Exponents and Radicals (SAT Math)
Exponent Rules
Rule 1: Product Rule
When multiplying same base, ADD exponents:
x a ⋅ x b = x a + b x^a \cdot x^b = x^{a+b} x a ⋅ x b = x a + b
Examples:
x 3 ⋅ x 5 = x 3 + 5 = x 8 x^3 \cdot x^5 = x^{3+5} = x^8 x 3 ⋅ x 5 = x 3 + 5 = x 8
2 4 ⋅ 2 3 = 2 4 + 3 = 2 7 = 128 2^4 \cdot 2^3 = 2^{4+3} = 2^7 = 128 2 4 ⋅ 2 3 = 2 4 + 3 = 2 7 = 128
Rule 2: Quotient Rule
When dividing same base, SUBTRACT exponents:
x a x b = x a − b \frac{x^a}{x^b} = x^{a-b} x b x a = x a − b
Examples:
x 7 x 4 = x 7 − 4 = x 3 \frac{x^7}{x^4} = x^{7-4} = x^3 x 4 x 7 = x 7 − 4 = x 3
5 6 5 2 = 5 6 − 2 = 5 4 = 625 \frac{5^6}{5^2} = 5^{6-2} = 5^4 = 625 5 2 5 6 = 5 6 − 2 = 5 4 = 625
Rule 3: Power Rule
When raising power to power, MULTIPLY exponents:
( x a ) b = x a b (x^a)^b = x^{ab} ( x a ) b = x ab
Examples:
( x 3 ) 4 = x 3 ⋅ 4 = x 12 (x^3)^4 = x^{3 \cdot 4} = x^{12} ( x 3 ) 4 = x 3 ⋅ 4 = x 12
( 2 2 ) 3 = 2 2 ⋅ 3 = 2 6 = 64 (2^2)^3 = 2^{2 \cdot 3} = 2^6 = 64 ( 2 2 ) 3 = 2 2 ⋅ 3 = 2 6 = 64
Rule 4: Power of a Product
Distribute the exponent:
( x y ) a = x a y a (xy)^a = x^a y^a ( x y ) a = x a y a
Examples:
( 3 x ) 2 = 3 2 ⋅ x 2 = 9 x 2 (3x)^2 = 3^2 \cdot x^2 = 9x^2 ( 3 x ) 2 = 3 2 ⋅ x 2 = 9 x 2
( 2 a b ) 3 = 2 3 a 3 b 3 = 8 a 3 b 3 (2ab)^3 = 2^3 a^3 b^3 = 8a^3b^3 ( 2 ab ) 3 = 2 3 a 3 b 3 = 8 a 3 b 3
Rule 5: Power of a Quotient
Distribute the exponent:
( x y ) a = x a y a \left(\frac{x}{y}\right)^a = \frac{x^a}{y^a} ( y x ) a = y a x a
Examples:
( x 3 ) 2 = x 2 3 2 = x 2 9 \left(\frac{x}{3}\right)^2 = \frac{x^2}{3^2} = \frac{x^2}{9} ( 3 x ) 2 = 3 2 x 2 = 9 x 2
( 2 y ) 4 = 2 4 y 4 = 16 y 4 \left(\frac{2}{y}\right)^4 = \frac{2^4}{y^4} = \frac{16}{y^4} ( y 2 ) 4 = y 4 2 4 = y 4 16
Special Exponents
Zero Exponent
Any number (except 0) to the zero power equals 1:
x 0 = 1 x^0 = 1 x 0 = 1 (where x ≠ 0 x \neq 0 x = 0 )
Examples:
5 0 = 1 5^0 = 1 5 0 = 1
( x 2 y 3 ) 0 = 1 (x^2y^3)^0 = 1 ( x 2 y 3 ) 0 = 1
− 2 ( 3 x ) 0 = − 2 ( 1 ) = − 2 -2(3x)^0 = -2(1) = -2 − 2 ( 3 x ) 0 = − 2 ( 1 ) = − 2 (only ( 3 x ) 0 = 1 (3x)^0 = 1 ( 3 x ) 0 = 1 )
Negative Exponents
Negative exponent means reciprocal:
x − a = 1 x a x^{-a} = \frac{1}{x^a} x − a = x a 1
Examples:
x − 3 = 1 x 3 x^{-3} = \frac{1}{x^3} x − 3 = x 3 1
2 − 4 = 1 2 4 = 1 16 2^{-4} = \frac{1}{2^4} = \frac{1}{16} 2 − 4 = 2 4 1 = 16 1
1 x − 2 = x 2 \frac{1}{x^{-2}} = x^2 x − 2 1 = x 2 (flipping reciprocal)
In fractions:
x − 2 y − 3 = y 3 x 2 \frac{x^{-2}}{y^{-3}} = \frac{y^3}{x^2} y − 3 x − 2 = x 2 y 3
Negative exponents "flip" to the other part of the fraction
Fractional Exponents
Fractional exponent = root:
x 1 n = x n x^{\frac{1}{n}} = \sqrt[n]{x} x n 1 = n x
Examples:
x 1 2 = x x^{\frac{1}{2}} = \sqrt{x} x 2 1 = x (square root)
x 1 3 = x 3 x^{\frac{1}{3}} = \sqrt[3]{x} x 3 1 = 3 x (cube root)
8 1 3 = 8 3 = 2 8^{\frac{1}{3}} = \sqrt[3]{8} = 2 8 3 1 = 3 8 = 2
General form:
x m n = x m n = ( x n ) m x^{\frac{m}{n}} = \sqrt[n]{x^m} = (\sqrt[n]{x})^m x n m = n x m = ( n x ) m
Examples:
8 2 3 = ( 8 3 ) 2 = 2 2 = 4 8^{\frac{2}{3}} = (\sqrt[3]{8})^2 = 2^2 = 4 8 3 2 = ( 3 8 ) 2 = 2 2 = 4
16 3 4 = ( 16 4 ) 3 = 2 3 = 8 16^{\frac{3}{4}} = (\sqrt[4]{16})^3 = 2^3 = 8 1 6 4 3 = ( 4 16 ) 3 = 2 3 = 8
Radical Rules
Simplifying Radicals
Product Rule:
a b = a ⋅ b \sqrt{ab} = \sqrt{a} \cdot \sqrt{b} ab = a ⋅ b
Example:
72 = 36 ⋅ 2 = 36 ⋅ 2 = 6 2 \sqrt{72} = \sqrt{36 \cdot 2} = \sqrt{36} \cdot \sqrt{2} = 6\sqrt{2} 72 = 36 ⋅ 2 = 36 ⋅ 2 = 6 2
Quotient Rule:
a b = a b \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} b a = b a
Example:
16 25 = 16 25 = 4 5 \sqrt{\frac{16}{25}} = \frac{\sqrt{16}}{\sqrt{25}} = \frac{4}{5} 25 16 = 25 16 = 5 4
Simplification Strategy
Find perfect square factors:
Example: Simplify 48 \sqrt{48} 48
Step 1: Factor into perfect square
48 = 16 ⋅ 3 48 = 16 \cdot 3 48 = 16 ⋅ 3
Step 2: Split the radical
48 = 16 ⋅ 3 = 16 ⋅ 3 \sqrt{48} = \sqrt{16 \cdot 3} = \sqrt{16} \cdot \sqrt{3} 48 = 16 ⋅ 3 = 16 ⋅ 3
Step 3: Simplify
= 4 3 = 4\sqrt{3} = 4 3
Common perfect squares: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144
Adding and Subtracting Radicals
Can only combine LIKE radicals (same radicand):
✓ 3 2 + 5 2 = 8 2 3\sqrt{2} + 5\sqrt{2} = 8\sqrt{2} 3 2 + 5 2 = 8 2
✓ 7 3 − 2 3 = 5 3 7\sqrt{3} - 2\sqrt{3} = 5\sqrt{3} 7 3 − 2 3 = 5 3
❌ 2 + 3 \sqrt{2} + \sqrt{3} 2 + 3 cannot be simplified (different radicands)
Sometimes need to simplify first:
Example: 50 + 8 \sqrt{50} + \sqrt{8} 50 + 8
50 = 25 ⋅ 2 = 5 2 \sqrt{50} = \sqrt{25 \cdot 2} = 5\sqrt{2} 50 = 25 ⋅ 2 = 5 2
8 = 4 ⋅ 2 = 2 2 \sqrt{8} = \sqrt{4 \cdot 2} = 2\sqrt{2} 8 = 4 ⋅ 2 = 2 2
50 + 8 = 5 2 + 2 2 = 7 2 \sqrt{50} + \sqrt{8} = 5\sqrt{2} + 2\sqrt{2} = 7\sqrt{2} 50 + 8 = 5 2 + 2 2 = 7 2
Multiplying Radicals
Multiply coefficients and radicands separately:
a b ⋅ c d = ( a ⋅ c ) b ⋅ d a\sqrt{b} \cdot c\sqrt{d} = (a \cdot c)\sqrt{b \cdot d} a b ⋅ c d = ( a ⋅ c ) b ⋅ d
Examples:
2 3 ⋅ 5 2 = 10 6 2\sqrt{3} \cdot 5\sqrt{2} = 10\sqrt{6} 2 3 ⋅ 5 2 = 10 6
3 6 ⋅ 2 6 = 6 36 = 6 ( 6 ) = 36 3\sqrt{6} \cdot 2\sqrt{6} = 6\sqrt{36} = 6(6) = 36 3 6 ⋅ 2 6 = 6 36 = 6 ( 6 ) = 36
Rationalizing the Denominator
Don't leave radicals in denominator:
1 a → 1 a ⋅ a a = a a \frac{1}{\sqrt{a}} \rightarrow \frac{1}{\sqrt{a}} \cdot \frac{\sqrt{a}}{\sqrt{a}} = \frac{\sqrt{a}}{a} a 1 → a 1 ⋅ a a = a a
Examples:
5 2 = 5 2 ⋅ 2 2 = 5 2 2 \frac{5}{\sqrt{2}} = \frac{5}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} = \frac{5\sqrt{2}}{2} 2 5 = 2 5 ⋅ 2 2 = 2 5 2
6 3 = 6 3 ⋅ 3 3 = 6 3 3 = 2 3 \frac{6}{\sqrt{3}} = \frac{6}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{6\sqrt{3}}{3} = 2\sqrt{3} 3 6 = 3 6 ⋅ 3 3 = 3 6 3 = 2 3
With binomial denominators, use conjugate:
1 2 + 3 ⋅ 2 − 3 2 − 3 = 2 − 3 4 − 3 = 2 − 3 \frac{1}{2 + \sqrt{3}} \cdot \frac{2 - \sqrt{3}}{2 - \sqrt{3}} = \frac{2 - \sqrt{3}}{4 - 3} = 2 - \sqrt{3} 2 + 3 1 ⋅ 2 − 3 2 − 3 = 4 − 3 2 − 3 = 2 − 3
Converting Between Forms
Radical to Exponent
x = x 1 2 \sqrt{x} = x^{\frac{1}{2}} x = x 2 1
x 2 3 = x 2 3 \sqrt[3]{x^2} = x^{\frac{2}{3}} 3 x 2 = x 3 2
1 x = x − 1 2 \frac{1}{\sqrt{x}} = x^{-\frac{1}{2}} x 1 = x − 2 1
Exponent to Radical
x 3 4 = x 3 4 x^{\frac{3}{4}} = \sqrt[4]{x^3} x 4 3 = 4 x 3
x − 1 3 = 1 x 3 x^{-\frac{1}{3}} = \frac{1}{\sqrt[3]{x}} x − 3 1 = 3 x 1
Why convert? Sometimes easier to use exponent rules, sometimes radical form is clearer
SAT Question Types
Type 1: Simplify Expressions
Strategy:
Apply exponent/radical rules step by step
Combine like terms
Simplify radicals completely
Type 2: Solve Equations with Exponents
Example: 2 x + 1 = 32 2^{x+1} = 32 2 x + 1 = 32
Solution:
Rewrite 32 as power of 2: 32 = 2 5 32 = 2^5 32 = 2 5
2 x + 1 = 2 5 2^{x+1} = 2^5 2 x + 1 = 2 5
Same base → exponents equal: x + 1 = 5 x + 1 = 5 x + 1 = 5
x = 4 x = 4 x = 4
Type 3: Solve Equations with Radicals
Example: x + 3 = 5 \sqrt{x + 3} = 5 x + 3 = 5
Solution:
Square both sides: x + 3 = 25 x + 3 = 25 x + 3 = 25
Solve: x = 22 x = 22 x = 22
Always check! 22 + 3 = 25 = 5 \sqrt{22 + 3} = \sqrt{25} = 5 22 + 3 = 25 = 5 ✓
Type 4: Simplify Radicals
Example: Simplify 200 \sqrt{200} 200
Solution:
200 = 100 ⋅ 2 200 = 100 \cdot 2 200 = 100 ⋅ 2
200 = 100 ⋅ 2 = 10 2 \sqrt{200} = \sqrt{100} \cdot \sqrt{2} = 10\sqrt{2} 200 = 100 ⋅ 2 = 10 2
Type 5: Compare Values
Which is larger: 2 100 2^{100} 2 100 or 4 50 4^{50} 4 50 ?
Solution:
Rewrite with same base: 4 50 = ( 2 2 ) 50 = 2 100 4^{50} = (2^2)^{50} = 2^{100} 4 50 = ( 2 2 ) 50 = 2 100
They're equal!
Common SAT Mistakes
❌ Confusing addition and multiplication of exponents
x 2 ⋅ x 3 = x 5 x^2 \cdot x^3 = x^5 x 2 ⋅ x 3 = x 5 (NOT x 6 x^6 x 6 )
( x 2 ) 3 = x 6 (x^2)^3 = x^6 ( x 2 ) 3 = x 6 (NOT x 5 x^5 x 5 )
❌ Distributing exponents incorrectly
( x + y ) 2 ≠ x 2 + y 2 (x + y)^2 \neq x^2 + y^2 ( x + y ) 2 = x 2 + y 2
Must use FOIL: ( x + y ) 2 = x 2 + 2 x y + y 2 (x + y)^2 = x^2 + 2xy + y^2 ( x + y ) 2 = x 2 + 2 x y + y 2
❌ Forgetting to flip negative exponents
x − 2 = 1 x 2 x^{-2} = \frac{1}{x^2} x − 2 = x 2 1 (NOT − x 2 -x^2 − x 2 )
❌ Not simplifying radicals completely
48 = 4 3 \sqrt{48} = 4\sqrt{3} 48 = 4 3 (NOT 2 12 2\sqrt{12} 2 12 )
❌ Squaring both sides creates extraneous solutions
Always check answers in original equation!
❌ Mishandling fractional exponents
x 2 3 = ( x 3 ) 2 x^{\frac{2}{3}} = (\sqrt[3]{x})^2 x 3 2 = ( 3 x ) 2 (root THEN power)
Quick Reference Table
| Expression | Equivalent | Example |
|------------|-----------|---------|
| x 0 x^0 x 0 | 1 1 1 | 5 0 = 1 5^0 = 1 5 0 = 1 |
| x − a x^{-a} x − a | 1 x a \frac{1}{x^a} x a 1 | x − 3 = 1 x 3 x^{-3} = \frac{1}{x^3} x − 3 = x 3 1 |
| x 1 2 x^{\frac{1}{2}} x 2 1 | x \sqrt{x} x | 16 1 2 = 4 16^{\frac{1}{2}} = 4 1 6 2 1 = 4 |
| x 1 n x^{\frac{1}{n}} x n 1 | x n \sqrt[n]{x} n x | 8 1 3 = 2 8^{\frac{1}{3}} = 2 8 3 1 = 2 |
| x m n x^{\frac{m}{n}} x n m | ( x n ) m (\sqrt[n]{x})^m ( n x ) m | 8 2 3 = 4 8^{\frac{2}{3}} = 4 8 3 2 = 4 |
| x a ⋅ x b x^a \cdot x^b x a ⋅ x b | x a + b x^{a+b} x a + b | x 2 ⋅ x 3 = x 5 x^2 \cdot x^3 = x^5 x 2 ⋅ x 3 = x 5 |
| x a x b \frac{x^a}{x^b} x b x a | x a − b x^{a-b} x a − b | x 5 x 2 = x 3 \frac{x^5}{x^2} = x^3 x 2 x 5 = x 3 |
| ( x a ) b (x^a)^b ( x a ) b | x a b x^{ab} x ab | ( x 2 ) 3 = x 6 (x^2)^3 = x^6 ( x 2 ) 3 = x 6 |
Practice Tips
✓ Memorize the rules — they appear on EVERY SAT
✓ Rewrite with same base when comparing or solving
✓ Convert between forms (radical ↔ exponent) for easier manipulation
✓ Factor out perfect squares when simplifying radicals
✓ Check solutions especially after squaring both sides
✓ Use calculator strategically for numerical values, but show algebraic work
Remember: Exponent and radical rules are fundamental — master these and many SAT problems become much easier!