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🎯⭐ INTERACTIVE LESSON

Exponents and Radicals

Learn step-by-step with interactive practice!

Exponents and Radicals - Complete Interactive Lesson

Part 1: Laws of Exponents

Exponents & Radicals

Part 1 of 7 — Exponent Rules

The Core Rules

RuleFormulaExample
Productam⋅an=am+na^m \cdot a^n = a^{m+n}x3⋅x4=x7x^3 \cdot x^4 = x^7
Quotientam/an=am−na^m / a^n = a^{m-n}x5/x2=x3x^5 / x^2 = x^3
Power(am)n=amn(a^m)^n = a^{mn}(x3)2=x6(x^3)^2 = x^6
Zeroa0=1a^0 = 1 (when a≠0a \neq 0)70=17^0 = 1
Negativea−n=1/ana^{-n} = 1/a^nx−2=1/x2x^{-2} = 1/x^2
Distribution(ab)n=anbn(ab)^n = a^n b^n(2x)3=8x3(2x)^3 = 8x^3

SAT Trap

(x+y)2≠x2+y2(x + y)^2 \neq x^2 + y^2 — you MUST FOIL!

(x+y)2=x2+2xy+y2(x + y)^2 = x^2 + 2xy + y^2

But (xy)2=x2y2(xy)^2 = x^2 y^2 ✓ — distribution works for products, NOT sums.


Worked Example 1

Simplify (2x3)2⋅x44x5\frac{(2x^3)^2 \cdot x^4}{4x^5}.

StepWork
Expand (2x3)2(2x^3)^2=4x6= 4x^6
Multiply numerator4x6⋅x4=4x104x^6 \cdot x^4 = 4x^{10}
Divide4x104x5=x5\frac{4x^{10}}{4x^5} = x^5

Worked Example 2

Rewrite 1x−3\frac{1}{x^{-3}} with positive exponents.

StepWork
Negative exponent in denominator1x−3=x3\frac{1}{x^{-3}} = x^3
Think of it as1÷1x3=x31 \div \frac{1}{x^3} = x^3

Exponent Rules 🎯

Negative Exponents in Fractions

A negative exponent "flips" a factor between numerator and denominator:

x−2y−3=y3x2\frac{x^{-2}}{y^{-3}} = \frac{y^3}{x^2}

Worked Example 3

Simplify 3a−2b36a4b−1\frac{3a^{-2}b^3}{6a^4b^{-1}}.

StepWork
Coefficients3/6=1/23/6 = 1/2
aa termsa−2/a4=a−6=1/a6a^{-2}/a^4 = a^{-6} = 1/a^6
bb termsb3/b−1=b3−(−1)=b4b^3/b^{-1} = b^{3-(-1)} = b^4
Finalb42a6\frac{b^4}{2a^6}

Common Base Conversions

NumberAs a Power of 2As a Power of 3
4222^2—
8232^3—
16242^4—
9—323^2
27—333^3
81—343^4

Harder Exponent Problems 🎯

Which Rule? 🔍

Identify the exponent rule used in each simplification.

Key Takeaways — Part 1

OperationWhat to Do with Exponents
Multiply same baseAdd: am⋅an=am+na^m \cdot a^n = a^{m+n}
Divide same baseSubtract: am/an=am−na^m / a^n = a^{m-n}
Power of a powerMultiply: (am)n=amn(a^m)^n = a^{mn}
Product to a powerDistribute: (ab)n=anbn(ab)^n = a^n b^n
Negative exponentReciprocal: a−n=1/ana^{-n} = 1/a^n
Zero exponentAlways 1: a0=1a^0 = 1 (a≠0a \neq 0)
  • Exponents do NOT distribute over addition: (a+b)n≠an+bn(a + b)^n \neq a^n + b^n
  • Convert to matching bases when comparing or solving equations

Part 2: Negative & Zero Exponents

Exponents & Radicals

Part 2 of 7 — Radicals and Rational Exponents

Radical ↔ Exponent Conversion

a1/n=anam/n=amn=(an)ma^{1/n} = \sqrt[n]{a} \qquad a^{m/n} = \sqrt[n]{a^m} = (\sqrt[n]{a})^m

Examples:

  • x1/2=xx^{1/2} = \sqrt{x}
  • x2/3=x23x^{2/3} = \sqrt[3]{x^2}
  • 82/3=(83)2=22=48^{2/3} = (\sqrt[3]{8})^2 = 2^2 = 4

Simplifying Radicals

50=25⋅2=52\sqrt{50} = \sqrt{25 \cdot 2} = 5\sqrt{2}

Look for perfect square factors: 4, 9, 16, 25, 36, 49, 64, 81, 100...

Rationalizing the Denominator

35=35⋅55=355\frac{3}{\sqrt{5}} = \frac{3}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}} = \frac{3\sqrt{5}}{5}


Worked Example 1

Evaluate 163/416^{3/4}.

StepWork
Root first (denominator = 4)164=2\sqrt[4]{16} = 2
Then power (numerator = 3)23=82^3 = 8
Answer163/4=816^{3/4} = 8

Worked Example 2

Rationalize 23+2\frac{2}{3 + \sqrt{2}}.

StepWork
Multiply by conjugate23+2⋅3−23−2\frac{2}{3+\sqrt{2}} \cdot \frac{3-\sqrt{2}}{3-\sqrt{2}}
Numerator2(3−2)=6−222(3 - \sqrt{2}) = 6 - 2\sqrt{2}
Denominator(3)2−(2)2=9−2=7(3)^2 - (\sqrt{2})^2 = 9 - 2 = 7
Answer6−227\frac{6 - 2\sqrt{2}}{7}

Radicals & Rational Exponents 🎯

Converting Between Forms

The SAT often asks you to rewrite an expression. Know these equivalences:

Radical FormExponent Form
x\sqrt{x}x1/2x^{1/2}
x3\sqrt[3]{x}x1/3x^{1/3}
1x\frac{1}{\sqrt{x}}x−1/2x^{-1/2}
xxx\sqrt{x}x3/2x^{3/2}
x3\sqrt{x^3}x3/2x^{3/2}

Worked Example 3

Rewrite x2x3\frac{x^2}{\sqrt[3]{x}} using a single exponent.

StepWork
Rewrite radicalx2x1/3\frac{x^2}{x^{1/3}}
Subtract exponentsx2−1/3=x5/3x^{2 - 1/3} = x^{5/3}

Worked Example 4

Simplify x4y6\sqrt{x^4 y^6}.

StepWork
Apply \sqrt{} to eachx4⋅y6\sqrt{x^4} \cdot \sqrt{y^6}
Simplify$x^2 \cdot

Conversion Practice 🎯

Radical or Exponent? 🔍

Convert each expression to the other form.

Key Takeaways — Part 2

ConceptKey Rule
am/na^{m/n}Denominator = root, numerator = power
OrderRoot first, then power (usually easier)
Simplify radicalsExtract perfect square/cube factors
RationalizeMultiply by aa\frac{\sqrt{a}}{\sqrt{a}} or conjugate
x⋅xx \cdot \sqrt{x}=x3/2= x^{3/2}
1x\frac{1}{\sqrt{x}}=x−1/2= x^{-1/2}

Part 3: Radicals & Roots

Exponents & Radicals

Part 3 of 7 — Scientific Notation & Large/Small Numbers

Scientific Notation: a×10na \times 10^n

Where 1≤∣a∣<101 \leq |a| < 10 and nn is an integer.

  • Large: 4,500,000=4.5×1064{,}500{,}000 = 4.5 \times 10^6
  • Small: 0.00032=3.2×10−40.00032 = 3.2 \times 10^{-4}

Operations with Scientific Notation

Multiply: (3×104)(2×105)=6×109(3 \times 10^4)(2 \times 10^5) = 6 \times 10^9

Divide: 8×1074×103=2×104\frac{8 \times 10^7}{4 \times 10^3} = 2 \times 10^4

Powers of 10 Shortcuts

  • Moving decimal right = smaller exponent
  • Moving decimal left = larger exponent
  • 103=1,00010^3 = 1{,}000 (3 zeros)

Worked Example 1

Multiply (4.2×105)(3×10−2)(4.2 \times 10^5)(3 \times 10^{-2}).

StepWork
Multiply coefficients4.2×3=12.64.2 \times 3 = 12.6
Add exponents105+(−2)=10310^{5 + (-2)} = 10^3
Result12.6×10312.6 \times 10^3
Adjust to proper form1.26×1041.26 \times 10^4

Worked Example 2

How many times larger is 6×1086 \times 10^8 than 3×1053 \times 10^5?

StepWork
Divide6×1083×105=2×103\frac{6 \times 10^8}{3 \times 10^5} = 2 \times 10^3
Answer2,0002{,}000 times larger

Scientific Notation 🎯

Adding/Subtracting in Scientific Notation

To add or subtract, the exponents must match first.

Worked Example 3

Add 3.5×104+2.1×1033.5 \times 10^4 + 2.1 \times 10^3.

StepWork
Match exponents2.1×103=0.21×1042.1 \times 10^3 = 0.21 \times 10^4
Add3.5×104+0.21×104=3.71×1043.5 \times 10^4 + 0.21 \times 10^4 = 3.71 \times 10^4

Worked Example 4

A cell has mass 8.3×10−128.3 \times 10^{-12} grams. How many cells in 1 gram?

StepWork
Divide18.3×10−12\frac{1}{8.3 \times 10^{-12}}
Simplify18.3×1012≈0.12×1012\frac{1}{8.3} \times 10^{12} \approx 0.12 \times 10^{12}
Proper form≈1.2×1011\approx 1.2 \times 10^{11}

SAT Tip: When comparing very large or very small numbers, look at the exponent first — bigger exponent = bigger number (for positive coefficients).

Real-World Scientific Notation 🎯

Convert and Compare 🔍

Select the correct scientific notation or comparison.

Key Takeaways — Part 3

OperationRule
MultiplyMultiply coefficients, add exponents
DivideDivide coefficients, subtract exponents
PowerRaise coefficient to power, multiply exponents
Add/SubtractMatch exponents first, then combine
CompareLook at exponent first (higher = bigger)
  • Always adjust so coefficient is between 1 and 10
  • SAT context: distances, populations, atomic sizes — the math stays the same

Part 4: Rational Exponents

Exponents & Radicals

Part 4 of 7 — Solving Equations with Exponents

Strategy 1: Make the Bases Match

If 23x=8x+12^{3x} = 8^{x+1}:

  • Rewrite 8=238 = 2^3: 23x=(23)x+1=23x+32^{3x} = (2^3)^{x+1} = 2^{3x+3}
  • Bases match → 3x=3x+33x = 3x + 3? That gives 0=30 = 3, so no solution.

Strategy 2: Bracket the Answer with Whole-Number Powers

If 3x=153^x = 15, no whole-number exponent works, because 1515 is not a power of 33. The SAT will not ask for an exact value here, but it might ask:

  • "Between which two integers is xx?" Since 32=9<15<27=333^2 = 9 < 15 < 27 = 3^3, xx is between 2 and 3.

Strategy 3: Exponential Equations from Context

"A population doubles every 5 years. Starting at 1000, when will it reach 8000?"

1000⋅2t/5=80001000 \cdot 2^{t/5} = 8000 → 2t/5=8=232^{t/5} = 8 = 2^3 → t/5=3t/5 = 3 → t=15t = 15 years.


Worked Example 1

Solve 25x−1=12525^{x-1} = 125.

StepWork
Rewrite as powers of 552(x−1)=535^{2(x-1)} = 5^3
Set exponents equal2(x−1)=32(x-1) = 3
Solve2x−2=32x - 2 = 3 → x=5/2x = 5/2

Worked Example 2

If 2a=52^a = 5, express 23a2^{3a} in terms of a number.

StepWork
Use power rule23a=(2a)32^{3a} = (2^a)^3
Substitute=53=125= 5^3 = 125

Exponential Equations 🎯

Exponential Growth and Decay

ModelFormulaExample
GrowthA=A0⋅rt/kA = A_0 \cdot r^{t/k}Population doubling (r=2r = 2)
DecayA=A0⋅rt/kA = A_0 \cdot r^{t/k}Radioactive half-life (r=1/2r = 1/2)
Percent growthA=A0(1+p)tA = A_0(1 + p)^t5% annual growth (p=0.05p = 0.05)
Percent decayA=A0(1−p)tA = A_0(1 - p)^t3% depreciation (p=0.03p = 0.03)

Worked Example 3

A car worth $20,000 depreciates 15% per year. When is it worth $10,000?

StepWork
Model20000(0.85)t=1000020000(0.85)^t = 10000
Simplify(0.85)t=0.5(0.85)^t = 0.5
Estimate0.854≈0.520.85^4 \approx 0.52, 0.855≈0.440.85^5 \approx 0.44
AnswerBetween 4 and 5 years

Worked Example 4

2x⋅4x+1=832^x \cdot 4^{x+1} = 8^3. Find xx.

StepWork
Convert to base 22x⋅22(x+1)=292^x \cdot 2^{2(x+1)} = 2^9
Simplify left side2x+2x+2=292^{x + 2x + 2} = 2^9
Set exponents equal3x+2=93x + 2 = 9
Solvex=7/3x = 7/3

Growth & Decay 🎯

Match the Base 🔍

Rewrite each number as a power of 2 or 3.

Key Takeaways — Part 4

StrategyWhen to Use
Match basesBoth sides can be written as same base
"Between which integers"Can't match bases; evaluate at integer exponents
2x+k=2x⋅2k2^{x+k} = 2^x \cdot 2^k"If 2x=n2^x = n, find 2x+k2^{x+k}"
Growth: (1+r)t(1 + r)^tPercent increase per period
Decay: (1−r)t(1 - r)^tPercent decrease per period
Half-life: (1/2)t/k(1/2)^{t/k}Quantity halves every kk units

Part 5: Simplifying Expressions

Exponents & Radicals

Part 5 of 7 — Radical Equations

Solving Radical Equations

  1. Isolate the radical on one side
  2. Square (or cube, etc.) both sides
  3. Solve the resulting equation
  4. CHECK for extraneous solutions!

Example: x+3=x−3\sqrt{x + 3} = x - 3

Square both sides: x+3=(x−3)2=x2−6x+9x + 3 = (x - 3)^2 = x^2 - 6x + 9

Rearrange: x2−7x+6=0x^2 - 7x + 6 = 0 → (x−1)(x−6)=0(x - 1)(x - 6) = 0

Check x=1x = 1: 4=1−3=−2\sqrt{4} = 1 - 3 = -2? No! 2≠−22 \neq -2 ❌ Extraneous!

Check x=6x = 6: 9=6−3=3\sqrt{9} = 6 - 3 = 3? Yes! ✓

Why Extraneous Solutions Appear

Squaring both sides can introduce false solutions because (−3)2=32=9(-3)^2 = 3^2 = 9. The squaring step "loses" the sign information.


Worked Example 1

Solve 5x+1=x+1\sqrt{5x + 1} = x + 1.

StepWork
Square both sides5x+1=(x+1)2=x2+2x+15x + 1 = (x+1)^2 = x^2 + 2x + 1
Rearrangex2−3x=0x^2 - 3x = 0
Factorx(x−3)=0x(x - 3) = 0 → x=0x = 0 or x=3x = 3
Check x=0x = 01=1\sqrt{1} = 1 and 0+1=10 + 1 = 1 ✓
Check x=3x = 316=4\sqrt{16} = 4 and 3+1=43 + 1 = 4 ✓
Both valid!x=0x = 0 and x=3x = 3

Radical Equations 🎯

Equations with Two Radicals

When there are two radicals, isolate one, square, then isolate the other and square again.

Worked Example 2

Solve x+5−x=1\sqrt{x + 5} - \sqrt{x} = 1.

StepWork
Isolate one radicalx+5=1+x\sqrt{x + 5} = 1 + \sqrt{x}
Square both sidesx+5=1+2x+xx + 5 = 1 + 2\sqrt{x} + x
Simplify4=2x4 = 2\sqrt{x} → x=2\sqrt{x} = 2
Solvex=4x = 4
Check9−4=3−2=1\sqrt{9} - \sqrt{4} = 3 - 2 = 1 ✓

Cube Root Equations

No extraneous solutions with cube roots (cubing preserves sign).

Worked Example 3

Solve 2x−13=3\sqrt[3]{2x - 1} = 3.

StepWork
Cube both sides2x−1=272x - 1 = 27
Solve2x=282x = 28 → x=14x = 14
No check neededCubing doesn't introduce extraneous solutions

SAT Tip: The SAT will specifically design problems to test whether you check for extraneous solutions. Always substitute back into the original equation.

Trickier Radical Equations 🎯

Valid or Extraneous? 🔍

For each solution, determine if it is valid.

Key Takeaways — Part 5

StepDetails
1. IsolateGet the radical alone on one side
2. RaiseSquare (or cube) both sides
3. SolveStandard algebra from here
4. CheckSubstitute back — always!
  • x≥0\sqrt{x} \geq 0 always — if the other side is negative, the solution is extraneous
  • Two radicals? Isolate one, square, isolate the other, square again
  • Cube roots: no extraneous solutions (cubing preserves sign)

Part 6: Problem-Solving Workshop

Exponents & Radicals

Part 6 of 7 — Simplifying Complex Expressions

Combining Radicals

  • an+bn=(a+b)na\sqrt{n} + b\sqrt{n} = (a + b)\sqrt{n} (like terms!)
  • a⋅b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}
  • ab=ab\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}

Example: 32+52−2=723\sqrt{2} + 5\sqrt{2} - \sqrt{2} = 7\sqrt{2}

But: 32+533\sqrt{2} + 5\sqrt{3} cannot be simplified further.

Simplify Before Combining

12+27=23+33=53\sqrt{12} + \sqrt{27} = 2\sqrt{3} + 3\sqrt{3} = 5\sqrt{3}


Worked Example 1

Simplify 18+50−8\sqrt{18} + \sqrt{50} - \sqrt{8}.

StepWork
Simplify each18=32\sqrt{18} = 3\sqrt{2}, 50=52\sqrt{50} = 5\sqrt{2}, 8=22\sqrt{8} = 2\sqrt{2}
Combine32+52−223\sqrt{2} + 5\sqrt{2} - 2\sqrt{2}
Result626\sqrt{2}

Worked Example 2

Simplify (x4y2)3/2\left(\frac{x^4}{y^2}\right)^{3/2}.

StepWork
Apply exponent to num. & denom.(x4)3/2(y2)3/2\frac{(x^4)^{3/2}}{(y^2)^{3/2}}
Multiply exponentsx6y3\frac{x^6}{y^3}

Simplifying Expressions 🎯

Multiplying Radical Expressions

Use FOIL when multiplying binomials with radicals.

Worked Example 3

Expand (3+5)(3−5)(3 + \sqrt{5})(3 - \sqrt{5}).

StepWork
Difference of squares(3)2−(5)2(3)^2 - (\sqrt{5})^2
Simplify9−5=49 - 5 = 4

This is the conjugate pattern — the radical disappears!

Worked Example 4

Expand (23+1)2(2\sqrt{3} + 1)^2.

StepWork
FOIL pattern(23)2+2(23)(1)+12(2\sqrt{3})^2 + 2(2\sqrt{3})(1) + 1^2
Simplify12+43+112 + 4\sqrt{3} + 1
Result13+4313 + 4\sqrt{3}

Worked Example 5

Simplify x2/3⋅x−1/6x1/2\frac{x^{2/3} \cdot x^{-1/6}}{x^{1/2}}.

StepWork
Add exponents in numeratorx2/3+(−1/6)=x4/6−1/6=x3/6=x1/2x^{2/3 + (-1/6)} = x^{4/6 - 1/6} = x^{3/6} = x^{1/2}
Subtract denominatorx1/2−1/2=x0=1x^{1/2 - 1/2} = x^0 = 1

Complex Simplification 🎯

Can These Be Combined? 🔍

Determine whether each pair can be simplified into a single term.

Key Takeaways — Part 6

RuleWhen It Works
an+bn=(a+b)na\sqrt{n} + b\sqrt{n} = (a+b)\sqrt{n}Same radicand only
a⋅b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}Always (for non-negative a,ba, b)
(a+b)(a−b)=a2−b(a + \sqrt{b})(a - \sqrt{b}) = a^2 - bConjugate pattern
Simplify first, then combine12+27=23+33\sqrt{12} + \sqrt{27} = 2\sqrt{3} + 3\sqrt{3}
  • Convert to exponent form for complex fraction simplification
  • Conjugate multiplication eliminates radicals in denominators
  • a+b≠a+b\sqrt{a} + \sqrt{b} \neq \sqrt{a + b} — radicals don't distribute over addition!

Part 7: Review & Applications

Exponents & Radicals

Part 7 of 7 — Review & SAT-Level Practice

Quick Reference Card

OperationRuleExample
am⋅ana^m \cdot a^nam+na^{m+n}x3⋅x4=x7x^3 \cdot x^4 = x^7
am/ana^m / a^nam−na^{m-n}x5/x2=x3x^5 / x^2 = x^3
(am)n(a^m)^namna^{mn}(x3)2=x6(x^3)^2 = x^6
a−na^{-n}1/an1/a^nx−2=1/x2x^{-2} = 1/x^2
am/na^{m/n}amn\sqrt[n]{a^m}82/3=48^{2/3} = 4
ab\sqrt{ab}a⋅b\sqrt{a}\cdot\sqrt{b}12=23\sqrt{12} = 2\sqrt{3}

Common SAT Exponent Traps

  1. (x+y)2≠x2+y2(x + y)^2 \neq x^2 + y^2 — must FOIL
  2. (−x)2=x2(-x)^2 = x^2 but −x2=−(x2)-x^2 = -(x^2) — order of operations!
  3. x2=∣x∣\sqrt{x^2} = |x|, not just xx
  4. a0=1a^0 = 1 for ALL nonzero aa, including negatives: (−5)0=1(-5)^0 = 1

Worked Example 1 — Trap-Style Problem

If (−3)4−34+(−3)3+33=?(-3)^4 - 3^4 + (-3)^3 + 3^3 = ?

StepWork
(−3)4(-3)^48181 (even power, positive)
343^48181
(−3)3(-3)^3−27-27 (odd power, negative)
333^32727
Combine81−81+(−27)+27=081 - 81 + (-27) + 27 = 0

Shortcut: Even powers make signs agree; odd powers make signs cancel.

Worked Example 2 — Multi-Rule Problem

If (2x3)2⋅x−44x2=xn\frac{(2x^3)^2 \cdot x^{-4}}{4x^2} = x^n, find nn.

StepWork
Expand numerator(2x3)2=4x6(2x^3)^2 = 4x^6
Multiply4x6⋅x−4=4x24x^6 \cdot x^{-4} = 4x^2
Divide4x24x2=x0=1\frac{4x^2}{4x^2} = x^0 = 1
Resultn=0n = 0

Mixed Review 🎯

SAT Strategy: Rewrite Everything as Powers of Small Primes

Many SAT problems look complex but simplify once you rewrite bases as powers of 2, 3, or 5.

Worked Example 3

If 8x=328^x = 32, what is xx?

StepWork
Rewrite as powers of 2(23)x=25(2^3)^x = 2^5
Simplify23x=252^{3x} = 2^5
Set exponents equal3x=53x = 5 → x=5/3x = 5/3

Worked Example 4

Simplify 9n+132n−1\frac{9^{n+1}}{3^{2n-1}}.

StepWork
Rewrite 9=329 = 3^2(32)n+132n−1=32n+232n−1\frac{(3^2)^{n+1}}{3^{2n-1}} = \frac{3^{2n+2}}{3^{2n-1}}
Subtract exponents3(2n+2)−(2n−1)=333^{(2n+2)-(2n-1)} = 3^3
Result2727

Worked Example 5

If x2+6x+9=7\sqrt{x^2 + 6x + 9} = 7, find xx.

StepWork
Recognize perfect square(x+3)2=7\sqrt{(x+3)^2} = 7
Apply $\sqrt{a^2} =a
Solvex+3=7x + 3 = 7 → x=4x = 4, or x+3=−7x + 3 = -7 → x=−10x = -10
Both validx=4x = 4 or x=−10x = -10

SAT-Level Challenge 🎯

Which Strategy? 🔍

For each problem, choose the best first step.

Key Takeaways — Full Topic Review

CategoryKey Rules
Multiplyingam⋅an=am+na^m \cdot a^n = a^{m+n}
Dividingam/an=am−na^m / a^n = a^{m-n}
Power of power(am)n=amn(a^m)^n = a^{mn}
Negative exponenta−n=1/ana^{-n} = 1/a^n
Rational exponentam/n=amna^{m/n} = \sqrt[n]{a^m}
Radical producta⋅b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}
Radical equationSquare both sides, check for extraneous
Trap: sign(−x)2≠−x2(-x)^2 \neq -x^2
Trap: addition(x+y)2≠x2+y2(x+y)^2 \neq x^2 + y^2
Trap: square root$\sqrt{x^2} =

SAT Strategies:

  • Rewrite all bases as powers of small primes (2, 3, 5)
  • Convert between radical and exponent form freely
  • Check extraneous solutions after squaring
  • For (−1)n(-1)^n: odd → −1-1, even → 11