Complex Numbers on the SAT - Complete Interactive Lesson
Part 1: Imaginary Unit
📝 Complex Numbers
Part 1 of 7 — Imaginary Numbers
i = √(-1), so i² = -1.
√(-a) = i√a for a > 0.
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Key Insight: Complex number: a + bi where a is real part, b is imaginary part.
SAT Tip: Pure imaginary: bi (when a = 0); real: a (when b = 0).
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Part 2: Complex Arithmetic
Complex Number Operations
Part 2 of 7 — Complex Number Operations
Add/subtract: combine real parts and imaginary parts separately.
(a + bi) + (c + di) = (a+c) + (b+d)i.
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Key Insight: Multiply using FOIL: (a + bi)(c + di) = ac + adi + bci + bdi² = (ac - bd) + (ad + bc)i.
SAT Tip: Remember: i² = -1, so replace i² with -1.
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Part 3: Complex Conjugates
Complex Number Applications
Part 3 of 7 — Complex Number Applications
Complex solutions come in conjugate pairs: a + bi and a - bi.
If the discriminant b² - 4ac < 0, the quadratic has complex roots.
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Key Insight: x = (-b ± i√(4ac - b²)) / (2a).
SAT Tip: Every polynomial of degree n has exactly n roots (counting complex and repeated).
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Part 4: Quadratics & Complex Roots
Powers of i
Part 4 of 7 — Powers of i
i¹ = i, i² = -1, i³ = -i, i⁴ = 1, then the pattern repeats.
To find iⁿ: divide n by 4, use the remainder.
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Key Insight: Remainder 0 → 1, remainder 1 → i, remainder 2 → -1, remainder 3 → -i.
SAT Tip: Example: i²³ → 23 ÷ 4 = 5 remainder 3 → i²³ = -i.
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Part 5: Powers of i
Complex Conjugates
Part 5 of 7 — Complex Conjugates
Conjugate of a + bi is a - bi.
(a + bi)(a - bi) = a² + b² (always real and positive).
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Key Insight: Use conjugates to divide complex numbers: multiply numerator and denominator by the conjugate of the denominator.
SAT Tip: Rationalizing: (3 + 2i)/(1 - i) × (1 + i)/(1 + i).
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Part 6: Problem-Solving Workshop
Problem-Solving Workshop
Part 6 of 7 — Problem-Solving Workshop
Conjugate of a + bi is a - bi.
(a + bi)(a - bi) = a² + b² (always real and positive).
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Key Insight: Use conjugates to divide complex numbers: multiply numerator and denominator by the conjugate of the denominator.
SAT Tip: Rationalizing: (3 + 2i)/(1 - i) × (1 + i)/(1 + i).
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Part 7: Review & Applications
Review & Applications
Part 7 of 7 — Review & Applications
Conjugate of a + bi is a - bi.
(a + bi)(a - bi) = a² + b² (always real and positive).
Check Your Understanding 🎯
Key Insight: Use conjugates to divide complex numbers: multiply numerator and denominator by the conjugate of the denominator.
SAT Tip: Rationalizing: (3 + 2i)/(1 - i) × (1 + i)/(1 + i).
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Match the Concepts 🔍