Skip to content Study Mondo Free study resources for students from Grade 4 through AP and test prep. 24 courses, 700+ topics.
Courses Features Company Stay Ahead in School Free weekly study tips, practice sets, and exam strategies. Join 10,000+ students.
ยฉ 2026 Study Mondo. Built for students.
APยฎ is a trademark registered by the College Board, which is not affiliated with, and does not endorse, this website.
Tables & Data - Interactive Lesson | Study Mondo
Tables & Data - Complete Interactive Lesson Part 1: Approximating Derivatives from Tables Working with Tables & Data
Part 1 of 7 โ Approximating Derivatives from Tables
Topic Overview
Part Topic 1 Approximating Derivatives from Tables 2 Riemann Sums from Tables 3 Trapezoidal Rule 4 MVT & IVT with Tables 5 Interpreting f โฒ f' f โฒ and f โฒ โฒ f'' f โฒโฒ from Data 6 AP-Style Free-Response Workshop 7 Comprehensive Assessment
Estimating f โฒ ( a ) f'(a) f โฒ ( a ) from a Table
When no formula is given, estimate the derivative using nearby values:
f โฒ ( a ) โ f ( b ) โ f ( c ) b โ c \boxed{f'(a) \approx \frac{f(b) - f(c)}{b - c}} f โฒ ( a ) โ b โ c
Three Approaches
Method Formula When to Use Forward difference f ( a + h ) โ f ( a ) h \frac{f(a+h) - f(a)}{h} h f ( a + h ) โ f ( a ) โ At left endpoints Backward difference
Key Fact: The symmetric difference quotient averages the forward and backward estimates and gives the best approximation for interior points.
Worked Example
x x x 1 3 5 8 f ( x ) f(x) f ( x ) 2 7 10 20
Estimate f โฒ ( 3 ) f'(3) f โฒ ( 3 ) :
Symmetric: f โฒ ( 3 ) โ f ( 5 ) โ f ( 1 ) 5 โ 1 = 10 โ 2 4 = 2 f'(3) \approx \frac{f(5) - f(1)}{5 - 1} = \frac{10 - 2}{4} = 2 f โฒ ( 3 ) โ 5 โ 1 f (
Estimate f โฒ ( 1 ) f'(1) f โฒ ( 1 ) (endpoint):
Forward: f โฒ ( 1 ) โ f ( 3 ) โ f ( 1 ) 3 โ 1 = 7 โ 2 2 = 2.5 f'(1) \approx \frac{f(3) - f(1)}{3 - 1} = \frac{7 - 2}{2} = 2.5 f โฒ ( 1 ) โ 3 โ 1 f (
Estimate f โฒ ( 8 ) f'(8) f โฒ ( 8 ) (right endpoint):
Backward: f โฒ ( 8 ) โ f ( 8 ) โ f ( 5 ) 8 โ 5 = 20 โ 10 3 = 10 3 f'(8) \approx \frac{f(8) - f(5)}{8 - 5} = \frac{20 - 10}{3} = \frac{10}{3} f โฒ ( 8 ) โ 8 โ 5 f
AP Tip: Always state units when they are given. If x x x is in seconds and f f f is in meters, then f โฒ f' f โฒ is in meters/second.
Practice โ Derivative Estimation ๐ฏ
x x x 0 2 5 7 10 f ( x ) f(x) f ( x ) 3 8 14 18 25
Build a derivative estimate step by step. ๐
t t t (s)0 4 10 15 s ( t ) s(t) s ( t ) (m)0 12 30 50
Estimate the derivative. โ๏ธ
x x x 1 3 6 10 g ( x ) g(x) g ( x ) 4 10 22 38
Key Takeaways โ Part 1
Use symmetric (central) differences for interior points
Use forward/backward differences at endpoints
Always include units in AP responses
Symmetric difference: f ( a + h ) โ f ( a โ h ) 2 h \frac{f(a+h) - f(a-h)}{2h} 2 h f ( a + h ) โ f ( a โ h ) โ is the most accurate
Part 2: Riemann Sums from Tables Working with Tables & Data
Part 2 of 7 โ Riemann Sums from Tables
Approximating Integrals from Data
When given a table with unequal subintervals , each subinterval has its own width:
โซ a b f ( x ) โ d x โ โ i = 1 n f ( x i โ ) โ
ฮ x i \boxed{\int_a^b f(x)\,dx \approx \sum_{i=1}^{n} f(x_i^*) \cdot \Delta x_i} โซ a
Part 3: MVT with Tables Working with Tables & Data
Part 3 of 7 โ Trapezoidal Rule
The Trapezoidal Approximation
For unequal subintervals , the trapezoidal rule averages the endpoints of each subinterval:
โซ a b f ( x ) โ d x โ โ i = 1 n ฮ x i 2 [ f ( x i โ 1 ) + f ( x i ) ] \boxed{\int_a^b f(x)\,dx \approx \sum_{i=1}^{n} \frac{\Delta x_i}{2}\bigl[f(x_{i-1}) + f(x_i)\bigr]} โซ
Part 4: IVT with Tables Working with Tables & Data
Part 4 of 7 โ MVT & IVT with Tables
Mean Value Theorem (MVT) with Tables
If f f f is continuous on [ a , b ] [a,b] [ a , b ] and differentiable on ( a , b ) (a,b) ( a , b ) :
โ โ
Part 5: Interpreting f' from Tables Working with Tables & Data
Part 5 of 7 โ Interpreting f โฒ f' f โฒ and f โฒ โฒ f'' f โฒโฒ from Data
Reading f โฒ f' f from a Table of
Part 6: Practice Workshop Working with Tables & Data
Part 6 of 7 โ AP-Style Free-Response Workshop
AP FRQ Table Problem Patterns
Part Typical Prompt Method (a) Approximate f โฒ ( c ) f'(c) f โฒ ( c ) Symmetric difference quotient (b) Approximate โซ a b f ( x ) โ d x \int_a^b f(x)\,dx
Part 7: Final Assessment Working with Tables & Data
Part 7 of 7 โ Comprehensive Assessment
Formula Reference
Technique Formula Key Detail Symmetric diff. quotient f ( a + h ) โ f ( a โ h ) 2 h \frac{f(a+h)-f(a-h)}{2h} 2 h f ( a + h ) โ f
f ( b ) โ f ( c )
โ
โ
f ( a ) โ f ( a โ h ) h \frac{f(a) - f(a-h)}{h} h f ( a ) โ f ( a โ h ) โ Symmetric (central) f ( a + h ) โ f ( a โ h ) 2 h \frac{f(a+h) - f(a-h)}{2h} 2 h f ( a + h ) โ f ( a โ h ) โ Interior points (most accurate)
5
)
โ
f
(
1
)
โ
=
4 10 โ 2 โ =
2
3
)
โ
f
(
1
)
โ
=
2 7 โ 2 โ =
2.5
(
8
)
โ
f
(
5
)
โ
=
3 20 โ 10 โ =
3 10 โ
b
โ
f
(
x
)
d
x
โ
i = 1 โ n โ
f
(
x i โ โ
)
โ
ฮ
x i โ
โ
Riemann Sum Types Type Value Used Description Left f ( x i โ 1 ) f(x_{i-1}) f ( x i โ 1 โ ) Left endpoint of each subinterval Right f ( x i ) f(x_i) f ( x i โ ) Right endpoint of each subinterval Midpoint f ( x ห i ) f(\bar{x}_i) f ( x ห i โ ) Midpoint value (if available)
Key Fact: With unequal subintervals, you MUST use each subinterval's own width ฮ x i \Delta x_i ฮ x i โ . Do NOT assume equal widths!
Worked Example t t t (hrs)0 2 5 8 10 R ( t ) R(t) R ( t ) (gal/hr)4 6 3 8 5
Subintervals: [ 0 , 2 ] , [ 2 , 5 ] , [ 5 , 8 ] , [ 8 , 10 ] [0,2], [2,5], [5,8], [8,10] [ 0 , 2 ] , [ 2 , 5 ] , [ 5 , 8 ] , [ 8 , 10 ] with widths 2 , 3 , 3 , 2 2, 3, 3, 2 2 , 3 , 3 , 2 .
R ( 0 ) โ
2 + R ( 2 ) โ
3 + R ( 5 ) โ
3 + R ( 8 ) โ
2 = 8 + 18 + 9 + 16 = 51 ย gal R(0) \cdot 2 + R(2) \cdot 3 + R(5) \cdot 3 + R(8) \cdot 2 = 8 + 18 + 9 + 16 = 51 \text{ gal} R ( 0 ) โ
2 + R ( 2 ) โ
3 + R ( 5 ) โ
3 + R ( 8 ) โ
2 = 8 + 18 + 9 + 16 = 51 ย gal
R ( 2 ) โ
2 + R ( 5 ) โ
3 + R ( 8 ) โ
3 + R ( 10 ) โ
2 = 12 + 9 + 24 + 10 = 55 ย gal R(2) \cdot 2 + R(5) \cdot 3 + R(8) \cdot 3 + R(10) \cdot 2 = 12 + 9 + 24 + 10 = 55 \text{ gal} R ( 2 ) โ
2 + R ( 5 ) โ
3 + R ( 8 ) โ
3 + R ( 10 ) โ
2 = 12 + 9 + 24 + 10 = 55 ย gal
AP Tip: The integral โซ a b R ( t ) โ d t \int_a^b R(t)\,dt โซ a b โ R ( t ) d t represents the total quantity (total gallons pumped). Always interpret the meaning of the integral in context.
Practice โ Riemann Sums ๐ฏ
t t t (min)0 3 7 12 v ( t ) v(t) v ( t ) (ft/min)5 8 2 6
Build a Riemann sum. ๐
Calculate the Riemann sum. โ๏ธ
t t t (s)0 5 8 14 a ( t ) a(t) a ( t ) (m/sยฒ)2 6 4 10
Key Takeaways โ Part 2
Each subinterval has its own width ฮ x i \Delta x_i ฮ x i โ
Left sum: use left endpoint values
Right sum: use right endpoint values
The integral represents the total accumulated quantity
a
b
โ
f
(
x
)
d
x
โ
i = 1 โ n โ
2 ฮ x i โ โ
[
f
(
x i โ 1 โ
)
+
f
(
x i โ
)
]
โ
Comparison: Left vs. Right vs. Trapezoid Method Formula (per subinterval) Accuracy Left f ( x i โ 1 ) โ
ฮ x i f(x_{i-1}) \cdot \Delta x_i f ( x i โ 1 โ ) โ
ฮ x i โ Depends on monotonicity Right f ( x i ) โ
ฮ x i f(x_i) \cdot \Delta x_i f ( x i โ ) โ
ฮ x i โ Depends on monotonicity Trapezoid ฮ x i 2 [ f ( x i โ 1 ) + f ( x i ) ] \frac{\Delta x_i}{2}[f(x_{i-1})+f(x_i)] 2 ฮ x i โ โ [ f ( x
Key Fact: The trapezoidal approximation equals the average of the left and right Riemann sums: T = L + R 2 T = \frac{L + R}{2} T = 2 L + R โ .
Over/Under Estimates If f f f is... Left sum Right sum Trapezoid Increasing Under Over Exact avg Decreasing Over Under Exact avg Concave up โ โ Over Concave down โ โ Under
Worked Example t t t (hrs)0 2 5 8 10 R ( t ) R(t) R ( t ) (gal/hr)4 6 3 8 5
T = 2 2 ( 4 + 6 ) + 3 2 ( 6 + 3 ) + 3 2 ( 3 + 8 ) + 2 2 ( 8 + 5 ) T = \frac{2}{2}(4+6) + \frac{3}{2}(6+3) + \frac{3}{2}(3+8) + \frac{2}{2}(8+5) T = 2 2 โ ( 4 + 6 ) + 2 3 โ ( 6 + 3 ) + 2 3 โ ( 3 + 8 ) + 2 2 โ ( 8 + 5 )
= 10 + 13.5 + 16.5 + 13 = 53 ย gal = 10 + 13.5 + 16.5 + 13 = 53 \text{ gal} = 10 + 13.5 + 16.5 + 13 = 53 ย gal
Verify: Left sum = 51 = 51 = 51 , Right sum = 55 = 55 = 55 , and 51 + 55 2 = 53 \frac{51+55}{2} = 53 2 51 + 55 โ = 53 . โ
Practice โ Trapezoidal Rule ๐ฏ
Build a trapezoidal estimate. ๐
t t t (s)0 4 10 15 v ( t ) v(t) v ( t ) (m/s)3 7 5 9
Apply the trapezoidal rule. โ๏ธ
x x x 1 3 8 10 f ( x ) f(x) f ( x ) 4 10 6 12
Key Takeaways โ Part 3
Trapezoidal rule: ฮ x 2 [ f ( x i โ 1 ) + f ( x i ) ] \frac{\Delta x}{2}[f(x_{i-1})+f(x_i)] 2 ฮ x โ [ f ( x i โ 1 โ ) + f ( x i โ )] per subinterval
T = L + R 2 T = \frac{L + R}{2} T = 2 L + R โ (average of left and right sums)
Concave up โ \Rightarrow โ trapezoid overestimates
Concave down โ \Rightarrow โ trapezoid underestimates
c โ ( a , b ) ย suchย thatย f โฒ ( c ) = f ( b ) โ f ( a ) b โ a \boxed{\exists\, c \in (a,b) \text{ such that } f'(c) = \frac{f(b) - f(a)}{b - a}} โ c โ ( a , b ) ย suchย thatย f โฒ ( c ) = b โ a f ( b ) โ f ( a ) โ โ
Intermediate Value Theorem (IVT) with Tables If f f f is continuous on [ a , b ] [a,b] [ a , b ] and k k k is between f ( a ) f(a) f ( a ) and f ( b ) f(b) f ( b ) :
โ โ c โ ( a , b ) ย suchย thatย f ( c ) = k \boxed{\exists\, c \in (a,b) \text{ such that } f(c) = k} โ c โ ( a , b ) ย suchย thatย f ( c ) = k โ
Comparison Theorem Hypothesis Conclusion MVT Continuous + differentiable Guarantees a specific f โฒ ( c ) f'(c) f โฒ ( c ) IVT Continuous only Guarantees f f f attains a value k k k
AP Tip: You MUST cite the theorem by name and verify all hypotheses for full credit.
Worked Example โ MVT f f f is differentiable on ( 1 , 4 ) (1,4) ( 1 , 4 ) .
By MVT, โ โ c โ ( 1 , 4 ) \exists\, c \in (1,4) โ c โ ( 1 , 4 ) such that f โฒ ( c ) = 12 โ 3 4 โ 1 = 3 f'(c) = \frac{12 - 3}{4 - 1} = 3 f โฒ ( c ) = 4 โ 1 12 โ 3 โ = 3 .
Worked Example โ IVT f f f is continuous. f ( 1 ) = 3 f(1) = 3 f ( 1 ) = 3 , f ( 4 ) = 12 f(4) = 12 f ( 4 ) = 12 .
Since 5 5 5 is between 3 3 3 and 12 12 12 , by IVT โ โ c โ ( 1 , 4 ) \exists\, c \in (1,4) โ c โ ( 1 , 4 ) such that f ( c ) = 5 f(c) = 5 f ( c ) = 5 .
MVT for f โฒ f' f โฒ (Second Derivative) If f โฒ f' f โฒ values are in a table and f โฒ f' f โฒ is differentiable:
f โฒ โฒ ( c ) = f โฒ ( b ) โ f โฒ ( a ) b โ a f''(c) = \frac{f'(b) - f'(a)}{b - a} f โฒโฒ ( c ) = b โ a f โฒ ( b ) โ f โฒ ( a ) โ
This is MVT applied to f โฒ f' f โฒ (guarantees f โฒ โฒ ( c ) f''(c) f โฒโฒ ( c ) exists).
Practice โ MVT & IVT ๐ฏ
f f f is continuous and differentiable.
x x x 2 5 8 11 f ( x ) f(x) f ( x ) 1 10 4 13
Apply the theorems. ๐
g g g is continuous on [ 0 , 10 ] [0,10] [ 0 , 10 ] . g ( 0 ) = โ 3 g(0) = -3 g ( 0 ) = โ 3 , g ( 4 ) = 5 g(4) = 5 g ( 4 ) = 5 , g ( 7 ) = 2 g(7) = 2 g ( 7 ) = 2 , g ( 10 ) = 8 g(10) = 8 g ( 10 ) = 8 .
Apply MVT. โ๏ธ
h h h is differentiable. h ( 2 ) = 7 h(2) = 7 h ( 2 ) = 7 , h ( 8 ) = 19 h(8) = 19 h ( 8 ) = 19 .
Key Takeaways โ Part 4
MVT guarantees a specific derivative value between two points
IVT guarantees a function attains any value between f ( a ) f(a) f ( a ) and f ( b ) f(b) f ( b )
Both require continuity; MVT also requires differentiability
Always cite the theorem by name on the AP exam
โฒ
Observation from Table Conclusion f f f values increase between entriesf โฒ > 0 f' > 0 f โฒ > 0 on that intervalf f f values decrease between entriesf โฒ < 0 f' < 0 f โฒ < 0 on that intervalf f f values change rapidly$ f f f values change slowly$
Concavity from First Differences Compute first differences ฮ f i = f ( x i + 1 ) โ f ( x i ) \Delta f_i = f(x_{i+1}) - f(x_i) ฮ f i โ = f ( x i + 1 โ ) โ f ( x i โ ) :
Ifย ฮ f ย isย increasing โ f โฒ โฒ > 0 ย (concaveย up) \boxed{\text{If } \Delta f \text{ is increasing} \Rightarrow f'' > 0 \text{ (concave up)}} Ifย ฮ f ย isย increasing โ f โฒโฒ > 0 ย (concaveย up) โ
Ifย ฮ f ย isย decreasing โ f โฒ โฒ < 0 ย (concaveย down) \boxed{\text{If } \Delta f \text{ is decreasing} \Rightarrow f'' < 0 \text{ (concave down)}} Ifย ฮ f ย isย decreasing โ f โฒโฒ < 0 ย (concaveย down) โ
Worked Example x x x 0 1 2 3 4 f ( x ) f(x) f ( x ) 2 5 9 14 20
First differences: ฮ f = 3 , 4 , 5 , 6 \Delta f = 3, 4, 5, 6 ฮ f = 3 , 4 , 5 , 6 (increasing)
โ f โฒ > 0 \Rightarrow f' > 0 โ f โฒ > 0 (increasing) and f โฒ โฒ > 0 f'' > 0 f โฒโฒ > 0 (concave up).
Second Derivative from a Table of f โฒ f' f โฒ If you have f โฒ f' f โฒ values, estimate f โฒ โฒ f'' f โฒโฒ the same way you estimate f โฒ f' f โฒ from f f f :
f โฒ โฒ ( a ) โ f โฒ ( b ) โ f โฒ ( c ) b โ c f''(a) \approx \frac{f'(b) - f'(c)}{b - c} f โฒโฒ ( a ) โ b โ c f โฒ ( b ) โ f โฒ ( c ) โ
AP Tip: When asked "is there a value c c c where f โฒ โฒ ( c ) = k f''(c) = k f โฒโฒ ( c ) = k ?", use MVT applied to f โฒ f' f โฒ .
Practice โ Interpreting Data ๐ฏ
x x x 0 2 4 6 8 f ( x ) f(x) f ( x ) 10 18 24 28 30
Analyze a table of f โฒ f' f โฒ values. ๐
x x x 1 3 5 7 f โฒ ( x ) f'(x) f โฒ ( x ) 4 1 -2 -5
Apply MVT to f โฒ f' f โฒ . โ๏ธ
f f f is twice-differentiable.
x x x 2 5 9 f โฒ ( x ) f'(x) f โฒ ( x ) 8 2 -6
Key Takeaways โ Part 5
Increasing first differences โ \Rightarrow โ concave up (f โฒ โฒ > 0 f'' > 0 f โฒโฒ > 0 )
Decreasing first differences โ \Rightarrow โ concave down (f โฒ โฒ < 0 f'' < 0 f โฒโฒ < 0 )
Estimate f โฒ โฒ f'' f โฒโฒ from f โฒ f' f โฒ values using the same techniques
MVT on f โฒ f' f โฒ guarantees a specific f โฒ โฒ ( c ) f''(c) f โฒโฒ ( c ) value
โซ a b โ
f
(
x
)
d
x
Trapezoidal rule or Riemann sum
(c) Use MVT to show f โฒ ( c ) = k f'(c) = k f โฒ ( c ) = k f ( b ) โ f ( a ) b โ a \frac{f(b)-f(a)}{b-a} b โ a f ( b ) โ f ( a ) โ and cite MVT
(d) Is the approximation over or under? Concavity determines this
Complete Worked FRQ
The temperature T ( t ) T(t) T ( t ) of a cooling object is recorded at several times. T T T is continuous and differentiable.
t t t (min)0 3 7 12 20 T ( t ) T(t) T ( t ) (ยฐF)200 170 140 120 100
(a) Estimate T โฒ ( 7 ) T'(7) T โฒ ( 7 ) with units. Explain the meaning.
T โฒ ( 7 ) โ T ( 12 ) โ T ( 3 ) 12 โ 3 = 120 โ 170 9 = โ 50 9 โ โ 5.56 ย ยฐF/min T'(7) \approx \frac{T(12) - T(3)}{12 - 3} = \frac{120 - 170}{9} = -\frac{50}{9} \approx -5.56 \text{ ยฐF/min} T โฒ ( 7 ) โ 12 โ 3 T ( 12 ) โ T ( 3 ) โ = 9 120 โ 170 โ = โ 9 50 โ โ โ 5.56 ย ยฐF/min
At t = 7 t = 7 t = 7 minutes, the temperature is decreasing at approximately 5.56 5.56 5.56 ยฐF per minute.
(b) Use trapezoidal rule to approximate โซ 0 20 T ( t ) โ d t \int_0^{20} T(t)\,dt โซ 0 20 โ T ( t ) d t . Interpret.
3 2 ( 200 + 170 ) + 4 2 ( 170 + 140 ) + 5 2 ( 140 + 120 ) + 8 2 ( 120 + 100 ) \frac{3}{2}(200+170) + \frac{4}{2}(170+140) + \frac{5}{2}(140+120) + \frac{8}{2}(120+100) 2 3 โ ( 200 + 170 ) + 2 4 โ ( 170 + 140 ) + 2 5 โ ( 140 + 120 ) + 2 8 โ ( 120 + 100 )
= 555 + 620 + 650 + 880 = 2705 = 555 + 620 + 650 + 880 = 2705 = 555 + 620 + 650 + 880 = 2705
The average temperature is 1 20 โซ 0 20 T โ d t โ 2705 20 = 135.25 \frac{1}{20}\int_0^{20} T\,dt \approx \frac{2705}{20} = 135.25 20 1 โ โซ 0 20 โ T d t โ 20 2705 โ = 135.25 ยฐF.
(c) Must there be a time c c c where T โฒ ( c ) = โ 5 T'(c) = -5 T โฒ ( c ) = โ 5 ?
T ( 20 ) โ T ( 0 ) 20 โ 0 = 100 โ 200 20 = โ 5 \frac{T(20)-T(0)}{20-0} = \frac{100-200}{20} = -5 20 โ 0 T ( 20 ) โ T ( 0 ) โ = 20 100 โ 200 โ = โ 5 . By MVT, โ โ c โ ( 0 , 20 ) \exists\, c \in (0,20) โ c โ ( 0 , 20 ) with T โฒ ( c ) = โ 5 T'(c) = -5 T โฒ ( c ) = โ 5 . โ
(d) Is the trapezoidal estimate an over or underestimate?
First differences: โ 30 , โ 30 , โ 20 , โ 20 -30, -30, -20, -20 โ 30 , โ 30 , โ 20 , โ 20 . The differences are nondecreasing (getting less negative), so T โฒ โฒ โฅ 0 T'' \ge 0 T โฒโฒ โฅ 0 (concave up). Trapezoid overestimates for concave up โ \Rightarrow โ overestimate .
AP-style questions ๐ฏ
f f f is twice-differentiable.
x x x 0 2 6 10 f ( x ) f(x) f ( x ) 1 5 9 21
Work through an FRQ. ๐
Water flows into a tank at rate R ( t ) R(t) R ( t ) liters/min.
t t t (min)0 4 9 15 R ( t ) R(t) R ( t ) (L/min)8 6 10 4
Trapezoidal approximation. โ๏ธ
t t t (s)0 3 8 12 v ( t ) v(t) v ( t ) (m/s)5 9 7 3
Key Takeaways โ Part 6
AP FRQs combine derivative estimates, integrals, MVT, and concavity
Always include units and contextual interpretation
Cite MVT/IVT by name and verify hypotheses
Concavity determines over/under for trapezoidal estimates
(
a
โ
h
)
โ
Left Riemann sum โ f ( x i โ 1 ) ฮ x i \sum f(x_{i-1})\Delta x_i โ f ( x i โ 1 โ ) ฮ x i โ Use left endpoints
Right Riemann sum โ f ( x i ) ฮ x i \sum f(x_i)\Delta x_i โ f ( x i โ ) ฮ x i โ Use right endpoints
Trapezoidal rule โ ฮ x i 2 [ f ( x i โ 1 ) + f ( x i ) ] \sum \frac{\Delta x_i}{2}[f(x_{i-1})+f(x_i)] โ 2 ฮ x i โ โ [ f ( x i โ 1 โ ) + f ( x i โ )] Average of L and R
MVT f โฒ ( c ) = f ( b ) โ f ( a ) b โ a f'(c) = \frac{f(b)-f(a)}{b-a} f โฒ ( c ) = b โ a f ( b ) โ f ( a ) โ Requires cont. + diff.
IVT f ( c ) = k f(c) = k f ( c ) = k for k k k between f ( a ) , f ( b ) f(a), f(b) f ( a ) , f ( b ) Requires continuity
Common AP Mistakes Mistake Correction Assuming equal subintervals Check ฮ x i \Delta x_i ฮ x i โ individually Forgetting units Always include units with derivatives and integrals Not citing MVT/IVT by name State the theorem and verify hypotheses Confusing over/under estimates Concavity determines trapezoid; monotonicity determines L/R Using wrong neighbors for f โฒ f' f โฒ Use closest surrounding points for symmetric difference
Assessment โ Set 1 ๐ฏ
f f f is twice-differentiable.
x x x 0 2 4 6 10 f ( x ) f(x) f ( x ) 1 5 4 10 22
Assessment โ Set 2 ๐ฏ
t t t (hr)0 1 4 6 10 R ( t ) R(t) R ( t ) (gal/hr)10 8 5 3 1
Complete the analysis. ๐
g g g is continuous and differentiable. g ( 1 ) = 3 g(1) = 3 g ( 1 ) = 3 , g ( 5 ) = 11 g(5) = 11 g ( 5 ) = 11 , g ( 9 ) = 7 g(9) = 7 g ( 9 ) = 7 .
Tables & Data โ Complete! ๐
Part Topic Status 1 Approximating Derivatives from Tables โ
2 Riemann Sums from Tables โ
3 Trapezoidal Rule โ
4 MVT & IVT with Tables โ
5 Interpreting f โฒ f' f โฒ and f โฒ โฒ f'' f โฒโฒ from Data โ
6 AP-Style Free-Response Workshop โ
7 Comprehensive Assessment โ
You have completed the full Tables & Data unit!
i โ 1 โ
)
+
f ( x i โ )]
Average of left and right