Skip to content

Buoyancy and Archimedes' Principle

Buoyant force, floating, sinking, and apparent weight in a fluid

Written and reviewed by the Study Mondo Education TeamLast updated
🎯⭐ INTERACTIVE LESSON

Try the Interactive Version!

Learn step-by-step with practice exercises built right in.

Start Interactive Lesson →

🛶 Buoyancy and Archimedes' Principle

When an object is submerged (fully or partially) in a fluid, the fluid exerts an upward buoyant force. This is just the net effect of pressure being larger on the bottom of the object than on the top.

Archimedes' Principle

Fb=ρfluid g VdispF_b = \rho_{\text{fluid}} \, g \, V_{\text{disp}}

  • ρfluid\rho_{\text{fluid}} = density of the fluid (not the object!)
  • VdispV_{\text{disp}} = volume of fluid displaced by the object

💡 Key Idea: Buoyant force equals the weight of the fluid displaced.


Floating, Sinking, Suspended

For an object of density ρobj\rho_{\text{obj}} in a fluid of density ρfluid\rho_{\text{fluid}}:

ConditionResult
ρobj<ρfluid\rho_{\text{obj}} < \rho_{\text{fluid}}Floats — only part submerged
ρobj=ρfluid\rho_{\text{obj}} = \rho_{\text{fluid}}Suspended anywhere in the fluid
ρobj>ρfluid\rho_{\text{obj}} > \rho_{\text{fluid}}Sinks to the bottom

For a floating object the buoyant force equals its weight:

ρfluidgVsub=ρobjgVobj\rho_{\text{fluid}} g V_{\text{sub}} = \rho_{\text{obj}} g V_{\text{obj}}

So the submerged fraction equals the density ratio:

VsubVobj=ρobjρfluid\frac{V_{\text{sub}}}{V_{\text{obj}}} = \frac{\rho_{\text{obj}}}{\rho_{\text{fluid}}}


Apparent Weight

When an object is fully submerged but not floating freely:

Wapparent=Wactual−Fb=(ρobj−ρfluid)gVW_{\text{apparent}} = W_{\text{actual}} - F_b = (\rho_{\text{obj}} - \rho_{\text{fluid}}) g V

This is what a scale reads when an object hangs from it underwater.


⚠️ Common Mistakes

  1. Using the wrong density. Buoyancy uses the fluid's density, not the object's.
  2. Forgetting partial submersion. A floating object only displaces enough fluid to balance its weight.
  3. Confusing weight and apparent weight. True weight does not change underwater — only the net downward force does.

Key Formulas

QuantityFormula
Buoyant forceFb=ρfluidgVdispF_b = \rho_{\text{fluid}} g V_{\text{disp}}
Float conditionρobj<ρfluid\rho_{\text{obj}} < \rho_{\text{fluid}}
Submerged fraction (floating)Vsub/Vobj=ρobj/ρfluidV_{\text{sub}}/V_{\text{obj}} = \rho_{\text{obj}}/\rho_{\text{fluid}}
Apparent weightWapp=W−FbW_{\text{app}} = W - F_b

📚 Practice Problems

1Problem 1easy

❓ Question:

A 5.0 kg block of aluminum (ρ=2700\rho = 2700 kg/m³) is fully submerged in water. Find the buoyant force on it.

💡 Show Solution

Volume of block: V=m/ρ=5.0/2700≈1.85×10−3V = m/\rho = 5.0/2700 \approx 1.85\times10^{-3} m³.

Buoyant force (fully submerged → Vdisp=VV_{\text{disp}} = V): Fb=ρwatergV=1000(9.8)(1.85×10−3)≈18.1 N.F_b = \rho_{\text{water}} g V = 1000(9.8)(1.85\times10^{-3}) \approx 18.1\text{ N}.

2Problem 2medium

❓ Question:

A wooden block of density 600 kg/m³ floats in water. What fraction of the block is submerged?

💡 Show Solution

Floating equilibrium: ρfluidVsub=ρobjVobj\rho_{\text{fluid}} V_{\text{sub}} = \rho_{\text{obj}} V_{\text{obj}}.

VsubVobj=6001000=0.60.\frac{V_{\text{sub}}}{V_{\text{obj}}} = \frac{600}{1000} = 0.60.

So 60% of the block is below the water surface.

3Problem 3medium

❓ Question:

A 2.0 kg metal sphere has a volume of 5.0×10−45.0\times10^{-4} m³ and is completely submerged in water while hanging from a string. Find the tension in the string.

💡 Show Solution

Weight: W=mg=2.0(9.8)=19.6W = mg = 2.0(9.8) = 19.6 N.

Buoyant force: Fb=ρwatergV=1000(9.8)(5.0×10−4)=4.9F_b = \rho_{\text{water}} g V = 1000(9.8)(5.0\times10^{-4}) = 4.9 N.

String tension balances net downward force: T=W−Fb=19.6−4.9=14.7 N.T = W - F_b = 19.6 - 4.9 = 14.7\text{ N}.

Explain using:

📌 Related Topics in Fluids

❓ Frequently Asked Questions

What is Buoyancy and Archimedes' Principle?▾
Buoyant force, floating, sinking, and apparent weight in a fluid
How can I study Buoyancy and Archimedes' Principle effectively?▾
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 3 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
Is this Buoyancy and Archimedes' Principle study guide free?▾
Yes — all study notes, flashcards, and practice problems for Buoyancy and Archimedes' Principle on Study Mondo are free to access. No account is needed.
What course covers Buoyancy and Archimedes' Principle?▾
Buoyancy and Archimedes' Principle is part of the AP Physics 1 course on Study Mondo, specifically in the Fluids section. You can explore the full course for more related topics and practice resources.
Are there practice problems for Buoyancy and Archimedes' Principle?▾
Yes, this page includes 3 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.