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Part 1: Linear Systems
๐ Systems of Linear Equations
Part 1 of 7
What Is a System?
A system of equations is a set of two or more equations with the same variables.
{2x+y=7xโy=2โ
A solution is an ordered pair (x,y) that satisfies ALL equations simultaneously.
Three Possible Outcomes
| Type | Graph | Solutions |
|---|
| Independent | Lines cross | Exactly one (x,y) |
| Inconsistent | Parallel lines | No solution |
| Dependent | Same line | Infinitely many |
Checking a Solution
Is (3,1) a solution to the system above?
- 2(3)+1=7 โ
- 3โ1=2 โ
Yes! Both equations are satisfied.
๐ Substitution Method
Steps:
- Solve one equation for one variable
- Substitute into the other equation
- Solve for the remaining variable
- Back-substitute to find the other
Example
{y=3xโ12x+y=
โ Elimination Method
Steps:
- Align equations in standard form (ax+by=c)
- Multiply one or both equations so a variable cancels
- Add (or subtract) the equations
- Solve and back-substitute
Example
{
Solve the Systems ๐งฎ
{2x+y=10xโy=2โ
1) = ?
Part 2: Substitution & Elimination
๐ Systems of Three Variables
Part 2 of 7
3ร3 Systems
โฉโจ
Part 3: Nonlinear Systems
๐ Nonlinear Systems
Part 3 of 7
What Are Nonlinear Systems?
At least one equation is not linear (contains x2, xy, x, etc.).
Part 4: Systems of Inequalities
๐ Systems of Inequalities
Part 4 of 7
Linear Inequalities in Two Variables
2x+yโค6
The solution is a half-plane โ all points on one side of the boundary line.
Graphing Steps
- Graph the boundary (=): solid if โค, dashed if
Part 5: Applications
๐ข Partial Fractions
Part 5 of 7
Why Partial Fractions?
Decompose complex fractions into simpler ones โ essential for integration in calculus!
(x+1)(x+2)5x+3
Part 6: Problem-Solving Workshop
๐ Applications of Systems
Part 6 of 7
Mixture Problems
Problem: Mix a 30% acid solution with a 70% acid solution to get 100 mL of 40% acid.
Let x = mL of 30%, y = mL of 70%.
{
Part 7: Review & Applications
๐ Systems of Equations โ Full Synthesis
Part 7 of 7
Method Selection Guide
| System Type | Best Method |
|---|
| One variable isolated | Substitution |
| Coefficients nearly match | Elimination |
| 3+ variables, systematic | Gaussian elimination |
| Nonlinear | Substitution |
| Optimization | Linear programming |
| Integration prep | Partial fractions |
Solution Types Summary
| Type | What Happens | Geometry |
|---|
| Unique | Consistent, one answer | Lines/curves cross |
| None | Inconsistent, contradiction (0) |
9
โ
Step 1: y is already isolated: y=3xโ1
Step 2: Substitute into equation 2:
2x+(3xโ1)=9
Step 3: Solve:
5xโ1=9โน5x=10โนx=2
Step 4: Back-substitute:
y=3(2)โ1=5
Solution: (2,5)
๐ก Substitution works best when one variable is already isolated or has coefficient 1.
3x+2y=122xโ2y=8โ
The y-terms already cancel when we add:
5x=20โนx=4
Back-substitute: 3(4)+2y=12โนy=0.
Solution: (4,0)
When Coefficients Don't Match
{3x+4y=102x+3y=7โ
Multiply eq1 by 3, eq2 by โ4:
9x+12y=30
โ8xโ12y=โ28
Add: x=2. Then y=1.
๐ก Elimination is ideal when coefficients are already close to matching.
x
3) {y=4x2x+y=18โ โ x = ?
โง
โ
x+y+z=62xโy+z=3x+2yโz=5โ
A solution is an ordered triple (x,y,z) โ a point in 3D space.
Method: Systematic Elimination
- Choose a variable to eliminate first (pick the easiest)
- Combine pairs of equations to get TWO equations in TWO variables
- Solve the 2ร2 system
- Back-substitute to find the third variable
Geometrically
- Each equation represents a plane in 3D
- The solution is where all three planes intersect
- Possibilities: one point, a line, a plane, or no intersection
๐ Worked Example
โฉโจโงโx+y+z=6(1)2xโy+z=3(2)x+2yโz=5(3)
Eliminate z: add (1) and (3):
(x+y+z)+(x+
Add (2) and (3):
(2xโy+z)+(x+2yโz)
Solve (A) and (B):
From (B): y=8โ3x. Sub into (A):
2x+3(8
Hmm, ugly numbers. Let's try a cleaner system for practice.
Cleaner Example
โฉโจโงโ
Add eq1+eq2: 2x+2z=8โนx+z=4.
Add eq2+eq3: 3x. Then , .
Solution: (1,2,3) โ
โ ๏ธ Special Cases in 3D
No Solution (Inconsistent)
โฉโจโงโx+y+z=1x+y+z=32x+yโz=0โ
Eq1 and eq2 say x+y+z equals both 1 and 3 โ contradiction!
Infinitely Many (Dependent)
โฉโจโงโ
Eq2 = 2รEq1, so we really have only 2 independent equations in 3 unknowns โ infinite solutions (a line).
Application: Curve Fitting
Find the quadratic y=ax2+bx+c through (1,:
โฉโจโงโ
Solving: a=1,b=2,c=3โนy=x.
Solve ๐งฎ
โฉโจโงโx+y+z=10xโy+z=4x+yโz=2โ
1) x = ?
2) y = ?
3) z = ?
โ
{x2+y2=25x+y=7โ
Possible Intersections
| Combination | Max Intersections |
|---|
| Line + Circle | 2 |
| Line + Parabola | 2 |
| Circle + Circle | 2 |
| Parabola + Parabola | 4 |
| Circle + Parabola | 4 |
Main Strategy: Substitution
Nonlinear systems almost always use substitution because elimination may not cancel cleanly.
๐ Line Meets Circle
{x2+y2=25x+y=7โ
From eq2: y=7โx. Substitute:
x2+(7โx)
x=3โนy=4 or x=4โนy=.
Solutions: (3,4) and (4,3).
Line Meets Parabola
{y=x2y=2x+3โ
x2=2x+3โนx2
Solutions: (3,9) and (โ1,1).
๐ฌ Two Conics
{x2+y2=10x2โy2=4โ
Add: 2x2=14โนx2=7โน
Subtract: 2y2=6โนy2=3โน
Four solutions: (ยฑ7โ,ยฑ3 โ all four sign combinations!
No-Solution Cases
{x2+y2=1x
Concentric circles with different radii โ never intersect.
One-Solution (Tangent)
{y=x2y=2xโ1โ
x2=2xโ1โนx2โ
Only x=1,y=1. The line is tangent to the parabola.
Nonlinear Systems Quiz ๐ฏ
Solve ๐งฎ
{y=x2โ1y=3xโ1โ
1) Smaller x-value: x = ?
2) Larger x-value: x = ?
3) Sum of the two y-values: y1โ+y2โ = ?
/
โฅ
Test a point (use (0,0) if not on the line) Shade the side that satisfies the inequalityExample: 2x+yโค6
- Boundary: y=โ2x+6 (solid line)
- Test (0,0): 0+0=0โค6 โ โ shade the origin side
Systems of Inequalities
The solution is the intersection of all shaded regions โ the overlap.
โฉโจโงโx+yโค5xโฅ0yโฅ0โ
This gives a triangular region in the first quadrant.
๐ฏ Feasible Regions & Corner Points
Bounded vs Unbounded
- Bounded: region is enclosed (polygon) โ happens when enough constraints
- Unbounded: region extends to infinity
Finding Corner Points
Corner points (vertices) are found by solving pairs of boundary equations simultaneously.
Example: โฉโจโงโx+yโค52x+yโค8xโฅ0,yโฅ0โ
Corner points:
- (0,0): intersection of x=0,y=0
- (4,0): intersection of
Why Corner Points Matter
Fundamental Theorem of Linear Programming: The max/min of a linear function on a feasible region occurs at a corner point.
๐ฐ Linear Programming
Optimize P=3x+2y subject to:
โฉโจโงโx+yโค52x+yโค8xโฅ0,yโฅ0โ
Evaluate P at each corner point:
| Corner | P=3x+2y |
|---|
| (0,0) | 0 |
|
Maximum profit: P=13 at (3,2).
Real-World Applications
- Manufacturing: maximize profit given resource constraints
- Nutrition: minimize cost while meeting dietary needs
- Scheduling: optimize efficiency under time limits
Linear Programming ๐งฎ
Maximize P=5x+4y with corners (0,0),(3,0),(2,3),(0,4).
1) P at (2,3) = ?
2) P at (0,4) = ?
3) Maximum value of P = ?
โ
=
x+1Aโ+
x+2Bโ
The Process
- Factor the denominator completely
- Write one fraction per factor
- Solve for the unknown constants
Case 1: Distinct Linear Factors
(x+1)(x+2)5x+3โ
Multiply both sides by (x+1)(x+2):
5x+3=A(x+2)+B(x+1)
Method 1 โ Strategic substitution:
- Let x=โ1: โ2=A(1)โนA=โ2
- Let x=โ2: โ7=B(โ1)โนB=7
(x+1)(x+2)5x+3โ=x+1โ2โ+x+27โ
๐ Repeated & Quadratic Factors
Case 2: Repeated Linear Factor
(xโ1)23x+5โ=xโ1Aโ+(xโ1)2Bโ
Multiply: 3x+5=A(xโ1)+B
x=1: 8=B. Expand: 3x+5=Axโ.
=xโ13โ+(xโ1)
Case 3: Irreducible Quadratic Factor
(x+1)(x2+1)2
Note: quadratic factor gets Bx+C (not just B).
x=โ1: 2โ1+3=A(2)โนA=.
Expand and equate: B=0,C=1.
=x+12โ+x
๐งฎ Coefficient Matching Method
When substitution isn't enough, equate coefficients of each power of x.
Example
(xโ1)(x2+x+1)x2+2โ=xโ1Aโ+x2+x+1Bx+Cโ
Multiply: x2+2=A(x2+x+
x=1: 3=3AโนA=1
Expand right side: x2+x+1+(Bx2โBx
Equate coefficients:
- x2: 1=1+BโนB=0
- :
=xโ11โ+x
๐ก Always check: is the degree of numerator < degree of denominator? If not, do long division first.
Partial Fractions Quiz ๐ฏ
Find the Constants ๐งฎ
(x+1)(xโ2)7x+1โ=x+1Aโ+xโ2Bโ
1) A = ? (set x=โ1)
2) B = ? (set x=2)
3) x(x+2)4โ=x. = ?
Partial Fractions Concepts ๐ฝ
x+y=100
0.30x+0.70y=40
โ
From eq1: y=100โx. Substitute:
0.30x+0.70(100โx)=40
0.30x+70โ0.70x=40
โ0.40x=โ30โนx=75
Answer: 75 mL of 30% and 25 mL of 70%.
โ๏ธ Distance/Rate/Time Problems
With Wind / Current
| Direction | Rate | Time | Distance |
|---|
| With wind | p+w | t1โ | d |
| Against wind | pโw | t2โ | d |
Example: Plane flies 600 mi with wind in 2 hrs, return in 3 hrs.
{(p+w)โ
2=600(pโw)โ
3
p+w=300 and pโw=200.
Add: 2p=500โนp=250 mph. w=50 mph.
Relative Motion
Two trains leave same station in opposite directions at 60 and 80 mph. When are they 350 mi apart?
60t+80t=350โน140t=350โนt=2.5 hours.
๐ฐ Investment & Work Problems
Investment
$10,000 split between 5% and 8% annual interest, earning $680 total.
{x+y=100000.05x+0.08y=680โ
x=10000โy: 0.05(10000โy)+0.08y=680
500โ0.05y+0.08y=680โน0.03y=180โนy
$4,000 at 5% and $6,000 at 8%.
Work Rate Problems
Worker A: job in 6 hrs. Worker B: job in 4 hrs. Together?
Rates: 61โ+41โ
Time together: 512โ=2.4 hours.
๐ก The key to word problems: define variables clearly and write equations for each constraint.
Word Problems ๐งฎ
1) Sum of two numbers is 20, difference is 6. Larger number = ?
2) 40% + 60% solutions mixed to get 200 mL of 45%. How many mL of 40%?
3) $5,000 at rate r earns $350/yr. Rate (%) = ?
=
5
| Infinite | Dependent, identity (0=0) | Same line/overlap |
Key Formulas
- Elimination: multiply to match, add/subtract
- Substitution: isolate, plug in, solve
- LP: evaluate objective at corner points
- Partial fractions: factor, decompose, solve for constants
๐ Mixed Practice Strategies
Quick-Solve Techniques
Symmetric systems: x+y=S,xโy=Dโนx=2S+Dโ,y=2SโDโ
Product-Sum: x+y=s,xy=p โ solve t2โ
Three-variable shortcut: Add all equations first to find x+y+z.
Example: Mixed Nonlinear
{x2+y=10x+y
By symmetry, try x=y: x2+x=10โน
But also check non-symmetric solutions: subtract equations:
x2โy2โ(xโy)
So either x=y or x+y=1 โ two families of solutions!
Common Pitfalls
- Forgetting to check solutions in ALL original equations
- Losing solutions when dividing by a variable (might be 0!)
- Not verifying extraneous solutions from squaring
๐ Calculus Connections
Systems Appear Everywhere
Related Rates (Calculus): Set up systems relating rates of change.
Optimization (Calculus): Lagrange multipliers create systems:
โf=ฮปโg
Differential Equations: Systems of DEs govern:
- Population dynamics (predator-prey)
- Electrical circuits
- Economic models
Linear Algebra Preview
Systems can be written as matrix equations:
[21โ1โ1โ][xyโ]=
This leads to matrices โ our next topic!
Final Calculations ๐งฎ
1) x+y=10,xy=21. Larger value = ?
2) (xโ1)(xโ2)1โ at x=3: value = ?
3) Max of P=x+2y at corners (0,0),(4,0),(: max = ?
โ
2
y
โ
z)=
6+
5โน
2x+
3y=
11(A)
=
3+
5โน
3x+
y=
8(B)
โ
3x)=
11โน
2x+
24โ
9x=
11โน
โ7x=
โ13โน
x=
713โ
x+y+z=6xโy+z=22x+yโz=1
โ
=
3โน
x=
1
x+y+z=42x+2y+2z=8xโy+z=0โ
6
)
,
(
2
,
11
)
,
(
3
,
18
)
a+b+c=64a+2b+c=119a+3b+c=18โ
2
+
2x+
3
2
=
25
x2+49โ14x+x2=25 2x2โ14x+24=0 x2โ7x+12=0 (xโ3)(xโ4)=0 3
โ
2xโ
3=
0โน
(xโ
3)(x+
1)=
0
x
=
y=
โ
)
2
+
y2
=
4
โ
2x+
1=
0โน
(xโ
1)2=
0
2x+y=8,y=0
(3,2): intersection of x+y=5,2x+y=8 (0,5): intersection of x+y=5,x=0 (4,0)
| (3,2) | 13 โ Maximum |
A+
8โน
A=
3
2
8
โ
x
2
+
x
+
3
โ
=
x+1Aโ+
x2+1Bx+Cโ
2
2
+
1
1
โ
1
)
+
(Bx+
C)(xโ
1)
+
Cxโ
C)
=(1+B)x2+(1โB+C)x+(1โC) x0
2=1โCโนC=โ1 2
+
x
+
1
โ1
โ
A
โ
+
x+2Bโ
=
600
โ
=
6000
=
122+3โ=
125โ
s
t
+
p=
0
2
=
10
โ
x
=
2.7
=
0โน
(xโ
y)(x+
yโ
1)=
0
[72โ]
2
,
3
)
,
(
0
,
5
)