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Part 1: Quadratic Fundamentals
Quadratic Equations
Part 1 of 7 โ Standard Form and Factoring
Quadratics are one of the most heavily tested topics on the SAT Math section.
Standard Form: ax2+bx+c=0
- a determines the direction of the parabola (up if a>0, down if a<0)
- The vertex is at x=โ
Factoring
To factor x2+bx+c, find two numbers that multiply to c and add to b.
Example: x2+7x+12=0
- Numbers that multiply to 12 and add to 7: 3 and 4
- (x+3)(x+4)=0 โ x=โ3 or
Factoring with leading coefficient โ 1
For 2x2+7x+3:
- Multiply aโ
c=6. Find numbers that multiply to 6 and add to 7: 1 and 6
- Split: 2x2
Zero Product Property
If ab=0, then a=0 or b=0. This is why factoring works for solving equations.
Factoring Quadratics ๐ฏ
Key Takeaways โ Part 1
- Standard form: ax2+bx+c, vertex at x=โb/(2a)
- Factoring: find two numbers that multiply to and add to (when )
Part 2: Factoring
Quadratic Equations
Part 2 of 7 โ The Quadratic Formula & Discriminant
The Quadratic Formula
For ax2+bx+c=0:
Part 3: Quadratic Formula
Quadratic Equations
Part 3 of 7 โ Vertex Form and Completing the Square
Vertex Form: y=a(xโh)2+k
Part 4: Vertex Form
Quadratic Equations
Part 4 of 7 โ Graphing Parabolas
Key Features of y=ax2+bx+c
- y-intercept: The point โ just read the constant
Part 5: Graphing Parabolas
Quadratic Equations
Part 5 of 7 โ Quadratic Word Problems
Projectile Motion
The SAT's classic quadratic word problem:
h(t)=โ16t2+v0โ
Part 6: Problem-Solving Workshop
Quadratic Equations
Part 6 of 7 โ Quadratic Systems and Intersections
Line Meets Parabola
To find where y=x2+2xโ3 and y= intersect:
Part 7: Review & Applications
Quadratic Equations
Part 7 of 7 โ SAT Quadratics Review & Hard Problems
Everything You Need to Know
| Form | Formula | Best For |
|---|
| Standard | ax2+bx+c | y-intercept, discriminant |
| Factored | |
2abโ
x=โ4
+
x+
6x+
3=
x(2x+
1)+
3(2x+
1)=
(x+
3)(2x+
1)
Zero product property: if the factors multiply to zero, at least one factor equals zeroAlways double-check by expanding your factored formUse this when factoring is difficult or impossible.
The Discriminant: ฮ=b2โ4ac
| Discriminant | # Solutions | Graph |
|---|
| ฮ>0 | 2 real solutions | Parabola crosses x-axis twice |
| ฮ=0 | 1 real solution (double root) | Parabola touches x-axis |
| ฮ<0 | 0 real solutions | Parabola doesn't touch x-axis |
SAT Favorite Question Type ๐ฏ
"For what values of k does x2+kx+9=0 have exactly one real solution?"
Set discriminant = 0: k2โ4(1)(9)=0 โ k2=36 โ k=ยฑ6
Quadratic Formula & Discriminant ๐ฏ
Key Takeaways โ Part 2
- Quadratic formula: memorize it โ it works for ALL quadratics
- Discriminant (b2โ4ac) tells you HOW MANY solutions without solving
- ฮ>0: 2 solutions, ฮ=0: 1 solution, ฮ<0: 0 real solutions
- "Exactly one solution" โ set discriminant equal to 0
(
h
,
k
)
a>0: opens up (minimum at vertex) a<0: opens down (maximum at vertex) Converting Standard โ Vertex Form (Completing the Square)
Example: y=x2+6x+2
- Group: y=(x2+6x)+2
- Half of 6 = 3, square it = 9
- Add and subtract 9 inside: y=(x2+6x+9)โ9+2
- Factor: y=(x+3)2โ7
Vertex: (โ3,โ7)
When to Use Each Form
| Form | Best For |
|---|
| Standard: ax2+bx+c | y-intercept (just read c), discriminant |
| Factored: a(xโr)(xโs) | x-intercepts (roots are r and s) |
| Vertex: a(xโh)2+k | Maximum/minimum value, vertex |
Key Takeaways โ Part 3
- Vertex form: a(xโh)2+k โ vertex at (h,k)
- Watch the sign: (x+3) means h=โ3
- Completing the square: half the b-coefficient, square it, add/subtract
- Use vertex form when the SAT asks for minimum, maximum, or "what is the least possible value"
(
0
,
c
)
x-intercepts (roots/zeros): Set y=0 and solve Vertex: (โ2abโ,f(โ2abโ)) Axis of symmetry: x=โ2abโ (vertical line through vertex) Direction: Up if a>0, down if a<0 The Symmetry Trick
If the roots are at x=r and x=s, then the axis of symmetry is at:
x=2r+sโ
This is the midpoint of the roots!
SAT Graph Reading Skills
When the SAT shows you a parabola:
- The vertex tells you the min/max
- The x-intercepts are the solutions to f(x)=0
- The y-intercept is f(0)
- f(x)>0 is where the graph is above the x-axis
- f(x)<0 is where the graph is below the x-axis
Key Takeaways โ Part 4
- Read the y-intercept directly from the constant c
- X-intercepts come from factoring or the quadratic formula
- Axis of symmetry = midpoint of roots = โb/(2a)
- Opens up (a>0) โ vertex is minimum; opens down (a<0) โ vertex is maximum
- "f(x)>0" means "where is the graph above the x-axis?"
t
+
h0โ
- h0โ = initial height (y-intercept)
- v0โ = initial velocity
- โ16 accounts for gravity (in feet; use โ4.9 for meters)
"When does it hit the ground?" โ Set h(t)=0
"What is the maximum height?" โ Find the vertex
Area Problems
"The length of a rectangle is 3 more than its width. The area is 40. Find the dimensions."
Let width =w. Then w(w+3)=40 โ w2+3wโ40=0 โ (w+8)(wโ5)=0
Width =5 (reject โ8), length =8.
Revenue/Profit Problems
"A store sells 100 items at $20 each. For every $1 increase in price, 5 fewer items sell."
Revenue =(20+x)(100โ5x)=โ5x2+0x+2000
Maximum revenue at vertex: x=0/(2โ
(โ5))=0... meaning $20 is already optimal!
Quadratic Word Problems ๐ฏ
Key Takeaways โ Part 5
- Projectile: h(t)=โ16t2+v0โt+h0โ โ max height at vertex, hits ground at h=0
- Area problems: set up the equation, expand, solve (reject negative answers for dimensions)
- Revenue: R=(price)(quantity) โ max revenue at vertex of the quadratic
- Always re-read the question: "When does it hit the ground?" โ "What is the max height?"
x+
1
Set equal: x2+2xโ3=x+1 โ x2+xโ4=0
Solve for x, then plug back in for y.
Number of Intersections
The discriminant of the resulting equation tells you:
- ฮ>0: 2 intersection points
- ฮ=0: 1 point (line is tangent to parabola)
- ฮ<0: 0 points (no intersection)
Two Parabolas
Set them equal: x2+3x+1=2x2โx+4
Rearrange to get a quadratic in standard form, then solve.
SAT Tip ๐ก
The SAT often asks: "At which point(s) does the line y=c intersect y=x2โ4?"
This is just solving x2โ4=c โ x2=c+4 โ x=ยฑc+4โ
Two solutions when c>โ4, one when c=โ4, none when c<โ4.
Key Takeaways โ Part 6
- To find intersections: set the equations equal, solve the resulting quadratic
- The discriminant of the combined equation โ number of intersection points
- "Tangent" = exactly one intersection = discriminant equals zero
- y=c intersects y=x2+k: solve x2+k=c to find x values
a(xโr)(xโs)
| Vertex | a(xโh)2+k | Max/min, vertex |
Sum and Product of Roots
For ax2+bx+c=0 with roots r and s:
- Sum: r+s=โb/a
- Product: rโ
s=c/a
This saves time when the SAT asks for r+s or rs without asking for individual roots.
Hard SAT Pattern: Equivalent Forms
"Which is equivalent to 2x2+12x+7?"
Complete the square: 2(x2+6x)+7=2(x2+6x+9โ9)+7=2(x+3)2โ11
Hard SAT Pattern: Creating Equations
"A quadratic has roots 3 and โ5." โ y=(xโ3)(x+5)=x2+2xโ15
Key Takeaways โ Part 7
- Sum of roots =โb/a, Product of roots =c/a (Vieta's formulas)
- Know all three forms and when each is most useful
- Completing the square: factor out a first, then complete inside the parentheses
- To create a quadratic from roots: y=a(xโr)(xโs), find a from another point