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🎯⭐ INTERACTIVE LESSON

Area of Composite Figures

Learn step-by-step with interactive practice!

Area of Composite Figures - Complete Interactive Lesson

Part 1: What Is a Composite Figure? 🧩

What Is a Composite Figure? 🧩

A composite figure (sometimes called a complex figure) is a shape made by putting together two or more basic shapes. Think of it like a puzzle: the big shape is built from smaller pieces you already know how to handle.

The basic building blocks are usually:

  • Rectangles and squares
  • Triangles
  • Circles and semicircles
  • Trapezoids and parallelograms

You see composite figures everywhere in real life:

  • The floor plan of a house
  • A garden split into different sections
  • A swimming pool shaped like a rectangle with a rounded end
  • Letters and logos like the giant "L" on a sign

The big idea is simple: break the messy shape into simple shapes, find each area, then combine them.

Review: The Area Formulas You Need 📐

Before we combine shapes, let's review the area formula for each basic piece. Keep this table handy!

ShapeFormulaMeaning
RectangleA=l×wA = l \times wlength times width
SquareA=s2A = s^2side times side
TriangleA=12bhA = \frac{1}{2}bhhalf of base times height
ParallelogramA=bhA = bhbase times height
TrapezoidA=12(b1+b2)hA = \frac{1}{2}(b_1 + b_2)hhalf the sum of the two bases, times height
CircleA=πr2A = \pi r^2pi times radius squared
SemicircleA=12πr2A = \frac{1}{2}\pi r^2half of a circle

Remember: the radius rr is half the diameter. If a circle's diameter is 66 cm, then r=3r = 3 cm.

We'll use π≈3.14\pi \approx 3.14 when we need a number for circle problems.

The 3-Step Strategy ✅

Every composite-figure problem follows the same plan:

Step 1 — Break it apart. Look for rectangles, triangles, and circles hiding inside. Draw a line to split the figure into simple pieces.

Step 2 — Find each area. Use the right formula for each piece and label your dimensions carefully.

Step 3 — Combine. Usually you add the pieces together:

Atotal=A1+A2+A3+…A_{total} = A_1 + A_2 + A_3 + \dots

Worked example — an L-shaped figure. Split the "L" into two rectangles:

  • Top rectangle: 88 ft by 33 ft → A1=8×3=24A_1 = 8 \times 3 = 24 ft2ft^{2}
  • Bottom rectangle: 55 ft by 44 ft → A2=5×4=20A_2 = 5 \times 4 = 20 ft2ft^{2}
  • Total: A=24+20=44A = 24 + 20 = 44 ft2ft^{2} ✓

That's it — split, solve each piece, then add!

Concept Check ✅

Let's make sure the main idea is clear before moving on.

Part 2: Worked Example: A "House" Shape 🏠

Worked Example: A "House" Shape 🏠

A house-shaped figure is a rectangle with a triangle roof on top.

  • Rectangle (the walls): 1212 m wide and 88 m tall
  • Triangle (the roof): base =12= 12 m, height =5= 5 m

Step 1 — Break it apart. It's already two pieces: one rectangle + one triangle.

Step 2 — Find each area.

  • Rectangle: A1=l×w=12×8=96A_1 = l \times w = 12 \times 8 = 96 m2m^{2}
  • Triangle: A2=12bh=12×12×5=12×60=30A_2 = \frac{1}{2}bh = \frac{1}{2} \times 12 \times 5 = \frac{1}{2} \times 60 = 30 m2m^{2}

Step 3 — Add them. A=96+30=126 m2✓A = 96 + 30 = 126 \text{ m}^2 ✓

Tip: For the triangle, multiply base times height first (12×5=6012 \times 5 = 60), then take half. The numbers stay friendly!

Worked Example: Rectangle + Semicircle 🏊

A swimming pool is a rectangle with a semicircle on one end.

  • Rectangle: 1010 cm long and 66 cm wide
  • Semicircle: it sits on the 66 cm end, so the diameter is 66 cm and the radius is r=3r = 3 cm

Step 1 — Break it apart. One rectangle + one semicircle.

Step 2 — Find each area (use π≈3.14\pi \approx 3.14).

  • Rectangle: A1=10×6=60A_1 = 10 \times 6 = 60 cm2cm^{2}
  • Semicircle: A2=12πr2=12×3.14×32=12×3.14×9=12×28.26=14.13A_2 = \frac{1}{2}\pi r^2 = \frac{1}{2} \times 3.14 \times 3^2 = \frac{1}{2} \times 3.14 \times 9 = \frac{1}{2} \times 28.26 = 14.13 cm2cm^{2}

Step 3 — Add them. A=60+14.13=74.13 cm2✓A = 60 + 14.13 = 74.13 \text{ cm}^2 ✓

Notice we found the radius by cutting the diameter in half. That's a super common step — watch for it!

Your Turn — Fill in the Boxes ✍️

A figure is a rectangle with a triangle on top (a "house" shape).

  • Rectangle: 99 ft wide and 66 ft tall
  • Triangle on top: base =9= 9 ft, height =4= 4 ft

Box 1: Area of the rectangle in ft2ft^{2} (use A=l×wA = l \times w) Box 2: Area of the triangle in ft2ft^{2} (use A=12bhA = \frac{1}{2}bh) Box 3: The total area in ft2ft^{2}

Part 3: Guided Practice: Choose the Answer

Guided Practice: Choose the Answer 🎯

Break each figure into basic shapes, then combine the areas.

Match the Piece to Its Formula 🔽

A composite figure is made of a rectangle and a semicircle. Choose the correct formula for each piece.

Part 4: Real-World Composite Figures 🌍

Real-World Composite Figures 🌍

Composite-figure math shows up whenever a real object isn't a perfect single shape.

Example — a garden. Maya's vegetable garden is shaped like a rectangle with a triangular flower bed attached to one end. To buy the right amount of soil, she needs the total area.

  • Rectangle part: 1515 ft by 88 ft → A1=15×8=120A_1 = 15 \times 8 = 120 ft2ft^{2}
  • Triangle part: base 88 ft, height 66 ft → A2=12×8×6=24A_2 = \frac{1}{2} \times 8 \times 6 = 24 ft2ft^{2}
  • Total area: 120+24=144120 + 24 = 144 ft2ft^{2}

So Maya needs enough soil to cover 144144 ft2ft^{2}. Breaking the garden into a rectangle and a triangle made the problem easy. Now try a couple yourself.

Word Problem — Fill in the Boxes ✍️

A classroom rug is shaped like a rectangle with a semicircle on one end.

  • Rectangle: 88 ft long and 44 ft wide
  • Semicircle on the 44 ft end: diameter =4= 4 ft, so radius r=2r = 2 ft

Use π≈3.14\pi \approx 3.14.

Box 1: The radius of the semicircle in ft Box 2: Area of the rectangle in ft2ft^{2} Box 3: Area of the semicircle in ft2ft^{2} (use A=12πr2A = \frac{1}{2}\pi r^2, rounded to two decimals)

Application Question 🧮

Use the subtraction method for this one.

Part 5: Summary: Putting It All Together 🎓

Summary: Putting It All Together 🎓

You now know how to find the area of any composite figure! Here's the whole plan in one place:

StepWhat you do
1. Break apartSplit the figure into rectangles, triangles, and circles
2. Find each areaUse the right formula for each piece
3. CombineAdd the pieces — or subtract a missing hole

The two methods:

  • Addition method: when pieces are joined together, find each area and add: A=A1+A2+…A = A_1 + A_2 + \dots
  • Subtraction method: when a piece is cut out, find the big area and subtract the missing piece: A=Abig−AholeA = A_{big} - A_{hole}

Key reminders:

  • The radius is half the diameter.
  • Area is always measured in square units (cm2cm^{2}, ft2ft^{2}, m2m^{2}).
  • A semicircle is half a circle: A=12πr2A = \frac{1}{2}\pi r^2.

Now take on the challenge questions below!

Challenge Questions 🏆

These mix the addition and subtraction methods. Take your time and work step by step.