Skip to content
🎯⭐ INTERACTIVE LESSON

Sequences & Series

Learn step-by-step with interactive practice!

Sequences & Series - Complete Interactive Lesson

Part 1: Arithmetic Sequences

📊 Sequences & Series — Arithmetic Sequences

Part 1 of 7

What Is a Sequence?

A sequence is an ordered list of numbers following a pattern. Each number is called a term.

a1,a2,a3,…,an,…a_1, a_2, a_3, \ldots, a_n, \ldots

Arithmetic Sequences

An arithmetic sequence has a constant difference between consecutive terms:

an=a1+(n−1)da_n = a_1 + (n-1)d

where d=an+1−and = a_{n+1} - a_n is the common difference.

Examples

  • 2,5,8,11,14,…2, 5, 8, 11, 14, \ldots → d=3d = 3
  • 20,15,10,5,0,…20, 15, 10, 5, 0, \ldots → d=−5d = -5
  • 12,1,32,2,…\frac{1}{2}, 1, \frac{3}{2}, 2, \ldots → d=12d = \frac{1}{2}

📝 Finding Terms and Sums

The nnth Term Formula

an=a1+(n−1)da_n = a_1 + (n-1)d

Example: a1=3,d=4a_1=3, d=4. Find a20a_{20}:

a20=3+19(4)=79a_{20} = 3 + 19(4) = 79

Arithmetic Series (Sum)

Sn=n2(a1+an)=n2[2a1+(n−1)d]S_n = \frac{n}{2}(a_1 + a_n) = \frac{n}{2}[2a_1 + (n-1)d]

Example: Sum the first 100100 positive integers.

a1=1,a100=100,n=100a_1 = 1, a_{100} = 100, n = 100

S100=1002(1+100)=50⋅101=5050S_{100} = \frac{100}{2}(1+100) = 50 \cdot 101 = 5050

💡 This is Gauss's famous result! He supposedly computed this as a schoolboy.

🧩 Applications

Finding Unknown Terms

If a5=17a_5 = 17 and a12=45a_{12} = 45:

a12−a5=(12−5)da_{12} - a_5 = (12-5)d

45−17=7d  ⟹  d=445 - 17 = 7d \implies d = 4

a1=a5−4d=17−16=1a_1 = a_5 - 4d = 17 - 16 = 1

Arithmetic Mean

The arithmetic mean of aa and bb is a+b2\frac{a+b}{2}, which is the term between them in an arithmetic sequence.

Insert 3 arithmetic means between 2 and 14:

a1=2,a5=14a_1 = 2, a_5 = 14. 14=2+4d  ⟹  d=314 = 2+4d \implies d = 3.

Sequence: 2,5,8,11,142, 5, 8, 11, 14.

Arithmetic Sequences Quiz 🎯

Arithmetic Sequence Practice 🧮

1) a1=5,d=7a_1=5, d=7. Find a10a_{10}:

2) Sum of first 5050 positive integers: S50S_{50} = ?

3) a3=11,a7=23a_3=11, a_7=23. Find dd:

Arithmetic Sequences Properties 🔽

Exit Quiz ✅

Part 2: Geometric Sequences

📊 Geometric Sequences

Part 2 of 7

Definition

A geometric sequence has a constant ratio between consecutive terms:

an=a1⋅rn−1a_n = a_1 \cdot r^{n-1}

where r=an+1anr = \frac{a_{n+1}}{a_n} is the common ratio.

Examples

Sequencea1a_1rr
3,6,12,24,…3, 6, 12, 24, \ldots3322
100,50,25,12.5,…100, 50, 25, 12.5, \ldots10010012\frac{1}{2}
1,−3,9,−27,…1, -3, 9, -27, \ldots11−3-3
5,5,5,5,…5, 5, 5, 5, \ldots5511

💡 If ∣r∣>1|r| > 1, terms grow; if ∣r∣<1|r| < 1, terms shrink; if r<0r < 0, terms alternate sign.

📝 Finite Geometric Series

Sn=a1⋅1−rn1−r(r≠1)S_n = a_1 \cdot \frac{1-r^n}{1-r} \quad (r \neq 1)

Example: Find S8S_8 for a1=3,r=2a_1=3, r=2

S8=3⋅1−281−2=3⋅1−256−1=3⋅255=765S_8 = 3 \cdot \frac{1-2^8}{1-2} = 3 \cdot \frac{1-256}{-1} = 3 \cdot 255 = 765

Geometric Mean

The geometric mean of positive aa and bb is ab\sqrt{ab}.

Insert a geometric mean between 4 and 16: 4⋅16=64=8\sqrt{4 \cdot 16} = \sqrt{64} = 8

Sequence: 4,8,164, 8, 16 with r=2r = 2.

📊 Arithmetic vs. Geometric

FeatureArithmeticGeometric
PatternAdd constant ddMultiply by constant rr
Formulaan=a1+(n−1)da_n = a_1+(n-1)dan=a1⋅rn−1a_n = a_1 \cdot r^{n-1}
Sumn2(a1+an)\frac{n}{2}(a_1+a_n)a11−rn1−ra_1\frac{1-r^n}{1-r}
GrowthLinearExponential
GraphStraight lineExponential curve

Key Insight

Arithmetic sequences grow by addition → linear growth.

Geometric sequences grow by multiplication → exponential growth (or decay if ∣r∣<1|r|<1).

Geometric Sequences Quiz 🎯

Geometric Sequence Practice 🧮

1) a1=5,r=2a_1=5, r=2. Find a8a_8:

2) a1=1000,r=12a_1=1000, r=\frac{1}{2}. Find a5a_5:

3) S4S_4 for a1=3,r=4a_1=3, r=4: (use the sum formula)

Geometric Sequences Properties 🔽

Exit Quiz ✅

Part 3: Series & Partial Sums

♾️ Infinite Geometric Series

Part 3 of 7

When Does an Infinite Sum Converge?

For a geometric series with ∣r∣<1|r| < 1, the partial sums approach a finite limit:

S∞=a11−rwhen ∣r∣<1S_\infty = \frac{a_1}{1-r} \quad \text{when } |r| < 1

If ∣r∣≥1|r| \geq 1, the series diverges (no finite sum).

Why It Works

As n→∞n \to \infty and ∣r∣<1|r| < 1, rn→0r^n \to 0:

Sn=a1⋅1−rn1−r→a11−rS_n = a_1 \cdot \frac{1-r^n}{1-r} \to \frac{a_1}{1-r}

Example

1+12+14+18+⋯=11−12=21 + \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \cdots = \frac{1}{1-\frac{1}{2}} = 2

📝 Worked Examples

Example 1: ∑n=0∞3(25)n\sum_{n=0}^{\infty} 3\left(\frac{2}{5}\right)^n

a1=3,r=25a_1 = 3, r = \frac{2}{5}. Since ∣r∣<1|r| < 1:

S=31−25=335=5S = \frac{3}{1-\frac{2}{5}} = \frac{3}{\frac{3}{5}} = 5

Example 2: Repeating Decimal 0.36‾0.\overline{36}

0.363636…=0.36+0.0036+0.000036+⋯0.363636\ldots = 0.36 + 0.0036 + 0.000036 + \cdots

a1=0.36,r=0.01a_1 = 0.36, r = 0.01

S=0.361−0.01=0.360.99=3699=411S = \frac{0.36}{1-0.01} = \frac{0.36}{0.99} = \frac{36}{99} = \frac{4}{11}

Example 3: Does ∑5(1.1)n\sum 5(1.1)^n converge?

r=1.1>1r = 1.1 > 1 → Diverges! No finite sum.

🌍 Applications

Bouncing Ball Total Distance

Ball dropped from h=10h = 10 m, rebounds to 35\frac{3}{5} of height each time.

Total distance = down + up + down + up + ...

=10+2∑n=1∞10(35)n=10+2⋅10⋅351−35=10+2⋅625=10+30=40= 10 + 2 \sum_{n=1}^{\infty} 10\left(\frac{3}{5}\right)^n = 10 + 2 \cdot \frac{10 \cdot \frac{3}{5}}{1-\frac{3}{5}} = 10 + 2 \cdot \frac{6}{\frac{2}{5}} = 10 + 30 = 40 m

Drug Dosage (Pharmacokinetics)

If 60% of a drug remains after each dose period and dose is 200 mg:

Long-term level = 2001−0.6=500\frac{200}{1-0.6} = 500 mg (steady state)

Infinite Series Quiz 🎯

Infinite Series Calculations 🧮

1) ∑n=0∞8(14)n\sum_{n=0}^{\infty} 8\left(\frac{1}{4}\right)^n = ?

2) 0.7‾=?90.\overline{7} = \frac{?}{9}. Enter the numerator.

3) ∑n=1∞610n\sum_{n=1}^{\infty} \frac{6}{10^n} = ? (Enter as a fraction like "2/3")

Convergence Concepts 🔽

Exit Quiz ✅

Part 4: Sigma Notation

🔢 Sigma Notation & Series

Part 4 of 7

Sigma (Summation) Notation

∑k=1nak=a1+a2+a3+⋯+an\sum_{k=1}^{n} a_k = a_1 + a_2 + a_3 + \cdots + a_n

  • kk = index of summation (dummy variable)
  • Lower limit: starting value
  • Upper limit: ending value

Examples

Sigma FormExpandedValue
∑k=14k\sum_{k=1}^{4} k1+2+3+41+2+3+41010
∑k=13k2\sum_{k=1}^{3} k^21+4+91+4+91414
∑k=032k\sum_{k=0}^{3} 2^k1+2+4+81+2+4+81515
∑k=153\sum_{k=1}^{5} 33+3+3+3+33+3+3+3+31515

📐 Properties of Summation

Linearity Rules

∑k=1n(ak+bk)=∑k=1nak+∑k=1nbk\sum_{k=1}^n (a_k + b_k) = \sum_{k=1}^n a_k + \sum_{k=1}^n b_k

∑k=1nc⋅ak=c⋅∑k=1nak\sum_{k=1}^n c \cdot a_k = c \cdot \sum_{k=1}^n a_k

Useful Closed-Form Sums

SumFormula
∑k=1n1\sum_{k=1}^n 1nn
∑k=1nk\sum_{k=1}^n kn(n+1)2\frac{n(n+1)}{2}
∑k=1nk2\sum_{k=1}^n k^2n(n+1)(2n+1)6\frac{n(n+1)(2n+1)}{6}
∑k=1nk3\sum_{k=1}^n k^3[n(n+1)2]2\left[\frac{n(n+1)}{2}\right]^2

Telescoping Sums

∑k=1n[f(k)−f(k−1)]=f(n)−f(0)\sum_{k=1}^n [f(k)-f(k-1)] = f(n)-f(0) — most terms cancel!

📝 Writing in Sigma Notation

Example 1: 2+4+6+8+⋯+1002+4+6+8+\cdots+100

Pattern: ak=2ka_k = 2k, from k=1k=1 to 5050.

∑k=1502k=2∑k=150k=2⋅50(51)2=2550\sum_{k=1}^{50} 2k = 2\sum_{k=1}^{50} k = 2 \cdot \frac{50(51)}{2} = 2550

Example 2: 1−12+14−18+⋯1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\cdots

Pattern: ak=(−12)ka_k = (-\frac{1}{2})^k, from k=0k=0 to ∞\infty.

∑k=0∞(−12)k=11+12=23\sum_{k=0}^{\infty}\left(-\frac{1}{2}\right)^k = \frac{1}{1+\frac{1}{2}} = \frac{2}{3}

Example 3: 11⋅2+12⋅3+13⋅4+⋯+199⋅100\frac{1}{1\cdot 2}+\frac{1}{2\cdot 3}+\frac{1}{3\cdot 4}+\cdots+\frac{1}{99\cdot 100}

Partial fractions: 1k(k+1)=1k−1k+1\frac{1}{k(k+1)} = \frac{1}{k}-\frac{1}{k+1} → telescoping!

∑k=199(1k−1k+1)=1−1100=99100\sum_{k=1}^{99}\left(\frac{1}{k}-\frac{1}{k+1}\right) = 1 - \frac{1}{100} = \frac{99}{100}

Sigma Notation Quiz 🎯

Sigma Calculations 🧮

1) ∑k=14k2\sum_{k=1}^{4} k^2 = ?

2) ∑k=110k\sum_{k=1}^{10} k = ?

3) ∑k=165\sum_{k=1}^{6} 5 = ?

Sigma Concepts 🔽

Exit Quiz ✅

Part 5: Infinite Geometric Series

🔁 Recursive Sequences & Special Sequences

Part 5 of 7

Recursive vs. Explicit Formulas

TypeDefinitionExample
Explicitana_n as a function of nnan=3n+1a_n = 3n+1
Recursiveana_n in terms of previous termsan=an−1+3a_n = a_{n-1}+3, a1=4a_1=4

The Fibonacci Sequence

F1=1,F2=1,Fn=Fn−1+Fn−2F_1=1, F_2=1, F_n = F_{n-1}+F_{n-2}

1,1,2,3,5,8,13,21,34,55,89,…1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, \ldots

Each term is the sum of the two preceding terms.

💡 The ratio of consecutive Fibonacci numbers approaches the Golden Ratio ϕ=1+52≈1.618\phi = \frac{1+\sqrt{5}}{2} \approx 1.618.

📝 Working with Recursive Formulas

Example 1: a1=2,an=3an−1−1a_1=2, a_n=3a_{n-1}-1

a1=2a_1 = 2 a2=3(2)−1=5a_2 = 3(2)-1 = 5 a3=3(5)−1=14a_3 = 3(5)-1 = 14 a4=3(14)−1=41a_4 = 3(14)-1 = 41

Example 2: Converting Recursive → Explicit

Given: a1=5,an=an−1+4a_1 = 5, a_n = a_{n-1}+4

This is arithmetic with d=4d=4: an=5+4(n−1)=4n+1a_n = 5+4(n-1) = 4n+1.

Example 3: Logistic Growth

Pn+1=r⋅Pn(1−Pn)P_{n+1} = r \cdot P_n(1-P_n)

This recursive formula models population growth with limited resources. Unlike geometric growth, it accounts for carrying capacity.

🌟 Special Sequences

Triangular Numbers

1,3,6,10,15,21,…1, 3, 6, 10, 15, 21, \ldots → Tn=n(n+1)2T_n = \frac{n(n+1)}{2}

Square Numbers

1,4,9,16,25,…1, 4, 9, 16, 25, \ldots → Sn=n2S_n = n^2

Factorial Sequence

1,1,2,6,24,120,…1, 1, 2, 6, 24, 120, \ldots → n!=n(n−1)(n−2)⋯1n! = n(n-1)(n-2)\cdots 1

Powers of 2

1,2,4,8,16,32,…1, 2, 4, 8, 16, 32, \ldots → an=2n−1a_n = 2^{n-1}

Harmonic Sequence

1,12,13,14,…1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \ldots → an=1na_n = \frac{1}{n}

The harmonic series ∑1n\sum \frac{1}{n} diverges — even though terms go to 0!

Recursive Sequences Quiz 🎯

Recursive Calculations 🧮

For a1=3,an=an−12−2a_1=3, a_n=a_{n-1}^2-2:

1) a2a_2 = ?

2) a3a_3 = ?

3) What is 5!5! (5 factorial)?

Special Sequences Concepts 🔽

Exit Quiz ✅

Part 6: Problem-Solving Workshop

🧮 Binomial Theorem

Part 6 of 7

Pascal's Triangle

111121133114641\begin{array}{c} 1 \\ 1 \quad 1 \\ 1 \quad 2 \quad 1 \\ 1 \quad 3 \quad 3 \quad 1 \\ 1 \quad 4 \quad 6 \quad 4 \quad 1 \end{array}

Each number is the sum of the two numbers above it.

Binomial Coefficients

(nk)=n!k!(n−k)!\binom{n}{k} = \frac{n!}{k!(n-k)!}

Read "nn choose kk" — the number of ways to select kk items from nn.

The Binomial Theorem

(a+b)n=∑k=0n(nk)an−kbk(a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k

📝 Expanding Binomials

Example 1: (x+y)4(x+y)^4

(40)x4+(41)x3y+(42)x2y2+(43)xy3+(44)y4\binom{4}{0}x^4 + \binom{4}{1}x^3y + \binom{4}{2}x^2y^2 + \binom{4}{3}xy^3 + \binom{4}{4}y^4

=x4+4x3y+6x2y2+4xy3+y4= x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4

Example 2: (2x−3)3(2x-3)^3

Let a=2x,b=−3a=2x, b=-3:

(2x)3+3(2x)2(−3)+3(2x)(−3)2+(−3)3(2x)^3 + 3(2x)^2(-3) + 3(2x)(-3)^2 + (-3)^3

=8x3−36x2+54x−27= 8x^3 - 36x^2 + 54x - 27

Finding a Specific Term

The (k+1)(k+1)th term of (a+b)n(a+b)^n is: (nk)an−kbk\binom{n}{k}a^{n-k}b^k

Find the 4th term of (x+2)6(x+2)^6: k=3k=3

(63)x3(2)3=20⋅x3⋅8=160x3\binom{6}{3}x^3(2)^3 = 20 \cdot x^3 \cdot 8 = 160x^3

🔑 Key Properties

Symmetry

(nk)=(nn−k)\binom{n}{k} = \binom{n}{n-k}

Example: (72)=(75)=21\binom{7}{2} = \binom{7}{5} = 21

Sum of Row

∑k=0n(nk)=2n\sum_{k=0}^n \binom{n}{k} = 2^n

(Set a=b=1a=b=1 in the binomial theorem)

Alternating Sum

∑k=0n(−1)k(nk)=0\sum_{k=0}^n (-1)^k\binom{n}{k} = 0

(Set a=1,b=−1a=1, b=-1)

Pascal's Rule

(nk)=(n−1k−1)+(n−1k)\binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k}

This is why each entry in Pascal's triangle is the sum of the two above it!

Binomial Theorem Quiz 🎯

Binomial Calculations 🧮

1) (83)\binom{8}{3} = ?

2) The coefficient of x4x^4 in (x+2)5(x+2)^5 is: (include the power of 2)

3) The sum of row 6 of Pascal's triangle: ∑k=06(6k)\sum_{k=0}^6 \binom{6}{k} = ?

Binomial Concepts 🔽

Exit Quiz ✅

Part 7: Review & Applications

🎯 Sequences & Series — Full Synthesis

Part 7 of 7

Master Summary

Typennth TermSum FormulaConvergence
Arithmetica1+(n−1)da_1+(n-1)dn2(a1+an)\frac{n}{2}(a_1+a_n)Always diverges
Geometrica1rn−1a_1 r^{n-1}a11−rn1−ra_1\frac{1-r^n}{1-r}$

Key Decision Tree

Is there a common difference? → Arithmetic

Is there a common ratio? → Geometric

Is it defined by previous terms? → Recursive

Does it involve (nk)\binom{n}{k}? → Binomial expansion

🗺️ Problem-Solving Strategies

Finding the Pattern

  1. Compute differences: a2−a1,a3−a2,…a_2-a_1, a_3-a_2, \ldots → constant? → arithmetic
  2. Compute ratios: a2/a1,a3/a2,…a_2/a_1, a_3/a_2, \ldots → constant? → geometric
  3. Check second differences → constant? → quadratic sequence

AP Exam Tips

  • Know both sum formulas cold
  • Practice converting between recursive and explicit
  • For convergence questions: only geometric with ∣r∣<1|r|<1
  • Telescoping sums: try partial fractions
  • Binomial: know how to find a specific term without expanding everything

📝 Mixed Practice

Problem 1

Sequence: 2,6,18,54,…2, 6, 18, 54, \ldots

Ratios: 6/2=36/2=3 → Geometric, r=3r=3. an=2(3)n−1a_n = 2(3)^{n-1}.

Problem 2

∑k=1∞45k\sum_{k=1}^{\infty} \frac{4}{5^k}

a1=4/5,r=1/5a_1 = 4/5, r = 1/5. S=4/51−1/5=4/54/5=1S = \frac{4/5}{1-1/5} = \frac{4/5}{4/5} = 1.

Problem 3

Find the coefficient of x2y3x^2y^3 in (x+y)5(x+y)^5:

(53)=10\binom{5}{3} = 10.

Problem 4

Find the sum: 1+3+5+⋯+991 + 3 + 5 + \cdots + 99

Arithmetic: a1=1,d=2,an=99a_1=1, d=2, a_n=99. n=50n = 50. S50=502(1+99)=2500S_{50} = \frac{50}{2}(1+99) = 2500.

Synthesis Quiz 🎯

Mixed Calculations 🧮

1) Sum of first 20 terms of 5,8,11,14,…5, 8, 11, 14, \ldots:

2) ∑n=1∞10(0.1)n\sum_{n=1}^{\infty} 10(0.1)^n = ? (Enter as a fraction)

3) (73)\binom{7}{3} = ?

Master Classification 🔽

Final Exit Quiz ✅