ) โ ( 2 n โ 1 ) = 3 3 3^{(2n+2)-(2n-1)} = 3^3 3 ( 2 n + 2 ) โ ( 2 n โ 1 ) = 3 3
=
7
Solve x + 3 = 7 x + 3 = 7 x + 3 = 7 โ x = 4 x = 4 x = 4 , or x + 3 = โ 7 x + 3 = -7 x + 3 = โ 7 โ x = โ 10 x = -10 x = โ 10
Both valid x = 4 x = 4 x = 4 or x = โ 10 x = -10 x = โ 10
โ
โ
=
2