Rational Functions and Their Graphs

Analyze rational functions including asymptotes, holes, and intercepts.

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Rational Functions and Their Graphs

Rational Functions

f(x)=P(x)Q(x)f(x) = \frac{P(x)}{Q(x)}

where P(x)P(x) and Q(x)Q(x) are polynomials, Q(x)0Q(x) \neq 0.

Domain

Exclude values where the denominator equals zero.

f(x)=x+1x24=x+1(x2)(x+2)f(x) = \frac{x+1}{x^2 - 4} = \frac{x+1}{(x-2)(x+2)}

Domain: x2x \neq 2 and x2x \neq -2

Vertical Asymptotes

Occur where denominator =0= 0 (after canceling common factors).

f(x)=x+1(x2)(x+2)f(x) = \frac{x+1}{(x-2)(x+2)}

Vertical asymptotes: x=2x = 2 and x=2x = -2

Horizontal Asymptotes

Compare degrees of numerator (nn) and denominator (mm):

| Condition | Horizontal Asymptote | |-----------|---------------------| | n<mn < m | y=0y = 0 | | n=mn = m | y=anbmy = \frac{a_n}{b_m} | | n>mn > m | None (oblique asymptote) |

Holes

A hole occurs when a factor cancels from both numerator and denominator.

f(x)=(x3)(x+1)(x3)(x+2)f(x) = \frac{(x-3)(x+1)}{(x-3)(x+2)}

Hole at x=3x = 3. To find the yy-coordinate: f(3)=3+13+2=45f(3) = \frac{3+1}{3+2} = \frac{4}{5}

Hole at (3,45)\left(3, \frac{4}{5}\right)

Oblique (Slant) Asymptotes

When degree of numerator = degree of denominator + 1, divide:

f(x)=x2+2x+1x1f(x) = \frac{x^2 + 2x + 1}{x - 1}

Long division gives: y=x+3y = x + 3 (oblique asymptote)

Graphing Steps

  1. Factor numerator and denominator
  2. Find holes (cancel common factors)
  3. Find x-intercepts (numerator = 0)
  4. Find y-intercept (f(0)f(0))
  5. Find vertical asymptotes (remaining denominator = 0)
  6. Find horizontal/oblique asymptote
  7. Plot additional points as needed

Important: A graph can cross a horizontal asymptote in the middle but approaches it as x±x \to \pm\infty. It can NEVER cross a vertical asymptote.

📚 Practice Problems

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