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Density and Pressure in Fluids

Density, pressure, hydrostatic pressure, and Pascal's principle

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💧 Density and Pressure

A fluid is anything that flows — gases and liquids. AP Physics 1 (Unit 8) treats fluids as incompressible and non-viscous unless told otherwise.

Density

ρ=mV\rho = \frac{m}{V}

  • ρ\rho = density (kg/m³)
  • mm = mass (kg)
  • VV = volume (m³)

Reference: ρwater=1000\rho_{\text{water}} = 1000 kg/m³ = 1 g/cm³.

Relative (specific) density = ρobject/ρwater\rho_{\text{object}}/\rho_{\text{water}}. If it's < 1 the object floats in water; > 1 it sinks.


Pressure

P=F⊥AP = \frac{F_\perp}{A}

  • PP = pressure (Pa = N/m²)
  • F⊥F_\perp = force perpendicular to the surface
  • AA = area

Pressure is a scalar — it acts in all directions at a point.


Hydrostatic (Gauge) Pressure

For a fluid at rest, the pressure increases linearly with depth:

P=P0+ρghP = P_0 + \rho g h

  • P0P_0 = pressure at the surface (often atmospheric, ≈1.0×105\approx 1.0\times10^{5} Pa)
  • ρgh\rho g h is called the gauge pressure — pressure above atmospheric

💡 Key Idea: Pressure depends only on depth and fluid density, not on container shape or total volume.


Pascal's Principle

A pressure change applied to an enclosed, incompressible fluid is transmitted undiminished to every point in the fluid.

For a hydraulic lift:

F1A1=F2A2\frac{F_1}{A_1} = \frac{F_2}{A_2}

A small force on a small piston produces a much larger force on a large piston (mechanical advantage = A2/A1A_2/A_1).


⚠️ Common Mistakes

  1. Using container shape: Pressure at depth hh does not depend on container shape — only hh.
  2. Confusing absolute vs. gauge pressure: Pabs=Patm+ρghP_{\text{abs}} = P_{\text{atm}} + \rho g h.
  3. Mixing units: 1 L = 0.001 m³. Always convert to SI.

Key Formulas

QuantityFormulaUnits
Densityρ=m/V\rho = m/Vkg/m³
PressureP=F/AP = F/APa = N/m²
Gauge pressureP=ρghP = \rho g hPa
Hydraulic liftF1/A1=F2/A2F_1/A_1 = F_2/A_2—

📚 Practice Problems

1Problem 1easy

❓ Question:

A diver descends to 12 m below the surface of a freshwater lake. What is the absolute pressure at that depth? (Patm=1.0×105P_{\text{atm}} = 1.0\times10^{5} Pa, g=9.8g = 9.8 m/s²)

💡 Show Solution

Hydrostatic pressure: ρgh=1000(9.8)(12)=1.176×105\rho g h = 1000(9.8)(12) = 1.176\times10^{5} Pa.

Absolute pressure: P=Patm+ρgh=1.0×105+1.176×105≈2.18×105P = P_{\text{atm}} + \rho g h = 1.0\times10^{5} + 1.176\times10^{5} \approx 2.18\times10^{5} Pa.

2Problem 2medium

❓ Question:

A hydraulic lift has a small piston of area 0.0050.005 m² and a large piston of area 0.200.20 m². What input force lifts a 1500 kg car?

💡 Show Solution

Weight to lift: W=mg=1500(9.8)=14,700W = mg = 1500(9.8) = 14{,}700 N.

Pascal's principle: F1/A1=F2/A2F_1/A_1 = F_2/A_2, so F1=F2A1A2=14,700⋅0.0050.20=367.5 N.F_1 = F_2 \frac{A_1}{A_2} = 14{,}700 \cdot \frac{0.005}{0.20} = 367.5\text{ N}.

3Problem 3medium

❓ Question:

A rectangular tank holds 0.40 m³ of olive oil (ρ=920\rho = 920 kg/m³). Find the mass of oil and the gauge pressure at the bottom of a 0.80 m column.

💡 Show Solution

Mass: m=ρV=920(0.40)=368m = \rho V = 920(0.40) = 368 kg.

Gauge pressure at depth 0.80 m: P=ρgh=920(9.8)(0.80)≈7.21×103P = \rho g h = 920(9.8)(0.80) \approx 7.21\times10^{3} Pa.

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📌 Related Topics in Fluids

❓ Frequently Asked Questions

What is Density and Pressure in Fluids?▾
Density, pressure, hydrostatic pressure, and Pascal's principle
How can I study Density and Pressure in Fluids effectively?▾
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 3 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
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What course covers Density and Pressure in Fluids?▾
Density and Pressure in Fluids is part of the AP Physics 1 course on Study Mondo, specifically in the Fluids section. You can explore the full course for more related topics and practice resources.
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Yes, this page includes 3 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.