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Equilibrium Constants and Expressions

Write equilibrium expressions and calculate Kc and Kp for reversible reactions.

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Equilibrium Constants and Expressions

Chemical Equilibrium

A reversible reaction reaches dynamic equilibrium when the forward and reverse rates are equal, and concentrations stop changing.

Equilibrium Expression

For the reaction: aA+bB⇌cC+dDaA + bB \rightleftharpoons cC + dD

Kc=[C]c[D]d[A]a[B]bK_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}

Rules for Writing KK Expressions

  1. Products over reactants, each raised to their stoichiometric coefficient
  2. Omit pure solids and pure liquids (activities = 1)
  3. Use molar concentrations for KcK_c, partial pressures for KpK_p

KcK_c vs KpK_p

Kp=Kc(RT)ΔnK_p = K_c(RT)^{\Delta n}

where Δn=moles gas products−moles gas reactants\Delta n = \text{moles gas products} - \text{moles gas reactants}

Magnitude of KK

KK ValueMeaning
K≫1K \gg 1Products favored at equilibrium
K≪1K \ll 1Reactants favored at equilibrium
K≈1K \approx 1Significant amounts of both

Manipulating KK

OperationNew KK
Reverse reactionK′=1KK' = \frac{1}{K}
Multiply by nnK′=KnK' = K^n
Add two reactionsK′=K1×K2K' = K_1 \times K_2

Reaction Quotient (QQ)

Same form as KK, but uses current concentrations:

Q=[C]c[D]d[A]a[B]b(at any moment)Q = \frac{[C]^c[D]^d}{[A]^a[B]^b} \quad \text{(at any moment)}

ComparisonDirection
Q<KQ < KReaction proceeds forward
Q>KQ > KReaction proceeds reverse
Q=KQ = KAt equilibrium

AP Chemistry Tip: The equilibrium expression only includes species in the aqueous or gaseous phase.

Explain using:

📋 AP Chemistry — Exam Format Guide

⏱ 3 hours 15 minutes📝 67 questions📊 3 sections
SectionFormatQuestionsTimeWeightCalculator
Multiple ChoiceMCQ6090 min50%✅
Free Response (Long)FRQ369 min30%✅
Free Response (Short)FRQ436 min20%✅

📊 Scoring: 1-5

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💡 Key Test-Day Tips

  • ✓Memorize common polyatomic ions
  • ✓Practice dimensional analysis
  • ✓Know your gas laws

⚠️ Common Mistakes: Equilibrium Constants and Expressions

Avoid these 3 frequent errors

🌍 Real-World Applications: Equilibrium Constants and Expressions

See how this math is used in the real world

📝 Worked Example: Stoichiometry — Limiting Reagent

Problem:

22 mol of H2H_2 reacts with 11 mol of O2O_2. How many grams of water are produced? Which is the limiting reagent? (2H2+O2→2H2O2H_2 + O_2 \to 2H_2O)

2Determine the limiting reagent
3Calculate moles of product
4Convert moles to grams

📌 Related Topics in Equilibrium

❓ Frequently Asked Questions

What is Equilibrium Constants and Expressions?▾
Write equilibrium expressions and calculate Kc and Kp for reversible reactions.
How can I study Equilibrium Constants and Expressions effectively?▾
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Regular review and active practice are key to retention.
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What course covers Equilibrium Constants and Expressions?▾
Equilibrium Constants and Expressions is part of the AP Chemistry course on Study Mondo, specifically in the Equilibrium section. You can explore the full course for more related topics and practice resources.