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🎯⭐ INTERACTIVE LESSON

Linear Equations and Inequalities

Learn step-by-step with interactive practice!

Linear Equations and Inequalities - Complete Interactive Lesson

Part 1: Linear Equations Basics

Linear Equations & Inequalities

Part 1 of 7 — Slope-Intercept and Standard Form

The SAT Math section heavily tests your ability to work with linear equations. You'll see these in both calculator and no-calculator modules. Mastering the two main forms — and converting between them — is essential.

Slope-Intercept Form: y=mx+by = mx + b

  • mm = slope (rate of change)
  • bb = y-intercept (value when x=0x = 0)

Example: A phone plan charges $45/month plus $0.10 per text. If yy is the monthly cost and xx is the number of texts:

y=0.10x+45y = 0.10x + 45

Standard Form: Ax+By=CAx + By = C

  • Useful for finding intercepts quickly
  • x-intercept: set y=0y = 0 → x=C/Ax = C/A
  • y-intercept: set x=0x = 0 → y=C/By = C/B

Worked Example 1

Convert 5x+4y=205x + 4y = 20 to slope-intercept form and identify the intercepts.

StepWork
Isolate yy4y=−5x+204y = -5x + 20
Divide by 4y=−54x+5y = -\frac{5}{4}x + 5
Read slopem=−5/4m = -5/4
Read y-interceptb=5b = 5 → point (0,5)(0, 5)
Find x-interceptSet y=0y = 0: 5x=205x = 20 → x=4x = 4 → point (4,0)(4, 0)

Worked Example 2

A streaming service costs $12/month after a one-time $5 setup fee. Write the total cost CC after mm months and find the cost after 6 months.

StepWork
Identify slope$12/month → m=12m = 12
Identify y-intercept$5 setup → b=5b = 5
Write equationC=12m+5C = 12m + 5
Evaluate at m=6m = 6C=12(6)+5=77C = 12(6) + 5 = 77

SAT Trap ⚠️

When the SAT gives you standard form and asks for the slope, students often forget to isolate yy first. The slope is NOT just A/BA/B — it's −A/B-A/B.

Slope-Intercept & Standard Form 🎯

Point-Slope Form: y−y1=m(x−x1)y - y_1 = m(x - x_1)

This form is ideal when you know a point on the line and the slope.

Worked Example 3

Write the equation of a line through (2,7)(2, 7) with slope 33.

StepWork
Point-slope setupy−7=3(x−2)y - 7 = 3(x - 2)
Distributey−7=3x−6y - 7 = 3x - 6
Slope-intercepty=3x+1y = 3x + 1

Worked Example 4

A line passes through (−1,4)(-1, 4) and (3,−8)(3, -8). Find its equation in standard form.

StepWork
Find slopem=−8−43−(−1)=−124=−3m = \frac{-8 - 4}{3 - (-1)} = \frac{-12}{4} = -3
Point-slopey−4=−3(x+1)y - 4 = -3(x + 1)
Expandy=−3x−3+4=−3x+1y = -3x - 3 + 4 = -3x + 1
Standard form3x+y=13x + y = 1

Slope Formula Shortcut

m=y2−y1x2−x1=riserunm = \frac{y_2 - y_1}{x_2 - x_1} = \frac{\text{rise}}{\text{run}}

SAT Tip: When two points are given and the question asks for the equation, always compute the slope first.

Building Equations from Points 🎯

Identify the Form 🔍

For each equation, select the correct form it is written in.

Key Takeaways — Part 1

FormTemplateWhen to Use
Slope-intercepty=mx+by = mx + bKnow slope & y-intercept
StandardAx+By=CAx + By = CFinding intercepts; slope =−A/B= -A/B
Point-slopey−y1=m(x−x1)y - y_1 = m(x - x_1)Know a point & slope
  • Real-world problems: the rate = slope, the starting value = y-intercept
  • Always isolate yy before identifying the slope from standard form
  • The slope formula m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1} works with any two points on the line
  • On the SAT, check which form the answer choices use before you start solving

Part 2: Multi-Step Equations

Linear Equations & Inequalities

Part 2 of 7 — Systems of Linear Equations

Systems of equations appear on nearly every SAT. You need to be fast and flexible with solving methods.

Method 1: Substitution

Best when one variable is already isolated.

Example: y=2x+1y = 2x + 1 3x+y=113x + y = 11

Substitute: 3x+(2x+1)=113x + (2x + 1) = 11 → 5x=105x = 10 → x=2x = 2, y=5y = 5

Method 2: Elimination

Best when coefficients can be matched easily.

Example: 2x+3y=72x + 3y = 7 2x−y=32x - y = 3

Subtract: 4y=44y = 4 → y=1y = 1, x=2x = 2


Worked Example 1 — Deciding Which Method

Solve: 3x+4y=183x + 4y = 18 and x−2y=−1x - 2y = -1

StepWork
Check for isolated variableSecond eq: x=2y−1x = 2y - 1 ✓ → use substitution
Substitute into first3(2y−1)+4y=183(2y - 1) + 4y = 18
Simplify6y−3+4y=186y - 3 + 4y = 18 → 10y=2110y = 21
Solve for yyy=2.1y = 2.1
Back-substitutex=2(2.1)−1=3.2x = 2(2.1) - 1 = 3.2

Worked Example 2 — Elimination with Multiplication

Solve: 2x+5y=12x + 5y = 1 and 3x+2y=−43x + 2y = -4

StepWork
Make xx-coefficients matchMultiply eq 1 by 3, eq 2 by 2
New system6x+15y=36x + 15y = 3 and 6x+4y=−86x + 4y = -8
Subtract11y=1111y = 11 → y=1y = 1
Back-substitute2x+5(1)=12x + 5(1) = 1 → x=−2x = -2

Special Cases

ConditionResultLines
One solutionx=a,y=bx = a, y = bLines intersect
No solution0=k0 = k (contradiction)Lines are parallel
Infinite solutions0=00 = 0 (identity)Lines are the same

SAT Strategy 💡

If the SAT asks "For what value of kk does the system have no solution?" — make the slopes equal but the y-intercepts different. Parallel lines = no solution.

Systems of Equations — Solving 🎯

The "Combo" Shortcut

Sometimes the SAT asks for an expression like x+yx + y or 2x−y2x - y rather than individual values. You can often find these directly!

Worked Example 3

Given: 4x+3y=174x + 3y = 17 and 2x+3y=112x + 3y = 11. Find 2x2x.

StepWork
Subtract equations(4x+3y)−(2x+3y)=17−11(4x + 3y) - (2x + 3y) = 17 - 11
Simplify2x=62x = 6

No need to find xx and yy separately!

Worked Example 4

Given: x+2y=5x + 2y = 5 and 3x−2y=73x - 2y = 7. Find x+yx + y.

StepWork
Add equations4x=124x = 12 → x=3x = 3
Substitute3+2y=53 + 2y = 5 → y=1y = 1
Answerx+y=4x + y = 4

SAT Tip: Always check if the requested expression can be obtained by adding or subtracting the two equations before solving individually.

Systems — Harder Problems 🎯

Classify the System 🔍

For each system, determine the number of solutions.

Key Takeaways — Part 2

StrategyWhen to Use
SubstitutionOne variable is already isolated
EliminationCoefficients match or nearly match
Combo shortcutSAT asks for an expression, not individual values
  • No solution: same slope, different intercept (parallel lines)
  • Infinite solutions: same slope AND same intercept (same line)
  • One solution: different slopes (lines intersect)
  • Always read what the question asks — xx? yy? x+yx + y? 3x−2y3x - 2y?
  • If the answer choices are simple numbers, try back-solving

Part 3: Variables on Both Sides

Linear Equations & Inequalities

Part 3 of 7 — Linear Inequalities

The SAT tests inequalities in both algebraic and graphical form.

Solving Linear Inequalities

Same rules as equations EXCEPT: flip the inequality sign when multiplying or dividing by a negative.

Example: −3x+6>12-3x + 6 > 12 −3x>6-3x > 6 x<−2(flip!)x < -2 \quad \text{(flip!)}

Compound Inequalities

−1<2x+3≤9-1 < 2x + 3 \leq 9

Subtract 3 from all parts: −4<2x≤6-4 < 2x \leq 6

Divide by 2: −2<x≤3-2 < x \leq 3


Worked Example 1

Solve 5−2x≥135 - 2x \geq 13 and graph the solution.

StepWork
Subtract 5−2x≥8-2x \geq 8
Divide by −2-2 (FLIP!)x≤−4x \leq -4
GraphSolid dot at −4-4, shade left

Worked Example 2

Solve the compound inequality −7<3x+2≤14-7 < 3x + 2 \leq 14.

StepWork
Subtract 2 from all parts−9<3x≤12-9 < 3x \leq 12
Divide all by 3−3<x≤4-3 < x \leq 4
Meaningxx is between −3-3 (exclusive) and 44 (inclusive)

Graphing Inequalities

  • y>mx+by > mx + b: shade above the line, dashed boundary
  • y≤mx+by \leq mx + b: shade below the line, solid boundary
  • The solution to a system of inequalities is the overlap region

SAT Pattern ⚠️

The SAT loves: "Which point is in the solution set of y>2x−1y > 2x - 1 and y<−x+5y < -x + 5?" Plug each answer choice into BOTH inequalities and check.

Inequalities — Basics 🎯

Systems of Inequalities on the SAT

When two inequalities define a region, the SAT typically asks:

  • "Which point is in the solution region?"
  • "Which inequality represents the shaded region?"

Worked Example 3

A student needs at least 60 hours of study across two subjects. They spend xx hours on math and yy hours on science, with at most 40 hours on math. Write the system.

ConstraintInequality
Total at least 60x+y≥60x + y \geq 60
Math at most 40x≤40x \leq 40
Both non-negativex≥0,  y≥0x \geq 0,\; y \geq 0

Worked Example 4

From a graph: a dashed line through (0,4)(0, 4) with slope −2-2, shaded below. Write the inequality.

StepWork
Equation of liney=−2x+4y = -2x + 4
Dashed = strictUse << or >> (not ≤\leq or ≥\geq)
Shaded belowy<−2x+4y < -2x + 4

SAT Tip: Solid line = ≤\leq or ≥\geq. Dashed line = << or >>. Always check the line type before selecting!

Inequality Applications 🎯

Inequality Symbols 🔍

Match each phrase to the correct inequality symbol.

Key Takeaways — Part 3

RuleDetail
Flip when negativeMultiply/divide by a negative → reverse the inequality
CompoundOperate on all three parts simultaneously
Graphing: line typeDashed = strict (<<, >>), Solid = inclusive (≤\leq, ≥\geq)
Graphing: shadingAbove = >> or ≥\geq, Below = << or ≤\leq
System overlapSolution is where both shaded regions intersect
  • To check a point: plug into BOTH inequalities — both must be true
  • "At most" = ≤\leq, "at least" = ≥\geq, "more than" = >>, "fewer than" = <<
  • Compound inequalities preserve ≤\leq vs << when dividing by a positive

Part 4: Systems of Equations

Linear Equations & Inequalities

Part 4 of 7 — Parallel and Perpendicular Lines

These concepts appear frequently in SAT geometry-meets-algebra questions.

Parallel Lines

  • Same slope, different y-intercepts
  • y=3x+2y = 3x + 2 is parallel to y=3x−5y = 3x - 5

Perpendicular Lines

  • Slopes are negative reciprocals: m1⋅m2=−1m_1 \cdot m_2 = -1
  • y=2x+1y = 2x + 1 is perpendicular to y=−12x+4y = -\frac{1}{2}x + 4

Finding the Equation of a Line

Given a point (x1,y1)(x_1, y_1) and slope mm:

y−y1=m(x−x1)(point-slope form)y - y_1 = m(x - x_1) \quad \text{(point-slope form)}


Worked Example 1

Find the line parallel to y=−4x+9y = -4x + 9 through the point (2,5)(2, 5).

StepWork
Same slopem=−4m = -4
Point-slopey−5=−4(x−2)y - 5 = -4(x - 2)
Simplifyy=−4x+8+5=−4x+13y = -4x + 8 + 5 = -4x + 13
Check−4(2)+13=5-4(2) + 13 = 5 ✓, and the y-intercept 13≠913 \neq 9, so the lines are distinct and parallel

Worked Example 2

Find the line perpendicular to y=3x+1y = 3x + 1 passing through (6,2)(6, 2).

StepWork
Original slopem=3m = 3
Perpendicular slopem⊥=−1/3m_{\perp} = -1/3
Point-slopey−2=−13(x−6)y - 2 = -\frac{1}{3}(x - 6)
Simplifyy=−13x+4y = -\frac{1}{3}x + 4

Midpoint and Distance

  • Midpoint: (x1+x22, y1+y22)\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}\right)
  • Distance: d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Parallel & Perpendicular — Basics 🎯

Perpendicular Bisectors

A perpendicular bisector of a segment passes through its midpoint at a right angle. This combines midpoint, perpendicular slope, and point-slope concepts.

Worked Example 3

Find the perpendicular bisector of the segment from A(1,3)A(1, 3) to B(5,7)B(5, 7).

StepWork
MidpointM=((1+5)/2, (3+7)/2)=(3,5)M = ((1+5)/2,\, (3+7)/2) = (3, 5)
Slope of AB‾\overline{AB}m=(7−3)/(5−1)=1m = (7-3)/(5-1) = 1
Perpendicular slopem⊥=−1m_{\perp} = -1
Equationy−5=−1(x−3)y - 5 = -1(x - 3) → y=−x+8y = -x + 8

Worked Example 4

The line 3x−6y=123x - 6y = 12 is parallel to kx+4y=8kx + 4y = 8. Find kk.

StepWork
Slope of first−6y=−3x+12-6y = -3x + 12 → y=12x−2y = \frac{1}{2}x - 2 → m1=1/2m_1 = 1/2
Slope of second4y=−kx+84y = -kx + 8 → y=−k4x+2y = -\frac{k}{4}x + 2 → m2=−k/4m_2 = -k/4
Set equal1/2=−k/41/2 = -k/4 → k=−2k = -2

SAT Tip: When comparing slopes from standard form, convert BOTH to slope-intercept. Don't try to compare standard form coefficients directly.

Parallel & Perpendicular — Harder Problems 🎯

Classify Line Relationships 🔍

For each pair of lines, determine their relationship.

Key Takeaways — Part 4

RelationshipSlope ConditionExample
Parallelm1=m2m_1 = m_2y=3x+1y = 3x + 1 ∥ y=3x−5y = 3x - 5
Perpendicularm1⋅m2=−1m_1 \cdot m_2 = -1y=2xy = 2x ⊥ y=−12xy = -\frac{1}{2}x
NeitherSlopes differ but product ≠−1\neq -1y=2xy = 2x and y=3xy = 3x
  • Point-slope form is your friend: y−y1=m(x−x1)y - y_1 = m(x - x_1)
  • Always convert standard form to slope-intercept before comparing slopes
  • Midpoint =(x1+x22,y1+y22)= \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)
  • Distance =(Δx)2+(Δy)2= \sqrt{(\Delta x)^2 + (\Delta y)^2}

Part 5: Modeling with Equations

Linear Equations & Inequalities

Part 5 of 7 — Word Problems with Linear Models

The SAT tests whether you can translate real-world scenarios into linear equations.

Setting Up Linear Models

  1. Identify the variables — what's changing? What's being measured?
  2. Find the rate (slope) — the per-unit change
  3. Find the starting value (y-intercept) — the initial amount

Common SAT Word Problem Types

Type 1 — Cost/Revenue: A rideshare charges $3 base + $1.50/mile. Total cost for mm miles: C=1.50m+3C = 1.50m + 3

Type 2 — Distance/Rate/Time: Two trains leave at the same time. Train A: 60 mph. Train B: 80 mph. If B starts 30 miles behind, when does B catch A? 80t=60t+3080t = 60t + 30 → 20t=3020t = 30 → t=1.5t = 1.5 hours

Type 3 — "Already...and then...": A pool has 200 gallons and is being filled at 15 gallons/minute. After tt minutes: V=15t+200V = 15t + 200


Worked Example 1

A cellphone company charges $40/month for a plan plus $0.05 per text message. Another company charges $25/month plus $0.15 per text. How many texts make the costs equal?

StepWork
Company A costCA=0.05t+40C_A = 0.05t + 40
Company B costCB=0.15t+25C_B = 0.15t + 25
Set equal0.05t+40=0.15t+250.05t + 40 = 0.15t + 25
Solve15=0.10t15 = 0.10t → t=150t = 150 texts
VerifyCA=0.05(150)+40=47.50C_A = 0.05(150) + 40 = 47.50 ✓

Reading Tables on the SAT

When given a table, calculate slope: m=ΔyΔxm = \frac{\Delta y}{\Delta x} using any two rows. Then find bb by plugging in one point.

Word Problems — Setup 🎯

Interpreting Slope and Y-Intercept in Context

The SAT frequently asks questions like:

  • "What does the slope represent in this context?"
  • "What is the meaning of the y-intercept?"

Worked Example 2

The equation C=0.12m+35C = 0.12m + 35 models a monthly phone bill, where CC is the cost in dollars and mm is the number of minutes used.

ComponentValueReal-World Meaning
Slope0.120.12Each additional minute costs $0.12
Y-intercept3535The base cost with zero minutes is $35
C(100)C(100)4747Using 100 minutes costs $47

Worked Example 3

From a table:

Hours Worked (xx)Pay (yy)
005050
44110110
88170170
StepWork
Slope(110−50)/(4−0)=60/4=15(110 - 50)/(4 - 0) = 60/4 = 15
Y-intercept5050 (from the table directly)
Equationy=15x+50y = 15x + 50
Interpretation$15/hour wage with a $50 signing bonus

SAT Tip: The SAT may phrase slope interpretation as "For every increase of 1 in xx, yy increases/decreases by ___." The answer is the slope.

Interpreting Models 🎯

Identify the Slope 🔍

For each scenario, select the correct slope value.

Key Takeaways — Part 5

ConceptHow to Find It
Slope from contextRate per unit ($/hour, miles/gallon, etc.)
Y-intercept from contextStarting value, initial amount, base cost
Slope from tableΔy/Δx\Delta y / \Delta x using any two rows
"When are they equal?"Set the two expressions equal
  • "Draining/decreasing" = negative slope; "filling/increasing" = positive slope
  • From a table: slope =Δy/Δx= \Delta y / \Delta x, then plug in a point for bb
  • Slope interpretation: "For every 1-unit increase in xx, yy changes by mm"
  • Check your model: plug a known data point back in to verify

Part 6: Problem-Solving Workshop

Linear Equations & Inequalities

Part 6 of 7 — Absolute Value and Literal Equations

Absolute Value Equations

∣ax+b∣=c|ax + b| = c splits into two cases (when c≥0c \geq 0):

ax+b=corax+b=−cax + b = c \quad \text{or} \quad ax + b = -c

Example: ∣2x−3∣=7|2x - 3| = 7

  • Case 1: 2x−3=72x - 3 = 7 → x=5x = 5
  • Case 2: 2x−3=−72x - 3 = -7 → x=−2x = -2

⚠️ If ∣ax+b∣=−k|ax + b| = -k where k>0k > 0: no solution (absolute value is never negative).

Absolute Value Inequalities

  • ∣x∣<a|x| < a: −a<x<a-a < x < a (AND — between)
  • ∣x∣>a|x| > a: x<−ax < -a or x>ax > a (OR — outside)

Worked Example 1

Solve ∣4x+1∣=11|4x + 1| = 11.

StepWork
Case 14x+1=114x + 1 = 11 → 4x=104x = 10 → x=5/2x = 5/2
Case 24x+1=−114x + 1 = -11 → 4x=−124x = -12 → x=−3x = -3
Solutionsx=5/2x = 5/2 or x=−3x = -3
Verify$

Worked Example 2

Solve ∣x−5∣≤3|x - 5| \leq 3.

StepWork
Set up compound−3≤x−5≤3-3 \leq x - 5 \leq 3
Add 52≤x≤82 \leq x \leq 8
In interval form[2,8][2, 8]

Absolute Value 🎯

Literal Equations (Solving for a Variable)

The SAT often asks you to rearrange a formula. Treat every other variable as a number.

Worked Example 3

Solve A=12bhA = \frac{1}{2}bh for hh.

StepWork
Multiply by 22A=bh2A = bh
Divide by bbh=2Abh = \frac{2A}{b}

Worked Example 4

Solve 1R=1R1+1R2\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} for RR.

StepWork
Common denominator1R=R2+R1R1R2\frac{1}{R} = \frac{R_2 + R_1}{R_1 R_2}
ReciprocalR=R1R2R1+R2R = \frac{R_1 R_2}{R_1 + R_2}

Worked Example 5

Solve F=95C+32F = \frac{9}{5}C + 32 for CC.

StepWork
Subtract 32F−32=95CF - 32 = \frac{9}{5}C
Multiply by 59\frac{5}{9}C=5(F−32)9C = \frac{5(F - 32)}{9}

SAT Strategy 💡: For literal equations, treat every other variable as a number. The solving process is identical — just letters instead of digits.

Literal Equations 🎯

Absolute Value Solutions 🔍

For each equation/inequality, select the number of solutions.

Key Takeaways — Part 6

Absolute Value ScenarioSetupSolution Type
$expr= c$ (c > 0)
$expr= 0$
$expr= -c$ (c > 0)
$expr< c$
$expr> c$
  • Literal equations: isolate the target variable using normal algebra steps
  • Treat all other variables as constants when solving for one variable
  • Always verify absolute value solutions by plugging back in

Part 7: Review & Applications

Linear Equations & Inequalities

Part 7 of 7 — SAT Mixed Practice & Review

Quick Reference

ConceptFormula/Rule
Slope-intercepty=mx+by = mx + b
Standard formAx+By=CAx + By = C, slope =−A/B= -A/B
Point-slopey−y1=m(x−x1)y - y_1 = m(x - x_1)
Slope formulam=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}
ParallelSame slope
Perpendicularm1⋅m2=−1m_1 \cdot m_2 = -1
System: no solutionSame slope, different intercepts
System: ∞ solutionsIdentical equations
Absolute value$
Literal equationsIsolate — treat others as constants

Common SAT Mistakes to Avoid

  1. Forgetting to flip the inequality sign when dividing by a negative
  2. Misreading what the question asks — "What is x+yx + y?" vs "What is xx?"
  3. Not checking answer choices by plugging back in
  4. Rushing standard form → slope conversion (slope is −A/B-A/B, not A/BA/B)
  5. Absolute value = negative → instant "no solution"

Time-Saving Strategies

  • Back-solve from answer choices — plug in each option when algebra is messy
  • Pick smart numbers — if the problem has fractions, choose a common denominator
  • Look for shortcuts — many system problems can be solved by adding/subtracting the equations directly
  • Estimate first — eliminate obviously wrong answers before computing

Mixed Review — Round 1 🎯

SAT-Style Hard Problems: Worked Solutions

Worked Example 1

The function f(x)=3x+kf(x) = 3x + k passes through the point where g(x)=−x+8g(x) = -x + 8 crosses the x-axis. Find kk.

StepWork
Find x-intercept of gg0=−x+80 = -x + 8 → x=8x = 8 → point (8,0)(8, 0)
Plug into ff0=3(8)+k0 = 3(8) + k → k=−24k = -24

Worked Example 2

In the xyxy-plane, line ℓ\ell passes through the origin and is perpendicular to 5x+2y=105x + 2y = 10. Which point is on line ℓ\ell?

StepWork
Slope of given liney=−52x+5y = -\frac{5}{2}x + 5 → m=−5/2m = -5/2
Perpendicular slopem⊥=2/5m_{\perp} = 2/5
Line through originy=25xy = \frac{2}{5}x
Check pointsAny point (a,2a/5)(a, 2a/5) works, e.g., (5,2)(5, 2)

Worked Example 3

If ∣2x−1∣+3=10|2x - 1| + 3 = 10, what is the product of the possible values of xx?

StepWork
Isolate absolute value$
Case 12x−1=72x - 1 = 7 → x=4x = 4
Case 22x−1=−72x - 1 = -7 → x=−3x = -3
Product4×(−3)=−124 \times (-3) = -12

Mixed Review — Round 2 (Hard) 🎯

Speed Round: What Strategy? 🔍

For each problem type, select the fastest solving approach.

Key Takeaways — Part 7 (Full Topic Review)

TopicCore SkillCommon Trap
Forms of linesConvert fluentlySlope from standard form is −A/B-A/B
SystemsChoose sub vs. elimRead what they ask (xx? yy? x+yx+y?)
InequalitiesFlip on × or ÷ by negative"At most" = ≤\leq, "at least" = ≥\geq
Parallel/PerpCompare slopesPerpendicular: m1⋅m2=−1m_1 \cdot m_2 = -1
Word problemsSlope = rate, bb = startDecreasing = negative slope
Absolute valueSplit into two cases$
Literal equationsIsolate target variableTreat other letters as numbers

Final SAT Strategies:

  • Back-solve from answer choices is your best friend on hard problems
  • Estimate to eliminate obviously wrong answers
  • Have your approach ready in the first 5 seconds — don't stare