🎯⭐ INTERACTIVE LESSON

Volumes of Revolution

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Volumes of Revolution - Complete Interactive Lesson

Part 1: Disk Method

Volumes of Revolution

Part 1 of 7 — Disk Method

Rotating Around the x-axis

When rotating y=f(x)y = f(x) around the xx-axis, each cross-section is a disk with radius f(x)f(x):

V=πab[f(x)]2dxV = \pi\int_a^b [f(x)]^2\,dx

Worked Example

Find the volume when y=xy = \sqrt{x} from x=0x = 0 to x=4x = 4 is rotated about the xx-axis.

V=π04(x)2dx=π04xdx=π[x22]04=π8=8πV = \pi\int_0^4 (\sqrt{x})^2\,dx = \pi\int_0^4 x\,dx = \pi\left[\frac{x^2}{2}\right]_0^4 = \pi \cdot 8 = 8\pi

Disk Method 🎯

Key Takeaways — Part 1

  1. Disk method: V=πab[R(x)]2dxV = \pi\int_a^b [R(x)]^2\,dx
  2. R(x)R(x) is the distance from the curve to the axis of rotation
  3. Don't forget to square the radius AND multiply by π\pi

Part 2: Washer Method

Volumes of Revolution

Part 2 of 7 — Washer Method

When There's a Hole

Rotating a region between two curves creates a washer (disk with a hole):

V=πab([R(x)]2[r(x)]2)dxV = \pi\int_a^b \left([R(x)]^2 - [r(x)]^2\right)\,dx

  • R(x)R(x) = outer radius (farther from axis)
  • r(x)r(x) = inner radius (closer to axis)

Worked Example

Region between y=xy = x and y=x2y = x^2, rotated about the xx-axis (x[0,1]x \in [0,1]).

Outer: R=xR = x. Inner: r=x2r = x^2.

V=π01(x2x4)dx=π[x33x55]01=π(1315)=2π15V = \pi\int_0^1 (x^2 - x^4)\,dx = \pi\left[\frac{x^3}{3} - \frac{x^5}{5}\right]_0^1 = \pi\left(\frac{1}{3} - \frac{1}{5}\right) = \frac{2\pi}{15}

Washer Method 🎯

Key Takeaways — Part 2

  1. Washer method: V=π[R2r2]dxV = \pi\int [R^2 - r^2]\,dx
  2. Identify outer and inner radii carefully
  3. The disk method is a special case where r=0r = 0

Part 3: Shell Method

Volumes of Revolution

Part 3 of 7 — Rotation About Other Axes

Rotating About y=ky = k or x=kx = k

When rotating about a line other than the xx-axis, adjust the radii:

Rotation about y=ky = k (horizontal line):

  • R(x)=f(x)kR(x) = |f(x) - k| (distance from outer curve to axis)
  • r(x)=g(x)kr(x) = |g(x) - k| (distance from inner curve to axis)

Worked Example

Rotate the region between y=x2y = x^2 and y=1y = 1 about y=2y = 2.

On [1,1][-1, 1]: Outer radius: R=2x2R = 2 - x^2. Inner radius: r=21=1r = 2 - 1 = 1.

V=π11[(2x2)212]dx=2π01(44x2+x41)dxV = \pi\int_{-1}^{1} [(2-x^2)^2 - 1^2]\,dx = 2\pi\int_0^1 (4-4x^2+x^4 - 1)\,dx =2π01(34x2+x4)dx=2π[3x4x33+x55]01=2π(343+15)=56π15= 2\pi\int_0^1 (3-4x^2+x^4)\,dx = 2\pi\left[3x - \frac{4x^3}{3} + \frac{x^5}{5}\right]_0^1 = 2\pi\left(3 - \frac{4}{3} + \frac{1}{5}\right) = \frac{56\pi}{15}

Rotation About Other Lines 🎯

Key Takeaways — Part 3

  1. Radius = distance from curve to axis of rotation
  2. When axis is below: R=f(x)kR = f(x) - k
  3. When axis is above: R=kf(x)R = k - f(x)
  4. Always think: what's farther (outer) vs closer (inner) to the axis

Part 4: Revolution About Other Axes

Volumes of Revolution

Part 4 of 7 — Cross-Sectional Volumes

Known Cross-Sections

Instead of rotating, we can have cross-sections that are squares, semicircles, equilateral triangles, etc.

V=abA(x)dxV = \int_a^b A(x)\,dx

where A(x)A(x) is the area of the cross-section at position xx.

Common Cross-Section Formulas

If the base goes from y=g(x)y = g(x) to y=f(x)y = f(x), the side length is s=f(x)g(x)s = f(x) - g(x).

Cross-sectionArea Formula
SquareA=s2A = s^2
SemicircleA=πs28A = \frac{\pi s^2}{8}
Equilateral triangleA=34s2A = \frac{\sqrt{3}}{4}s^2
Isosceles right triangle (leg = side)A=s22A = \frac{s^2}{2}

Worked Example

Base is the region between y=xy = \sqrt{x} and y=0y = 0 on [0,4][0, 4]. Cross-sections perpendicular to xx-axis are squares.

s=x0=xs = \sqrt{x} - 0 = \sqrt{x}. A=(x)2=xA = (\sqrt{x})^2 = x.

V=04xdx=[x22]04=8V = \int_0^4 x\,dx = \left[\frac{x^2}{2}\right]_0^4 = 8

Cross-Section Volumes 🎯

Key Takeaways — Part 4

  1. Cross-section problems: V=A(x)dxV = \int A(x)\,dx
  2. Find the side length from the base region, then apply the area formula
  3. This is a common AP free-response topic!

Part 5: Cross-Section Volumes

Volumes of Revolution

Part 5 of 7 — Disk/Washer in yy

Rotating About the yy-axis Using dydy

V=πcd[R(y)]2dyV = \pi\int_c^d [R(y)]^2\,dy

Worked Example

y=x2y = x^2 from y=0y = 0 to y=4y = 4, rotated about the yy-axis.

x=yx = \sqrt{y}, so R=yR = \sqrt{y}.

V=π04ydy=π[y22]04=8πV = \pi\int_0^4 y\,dy = \pi\left[\frac{y^2}{2}\right]_0^4 = 8\pi

y-Axis Rotation 🎯

Key Takeaways — Part 5

  • For yy-axis rotation, express xx as a function of yy
  • Use dy\int dy with the same disk/washer formulas

Part 6: Problem-Solving Workshop

Volumes of Revolution

Part 6 of 7 — AP-Style Workshop

AP-Style Volume Problems 🎯

Workshop Complete!

Part 7: Review & Applications

Volumes of Revolution — Review

Part 7 of 7 — Comprehensive Assessment

MethodFormula
DiskV=π[R]2dxV = \pi\int [R]^2\,dx
WasherV=π[R2r2]dxV = \pi\int [R^2 - r^2]\,dx
Cross-sectionV=A(x)dxV = \int A(x)\,dx

Final Assessment 🎯

Volumes of Revolution — Complete! ✅

You have mastered:

  • ✅ Disk method (single curve rotation)
  • ✅ Washer method (two curves, hole in middle)
  • ✅ Rotation about non-standard axes
  • ✅ Cross-sectional volumes with known shapes