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🎯⭐ INTERACTIVE LESSON

AP Precalculus Exam Review

Learn step-by-step with interactive practice!

AP Precalculus Exam Review - Complete Interactive Lesson

Part 1: Exam Format, Pacing and the Calculator Split

🎓 AP Precalculus Exam Review

Part 1 of 7 — Exam Format, Pacing and the Calculator Split

Topic Overview

PartReview Topic
1Exam Format, Pacing and the Calculator Split
2Unit 1: Rates of Change and Polynomial Functions
3Unit 1: Rational Functions, Transformations and Models
4Unit 2: Sequences, Exponential and Logarithmic Functions
5Unit 3: Trigonometric Functions and Sinusoidal Models
6Unit 3: Inverse Trigonometry, Equations, Identities and Polar Functions
7Final Mixed Set: Part A and Part B Practice

The 2027 AP Precalculus Exam

SectionPartQuestionsTimeCalculatorPace
I: Multiple Choice (62.5%)A2965 minnoneabout 2 min 15 s per question
I: Multiple ChoiceB1340 mingraphing calculatorabout 3 min per question
II: Free Response (37.5%)AQ1, Q235 mingraphing calculatorFunction Concepts; Non-Periodic Modeling
II: Free ResponseBQ3, Q435 minnonePeriodic Modeling; Symbolic Manipulations

Every multiple-choice question has four choices and there is no penalty for a wrong answer: answer every question.

What Is Tested

UnitContentApproximate weight
1Polynomial and Rational Functions (rates of change, polynomials, rational functions, transformations, modeling)about 35%
2Exponential and Logarithmic Functions (sequences, exponential and log functions, composition and inverses, data modeling, semi-log plots)about 32%
3Trigonometric and Polar Functions (trig functions and graphs, sinusoidal models, inverses, equations, identities, polar coordinates)about 33%
4Parameters, vectors, matricesnot assessed

The three assessed units carry roughly equal weight. There is no safe unit to skip.

The Calculator Split

Without a calculator (Part A, Q3, Q4)With a graphing calculator (Part B, Q1, Q2)
unit-circle values: cos⁡5π6=−32\cos\frac{5\pi}{6} = -\frac{\sqrt{3}}{2}regression: linear, quadratic, cubic, exponential, logarithmic, sinusoidal
log properties and exact solving: log⁡2x+log⁡2(x−2)=3\log_2 x + \log_2(x - 2) = 3numeric solving: where does the model equal 5050?
factoring, identities, equivalent formsevaluating ln⁡7\ln 7, sin⁡2.3\sin 2.3, 1.29991.299^{9}
end behavior and asymptotes with limit notationgraphing to count solutions or find extrema
reading tables and graphs for rates of changefinding residuals and comparing models

Key Fact: Part A is the long part: 29 questions in 65 minutes. Two passes beat one slow pass: answer what you know, mark what you don't, come back.

Format check. 🎯

Test-day rules. 🔽

Key Takeaways — Part 1

  • Section I: 29 questions in 65 min without a calculator, then 13 in 40 min with one; Section II: Q1–Q2 with a calculator, Q3–Q4 without, 35 min each
  • Units 1, 2, 3 are about 35 / 32 / 33%; Unit 4 is not assessed
  • Four choices, no penalty: answer everything, two passes through Part A
  • Know which skills are exact, by hand and which are calculator skills

Part 2: Unit 1: Rates of Change and Polynomial Functions

🎓 AP Precalculus Exam Review

Part 2 of 7 — Unit 1: Rates of Change and Polynomial Functions

Exam Weight: Unit 1 is about 35% of the exam. This part covers CED 1.1–1.6 and 1.10; Part 3 covers 1.7–1.9 and 1.11–1.14.

Rates of Change (1.1–1.4)

IdeaWhat to compute or say
Average rate of change on [a,b][a, b]f(b)−f(a)b−a\dfrac{f(b) - f(a)}{b - a}: slope of the secant line, with units
Linear functionrate of change is constant (first differences equal)
Quadratic functionrate of change changes at a constant rate (second differences equal)
Increasing / decreasingsign of the rate of change on the interval
Concave up / downthe rate of change is increasing / decreasing
Point of inflectionwhere concavity changes
From a tablecompare successive average rates of change on equal-width intervals

Polynomial Functions (1.5–1.6, 1.10)

FactDetail
Degree nnat most nn real zeros; at most n−1n - 1 local extrema; nnth differences constant for equally spaced inputs
End behaviordecided by the leading term anxna_nx^n: even degree, same direction both ways (++ if an>0a_n > 0); odd degree, opposite directions
Zero of multiplicity mmodd mm: graph crosses; even mm: graph touches and turns; m≥2m \ge 2: the graph flattens there
Between consecutive zerosexactly one local extremum when the zeros are simple; a local maximum or minimum occurs where the function changes from increasing to decreasing or back
Non-real zeroscome in conjugate pairs when the coefficients are real; a degree-nn polynomial has nn complex zeros counted with multiplicity
Even / odd functionf(−x)=f(x)f(-x) = f(x): symmetric about the yy-axis; f(−x)=−f(x)f(-x) = -f(x): symmetric about the origin
Global vs locala polynomial of even degree has a global maximum or minimum; odd degree has neither

Key Fact: "The rate of change is decreasing" does not mean the function is decreasing. f(x)=xf(x) = \sqrt{x} increases while its rate of change decreases.

Unit 1 practice (no calculator). 🎯

Quick computations. ✍️

1) The average rate of change of f(x)=x3f(x) = x^3 on the interval [1,2][1, 2]:

2) For equally spaced inputs, a table of values has constant third differences (and non-constant second differences). The degree of the polynomial:

3) The number of distinct real zeros of p(x)=(x2+1)(x−2)(x+5)p(x) = (x^2 + 1)(x - 2)(x + 5):

Key Takeaways — Part 2

  • Average rate of change =ΔyΔx= \frac{\Delta y}{\Delta x} with units; constant first differences mean linear, constant second differences mean quadratic
  • Increasing/decreasing is about the function; concave up/down is about its rate of change
  • End behavior comes from the leading term; multiplicity decides cross (odd) or touch (even)
  • Non-real zeros come in conjugate pairs; a degree-nn polynomial has at most nn real zeros and n−1n - 1 local extrema

Part 3: Unit 1: Rational Functions, Transformations and Models

🎓 AP Precalculus Exam Review

Part 3 of 7 — Unit 1: Rational Functions, Transformations and Models

Rational Functions (1.7–1.9, 1.11)

FeatureHow to find itHow to state it
Vertical asymptote x=ax = adenominator zero and numerator nonzero at aa (after cancelling common factors)lim⁡x→a+r(x)=±∞\lim_{x \to a^+} r(x) = \pm\infty
Hole at x=ax = aa factor (x−a)(x - a) common to numerator and denominatorlim⁡x→ar(x)=\lim_{x \to a} r(x) = the cancelled function's value at aa
Horizontal asymptotedegree top << bottom: y=0y = 0; equal: ratio of leading coefficients; top >> bottom: nonelim⁡x→±∞r(x)=c\lim_{x \to \pm\infty} r(x) = c
Slant asymptotedegree top == degree bottom +1+ 1: the quotient from polynomial long divisionr(x)≈mx+br(x) \approx mx + b for large ∣x∣\lvert x \rvert
Zeroszeros of the numerator that are not holesxx-intercepts
Rational inequalitysign chart over the zeros and the undefined points; never multiply by a denominator of unknown signinterval notation, excluding undefined points

Transformations (1.12)

FormEffect on the graph of ff
f(x)+kf(x) + kshift up kk
f(x−h)f(x - h)shift right hh
a f(x)a\,f(x)vertical stretch by ∣a∣\lvert a \rvert; reflect over the xx-axis if a<0a < 0
f(bx)f(bx)horizontal compression by 1∣b∣\dfrac{1}{\lvert b \rvert}; reflect over the yy-axis if b<0b < 0
Orderinside changes act on inputs (horizontal), outside changes act on outputs (vertical); apply stretches and reflections before shifts

Choosing a Model (1.13–1.14)

Signal in the data or contextModel
constant first differences, constant ratelinear
constant second differences, one turning pointquadratic
two turning points, a point of inflectioncubic
a limiting value as the input growsrational (horizontal asymptote), or exponential approaching a horizontal asymptote
the rule changes at certain inputs (fees, tax brackets, speed limits)piecewise-defined
domain restricted by the contextstate the domain with the model: lengths positive, counts whole numbers

Key Fact: For a hole, cancel first, then evaluate: r(x)=(x−2)(x+2)(x−2)(x+1)r(x) = \dfrac{(x - 2)(x + 2)}{(x - 2)(x + 1)} has a hole at (2,43)\left(2, \dfrac{4}{3}\right) and a vertical asymptote only at x=−1x = -1.

Unit 1 practice (no calculator). 🎯 Questions 1 and 2 use the graph above.

Choosing a model. 🔽

Key Takeaways — Part 3

  • Cancel common factors first: a cancelled factor is a hole, a remaining denominator zero is a vertical asymptote
  • Horizontal asymptotes come from comparing degrees; state every asymptote with limit notation
  • Inside changes are horizontal (f(bx)f(bx) compresses by 1∣b∣\frac{1}{\lvert b \rvert}, f(x−h)f(x - h) shifts right); outside changes are vertical
  • Model choice follows differences, turning points, limiting values and rule changes; state the domain in context

Part 4: Unit 2: Sequences, Exponential and Logarithmic Functions

🎓 AP Precalculus Exam Review

Part 4 of 7 — Unit 2: Sequences, Exponential and Logarithmic Functions

Exam Weight: Unit 2 is about 32% of the exam (CED 2.1–2.15).

Sequences (2.1–2.2)

TypeRuleFunction it matches
Arithmetic, common difference ddan=ak+d(n−k)a_n = a_k + d(n - k)linear: constant rate of change
Geometric, common ratio rrgn=gk⋅r n−kg_n = g_k \cdot r^{\,n - k}exponential: constant ratio

Exponential Functions (2.3–2.6)

FactDetail
f(x)=a⋅bxf(x) = a \cdot b^xa=f(0)a = f(0); bb is the ratio of outputs for a unit increase in xx; growth if b>1b > 1, decay if 0<b<10 < b < 1
Percent changeb=1+rb = 1 + r: a base of 1.2991.299 is a 29.9%29.9\% increase per unit; 0.850.85 is a 15%15\% decrease
From two points (x1,y1),(x2,y2)(x_1, y_1), (x_2, y_2)b=(y2y1)1/(x2−x1)b = \left(\dfrac{y_2}{y_1}\right)^{1/(x_2 - x_1)}, then solve for aa
Horizontal asymptotey=0y = 0 for a⋅bxa \cdot b^x; y=ky = k for a⋅bx+ka \cdot b^x + k; stated with lim⁡x→−∞\lim_{x \to -\infty} (growth) or lim⁡x→∞\lim_{x \to \infty} (decay)
Equivalent formsa⋅bx=a⋅(b1/k)kxa \cdot b^{x} = a \cdot \left(b^{1/k}\right)^{kx}, so 8x/3=2x8^{x/3} = 2^x and (1.06)x(1.06)^{x} is (1.0612)x/12(1.06^{12})^{x/12} per year of months
Always concave upthe rate of change of a⋅bxa \cdot b^x (a>0a > 0) is increasing whether the function grows or decays

Composition and Inverses (2.7–2.8)

FactDetail
(f∘g)(x)=f(g(x))(f \circ g)(x) = f(g(x))evaluate the inside function first; the domain needs xx in the domain of gg and g(x)g(x) in the domain of ff
Inverseswaps inputs and outputs: f(a)=b  ⟺  f−1(b)=af(a) = b \iff f^{-1}(b) = a; graph reflects over y=xy = x; domain and range swap
Exists whenff is one-to-one (strictly increasing or strictly decreasing suffices)
Exponential and loglog⁡bx\log_b x is the inverse of bxb^x: blog⁡bx=xb^{\log_b x} = x and log⁡b(bx)=x\log_b(b^x) = x

Logarithmic Functions (2.9–2.13)

FactDetail
Definitionlog⁡bx=y  ⟺  by=x\log_b x = y \iff b^y = x (b>0b > 0, b≠1b \ne 1, x>0x > 0)
Propertieslog⁡b(MN)=log⁡bM+log⁡bN\log_b(MN) = \log_b M + \log_b N; log⁡bMN=log⁡bM−log⁡bN\log_b\dfrac{M}{N} = \log_b M - \log_b N; log⁡bMp=plog⁡bM\log_b M^p = p\log_b M
Change of baselog⁡bx=ln⁡xln⁡b\log_b x = \dfrac{\ln x}{\ln b}
Graphdomain x>0x > 0, vertical asymptote x=0x = 0 (lim⁡x→0+log⁡bx=−∞\lim_{x \to 0^+} \log_b x = -\infty for b>1b > 1), increasing and concave down, no horizontal asymptote
Solvingisolate the exponential or the log, convert, then check the domain

Data Modeling and Semi-log Plots (2.14–2.15)

FactDetail
Residualactual −- predicted; a pattern in the residual plot means the model type is wrong
Semi-log plotlog⁡y\log y against xx: exponential data looks linear; slope =log⁡b= \log b, intercept =log⁡a= \log a
Log modely=a+bln⁡xy = a + b\ln x: outputs change by equal amounts when the input is multiplied by a constant factor

Key Fact: "Proportional growth" (equal ratios over equal input steps) is the test for an exponential model, exactly as "equal differences" is the test for a linear one.

Unit 2 practice (no calculator). 🎯

Quick computations. ✍️

1) log⁡381\log_3 81:

2) The solution of 2x=202^x = 20, to three decimal places (calculator):

3) In an arithmetic sequence with a1=7a_1 = 7 and common difference 44, the value of a10a_{10}:

Key Takeaways — Part 4

  • Arithmetic ↔\leftrightarrow linear (constant difference); geometric ↔\leftrightarrow exponential (constant ratio)
  • f(x)=a⋅bxf(x) = a \cdot b^x: a=f(0)a = f(0), b=1+rb = 1 + r; find bb from two points with (y2y1)1/(x2−x1)\left(\frac{y_2}{y_1}\right)^{1/(x_2 - x_1)}
  • Inverses swap inputs and outputs; log⁡bx\log_b x undoes bxb^x; check the domain after solving a log equation
  • A linear semi-log plot means exponential data; a patterned residual plot means the wrong model type

Part 5: Unit 3: Trigonometric Functions and Sinusoidal Models

🎓 AP Precalculus Exam Review

Part 5 of 7 — Unit 3: Trigonometric Functions and Sinusoidal Models

Exam Weight: Unit 3 is about 33% of the exam. This part covers CED 3.1–3.8; Part 6 covers 3.9–3.15.

Angles and the Unit Circle (3.1–3.3)

FactDetail
Radian measureθ=sr\theta = \dfrac{s}{r}; arc length s=rθs = r\theta; π\pi radians =180∘= 180^\circ
Coterminal anglesdiffer by multiples of 2π2\pi
On the unit circlethe point at angle θ\theta is (cos⁡θ,sin⁡θ)(\cos\theta, \sin\theta); tan⁡θ=sin⁡θcos⁡θ\tan\theta = \dfrac{\sin\theta}{\cos\theta} is the slope of the terminal ray
Special valuessin⁡π6=12\sin\frac{\pi}{6} = \frac{1}{2}, sin⁡π4=22\sin\frac{\pi}{4} = \frac{\sqrt{2}}{2}, sin⁡π3=32\sin\frac{\pi}{3} = \frac{\sqrt{3}}{2}; cosine reverses the order
Signs by quadrantI: all positive; II: sine; III: tangent; IV: cosine
Reference anglethe acute angle to the xx-axis; the same value with the quadrant's sign

Sine, Cosine and Tangent as Functions (3.4, 3.8)

FunctionPeriodDomainRangeKey features
sin⁡x\sin x2π2\piall reals[−1,1][-1, 1]odd; zeros at kπk\pi; max 11 at π2+2kπ\frac{\pi}{2} + 2k\pi
cos⁡x\cos x2π2\piall reals[−1,1][-1, 1]even; zeros at π2+kπ\frac{\pi}{2} + k\pi; max 11 at 2kπ2k\pi
tan⁡x\tan xπ\pix≠π2+kπx \ne \frac{\pi}{2} + k\piall realsodd; vertical asymptotes where cos⁡x=0\cos x = 0; always increasing between asymptotes

Sinusoidal Functions (3.5–3.7)

For f(x)=asin⁡(b(x+c))+df(x) = a\sin\big(b(x + c)\big) + d (or with cosine):

FeatureFormula
Amplitude∣a∣=max⁡−min⁡2\lvert a \rvert = \dfrac{\max - \min}{2}
Midliney=d=max⁡+min⁡2y = d = \dfrac{\max + \min}{2}
Period2π∣b∣\dfrac{2\pi}{\lvert b \rvert}, so b=2πperiodb = \dfrac{2\pi}{\text{period}}
Frequency1period=∣b∣2π\dfrac{1}{\text{period}} = \dfrac{\lvert b \rvert}{2\pi} cycles per unit
Phase shift−c-c (the graph of sin⁡(b(x+c))\sin(b(x + c)) is shifted left cc)
Concavityconcave down above the midline, concave up below it; points of inflection on the midline

Building a model: read max, min and period from the context; midline and amplitude from max and min; bb from the period; choose sine or cosine (and a sign) by where the cycle starts; then shift if needed.

Key Fact: The graph of a sinusoid is steepest at the midline and flat at the maximum and minimum. Its rate of change is largest in size where it crosses the midline.

Unit 3 practice (no calculator). 🎯 Question 1 uses the graph above.

Exact values and features. ✍️

1) sin⁡(5π6)\sin\left(\dfrac{5\pi}{6}\right):

2) The amplitude of y=−4cos⁡(3x)+2y = -4\cos(3x) + 2:

3) The period of y=5sin⁡(π4x)y = 5\sin\left(\dfrac{\pi}{4}x\right):

Key Takeaways — Part 5

  • Unit-circle values by reference angle and quadrant sign; tan⁡θ\tan\theta is the slope sin⁡θcos⁡θ\frac{\sin\theta}{\cos\theta}
  • sin⁡\sin and cos⁡\cos have period 2π2\pi; tan⁡\tan has period π\pi and asymptotes where cos⁡x=0\cos x = 0
  • Sinusoid: amplitude max⁡−min⁡2\frac{\max - \min}{2}, midline max⁡+min⁡2\frac{\max + \min}{2}, b=2πperiodb = \frac{2\pi}{\text{period}}, shift decided by where the cycle starts
  • Steepest at the midline, flat at the extremes; concave down above the midline, concave up below

Part 6: Unit 3: Inverse Trigonometry, Equations, Identities and Polar Functions

🎓 AP Precalculus Exam Review

Part 6 of 7 — Unit 3: Inverse Trigonometry, Equations, Identities and Polar Functions

Inverse Trigonometric Functions (3.9)

FunctionDomainRangeQuadrants of the output
arcsin⁡x\arcsin x[−1,1][-1, 1][−π2,π2]\left[-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right]IV (negative inputs), I (positive)
arccos⁡x\arccos x[−1,1][-1, 1][0,π][0, \pi]I (positive inputs), II (negative)
arctan⁡x\arctan xall reals(−π2,π2)\left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)IV (negative inputs), I (positive)

arcsin⁡(sin⁡x)=x\arcsin(\sin x) = x only when xx is in the range of arcsine; otherwise find the angle in range with the same sine.

Trigonometric Equations and Inequalities (3.10)

SituationMethod
sin⁡θ=k\sin\theta = k on [0,2π)[0, 2\pi)one solution from the unit circle, the second by symmetry: π−θ1\pi - \theta_1 (sine), 2π−θ12\pi - \theta_1 (cosine), θ1+π\theta_1 + \pi (tangent)
All solutionsadd 2πk2\pi k (sine, cosine) or πk\pi k (tangent)
Multiple angle sin⁡(2θ)=k\sin(2\theta) = k on [0,2π)[0, 2\pi)solve for 2θ2\theta on [0,4π)[0, 4\pi), then divide: twice as many solutions
Quadratic in a trig functionfactor: 2sin⁡2θ−sin⁡θ=sin⁡θ(2sin⁡θ−1)2\sin^2\theta - \sin\theta = \sin\theta(2\sin\theta - 1)
Two different functionsuse an identity to leave one function
Inequality sin⁡θ>k\sin\theta > ksolve the equation, then test the arcs of the unit circle between the solutions

Identities and Equivalent Forms (3.11–3.12)

IdentityForm
Pythagoreansin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1, 1+tan⁡2θ=sec⁡2θ1 + \tan^2\theta = \sec^2\theta, 1+cot⁡2θ=csc⁡2θ1 + \cot^2\theta = \csc^2\theta
Sum and differencesin⁡(α±β)=sin⁡αcos⁡β±cos⁡αsin⁡β\sin(\alpha \pm \beta) = \sin\alpha\cos\beta \pm \cos\alpha\sin\beta; cos⁡(α±β)=cos⁡αcos⁡β∓sin⁡αsin⁡β\cos(\alpha \pm \beta) = \cos\alpha\cos\beta \mp \sin\alpha\sin\beta
Double anglesin⁡(2θ)=2sin⁡θcos⁡θ\sin(2\theta) = 2\sin\theta\cos\theta; cos⁡(2θ)=cos⁡2θ−sin⁡2θ=2cos⁡2θ−1=1−2sin⁡2θ\cos(2\theta) = \cos^2\theta - \sin^2\theta = 2\cos^2\theta - 1 = 1 - 2\sin^2\theta
Reciprocal and quotientsec⁡θ=1cos⁡θ\sec\theta = \dfrac{1}{\cos\theta}, csc⁡θ=1sin⁡θ\csc\theta = \dfrac{1}{\sin\theta}, cot⁡θ=cos⁡θsin⁡θ\cot\theta = \dfrac{\cos\theta}{\sin\theta}

Polar Coordinates and Polar Functions (3.13–3.15)

FactDetail
Conversionsx=rcos⁡θx = r\cos\theta, y=rsin⁡θy = r\sin\theta; r2=x2+y2r^2 = x^2 + y^2, tan⁡θ=yx\tan\theta = \dfrac{y}{x} with the quadrant checked
Negative rr(−r,θ)(-r, \theta) is the same point as (r,θ+π)(r, \theta + \pi)
Circlesr=ar = a (center at the pole); r=acos⁡θr = a\cos\theta or r=asin⁡θr = a\sin\theta (through the pole, diameter ∣a∣\lvert a \rvert)
Roses r=acos⁡(kθ)r = a\cos(k\theta)kk petals if kk is odd, 2k2k petals if kk is even
Limaçons r=a+bcos⁡θr = a + b\cos\thetainner loop if ∣b∣>∣a∣\lvert b \rvert > \lvert a \rvert; cardioid if ∣a∣=∣b∣\lvert a \rvert = \lvert b \rvert; dimpled or convex if ∣a∣>∣b∣\lvert a \rvert > \lvert b \rvert
Rate of changewhere rr is increasing with θ\theta the point moves away from the pole; where rr is decreasing it moves toward the pole (for r>0r > 0)
Complex numbersz=a+bi=r(cos⁡θ+isin⁡θ)z = a + bi = r(\cos\theta + i\sin\theta) with r=a2+b2r = \sqrt{a^2 + b^2}

Key Fact: For sin⁡(2θ)=k\sin(2\theta) = k on 0≤θ<2π0 \le \theta < 2\pi, the inside angle 2θ2\theta runs through two full turns, so expect four solutions when ∣k∣<1\lvert k \rvert < 1.

Unit 3 practice (no calculator). 🎯

Polar graphs. 🔽

Key Takeaways — Part 6

  • Inverse trig outputs live in fixed ranges: arcsin⁡,arctan⁡\arcsin, \arctan in [−π2,π2]\left[-\frac{\pi}{2}, \frac{\pi}{2}\right], arccos⁡\arccos in [0,π][0, \pi]
  • Solve trig equations with the unit circle and symmetry; a multiple angle kθk\theta multiplies the number of solutions by kk
  • Identities are tools for one function: Pythagorean substitutions and the three forms of cos⁡(2θ)\cos(2\theta)
  • Polar: convert with x=rcos⁡θx = r\cos\theta, y=rsin⁡θy = r\sin\theta; roses have kk or 2k2k petals; rr increasing means moving away from the pole

Part 7: Final Mixed Set: Part A and Part B Practice

🎓 AP Precalculus Exam Review

Part 7 of 7 — Final Mixed Set: Part A and Part B Practice

How to Use This Set

The questions below mix all three units the way the exam does. The first four are Part A style: no calculator, about 2 minutes 15 seconds each. The last two are Part B style: use a graphing calculator, about 3 minutes each. Time yourself, then review every explanation, including the ones you got right.

The Final Checklist

Before the examDuring Part A (no calculator)During Part B (calculator)
unit-circle values cold: π6,π4,π3\frac{\pi}{6}, \frac{\pi}{4}, \frac{\pi}{3} and their reflectionstwo passes: bank the sure questions, mark the restenter data once, store the regression, reuse it
log properties and the three forms of cos⁡(2θ)\cos(2\theta)eliminate choices with end behavior, domain, signsolve numerically by intersection; read to three decimals
asymptote rules by degree comparisonevery answer exact: π\pi, radicals, fractionscheck that an intersection is inside the asked interval
midline, amplitude, period formulasfor "all solutions", count how many the interval should holda model prediction is approximately

Key Fact: The exam rewards recognition: naming the model type from differences or ratios, the asymptote from the degrees, the quadrant from the signs. Each recognition saves a minute.

Part A style: no calculator. 🎯 Four questions, about 9 minutes.

Part B style: graphing calculator. 🎯 Two questions, about 6 minutes. Report decimals to three places.

Last exact checks. ✍️

1) The average rate of change of f(x)=2xf(x) = 2^x on the interval [1,3][1, 3]:

2) The value of cos⁡π\cos\pi:

3) The value of log⁡28+log⁡24\log_2 8 + \log_2 4:

Key Takeaways — AP Precalculus Exam Review

UnitRecognizeComputeSay
1model type from differences; asymptotes from degrees; multiplicity from the graphaverage rates of change; zeros; transformed pointsincreasing/decreasing and concave up/down, with limit notation for asymptotes
2exponential from ratios; log from doubling inputs; linear semi-log plotbb from two points; inverses by swapping; log equations with a domain checkpercent change per unit; "approximately" for model outputs
3quadrant from signs; period from bb; petals from kkexact unit-circle values; all solutions in an interval; polar conversionsmidline/amplitude/period; "moves toward or away from the pole"
  • 42 multiple-choice in 105 minutes, then 4 free-response in 70; Units 1–3 about 35 / 32 / 33%
  • Part A and Q3–Q4: exact by hand; Part B and Q1–Q2: calculator, three decimals
  • Answer every multiple-choice question; attempt every free-response part