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🎯⭐ INTERACTIVE LESSON

Ratios, Proportions, and Percents

Learn step-by-step with interactive practice!

Ratios, Proportions, and Percents - Complete Interactive Lesson

Part 1: Ratios & Rates

Ratios, Proportions & Percentages

Part 1 of 7 — Ratios and Rates

Ratios

A ratio compares two quantities: a:ba : b or ab\frac{a}{b}.

If the ratio of boys to girls is 3:53:5 and there are 40 students total:

  • Total parts = 3+5=83 + 5 = 8
  • Boys = (3/8)(40)=15(3/8)(40) = 15
  • Girls = (5/8)(40)=25(5/8)(40) = 25

Rates

A rate is a ratio with units: miles/hour, dollars/item, people/year.

Unit Rate = rate per one unit. "$7.50 for 3 pounds" → $2.50 per pound.

Proportions

ab=cd  ⟹  ad=bc(cross multiply)\frac{a}{b} = \frac{c}{d} \implies ad = bc \quad \text{(cross multiply)}

Example: If 3 widgets cost $14, how much do 7 widgets cost?

314=7x  ⟹  3x=98  ⟹  x=983≈$32.67\frac{3}{14} = \frac{7}{x} \implies 3x = 98 \implies x = \frac{98}{3} \approx \$32.67


Worked Example 1 — Three-Part Ratio

In a mixture, red, blue, and yellow paint are in the ratio 2:3:52:3:5. If the total is 60 liters, how much blue paint is there?

StepWork
Total parts2+3+5=102 + 3 + 5 = 10
Blue fraction3/103/10
Blue amount(3/10)(60)=18(3/10)(60) = 18 liters

Worked Example 2 — Comparing Unit Rates

Store A sells 5 lb of apples for $8.50. Store B sells 3 lb for $4.80. Which is cheaper per pound?

StoreCalculationUnit Rate
A8.50÷58.50 \div 5$1.70/lb
B4.80÷34.80 \div 3$1.60/lb

Store B is cheaper by $0.10 per pound.

Ratios & Rates 🎯

Ratio Problems with Unknowns

Sometimes the SAT gives you a ratio and one part, not the total.

Worked Example 3

The ratio of cats to dogs at a shelter is 5:35:3. If there are 24 dogs, how many cats are there?

StepWork
Set up proportioncatsdogs=53\frac{\text{cats}}{\text{dogs}} = \frac{5}{3}
Substitutec24=53\frac{c}{24} = \frac{5}{3}
Cross multiply3c=1203c = 120 → c=40c = 40

Worked Example 4

A car averages 32 miles per gallon. Gas costs $3.60 per gallon. What is the fuel cost for a 480-mile trip?

StepWork
Gallons needed480÷32=15480 \div 32 = 15 gallons
Cost15×3.60=5415 \times 3.60 = 54, i.e. $54

Harder Ratio Problems 🎯

Ratio, Rate, or Proportion? 🔍

Classify each problem type.

Key Takeaways — Part 1

ConceptFormulaWhen to Use
Ratio a:ba:bPart =aa+b×T= \frac{a}{a+b} \times TGiven total
Ratio with one partab=xknown\frac{a}{b} = \frac{x}{\text{known}}Given one quantity
Unit rateDivide total by countComparing costs/speeds
Cross multiplyad=bcad = bcSolving proportions
  • Set up proportions with matching units on each side
  • Three-part ratios: add all parts for the total
  • Unit rates let you compare which deal is better

Part 2: Proportional Reasoning

Ratios, Proportions & Percentages

Part 2 of 7 — Percentages

Percent Basics

p%p\% means p100\frac{p}{100}.

  • "What is 15% of 80?" → 0.15×80=120.15 \times 80 = 12
  • "12 is what percent of 80?" → 1280=0.15=15%\frac{12}{80} = 0.15 = 15\%
  • "12 is 15% of what?" → 12=0.15x12 = 0.15x → x=80x = 80

Percent Change

Percent change=New−OldOld×100%\text{Percent change} = \frac{\text{New} - \text{Old}}{\text{Old}} \times 100\%

Example: Price goes from $40 to $52: 52−4040×100=30%\frac{52 - 40}{40} \times 100 = 30\% increase

Multiplier Method (Faster!)

  • Increase of p%p\%: multiply by 1+p/1001 + p/100
  • Decrease of p%p\%: multiply by 1−p/1001 - p/100

20% increase on $80: 80×1.20=9680 \times 1.20 = 96, i.e. $96

15% discount on $200: 200×0.85=170200 \times 0.85 = 170, i.e. $170

Successive Percent Changes ⚠️

A 20% increase followed by a 20% decrease is NOT back to the original!

100×1.20=120100 \times 1.20 = 120, then 120×0.80=96120 \times 0.80 = 96 — that's a 4% net decrease.


Worked Example 1 — Finding the Original

After a 30% discount, a jacket costs $56. What was the original price?

StepWork
Multiplier for 30% off1−0.30=0.701 - 0.30 = 0.70
Set up equation0.70x=560.70x = 56
Solvex=56÷0.70=80x = 56 \div 0.70 = 80, i.e. $80

⚠️ Common mistake: adding 30% to $56 gives $72.80, which is WRONG.

Worked Example 2 — Successive Changes

A stock rises 25% one year, then falls 20% the next. If it started at $200, what is its final value?

StepWork
After 25% rise200×1.25=250200 \times 1.25 = 250
After 20% fall250×0.80=200250 \times 0.80 = 200
Net change200−200200=0%\frac{200 - 200}{200} = 0\%

This time it happens to be zero — but that's because 1.25×0.80=1.001.25 \times 0.80 = 1.00 exactly.

Percentages 🎯

Tax, Tip, and Markup

These are all "percent increase" problems.

Worked Example 3

A meal costs $42. Tax is 8% and tip is 20% (on the pre-tax amount). What is the total?

ComponentCalculationAmount
Meal—$42.00
Tax (8%)42×0.0842 \times 0.08$3.36
Tip (20%)42×0.2042 \times 0.20$8.40
Total—$53.76

With multiplier: 42×(1+0.08+0.20)=42×1.28=53.7642 \times (1 + 0.08 + 0.20) = 42 \times 1.28 = 53.76, i.e. $53.76

Worked Example 4

A store marks up items 40% then offers a 10% "sale." What is the net markup?

StepMultiplier
40% markup1.401.40
10% discount0.900.90
Net1.40×0.90=1.261.40 \times 0.90 = 1.26

The net markup is 26%, not 30%.

Percent Applications 🎯

What Multiplier? 🔍

Choose the correct multiplier for each scenario.

Key Takeaways — Part 2

ScenarioMultiplierExample
p%p\% increase1+p/1001 + p/10020% increase → ×1.20×1.20
p%p\% decrease1−p/1001 - p/10015% off → ×0.85×0.85
Find originalDivide by multipliersale÷0.75\text{sale} ÷ 0.75
Successive changesMultiply multipliers1.25×0.80=1.001.25 × 0.80 = 1.00
  • Percent change: always divide by the original
  • Successive discounts: multiply multipliers, don't add percentages
  • Tax + tip: both are increases on the base price
  • "What was the original?" → divide by the multiplier, don't reverse-add

Part 3: Percentages

Ratios, Proportions & Percentages

Part 3 of 7 — Direct and Inverse Variation

Direct Variation: y=kxy = kx

"yy is directly proportional to xx" means as xx doubles, yy doubles.

Constant of proportionality: k=y/xk = y/x

Example: If y=12y = 12 when x=4x = 4, then k=3k = 3 and y=3xy = 3x.

Inverse Variation: y=k/xy = k/x

"yy is inversely proportional to xx" means as xx doubles, yy halves.

Product is constant: xy=kxy = k

Example: If y=6y = 6 when x=8x = 8, then k=48k = 48 and y=48/xy = 48/x.

When x=12x = 12: y=48/12=4y = 48/12 = 4

Joint Variation

"zz varies directly with xx and inversely with yy": z=kx/yz = kx/y

SAT Application

Speed and time for a fixed distance: d=rtd = rt, so t=d/rt = d/r — time is inversely proportional to rate.

If you double your speed, the trip takes half the time.


Worked Example 1 — Direct Variation from a Table

Does this table show direct variation?

xx25810
yy6152430
Checky/xy/x
6/26/233
15/515/533
24/824/833
30/1030/1033

Yes — k=3k = 3 is constant, so y=3xy = 3x.

Worked Example 2 — Inverse Variation Application

It takes 4 painters 9 days to paint a building. How long for 6 painters?

StepWork
Workers × time = constant4×9=364 \times 9 = 36 worker-days
New equation6×t=366 \times t = 36
Solvet=6t = 6 days

Variation 🎯

Recognizing Variation on the SAT

The SAT often disguises variation problems. Here are keywords to watch for:

KeywordTypeEquation
"proportional to"Directy=kxy = kx
"varies directly"Directy=kxy = kx
"varies inversely"Inversexy=kxy = k
"constant product"Inversexy=kxy = k
"varies jointly with xx and yy"Joint directz=kxyz = kxy

Worked Example 3 — Joint Variation

zz varies directly with xx and inversely with y2y^2. If z=8z = 8 when x=4x = 4 and y=1y = 1, find zz when x=6x = 6 and y=2y = 2.

StepWork
Set up formulaz=kxy2z = \frac{kx}{y^2}
Find kk8=k(4)128 = \frac{k(4)}{1^2} → k=2k = 2
Use new valuesz=2(6)22=124=3z = \frac{2(6)}{2^2} = \frac{12}{4} = 3

Worked Example 4 — Graph Clue

The graph of yy vs xx passes through the origin and is a straight line. What type of variation?

Direct variation — y=kxy = kx always passes through (0,0)(0, 0) and has slope kk.

If the graph is a hyperbola (y=k/xy = k/x), it's inverse variation.

Variation Applications 🎯

Direct or Inverse? 🔍

Classify each relationship.

Key Takeaways — Part 3

TypeEquationConstantGraph
Directy=kxy = kxy/x=ky/x = kLine through origin
Inversey=k/xy = k/xxy=kxy = kHyperbola
Jointz=kxyz = kxy—3D surface
  • Find kk from a known pair, then use it for all other questions
  • "Proportional to" on the SAT usually means direct variation
  • Inverse variation: product stays constant as one goes up, the other goes down
  • Watch for y=kx2y = kx^2 or y=kxy = k\sqrt{x} — these are NOT simple direct/inverse

Part 4: Unit Conversion

Ratios, Proportions & Percentages

Part 4 of 7 — Unit Conversions

Dimensional Analysis

Convert units by multiplying by fractions equal to 1:

"Convert 30 mph to feet per second"

30mileshour×5,280 feet1 mile×1 hour3,600 seconds=44 ft/s30 \frac{\text{miles}}{\text{hour}} \times \frac{5,280 \text{ feet}}{1 \text{ mile}} \times \frac{1 \text{ hour}}{3,600 \text{ seconds}} = 44 \text{ ft/s}

Common Conversions (SAT-relevant)

GivenConversion
1 mile5,280 feet
1 kilometer1,000 meters
1 hour60 minutes = 3,600 seconds
1 gallon4 quarts
1 pound16 ounces

SAT Unit Conversion Strategy

  1. Write the starting quantity as a fraction
  2. Multiply by conversion factors so unwanted units cancel
  3. Compute the result

The SAT provides conversion factors in the problem — you don't need to memorize them. Focus on the METHOD of canceling units.


Worked Example 1 — Multi-Step Conversion

A pump moves water at 5 gallons per minute. How many quarts per hour is that?

StepWork
Start5 gal/min5 \text{ gal/min}
Gallons → quarts×4 qt1 gal=20 qt/min× \frac{4 \text{ qt}}{1 \text{ gal}} = 20 \text{ qt/min}
Minutes → hours×60 min1 hr=1,200 qt/hr× \frac{60 \text{ min}}{1 \text{ hr}} = 1{,}200 \text{ qt/hr}

Worked Example 2 — Area Conversion

A room is 12 feet by 15 feet. What is the area in square yards? (1 yard = 3 feet)

StepWork
Area in sq ft12×15=180 ft212 × 15 = 180 \text{ ft}^2
Convert180÷9=20 yd2180 ÷ 9 = 20 \text{ yd}^2

⚠️ For area, you divide by 32=93^2 = 9 (not by 3). For volume, divide by 33=273^3 = 27.

Unit Conversions 🎯

Conversions with Rates

When converting rates, both the numerator and denominator units may change.

Worked Example 3

A factory produces 480 widgets per 8-hour shift. Express this in widgets per minute.

StepWork
Per hour480÷8=60480 ÷ 8 = 60 widgets/hr
Per minute60÷60=160 ÷ 60 = 1 widget/min

Worked Example 4

A density is given as 2.7 g/cm3g/cm^{3}. Convert to kg/m3kg/m^{3}. (1 kg = 1000 g, 1 m = 100 cm)

StepWork
Grams → kg÷1000÷ 1000
cm3cm^{3} → m3m^{3}÷(100)3=÷1,000,000÷ (100)^3 = ÷ 1{,}000{,}000
Combined2.7×1,000,0001,000=2,7002.7 × \frac{1{,}000{,}000}{1{,}000} = 2{,}700 kg/m3kg/m^{3}

The numerator and denominator conversions partially cancel — a common SAT shortcut.

Conversion Chain Template

Start×new unitold unit×new unitold unit=Result\text{Start} \times \frac{\text{new unit}}{\text{old unit}} \times \frac{\text{new unit}}{\text{old unit}} = \text{Result}

Write every step with units. If units don't cancel correctly, something is flipped.

Harder Conversions 🎯

Which Conversion Factor? 🔍

Pick the correct factor to go from the starting unit to the target unit.

Key Takeaways — Part 4

SituationKey Idea
Single unitMultiply by conversion fraction
Rate (two units)Convert numerator AND denominator
Area unitsSquare the linear factor: ft2ft^{2} → yd2yd^{2} \div 9
Volume unitsCube the linear factor: ft3ft^{3} → yd3yd^{3} ÷ 27
  • Write units at every step — if they don't cancel, something is wrong
  • SAT always provides conversion factors; focus on the method
  • Going from bigger to smaller units → multiply; smaller to bigger → divide
  • For area/volume: square or cube the conversion factor

Part 5: Scale & Modeling

Ratios, Proportions & Percentages

Part 5 of 7 — Scale Factors and Similar Figures

Scale Factor

If two figures are similar with a scale factor of kk:

  • Lengths scale by kk
  • Areas scale by k2k^2
  • Volumes scale by k3k^3

Similar Triangles

Two triangles are similar if they have the same angles (AA similarity).

If triangle AA has sides 3, 4, 5 and triangle BB has a side of 6 corresponding to 3:

  • Scale factor k=6/3=2k = 6/3 = 2
  • Other sides of BB: 4×2=84 \times 2 = 8 and 5×2=105 \times 2 = 10
  • Area of BB = Area of A×k2=Aarea×4A \times k^2 = A_{\text{area}} \times 4

Map/Model Problems

"On a map, 1 inch = 25 miles. Two cities are 3.5 inches apart."

Distance =3.5×25=87.5= 3.5 \times 25 = 87.5 miles.

SAT Application

Scale factors appear in:

  • Similar triangle problems
  • Map and blueprint questions
  • Geometry problems with dilations

Worked Example 1 — Area from Scale Factor

Two similar pentagons have perimeters of 20 cm and 30 cm. If the smaller has an area of 50 cm2cm^{2}, what is the area of the larger?

StepWork
Scale factork=30/20=1.5k = 30/20 = 1.5
Area factork2=2.25k^2 = 2.25
Larger area50×2.25=112.550 \times 2.25 = 112.5 cm2cm^{2}

Worked Example 2 — Volume from Scale Factor

A model car is built at 1:24 scale. If the model holds 0.5 mL of fuel in its tank, what does the actual tank hold?

StepWork
Scale factork=24k = 24
Volume factork3=13,824k^3 = 13{,}824
Actual volume0.5×13,824=6,9120.5 \times 13{,}824 = 6{,}912 mL ≈6.9≈ 6.9 liters

Scale Factors 🎯

Similar Triangles on the SAT

The SAT loves problems where you must first identify similar triangles, then set up a proportion.

Worked Example 3

A 6-foot person casts a 4-foot shadow. A tree next to them casts a 20-foot shadow. How tall is the tree?

StepWork
Set up similar trianglesheightshadow=64\frac{\text{height}}{\text{shadow}} = \frac{6}{4}
Apply to treeh20=64\frac{h}{20} = \frac{6}{4}
Solveh=6×204=30h = \frac{6 \times 20}{4} = 30 feet

Worked Example 4

On a map, the scale is 1 inch : 40 miles. Two cities are 6.5 inches apart on the map. A car travels at 65 mph. How long is the drive?

StepWork
Actual distance6.5×40=2606.5 \times 40 = 260 miles
Time260÷65=4260 \div 65 = 4 hours

The Scale Factor Cheat Sheet

What scales?Factor
Length, perimeter, heightkk
Area, surface areak2k^2
Volume, capacity, weight*k3k^3

*Weight scales as k3k^3 when density is the same.

Applied Scale Problems 🎯

What Power of kk? 🔍

For each quantity, decide whether it scales by kk, k2k^2, or k3k^3.

Key Takeaways — Part 5

MeasurementScaling FactorExample (k=3k = 3)
Lengthkk×3 \times 3
Areak2k^2×9 \times 9
Volumek3k^3×27 \times 27
Angles1 (unchanged)Same
  • Find kk by dividing corresponding lengths
  • Shadow problems → similar triangles → set up proportion
  • Map problems → multiply map distance by scale
  • The SAT frequently combines scale factors with other ratio concepts

Part 6: Problem-Solving Workshop

Ratios, Proportions & Percentages

Part 6 of 7 — Mixture and Work Problems

Mixture Problems

"How many liters of 60% acid solution must be mixed with 10 liters of 20% acid to get a 40% solution?"

Let xx = liters of 60% solution:

0.60x+0.20(10)=0.40(x+10)0.60x + 0.20(10) = 0.40(x + 10) 0.60x+2=0.40x+40.60x + 2 = 0.40x + 4 0.20x=20.20x = 2 x=10 litersx = 10 \text{ liters}

Work/Rate Problems

"Pipe A fills a tank in 6 hours, Pipe B in 4 hours. Together?"

  • Rate A: 1/61/6 tank/hour
  • Rate B: 1/41/4 tank/hour
  • Combined: 1/6+1/4=2/12+3/12=5/121/6 + 1/4 = 2/12 + 3/12 = 5/12 tank/hour
  • Time: 12/5=2.412/5 = 2.4 hours

SAT Strategy for Rate Problems

Rate×Time=Work\text{Rate} \times \text{Time} = \text{Work}

Add rates when working together. The combined rate is always faster than either individual rate.


Worked Example 1 — Mixture Table Method

A chemist has 40 mL of 70% alcohol and wants to dilute it to 50% alcohol by adding water. How much water?

ComponentVolume% AlcoholAmount of Alcohol
Solution40 mL70%28 mL
Waterxx mL0%0 mL
Mixture40+x40 + x mL50%0.50(40+x)0.50(40 + x) mL

28=0.50(40+x)  ⟹  28=20+0.5x  ⟹  x=16 mL28 = 0.50(40 + x) \implies 28 = 20 + 0.5x \implies x = 16 \text{ mL}

Worked Example 2 — Work Problem with One Working Then Both

Machine A takes 10 hours alone. Machine B takes 15 hours alone. If A works for 3 hours, then both work together, how much longer until done?

StepWork
A's rate1/101/10 per hour
B's rate1/151/15 per hour
A does in 3 hrs3/103/10 of the job
Remaining1−3/10=7/101 - 3/10 = 7/10
Combined rate1/10+1/15=5/30=1/61/10 + 1/15 = 5/30 = 1/6
Time for rest(7/10)÷(1/6)=42/10=4.2(7/10) ÷ (1/6) = 42/10 = 4.2 hours

Mixtures & Work 🎯

More Mixture Scenarios

Worked Example 3 — Mixing Two Concentrations

How many liters of 80% juice must be mixed with 12 liters of 30% juice to get 50% juice?

ComponentVolumeJuice
80% juicexx0.80x0.80x
30% juice120.30(12)=3.60.30(12) = 3.6
Mixturex+12x + 120.50(x+12)0.50(x + 12)

0.80x+3.6=0.50x+60.80x + 3.6 = 0.50x + 6 0.30x=2.40.30x = 2.4 x=8 litersx = 8 \text{ liters}

Worked Example 4 — Work Problem: Draining While Filling

A tap fills a tank in 5 hours. A drain empties it in 8 hours. If both are open, how long to fill?

StepWork
Fill rate+1/5+1/5 tank/hr
Drain rate−1/8-1/8 tank/hr
Net rate1/5−1/8=8/40−5/40=3/401/5 - 1/8 = 8/40 - 5/40 = 3/40
Time40/3≈13.340/3 ≈ 13.3 hours

The drain slows down the filling but doesn't stop it (fill rate > drain rate).

Advanced Rate Problems 🎯

Set Up the Equation 🔍

For each scenario, choose the correct equation setup.

Key Takeaways — Part 6

Problem TypeKey Setup
Work (together)1/a+1/b=1/t1/a + 1/b = 1/t
Work (one starts early)Find remaining work, then use combined rate
Fill & drainSubtract drain rate: 1/a−1/b1/a - 1/b
MixtureAmount1_1 + Amount2_2 = Amountmix_{\text{mix}}
Workers × timeTotal work = workers × time (constant)
  • Never add times — always convert to rates first
  • Use a table for mixture problems: Volume × Concentration = Amount
  • For fill-and-drain: if drain rate > fill rate, the tank never fills
  • Combined time is always less than the fastest individual time

Part 7: Review & Applications

Ratios, Proportions & Percentages

Part 7 of 7 — Review & SAT Mixed Practice

Quick Reference

TopicKey Formula
Ratio a:ba:b, total TTPart =aa+b×T= \frac{a}{a+b} \times T
Proportionab=cd\frac{a}{b} = \frac{c}{d} → cross multiply
Percent of=partwhole×100= \frac{\text{part}}{\text{whole}} \times 100
Percent change=new−oldold×100= \frac{\text{new} - \text{old}}{\text{old}} \times 100
Direct variationy=kxy = kx
Inverse variationxy=kxy = k
Scale: length×k\times k
Scale: area×k2\times k^2
Scale: volume×k3\times k^3

Common SAT Mistakes

  1. Dividing percent change by the new value instead of the old
  2. Assuming successive percent increases/decreases cancel out
  3. Adding times instead of rates in work problems
  4. Forgetting that the ratio a:ba:b has a+ba + b total parts, not a×ba \times b

Worked Example 1 — Multi-Concept

A store buys items for $50 and marks them up 60%. During a sale, they offer 25% off. What is the sale price?

StepWork
Markup50×1.60=8050 \times 1.60 = 80, i.e. $80
Sale discount80×0.75=6080 \times 0.75 = 60, i.e. $60
Net multiplier1.60×0.75=1.201.60 \times 0.75 = 1.20 → 20% net markup

Worked Example 2 — Proportion with Ratio Shift

In a class, boys to girls is 3:53:5. If 4 more boys join, the ratio becomes 1:11:1. How many students were originally in the class?

StepWork
Let partsBoys =3k= 3k, Girls =5k= 5k
After 4 boys join3k+4=5k3k + 4 = 5k
Solve4=2k4 = 2k → k=2k = 2
Original total3(2)+5(2)=163(2) + 5(2) = 16 students

Mixed Review 🎯

SAT Strategy Playbook

Worked Example 3 — Working Backwards

After a 10% raise, Maya earns $55,000. Then she gets a 5% bonus on the new salary. What was her original salary, and what is the bonus?

StepWork
Original salary1.10x=550001.10x = 55000 → x=50000x = 50000, i.e. $50,000
Bonus55000×0.05=275055000 \times 0.05 = 2750, i.e. $2,750
Total compensation55000+2750=5775055000 + 2750 = 57750, i.e. $57,750

Worked Example 4 — Scale + Percent

A blueprint uses a 1:50 scale. A room on the blueprint is 6 cm × 8 cm. The builder adds 20% to the area for a patio. What is the total real area?

StepWork
Real dimensions6×50=3006 \times 50 = 300 cm, 8×50=4008 \times 50 = 400 cm
Convert to meters33 m × 44 m
Room area1212 m2m^{2}
With patio (+20%)12×1.20=14.412 \times 1.20 = 14.4 m2m^{2}

Top 5 SAT Strategies for This Topic

  1. Is it direct or inverse? — If one goes up while the other goes down, it's inverse.
  2. Use multipliers — Never add/subtract percentages directly.
  3. Draw a table — For mixtures, lay out Volume × Concentration = Amount.
  4. Check with easy numbers — Substitute 100100 to verify percent problems.
  5. Units must match — In proportions, keep the same units on each side.

SAT-Level Challenge 🎯

Which Strategy? 🔍

For each problem, choose the best approach.

Key Takeaways — Full Topic Review

CategoryFormulaCommon Trap
Ratiosaa+b×T\frac{a}{a+b} \times TForgetting to add parts
Proportionsad=bcad = bcMismatched units
Percent changeΔold×100\frac{\Delta}{\text{old}} \times 100Dividing by new value
Finding originalsale÷(1−r)\text{sale} \div (1 - r)Adding percent to sale price
Successive %Multiply multipliersAdding percentages
Direct variationy=kxy = kx, y/x=ky/x = kConfusing with inverse
Inverse variationxy=kxy = kAdding instead of multiplying
Scale factorL → kk, A → k2k^2, V → k3k^3Using kk for area
Work problemsAdd rates, not timesAdding times
MixturesVol × Conc = AmountAveraging concentrations

Final SAT Tips:

  • Expect 4-6 ratio/proportion/percent questions per test
  • Always write units to catch dimensional errors
  • Use multipliers for percent problems — never add/subtract percentages directly
  • For work problems: Rate × Time = Work, add rates when working together