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🎯⭐ INTERACTIVE LESSON

Types of Chemical Reactions

Learn step-by-step with interactive practice!

Types of Chemical Reactions - Complete Interactive Lesson

Part 1: Synthesis & Decomposition

⚗️ Synthesis & Decomposition Reactions

Part 1 of 7 — Building Up and Breaking Down


Topics in This Part

Section
🎯 Synthesis (Combination) Reactions
General Form
Classic Examples
Key Pattern
Real-World Example

🔑 Key Concept: Mastering this material will strengthen your foundation for both the AP Chemistry exam and more advanced chemistry topics.


What You'll Master in Part 1

  • Understanding the core concepts covered in Part 1
  • Applying these ideas to solve practice problems
  • Building toward AP exam readiness for this topic

🎯 Synthesis (Combination) Reactions

A synthesis reaction occurs when two or more reactants combine to form a single product.


General Form

A+B→AB\boxed{A + B \rightarrow AB}


Classic Examples

ReactantsProductBalanced Equation
Metal + NonmetalIonic compound2Na+Cl2→2NaCl2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl}
Metal oxide + WaterMetal hydroxideCaO+H2O→Ca(OH)2\text{CaO} + \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2
Nonmetal oxide + WaterAcidSO3+H2O→H2SO4\text{SO}_3 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{SO}_4
Two elementsCompound2H2+O2→2H2O2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}

Key Pattern

🔑 Key Concept: Look for multiple reactants forming one product. The number of reactants is always greater than the number of products (which is 1).


Real-World Example

Rust formation is a synthesis reaction: 4Fe+3O2→2Fe2O3\boxed{4\text{Fe} + 3\text{O}_2 \rightarrow 2\text{Fe}_2\text{O}_3}

⚗️ Decomposition Reactions

A decomposition reaction occurs when a single reactant breaks down into two or more simpler products.


General Form

AB→A+B\boxed{AB \rightarrow A + B}


Classic Examples

ReactantProductsBalanced Equation
Metal carbonateMetal oxide + CO2CO_{2}CaCO3→CaO+CO2\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2
Metal hydroxideMetal oxide + H2OH_{2}OCa(OH)2→CaO+H2O\text{Ca(OH)}_2 \rightarrow \text{CaO} + \text{H}_2\text{O}
Metal chlorateMetal chloride + O2O_{2}2KClO3→2KCl+3O22\text{KClO}_3 \rightarrow 2\text{KCl} + 3\text{O}_2
Water (electrolysis)H2H_{2} + O2O_{2}2H2O→2H2+O22\text{H}_2\text{O} \rightarrow 2\text{H}_2 + \text{O}_2

Key Pattern

🔑 Key Concept: Look for one reactant producing multiple products. Decomposition often requires energy input (heat, electricity, or light).


Common Triggers

  • Heating (symbol: Δ\Delta above arrow) — thermal decomposition
  • Electrolysis — using electrical energy
  • Photodecomposition — light-driven breakdown (e.g., AgBr in photography)

🎯 Synthesis vs. Decomposition — A Comparison

FeatureSynthesisDecomposition
DirectionSimpler → ComplexComplex → Simpler
ReactantsTwo or moreOne
ProductsOneTwo or more
EnergyOften releases energyOften requires energy
General formA+B→ABA + B \rightarrow ABAB→A+BAB \rightarrow A + B

Memory Trick

💡 Tip: Use word roots to remember:

  • Synthesis = "put together" (syn- means together)
  • Decomposition = "break apart" (de- means undo, compose means put together)

These reactions are essentially reverses of each other. If a synthesis reaction forms a compound, the decomposition of that compound yields the original elements or simpler compounds.

Synthesis & Decomposition Concept Quiz 🎯

Identify the Reaction Type 🧮

For each reaction, type synthesis or decomposition.

1) 2Al+3Br2→2AlBr32\text{Al} + 3\text{Br}_2 \rightarrow 2\text{AlBr}_3

2) 2HgO→Δ2Hg+O22\text{HgO} \xrightarrow{\Delta} 2\text{Hg} + \text{O}_2

3) N2+3H2→2NH3\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3

Fill in the Blanks — Synthesis & Decomposition 🔽

Exit Quiz — Synthesis & Decomposition ✅

Part 2: Single & Double Replacement

🔄 Single & Double Replacement Reactions

Part 2 of 7 — Trading Partners


Topics in This Part

Section
📌 Single Replacement (Single Displacement)
General Form
Examples
No Reaction Example
📌 The Activity Series

🔑 Key Concept: Mastering this material will strengthen your foundation for both the AP Chemistry exam and more advanced chemistry topics.


What You'll Master in Part 2

  • Understanding the core concepts covered in Part 2
  • Applying these ideas to solve practice problems
  • Building toward AP exam readiness for this topic

📌 Single Replacement (Single Displacement)

A more reactive element displaces a less reactive element from a compound.


General Form

A+BC→AC+B\boxed{A + BC \rightarrow AC + B}

Element A replaces element B in compound BC, but only if A is more reactive than B.


Examples

ReactionEquation
Metal replaces metalZn+CuSO4→ZnSO4+Cu\text{Zn} + \text{CuSO}_4 \rightarrow \text{ZnSO}_4 + \text{Cu}
Metal replaces hydrogenMg+2HCl→MgCl2+H2\text{Mg} + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2
Halogen replaces halogenCl2+2NaBr→2NaCl+Br2\text{Cl}_2 + 2\text{NaBr} \rightarrow 2\text{NaCl} + \text{Br}_2

No Reaction Example

Cu+ZnSO4→No Reaction\text{Cu} + \text{ZnSO}_4 \rightarrow \text{No Reaction}

⚠️ Warning: Copper is less reactive than zinc, so it cannot displace zinc from solution. Always check the activity series before predicting products — if the free element is below the element in the compound, no reaction occurs.

📌 The Activity Series

The activity series ranks metals (and hydrogen) by their ability to lose electrons and form cations. A higher metal can replace a lower one.


Metal Activity Series (Most → Least Reactive)

Most ReactiveLeast Reactive
Li, K, Ba, Ca, NaMg, Al, Zn, FeNi, Sn, Pb, H2H_{2}Cu, Hg, Ag, Pt, Au

Key Rules

🔑 Key Concept: The activity series determines which replacement reactions will occur:

  1. A metal above H2H_{2} can react with acids to produce H2H_{2} gas
  2. A metal below H2H_{2} (Cu, Ag, Au) cannot dissolve in common acids
  3. A metal can replace any metal below it in solution
  4. A halogen can replace any halogen below it: F2F_{2} > Cl2Cl_{2} > Br2Br_{2} > I2I_{2}

Memory Aid

Little Kids Bake Cakes Naturally → Makes All Zealous Fellows... → Nice Snacks Pbring Happiness → Curious Humming Agent Ptays Auto

📌 Double Replacement (Double Displacement / Metathesis)

Two ionic compounds in solution exchange ions to form two new compounds.


General Form

AB+CD→AD+CB\boxed{AB + CD \rightarrow AD + CB}

The cations and anions switch partners.


Driving Forces

A double replacement reaction occurs when one of the products is:

  1. A precipitate (insoluble solid, denoted ↓)
  2. Water (a molecular compound)
  3. A gas (escapes the solution, denoted ↑)

Examples

Driving ForceReaction
PrecipitateAgNO3+NaCl→AgCl↓+NaNO3\text{AgNO}_3 + \text{NaCl} \rightarrow \text{AgCl}\downarrow + \text{NaNO}_3
WaterHCl+NaOH→NaCl+H2O\text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O}
GasNa2CO3+2HCl→2NaCl+H2O+CO2↑\text{Na}_2\text{CO}_3 + 2\text{HCl} \rightarrow 2\text{NaCl} + \text{H}_2\text{O} + \text{CO}_2\uparrow

Neutralization

The reaction of an acid with a base to form salt and water is a special case of double replacement:

Acid+Base→Salt+Water\boxed{\text{Acid} + \text{Base} \rightarrow \text{Salt} + \text{Water}}

Replacement Reactions Quiz 🎯

Predict the Reaction 🧮

For each scenario, indicate if a reaction occurs. Type the chemical formula of the solid metal produced, or type NR if no reaction occurs.

1) Fe+CuSO4→\text{Fe} + \text{CuSO}_4 \rightarrow ? (Iron is above copper in the activity series)

2) Cu+AgNO3→\text{Cu} + \text{AgNO}_3 \rightarrow ? (Copper is above silver in the activity series)

3) Ag+HCl→\text{Ag} + \text{HCl} \rightarrow ? (Silver is below hydrogen in the activity series)

Replacement Reactions — Fill in the Blanks 🔽

Exit Quiz — Single & Double Replacement ✅

Part 3: Combustion Reactions

🔥 Combustion Reactions

Part 3 of 7 — Burning It Down


Topics in This Part

Section
📌 Complete Combustion of Hydrocarbons
General Form
Common Examples
Key Recognition
📌 Combustion of Oxygenated Compounds

🔑 Key Concept: Mastering this material will strengthen your foundation for both the AP Chemistry exam and more advanced chemistry topics.


What You'll Master in Part 3

  • Understanding the core concepts covered in Part 3
  • Applying these ideas to solve practice problems
  • Building toward AP exam readiness for this topic

📌 Complete Combustion of Hydrocarbons

When a hydrocarbon (a compound containing only C and H) burns in excess oxygen, the products are always carbon dioxide and water.


General Form

CxHy+(x+y4)O2→xCO2+y2H2O\boxed{\text{C}_x\text{H}_y + \left(x + \frac{y}{4}\right)\text{O}_2 \rightarrow x\text{CO}_2 + \frac{y}{2}\text{H}_2\text{O}}


Common Examples

HydrocarbonBalanced Equation
Methane (CH4)(CH_{4})CH4+2O2→CO2+2H2O\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}
Propane (C3H8)(C_{3}H_{8})C3H8+5O2→3CO2+4H2O\text{C}_3\text{H}_8 + 5\text{O}_2 \rightarrow 3\text{CO}_2 + 4\text{H}_2\text{O}
Octane (C8H18)(C_{8}H_{18})2C8H18+25O2→16CO2+18H2O2\text{C}_8\text{H}_{18} + 25\text{O}_2 \rightarrow 16\text{CO}_2 + 18\text{H}_2\text{O}
Ethylene (C2H4)(C_{2}H_{4})C2H4+3O2→2CO2+2H2O\text{C}_2\text{H}_4 + 3\text{O}_2 \rightarrow 2\text{CO}_2 + 2\text{H}_2\text{O}

Key Recognition

💡 Tip: If you see a hydrocarbon + O2O_{2} → it's combustion. The products are always CO2CO_{2} + H2OH_{2}O for complete combustion.

📌 Combustion of Oxygenated Compounds

Compounds containing C, H, and O (like alcohols and sugars) also undergo combustion. The products are still CO2CO_{2} and H2OH_{2}O.


Examples

CompoundBalanced Equation
Methanol (CH3OH)(CH_{3}OH)2CH3OH+3O2→2CO2+4H2O2\text{CH}_3\text{OH} + 3\text{O}_2 \rightarrow 2\text{CO}_2 + 4\text{H}_2\text{O}
Ethanol (C2H5OH)(C_{2}H_{5}OH)C2H5OH+3O2→2CO2+3H2O\text{C}_2\text{H}_5\text{OH} + 3\text{O}_2 \rightarrow 2\text{CO}_2 + 3\text{H}_2\text{O}
Glucose (C6H12O6)(C_{6}H_{12}O_{6})C6H12O6+6O2→6CO2+6H2O\text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{CO}_2 + 6\text{H}_2\text{O}

Cellular Respiration

💡 Tip: Glucose combustion is chemically identical to cellular respiration — your body "burns" glucose to release energy!

C6H12O6+6O2→6CO2+6H2O+energy\boxed{\text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{CO}_2 + 6\text{H}_2\text{O} + \text{energy}}

📌 Complete vs. Incomplete Combustion

Complete Combustion

  • Occurs with excess oxygen
  • Products: CO2CO_{2} + H2OH_{2}O
  • Blue flame
  • Maximum energy released

Incomplete Combustion

  • Occurs with limited oxygen
  • Products may include: CO (carbon monoxide), C (soot), or both, along with H2OH_{2}O
  • Yellow/orange flame
  • Less energy released

⚠️ Warning: Carbon monoxide (CO) is toxic and odorless — this is why proper ventilation matters. CO binds to hemoglobin more strongly than O2O_{2}, preventing oxygen transport.


Comparison

FeatureCompleteIncomplete
O2O_{2} supplyExcessLimited
Carbon productCO2CO_{2}CO and/or C (soot)
Flame colorBlueYellow/orange
Energy outputMaximumLess
SafetySaferDangerous (CO)

Incomplete Combustion Example

2CH4+3O2→2CO+4H2O2\text{CH}_4 + 3\text{O}_2 \rightarrow 2\text{CO} + 4\text{H}_2\text{O}

With even less oxygen:

CH4+O2→C+2H2O\text{CH}_4 + \text{O}_2 \rightarrow \text{C} + 2\text{H}_2\text{O}

Combustion Reactions Quiz 🎯

Balance the Combustion Equations 🧮

Find the coefficient of O2O_{2} needed for complete combustion. Enter just the number.

1) C2H2+‾ O2→2CO2+H2O\text{C}_2\text{H}_2 + \underline{\hspace{1em}}\,\text{O}_2 \rightarrow 2\text{CO}_2 + \text{H}_2\text{O} → coefficient of O2O_{2} = ?

2) 2C4H10+‾ O2→8CO2+10H2O2\text{C}_4\text{H}_{10} + \underline{\hspace{1em}}\,\text{O}_2 \rightarrow 8\text{CO}_2 + 10\text{H}_2\text{O} → coefficient of O2O_{2} = ?

3) C2H5OH+‾ O2→2CO2+3H2O\text{C}_2\text{H}_5\text{OH} + \underline{\hspace{1em}}\,\text{O}_2 \rightarrow 2\text{CO}_2 + 3\text{H}_2\text{O} → coefficient of O2O_{2} = ?

Round all answers to 3 significant figures.

Combustion Concepts — Fill in the Blanks 🔽

Exit Quiz — Combustion Reactions ✅

Part 4: Precipitation Reactions

⚖️ Balancing Chemical Equations

Part 4 of 7 — The Coefficient Method


Topics in This Part

Section
⚖️ Rules for Balancing Equations
What You CAN Do
What You CANNOT Do
Step-by-Step Method
Example: Balancing Al+O2→Al2O3\text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3

🔑 Key Concept: Mastering this material will strengthen your foundation for both the AP Chemistry exam and more advanced chemistry topics.


What You'll Master in Part 4

  • Understanding the core concepts covered in Part 4
  • Applying these ideas to solve practice problems
  • Building toward AP exam readiness for this topic

⚖️ Rules for Balancing Equations

What You CAN Do

  • Change coefficients (the big numbers in front of formulas)

What You CANNOT Do

⚠️ Warning: Never change subscripts — that changes the identity of the compound! You also cannot add or remove substances. Only adjust coefficients.


Step-by-Step Method

  1. Write the unbalanced equation
  2. Count atoms of each element on both sides
  3. Balance one element at a time using coefficients
  4. Start with the most complex substance or elements that appear in only one reactant and one product
  5. Balance hydrogen and oxygen last (they often appear in multiple compounds)
  6. Check that all atoms are balanced
  7. Simplify coefficients to smallest whole numbers

Example: Balancing Al+O2→Al2O3\text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3

StepEquationAlO
StartAl+O2→Al2O3\text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_31 vs 22 vs 3
Balance Al2Al+O2→Al2O32\text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_32 vs 2 ✓2 vs 3
Balance O2Al+1.5O2→Al2O32\text{Al} + 1.5\text{O}_2 \rightarrow \text{Al}_2\text{O}_32 vs 2 ✓3 vs 3 ✓
Whole numbers4Al+3O2→2Al2O34\text{Al} + 3\text{O}_2 \rightarrow 2\text{Al}_2\text{O}_34 vs 4 ✓6 vs 6 ✓

⚛️ The Polyatomic Ion Shortcut

💡 Tip: When a polyatomic ion appears unchanged on both sides of an equation, treat it as a single unit rather than balancing individual atoms.


Example

Ca(OH)2+H3PO4→Ca3(PO4)2+H2O\text{Ca(OH)}_2 + \text{H}_3\text{PO}_4 \rightarrow \text{Ca}_3(\text{PO}_4)_2 + \text{H}_2\text{O}

Instead of counting individual H, O, and P atoms, notice:

  • PO4PO_{4} appears on both sides — treat it as one unit
  • Balance PO4PO_{4}: need 2 on left → coefficient of H3PO4H_{3}PO_{4} = 2 ✓
  • Balance Ca: need 3 on right → coefficient of Ca(OH)2Ca(OH)_{2} = 3 ✓
  • Count H: left has 3(2) + 2(3) = 12. Right needs 12 → coefficient of H2OH_{2}O = 6
  • Check O from OH and H2OH_{2}O: left 3(2) = 6 from OH; right 6 from H2OH_{2}O ✓

3Ca(OH)2+2H3PO4→Ca3(PO4)2+6H2O\boxed{3\text{Ca(OH)}_2 + 2\text{H}_3\text{PO}_4 \rightarrow \text{Ca}_3(\text{PO}_4)_2 + 6\text{H}_2\text{O}}


Common Polyatomic Ions to Watch For

IonFormulaIonFormula
SulfateSO42−SO_{4}^{2-}NitrateNO3−NO_{3}^{-}
PhosphatePO43−PO_{4}^{3-}CarbonateCO32−CO_{3}^{2-}
HydroxideOH−OH^{-}AmmoniumNH4+NH_{4}^{+}

🧪 Worked Examples

Example 1

Problem: Balance Fe+O2→Fe2O3\text{Fe} + \text{O}_2 \rightarrow \text{Fe}_2\text{O}_3

Solution:

  • Balance Fe: 2Fe+O2→Fe2O32\text{Fe} + \text{O}_2 \rightarrow \text{Fe}_2\text{O}_3 → Fe: 2 = 2 ✓
  • Balance O: need 3 O on left, but O2O_{2} gives even numbers → use LCM of 2 and 3 = 6
  • 2Fe+1.5O2→Fe2O32\text{Fe} + 1.5\text{O}_2 \rightarrow \text{Fe}_2\text{O}_3 → multiply all by 2: 4Fe+3O2→2Fe2O3\boxed{4\text{Fe} + 3\text{O}_2 \rightarrow 2\text{Fe}_2\text{O}_3}

Check: Fe: 4 = 4 ✓, O: 6 = 6 ✓


Example 2

Problem: Balance Al+HCl→AlCl3+H2\text{Al} + \text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2

Solution:

  • Balance Cl: Al+3HCl→AlCl3+H2\text{Al} + 3\text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2
  • Balance H: 3H on left, 2H on right → LCM = 6
  • Al+6HCl→2AlCl3+3H2\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2 → wait, now Cl: 6 vs 6 ✓
  • Balance Al: need 2 on left: 2Al+6HCl→2AlCl3+3H2\boxed{2\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2}

Check: Al: 2 = 2 ✓, H: 6 = 6 ✓, Cl: 6 = 6 ✓

Balancing Equations Quiz 🎯

Find the Missing Coefficients 🧮

Balance each equation. Enter the coefficient of the indicated substance.

1) ‾ N2+‾ H2→‾ NH3\underline{\hspace{1em}}\,\text{N}_2 + \underline{\hspace{1em}}\,\text{H}_2 \rightarrow \underline{\hspace{1em}}\,\text{NH}_3 → coefficient of H2H_{2} = ?

2) ‾ Al+‾ HCl→‾ AlCl3+‾ H2\underline{\hspace{1em}}\,\text{Al} + \underline{\hspace{1em}}\,\text{HCl} \rightarrow \underline{\hspace{1em}}\,\text{AlCl}_3 + \underline{\hspace{1em}}\,\text{H}_2 → coefficient of HCl = ?

3) ‾ Fe2O3+‾ CO→‾ Fe+‾ CO2\underline{\hspace{1em}}\,\text{Fe}_2\text{O}_3 + \underline{\hspace{1em}}\,\text{CO} \rightarrow \underline{\hspace{1em}}\,\text{Fe} + \underline{\hspace{1em}}\,\text{CO}_2 → coefficient of CO = ?

Balancing Strategy — Fill in the Blanks 🔽

Exit Quiz — Balancing Equations ✅

Part 5: Balancing Chemical Equations

🔮 Predicting Products

Part 5 of 7 — Using Reaction Types to Predict What Forms


Topics in This Part

Section
🎯 Product Prediction Strategy
Step 1: Classify the Reactants
Step 2: Apply the Pattern
Step 3: Balance the Equation
🎯 Predicting Synthesis Products

🔑 Key Concept: Mastering this material will strengthen your foundation for both the AP Chemistry exam and more advanced chemistry topics.


What You'll Master in Part 5

  • Understanding the core concepts covered in Part 5
  • Applying these ideas to solve practice problems
  • Building toward AP exam readiness for this topic

🎯 Product Prediction Strategy

🔑 Key Concept: The key to predicting products is to first identify the reaction type, then apply the pattern for that type.

Step 1: Classify the Reactants

Reactant PatternLikely Reaction Type
Two or more elements/compounds combiningSynthesis
One compound alone (+ heat/energy)Decomposition
Element + compoundSingle replacement
Two ionic compounds in solutionDouble replacement
Organic compound + O2O_{2}Combustion

Step 2: Apply the Pattern

Reaction TypeProduct Pattern
SynthesisOne compound
DecompositionSimpler substances
Single replacementNew element + new compound
Double replacementTwo new compounds (swap ions)
CombustionCO2CO_{2} + H2OH_{2}O

Step 3: Balance the Equation

After predicting the products, balance the equation using the coefficient method.

🎯 Predicting Synthesis Products

Metal + Nonmetal → Ionic Compound

Use charges to determine the formula:

ReactantsChargesProduct
Na + Cl2Cl_{2}Na+Na^{+}, Cl−Cl^{-}NaCl
Mg + O2O_{2}Mg2+Mg^{2+}, O2−O^{2-}MgO
Al + Br2Br_{2}Al3+Al^{3+}, Br−Br^{-}AlBr3AlBr_{3}
Ca + N2N_{2}Ca2+Ca^{2+}, N3−N^{3-}Ca3N2Ca_{3}N_{2}

Nonmetal Oxide + Water → Acid

Oxide+ H2OH_{2}OAcid
CO2CO_{2}H2OH_{2}OH2CO3H_{2}CO_{3}
SO3SO_{3}H2OH_{2}OH2SO4H_{2}SO_{4}
N2O5N_{2}O_{5}H2OH_{2}O2HNO32HNO_{3}

Metal Oxide + Water → Base (Metal Hydroxide)

Oxide+ H2OH_{2}OBase
Na2ONa_{2}OH2OH_{2}O2NaOH
CaOH2OH_{2}OCa(OH)2Ca(OH)_{2}
K2OK_{2}OH2OH_{2}O2KOH

🔮 Predicting Decomposition Products

Common Decomposition Patterns

Compound TypeProductsExample
Metal carbonateMetal oxide + CO2CO_{2}CaCO3→CaO+CO2\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2
Metal hydroxideMetal oxide + H2OH_{2}OMg(OH)2→MgO+H2O\text{Mg(OH)}_2 \rightarrow \text{MgO} + \text{H}_2\text{O}
Metal chlorateMetal chloride + O2O_{2}2KClO3→2KCl+3O22\text{KClO}_3 \rightarrow 2\text{KCl} + 3\text{O}_2
Metal oxideMetal + O2O_{2}2HgO→2Hg+O22\text{HgO} \rightarrow 2\text{Hg} + \text{O}_2
AcidNonmetal oxide + H2OH_{2}OH2CO3→CO2+H2O\text{H}_2\text{CO}_3 \rightarrow \text{CO}_2 + \text{H}_2\text{O}

Key Memory Tool

💡 Tip: Think of decomposition as "un-synthesizing" — the reverse of combining:

  • Carbonates → oxide + CO2CO_{2}
  • Hydroxides → oxide + H2OH_{2}O
  • Chlorates → chloride + O2O_{2}

🔮 Predicting Replacement Products

Single Replacement

  1. Check the activity series — will the reaction occur?
  2. The free element replaces the corresponding element in the compound

Zn+CuSO4→ZnSO4+Cu\text{Zn} + \text{CuSO}_4 \rightarrow \text{ZnSO}_4 + \text{Cu}

Zn replaces Cu because Zn is higher in the activity series.

⚠️ Warning: A common error is forgetting to check the activity series. If the free element is below the element in the compound, write NR (no reaction).


Double Replacement

  1. Identify the cations and anions
  2. Swap partners: cation1cation_{1} + anion2anion_{2} and cation2cation_{2} + anion1anion_{1}
  3. Write correct formulas using ion charges
  4. Check for a driving force (precipitate, gas, or water)

Pb(NO3)2+2KI→PbI2↓+2KNO3\text{Pb(NO}_3)_2 + 2\text{KI} \rightarrow \text{PbI}_2\downarrow + 2\text{KNO}_3

  • Pb2+Pb^{2+} pairs with I−I^{-} → PbI2PbI_{2} (insoluble precipitate — driving force!)
  • K+K^{+} pairs with NO3−NO_{3}^{-} → KNO3KNO_{3} (soluble)

Product Prediction Quiz 🎯

Predict the Products 🧮

Write the chemical formula of the main product. Use standard notation (no spaces, no charges).

1) Synthesis: K+Cl2→\text{K} + \text{Cl}_2 \rightarrow ? (K has charge +1, Cl has charge −1)

2) Decomposition: MgCO3→Δ\text{MgCO}_3 \xrightarrow{\Delta} ? + CO2CO_{2} — what is the other product?

3) Combustion: CH4+2O2→\text{CH}_4 + 2\text{O}_2 \rightarrow ? + 2H2O2H_{2}O — what is the other product?

Prediction Strategy — Fill in the Blanks 🔽

Exit Quiz — Predicting Products ✅

Part 6: Problem-Solving Workshop

🛠️ Problem-Solving Workshop

Part 6 of 7 — Identifying, Balancing, and Predicting


Practice Makes Perfect

This workshop features multi-step problems that mirror the AP Chemistry exam format. Each problem requires you to combine concepts from previous parts and show your work clearly.

🔑 Why this matters: The AP Chemistry exam rewards students who can apply concepts to unfamiliar problems — structured practice is the best preparation.


What You'll Master in Part 6

  • Working through complete multi-step problems from start to finish
  • Building problem-solving strategies you can apply on the AP exam
  • Identifying which concepts to apply and in what order

📌 The Complete Workflow

Step 1: Identify the Reaction Type

💡 Tip: On the AP exam, quickly classify reactions by counting reactants/products and looking for O2O_{2}, free elements, or ionic compounds exchanging partners.

ClueReaction Type
Multiple reactants → one productSynthesis
One reactant → multiple productsDecomposition
Element + compound → element + compoundSingle replacement
Two compounds → two new compoundsDouble replacement
Fuel + O2O_{2} → CO2CO_{2} + H2OH_{2}OCombustion

Step 2: Predict Products

Apply the rules for that reaction type:

  • Synthesis: combine to form one compound
  • Decomposition: break into simpler substances
  • Single replacement: check activity series, swap element
  • Double replacement: swap cations, check for driving force
  • Combustion: products are CO2CO_{2} + H2OH_{2}O

Step 3: Write Correct Formulas

Use ion charges for ionic compounds. Don't forget subscripts!


Step 4: Balance the Equation

Use coefficients. Check every atom. Simplify to smallest whole numbers.

🧪 Worked Examples

Example 1

Problem: Mg+N2→\text{Mg} + \text{N}_2 \rightarrow ?

Solution:

  1. Type: Two elements combining → Synthesis
  2. Product: Mg2+Mg^{2+} + N3−N^{3-} → Mg3N2Mg_{3}N_{2} (cross charges: 3 Mg, 2 N)
  3. Balance:

3Mg+N2→Mg3N2\boxed{3\text{Mg} + \text{N}_2 \rightarrow \text{Mg}_3\text{N}_2}


Example 2

Problem: Fe+AgNO3→\text{Fe} + \text{AgNO}_3 \rightarrow ?

Solution:

  1. Type: Element + compound → Single replacement
  2. Activity series: Fe is above Ag → reaction proceeds
  3. Product: Fe replaces Ag. Fe has charge +2 → Fe(NO3)2Fe(NO_{3})_{2} + Ag
  4. Balance:

Fe+2AgNO3→Fe(NO3)2+2Ag\boxed{\text{Fe} + 2\text{AgNO}_3 \rightarrow \text{Fe(NO}_3)_2 + 2\text{Ag}}


Example 3

Problem: Na2CO3+CaCl2→\text{Na}_2\text{CO}_3 + \text{CaCl}_2 \rightarrow ?

Solution:

  1. Type: Two ionic compounds → Double replacement
  2. Swap: Na+Na^{+} with Cl−Cl^{-} → NaCl; Ca2+Ca^{2+} with CO32−CO_{3}^{2-} → CaCO3CaCO_{3}
  3. Driving force: CaCO3CaCO_{3} is insoluble → precipitate forms ✓
  4. Balance:

Na2CO3+CaCl2→CaCO3↓+2NaCl\boxed{\text{Na}_2\text{CO}_3 + \text{CaCl}_2 \rightarrow \text{CaCO}_3\downarrow + 2\text{NaCl}}

Classify and Analyze 🎯

Full Workflow Practice 🧮

Identify each reaction type. Type: synthesis, decomposition, single, double, or combustion.

1) 4Fe+3O2→2Fe2O34\text{Fe} + 3\text{O}_2 \rightarrow 2\text{Fe}_2\text{O}_3

2) AgNO3+NaCl→AgCl+NaNO3\text{AgNO}_3 + \text{NaCl} \rightarrow \text{AgCl} + \text{NaNO}_3

3) C2H6+72O2→2CO2+3H2O\text{C}_2\text{H}_6 + \frac{7}{2}\text{O}_2 \rightarrow 2\text{CO}_2 + 3\text{H}_2\text{O}

Predict Products and Balance 🔬

Workshop Review — Fill in the Blanks 🔽

Exit Quiz — Problem-Solving Workshop ✅

Part 7: Synthesis & AP Review

🎓 Synthesis & AP Review

Part 7 of 7 — AP-Style Questions on Reaction Classification


Bringing It All Together

This comprehensive review connects every concept from Parts 1–6 with AP-style problems. The questions are designed to mirror what you'll see on the actual exam — multi-step, multi-concept, and requiring clear written explanations.

🔑 Why this matters: AP Chemistry exam questions rarely test one concept in isolation — success requires connecting ideas across topics.


What You'll Master in Part 7

  • Solving AP-style questions that integrate multiple concepts from this unit
  • Writing clear, concise explanations using proper chemistry terminology
  • Identifying and avoiding common AP exam traps and mistakes

📋 Complete Reaction Type Summary

TypeGeneral FormKey Signal
SynthesisA+B→ABA + B \rightarrow ABMany → one
DecompositionAB→A+BAB \rightarrow A + BOne → many (often with Δ\Delta)
Single ReplacementA+BC→AC+BA + BC \rightarrow AC + BFree element + compound
Double ReplacementAB+CD→AD+CBAB + CD \rightarrow AD + CBTwo ionic compounds swap ions
CombustionFuel+O2→CO2+H2O\text{Fuel} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O}Organic + O2O_{2}

🔑 Key Concept: To classify any reaction, follow this decision tree: (1) Only one reactant? → Decomposition. (2) Only one product? → Synthesis. (3) O2O_{2} + fuel → CO2CO_{2} + H2OH_{2}O? → Combustion. (4) Free element + compound? → Single replacement. (5) Two ionic compounds? → Double replacement.


📌 AP Exam Tips

  1. Read carefully — the AP exam often describes reactions in words rather than symbols
  2. Know the activity series — required for predicting single replacement
  3. Know solubility rules — required for identifying precipitates in double replacement
  4. Balancing must be correct — even if the products are right, unbalanced equations lose points
  5. State symbols matter — (s), (l), (g), (aq) are often tested
  6. Net ionic equations — AP frequently asks for these in double replacement reactions

💡 Tip: On the AP exam, quickly scan for visual cues: a lone reactant (decomposition), O2O_{2} on the left with CO2CO_{2} + H2OH_{2}O on the right (combustion), a free element mixed with a compound (single replacement), or two aqueous ionic compounds (double replacement).

⚠️ Warning: Common errors when predicting products: (1) writing incorrect ionic formulas by not cross-checking charges, (2) forgetting to consult the activity series for single replacement, (3) predicting a double replacement when no driving force exists (no precipitate, gas, or water), and (4) submitting unbalanced equations.

🔄 Net Ionic Equations — Quick Review

For double replacement reactions in solution, the AP exam often asks for net ionic equations.


📌 Step-by-Step Method

StepActionExample
1Write balanced molecular equationAgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq)\text{AgNO}_3(\text{aq}) + \text{NaCl}(\text{aq}) \rightarrow \text{AgCl}(\text{s}) + \text{NaNO}_3(\text{aq})
2Split soluble ionic compounds into ionsAg++NO3−+Na++Cl−→AgCl(s)+Na++NO3−\text{Ag}^+ + \text{NO}_3^- + \text{Na}^+ + \text{Cl}^- \rightarrow \text{AgCl}(\text{s}) + \text{Na}^+ + \text{NO}_3^-
3Cancel spectator ions (unchanged on both sides)Na+Na^{+} and NO3−NO_{3}^{-} cancel
4Write the net ionic equationAg+(aq)+Cl−(aq)→AgCl(s)\text{Ag}^+(\text{aq}) + \text{Cl}^-(\text{aq}) \rightarrow \text{AgCl}(\text{s})

🧪 What to Split vs. Keep Whole

Split into ionsKeep as one formula
Soluble ionic compounds (aq)Precipitates (s)
Strong acids (aq)Weak acids / bases
Strong bases (aq)Water, gases

💡 Spectator ions appear unchanged on both sides — they don't participate in the actual reaction.

AP-Style Questions — Set 1 🎯

AP-Style Identification 🧮

Classify each reaction. Type: synthesis, decomposition, single, double, or combustion.

1) 2Na+Cl2→2NaCl2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl}

2) Pb(NO3)2(aq)+2KI(aq)→PbI2(s)+2KNO3(aq)\text{Pb(NO}_3)_2(\text{aq}) + 2\text{KI}(\text{aq}) \rightarrow \text{PbI}_2(\text{s}) + 2\text{KNO}_3(\text{aq})

3) 2C8H18+25O2→16CO2+18H2O2\text{C}_8\text{H}_{18} + 25\text{O}_2 \rightarrow 16\text{CO}_2 + 18\text{H}_2\text{O}

AP-Style Questions — Set 2 🔬

Comprehensive Review — Fill in the Blanks 🔽

Final Exit Quiz — Reaction Types Mastery ✅