The Complex Number System

Define and perform operations with complex numbers including the imaginary unit i.

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The Complex Number System

The Imaginary Unit

i=1soi2=1i = \sqrt{-1} \quad \text{so} \quad i^2 = -1

Complex Numbers

A complex number has the form: a+bia + bi where aa is the real part and bb is the imaginary part.

Examples: 3+2i3 + 2i, 14i-1 - 4i, 55 (real), 7i7i (pure imaginary)

Operations with Complex Numbers

Addition and Subtraction

Combine like terms: (3+2i)+(15i)=43i(3 + 2i) + (1 - 5i) = 4 - 3i (6i)(2+3i)=44i(6 - i) - (2 + 3i) = 4 - 4i

Multiplication (FOIL)

(2+3i)(4i)=82i+12i3i2=8+10i+3=11+10i(2 + 3i)(4 - i) = 8 - 2i + 12i - 3i^2 = 8 + 10i + 3 = 11 + 10i

Powers of ii

i1=i,i2=1,i3=i,i4=1i^1 = i, \quad i^2 = -1, \quad i^3 = -i, \quad i^4 = 1

The pattern repeats every 4 powers. For ini^n, find nmod4n \mod 4.

Complex Conjugates

The conjugate of a+bia + bi is abia - bi.

(a+bi)(abi)=a2+b2(a + bi)(a - bi) = a^2 + b^2

Division

Multiply by the conjugate of the denominator: 3+2i1i=(3+2i)(1+i)(1i)(1+i)=3+3i+2i+2i21+1=1+5i2=12+52i\frac{3 + 2i}{1 - i} = \frac{(3+2i)(1+i)}{(1-i)(1+i)} = \frac{3+3i+2i+2i^2}{1+1} = \frac{1+5i}{2} = \frac{1}{2} + \frac{5}{2}i

Solving Equations with Complex Solutions

x2+4=0    x2=4    x=±2ix^2 + 4 = 0 \implies x^2 = -4 \implies x = \pm 2i

x26x+13=0x^2 - 6x + 13 = 0 x=6±36522=6±162=6±4i2=3±2ix = \frac{6 \pm \sqrt{36-52}}{2} = \frac{6 \pm \sqrt{-16}}{2} = \frac{6 \pm 4i}{2} = 3 \pm 2i

Key insight: Complex solutions to polynomials with real coefficients always come in conjugate pairs.

📚 Practice Problems

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