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Area of Composite Figures

Find area of complex shapes

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Area of Composite Figures

A composite figure is a shape made up of two or more basic shapes. To find the area, you break it into simpler shapes, find each area, then add them together!


What Is a Composite Figure?

A composite figure (also called a complex figure) is created by combining basic shapes like:

  • Rectangles
  • Triangles
  • Circles
  • Trapezoids
  • Semicircles

Real-world examples:

  • Floor plans of houses
  • Gardens with multiple sections
  • Swimming pools with different depths
  • Letters and logos

Review: Area Formulas for Basic Shapes

Rectangle: A = length × width = lw

Square: A = side × side = s²

Triangle: A = (1/2) × base × height = (1/2)bh

Parallelogram: A = base × height = bh

Trapezoid: A = (1/2) × (base₁ + base₂) × height = (1/2)(b₁ + b₂)h

Circle: A = πr² (where r = radius)

Semicircle: A = (1/2)πr² (half of a circle)


Strategy for Finding Area of Composite Figures

Step 1: Break the figure into basic shapes

  • Look for rectangles, triangles, circles, etc.
  • Draw lines to separate shapes

Step 2: Find the area of each basic shape

  • Use appropriate formula for each piece
  • Label dimensions carefully

Step 3: Add all the areas together

  • Total Area = Area₁ + Area₂ + Area₃ + ...

Method 1: Addition Method

Break the figure into parts and ADD the areas.

Example 1: L-Shaped Figure

An L-shaped figure can be split into two rectangles:

  • Top rectangle: 8 ft × 3 ft
  • Bottom rectangle: 5 ft × 4 ft

Solution:

Area of top rectangle: A₁ = 8 × 3 = 24 ft²

Area of bottom rectangle: A₂ = 5 × 4 = 20 ft²

Total Area: A = 24 + 20 = 44 ft²

Answer: 44 ft²

Example 2: Rectangle with Triangle on Top

A house-shaped figure: rectangle base with triangular roof

  • Rectangle: 12 m × 8 m
  • Triangle: base = 12 m, height = 5 m

Solution:

Rectangle area: A₁ = 12 × 8 = 96 m²

Triangle area: A₂ = (1/2) × 12 × 5 = 30 m²

Total Area: A = 96 + 30 = 126 m²

Answer: 126 m²

Example 3: Rectangle with Semicircle

A shape with rectangle (10 cm × 6 cm) and semicircle on one end (diameter = 6 cm, radius = 3 cm)

Solution:

Rectangle area: A₁ = 10 × 6 = 60 cm²

Semicircle area: A₂ = (1/2)π(3²) = (1/2)π(9) = 4.5π ≈ 14.14 cm²

Total Area: A = 60 + 14.14 ≈ 74.14 cm²

Answer: About 74.14 cm²


Method 2: Subtraction Method

Sometimes it's easier to find a large shape's area, then SUBTRACT a missing piece!

Example 1: Rectangle with Corner Cut Out

A 10 in × 8 in rectangle with a 3 in × 2 in rectangle cut from one corner.

Solution:

Large rectangle area: A₁ = 10 × 8 = 80 in²

Cut-out rectangle area: A₂ = 3 × 2 = 6 in²

Remaining Area: A = 80 - 6 = 74 in²

Answer: 74 in²

Example 2: Circle with Hole

A circular disc with outer radius 10 cm and a circular hole with radius 4 cm.

Solution:

Outer circle area: A₁ = π(10²) = 100π cm²

Inner circle (hole) area: A₂ = π(4²) = 16π cm²

Remaining Area: A = 100π - 16π = 84π ≈ 263.89 cm²

Answer: About 263.89 cm²

Example 3: Rectangle with Triangle Removed

A 15 ft × 10 ft rectangle with a triangle (base = 6 ft, height = 4 ft) removed from one corner.

Solution:

Rectangle area: A₁ = 15 × 10 = 150 ft²

Triangle area: A₂ = (1/2) × 6 × 4 = 12 ft²

Remaining Area: A = 150 - 12 = 138 ft²

Answer: 138 ft²


Finding Missing Dimensions

Sometimes you need to calculate missing dimensions before finding areas!

Example: T-Shaped Figure

A T-shaped figure:

  • Top horizontal bar: 12 cm × 3 cm
  • Vertical stem: ? cm × 4 cm
  • Total height: 10 cm

Step 1: Find missing dimension Vertical stem height = 10 - 3 = 7 cm

Step 2: Find areas Top bar: 12 × 3 = 36 cm² Vertical stem: 7 × 4 = 28 cm²

Step 3: Add Total = 36 + 28 = 64 cm²

Answer: 64 cm²


Working with Multiple Shapes

Example: Complex Floor Plan

A room has:

  • Main rectangular area: 20 ft × 15 ft
  • Alcove (small rectangle): 8 ft × 5 ft
  • Circular bay window: radius = 4 ft (semicircle)

Solution:

Main room: A₁ = 20 × 15 = 300 ft²

Alcove: A₂ = 8 × 5 = 40 ft²

Bay window (semicircle): A₃ = (1/2)π(4²) = 8π ≈ 25.13 ft²

Total Area: A = 300 + 40 + 25.13 = 365.13 ft²

Answer: About 365 ft²


Real-World Applications

Landscaping

Problem: A garden has a rectangular section (15 m × 10 m) and a triangular section (base = 10 m, height = 6 m). How much area needs to be planted?

Solution: Rectangle: 15 × 10 = 150 m² Triangle: (1/2) × 10 × 6 = 30 m² Total: 150 + 30 = 180 m²

Answer: 180 m²

Painting

Problem: A wall shaped like a house (rectangle with triangle on top) needs paint. Rectangle is 12 ft × 8 ft, triangle has base 12 ft and height 3 ft. One gallon covers 50 ft². How many gallons needed?

Solution: Rectangle: 12 × 8 = 96 ft² Triangle: (1/2) × 12 × 3 = 18 ft² Total: 96 + 18 = 114 ft² Gallons: 114 ÷ 50 = 2.28 → Need 3 gallons

Answer: 3 gallons

Flooring

Problem: An L-shaped room needs tile. One section is 14 ft × 10 ft, the other is 8 ft × 6 ft. Tiles cost $3 per square foot. What's the total cost?

Solution: Section 1: 14 × 10 = 140 ft² Section 2: 8 × 6 = 48 ft² Total area: 188 ft² Cost: 188 × 3=3 = 564

Answer: $564


Using Both Addition and Subtraction

Example: Swimming Pool

A rectangular pool (20 m × 10 m) has a semicircular extension on one end (radius = 5 m), but a rectangular shallow area (4 m × 3 m) is excluded from the total.

Solution:

Main pool: A₁ = 20 × 10 = 200 m²

Semicircular extension (add): A₂ = (1/2)π(5²) = 12.5π ≈ 39.27 m²

Shallow area to exclude (subtract): A₃ = 4 × 3 = 12 m²

Total: A = 200 + 39.27 - 12 = 227.27 m²

Answer: About 227 m²


Tips for Success

Tip 1: Sketch and label

  • Draw the figure neatly
  • Label all dimensions
  • Mark where you're splitting shapes

Tip 2: Look for patterns

  • Can you make rectangles?
  • Do you see triangles?
  • Are there circles or parts of circles?

Tip 3: Choose your method

  • Addition: When adding sections makes sense
  • Subtraction: When removing a piece is easier
  • Sometimes you can use either method!

Tip 4: Track units

  • Keep units consistent (all feet or all meters)
  • Final answer is in square units (ft², m², etc.)

Tip 5: Use formulas correctly

  • Triangle: Don't forget the 1/2!
  • Circle: π ≈ 3.14 or use calculator's π button
  • Check which dimension is base vs. height

Common Mistakes to Avoid

❌ Mistake 1: Counting overlapping areas twice

  • Make sure pieces don't overlap!
  • Each part of the figure should be counted exactly once

❌ Mistake 2: Using wrong dimensions

  • Base and height must be perpendicular
  • For circles, make sure you have radius (not diameter!)

❌ Mistake 3: Forgetting to add/subtract all pieces

  • Count all sections of the composite figure

❌ Mistake 4: Unit errors

  • Mixing feet and inches
  • Forgetting to convert
  • Writing final answer without square units

❌ Mistake 5: Calculation errors with π

  • Semicircle is HALF the circle, don't forget the 1/2
  • Use consistent value for π (3.14 or calculator)

Practice Strategy

Step 1: Identify

  • What basic shapes make up this figure?

Step 2: Decide on method

  • Addition (add pieces) or subtraction (remove pieces)?

Step 3: Find missing dimensions

  • Do you need to calculate any lengths?

Step 4: Calculate each area

  • Use correct formula for each shape
  • Show your work!

Step 5: Combine

  • Add or subtract as needed
  • Include units!

Step 6: Check reasonableness

  • Does your answer make sense?
  • Is it bigger/smaller than you expected?

Different Ways to Break Up the Same Figure

Example: An L-shape can be split multiple ways:

Method 1: Two rectangles (horizontal cut) Method 2: Two rectangles (vertical cut) Method 3: Large rectangle minus missing corner

All methods give the SAME ANSWER! Choose whichever is easiest for you.


Quick Reference

Addition Method: Total Area = A₁ + A₂ + A₃ + ...

Subtraction Method: Total Area = Large Area - Removed Area

Key Formulas:

  • Rectangle: lw
  • Triangle: (1/2)bh
  • Circle: πr²
  • Semicircle: (1/2)πr²

Remember:

  • Break complex into simple
  • Use appropriate formulas
  • Add or subtract as needed
  • Keep track of units!

Summary

Composite figures are made up of multiple basic shapes.

Strategy:

  1. Break into simpler shapes (rectangles, triangles, circles, etc.)
  2. Find area of each piece using appropriate formula
  3. Add areas together (or subtract if removing a piece)

Two Main Methods:

  • Addition: Add all the pieces
  • Subtraction: Large shape minus removed piece

Applications:

  • Floor plans and architecture
  • Landscaping and gardening
  • Painting and flooring
  • Manufacturing and design

Understanding composite figures is essential for real-world problem solving, construction, design, and advanced geometry!

📚 Practice Problems

1Problem 1easy

❓ Question:

Find the area of an L-shaped figure made of two rectangles: one is 5 ft by 3 ft, and the other is 4 ft by 2 ft.

💡 Show Solution

Break into two rectangles and add:

Rectangle 1: A₁ = 5 × 3 = 15 ft² Rectangle 2: A₂ = 4 × 2 = 8 ft²

Total Area = 15 + 8 = 23 ft²

Answer: 23 ft²

2Problem 2easy

❓ Question:

A rectangular garden is 10 m by 8 m with a rectangular pond inside that is 3 m by 2 m. What is the area of the garden NOT covered by the pond?

💡 Show Solution

Use the subtraction method:

Area of garden: A₁ = 10 × 8 = 80 m² Area of pond: A₂ = 3 × 2 = 6 m²

Area NOT covered = 80 - 6 = 74 m²

Answer: 74 m²

3Problem 3medium

❓ Question:

Find the area of a figure that is a rectangle (12 cm by 6 cm) with a semicircle on top (diameter 6 cm). Use π ≈ 3.14.

💡 Show Solution

Break into rectangle + semicircle:

Rectangle: A₁ = 12 × 6 = 72 cm²

Semicircle:

  • Radius = 6/2 = 3 cm
  • Full circle area = πr² = 3.14 × 3² = 3.14 × 9 = 28.26 cm²
  • Semicircle area = 28.26/2 = 14.13 cm²

Total Area = 72 + 14.13 = 86.13 cm²

Answer: 86.13 cm²

4Problem 4medium

❓ Question:

A trapezoid-shaped pool deck has parallel sides of 15 ft and 10 ft, with a height of 8 ft. There is a rectangular hot tub (4 ft by 3 ft) cut out of the deck. What is the remaining deck area?

💡 Show Solution

Step 1: Area of trapezoid deck A = (1/2)(b₁ + b₂)h A = (1/2)(15 + 10)(8) A = (1/2)(25)(8) A = 100 ft²

Step 2: Area of hot tub A = 4 × 3 = 12 ft²

Step 3: Subtract Remaining deck = 100 - 12 = 88 ft²

Answer: 88 ft²

5Problem 5hard

❓ Question:

A figure consists of a square (side 10 in), with a triangle on top (base 10 in, height 6 in) and a semicircle cut out of the bottom (diameter 10 in). Find the total area. Use π ≈ 3.14.

💡 Show Solution

Addition and subtraction method:

Square: A₁ = 10² = 100 in²

Triangle: A₂ = (1/2)(10)(6) = 30 in²

Semicircle (cut out):

  • Radius = 10/2 = 5 in
  • Full circle = π(5²) = 3.14(25) = 78.5 in²
  • Semicircle = 78.5/2 = 39.25 in²

Total = Square + Triangle - Semicircle Total = 100 + 30 - 39.25 = 90.75 in²

Answer: 90.75 in²

Explain using:

📌 Related Topics in Geometry

❓ Frequently Asked Questions

What is Area of Composite Figures?▾
Find area of complex shapes
How can I study Area of Composite Figures effectively?▾
Start by reading the study notes and working through the examples on this page. Then use the flashcards to test your recall. Practice with the 5 problems provided, checking solutions as you go. Regular review and active practice are key to retention.
Is this Area of Composite Figures study guide free?▾
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What course covers Area of Composite Figures?▾
Area of Composite Figures is part of the Grade 7 Math course on Study Mondo, specifically in the Geometry section. You can explore the full course for more related topics and practice resources.
Are there practice problems for Area of Composite Figures?▾
Yes, this page includes 5 practice problems with detailed solutions. Each problem includes a step-by-step explanation to help you understand the approach.