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Part 1: Core Concepts
Power Series โ Definition & Convergence
Part 1 of 7 โ Introduction to Power Series
What Is a Power Series?
A power series centered at x=c is:
n=0โโโanโ(xโc)n=
When c=0, this is a Maclaurin-type power series: โanโxn.
Key Terminology
| Term | Meaning |
|---|
| Center c | The point about which the series is expanded |
| Coefficients anโ | The constants multiplying each power |
| Radius of convergence R | Series converges for $ |
| Interval of convergence |
Three Convergence Possibilities
For any power series, exactly ONE is true:
- Converges only at x=c (radius R=0)
- Converges for all x (radius R=โ)
- Converges for and diverges for (finite )
AP Tip: The Ratio Test is the primary tool for finding the radius of convergence.
Finding the Radius with the Ratio Test
For โanโ(xโc)n, apply the Ratio Test:
Finding Radius of Convergence
Summary
- Power series: โanโ(xโc)n โ an "infinite polynomial"
- Radius found via Ratio Test:
Part 2: Worked Examples
Power Series โ Interval of Convergence
Part 2 of 7 โ Endpoint Testing
From Radius to Interval
After finding R, the open interval (cโR,ย c+R) is guaranteed. But endpoints need individual testing.
Endpoint Testing Procedure
- Find using Ratio/Root Test
Part 3: Problem-Solving Patterns
Power Series โ Operations
Part 3 of 7 โ Differentiation, Integration, and Manipulation
Term-by-Term Differentiation
If f(x)=โn=0โโa with radius , then:
Part 4: Graphs and Interpretation
Power Series โ Function Representation
Part 4 of 7 โ Building Series from Known Functions
The Essential Known Series
Memorize these โ they're the building blocks:
| Function | Series | IOC |
|---|
| 1โx1โ | |
Part 5: Applications
Power Series โ Differential Equations & AP Strategies
Part 5 of 7 โ Series Solutions & Exam Techniques
Power Series Solutions to DEs
Some AP problems ask you to find coefficients of a power series solution to a DE.
Setup: Assume y=โanโx
Part 6: Exam Strategy
Power Series โ Problem-Solving Workshop
Part 6 of 7 โ Mixed Practice
Workshop Focus Areas
| Skill | What to Practice |
|---|
| Finding R | Ratio Test on coefficients |
| Endpoint testing | Substitute x=cยฑR, test convergence |
| Series manipulation | Substitution, differentiation, integration |
| Coefficient extraction | |
Part 7: Mixed Review
Power Series โ Comprehensive Review
Part 7 of 7 โ Complete Topic Review
Power Series Checklist
| Skill | Key Points |
|---|
| Definition | โanโ(xโc)n; converges in interval around |
a
0โ
+
a1โ
(
x
โ
c
)
+
a2โ
(
x
โ
c
)2
+
โฏ
โ
| Full interval including endpoint analysis |
โฃxโcโฃ<R
โฃxโcโฃ>R L=limnโโโโanโan+1โโโโ
โฃxโcโฃ Converges when L<1, i.e., โฃxโcโฃ<limโฃan+1โ/anโโฃ1โ.
R=limnโโโโฃan+1โ/anโโฃ1โโ
Example: โn=0โโn!xnโ
โanโan+1โโโ=n+11โโ0
So L=0โ
โฃxโฃ=0<1 for all x. Radius R=โ. (This is the series for ex.)
Example: โn=0โโn!xn
โanโan+1โโโ=n+1โโ
So L=โ for any x๎ =0. Radius R=0. Converges only at x=0.
R=1/limโฃan+1โ/anโโฃ
Three possibilities: R=0, R=โ, or finite R Endpoints must ALWAYS be tested separately
Next: Part 2 โ Interval of Convergence (Endpoint Testing).
R
Substitute x=cโR into โanโ(xโc)n โ get a numerical series Substitute x=c+R โ get another numerical series Test each for convergence (often p-series, alternating, geometric, etc.) Complete Example: โn=1โโnxnโ
Step 1: โฃan+1โ/anโโฃ=n/(n+1)โ1. So R=1.
Step 2: At x=1: โ1/n โ diverges (harmonic)
Step 3: At x=โ1: โ(โ1)n/n โ converges (alternating harmonic)
Intervalย ofย convergence:ย [โ1,1)โ
AP Tip: The interval notation matters! Use brackets [ for included endpoints, parentheses ( for excluded.
Common Endpoint Patterns
| Series | R | At x=c+R | At x=cโR | IOC |
|---|
| โxn/n | 1 | โ1/n div. | โ(โ1) conv. |
Key Insight
At the positive endpoint (x=c+R): all terms are positive โ test with p-series, comparison, etc.
At the negative endpoint (x=cโR): signs alternate โ often use AST.
Common outcome: one endpoint includes (alternating convergence), one excludes (divergence).
Endpoint Testing Practice
Summary
- After finding R, always test both endpoints
- Positive endpoint often yields a positive-term series
- Negative endpoint often yields an alternating series
- Four possible IOC shapes: (a,b), [a,b), (a,b], [a,b]
- AP exam ALWAYS expects endpoint testing โ don't skip it!
Next: Part 3 โ Operations on Power Series.
n
โ
(
x
โ
c)n
fโฒ(x)=n=1โโโnanโ(xโc)nโ1โ
The derivative has the same radius R (but possibly different endpoint behavior).
Term-by-Term Integration
โซf(x)dx=C+n=0โโโn+1anโ(xโc)n+1โโ
Also has radius R (but possibly different endpoint behavior).
Example: From Geometric to ln
1โx1โ=โn=0โโxn,โฃxโฃ<1
โln(1โx)=โn=0โโn+1xn+1โ=โn=1โโnxnโ
So ln(1โx)=โโn=1โโnxnโ, or equivalently ln(1+x)=โn=1โโ.
AP Tip: Deriving series by differentiating/integrating known series is a VERY common AP technique.
Substitution
Replace x with an expression in a known series:
1โx1โ=โxnโน1+x21โ=โ(โx2)n=โ(โ1)nx2n
Then integrate: arctanx=โn=0โโ2n
Addition and Multiplication
- Addition: โanโxn+โb (radius = min of the two)
Radius Under Operations
| Operation | New Radius |
|---|
| Differentiation | Same R |
| Integration | Same R |
| Substitution xโg(x) | Solve $ |
| Addition | |
Summary
- Differentiate and integrate power series term by term
- Radius stays the same (endpoints may change)
- Substitution lets you build new series from known ones
- Key chain: 1/(1โx)โln(1โx)โarctanx via integration/substitution
Next: Part 4 โ Representing Functions as Power Series.
โn=0โโxn
| ex | โn=0โโn!xnโ | (โโ,โ) |
| sinx | โn=0โโ(2n+1)!(โ1)nx2n+1โ | (โโ,โ) |
| cosx | โn=0โโ(2n)!(โ1)nx2nโ | (โโ,โ) |
| ln(1+x) | โn=1โโn(โ1)n+1xnโ | (โ1,1] |
| arctanx | โn=0โโ2n+1(โ1)nx2n+1โ | [โ1,1] |
Mostย APย powerย seriesย problemsย reduceย toย manipulatingย theseย six.โ
AP Tip: You'll often need to find a series by relating the function to one of these through substitution, differentiation, or integration.
Technique: Partial Fractions + Geometric
Find the series for f(x)=2โx3โ:
2โx3โ=23โโ
IOC: โฃx/2โฃ<1โนโฃxโฃ<2
Technique: Composition
Find the series for ex2:
eu=โun/n!. Set u=x:
ex2=โn
Technique: Integration of Known Series
Find the series for โซ0xโeโt2dt (no elementary form!):
eโt2=โ(โ1)nt. Integrate:
This is related to the error function erf(x) โ series representation gives exact computation!
Summary
- Six essential series to memorize (geometric, ex, sin, cos, ln, arctan)
- Build new series via substitution, multiplication, differentiation, integration
- Partial fractions reduce rational functions to geometric-type series
- Series let you "compute" functions with no elementary antiderivative
Next: Part 5 โ Power Series and Differential Equations.
n
=
a0โ+
a1โx+
a2โx2+
a3โx3+
โฏ
Then yโฒ=โn=1โโnanโxnโ1=a1โ+2a2โx+3a3โx2+โฏ
Example: yโฒ=y, y(0)=1
Substituting: a1โ+2a2โx+3a3โx2+โฏ=a0โ+a1โx+a2โx2+โฏ
Matching coefficients: a1โ=a0โ=1, 2a2โ=a1โโa2โ=1/2, 3a3โ=a2โโa3โ
Pattern: anโ=1/n! โ solution is y=ex โ
AP Tip: These problems typically ask for the first 3 or 4 nonzero terms, not the general pattern.
Common AP FRQ Formats
Type 1: "Write the first four nonzero terms..."
- Use known series + operations
- Example: First 4 terms of exsinx โ multiply truncated series
Type 2: "Find the coefficient of xn..."
- Use Taylor formula: anโ=f(n)(0)/n!
- Or manipulate known series
Type 3: "Use the series to approximate..."
- Evaluate at specific x, bound error
- Use alternating series error bound when applicable
Type 4: "Find the interval of convergence"
- Ratio test for R, then test endpoints
Quick AP Checks
f(x)=
So if you know the series, you know the derivatives at the center:
f(n)(c)=n!โ
anโ
Summary
- Power series can solve DEs by matching coefficients
- f(n)(c)=n!โ
anโ connects series coefficients to derivatives
- AP FRQ: "first four nonzero terms" is the most common format
- Build series from known ones rather than computing derivatives
Next: Part 6 โ Problem-Solving Workshop.
anโ=f(n)(c)/n!
| Series building | From known series to new functions |
Workshop Takeaways
- Ratio Test is the go-to for finding R
- Endpoint testing is mandatory on the AP exam
- Building series from known ones is faster than computing derivatives
- f(n)(c)=n!โ
anโ is a powerful shortcut
Next: Part 7 โ Comprehensive Review.
| Radius | Ratio Test: $R = 1/\lim |
| Endpoints | Test separately; four possible IOC shapes |
| Operations | Differentiate/integrate term-by-term; same R |
| Known series | 1/(1โx), ex, sinx, cosx, ln(1+x), arctanx |
| Coefficients | anโ=f(n)(c)/n! |
| DE solutions | Match coefficients after substituting series |
Powerย seriesย =ย theย bridgeย betweenย algebraย andย analysisย onย theย APย exam.โ
Power Series โ Complete Summary
You've mastered:
- Definition & radius โ Ratio Test for R, three convergence scenarios
- Endpoint testing โ individual analysis, four IOC shapes
- Operations โ differentiate, integrate, substitute term-by-term
- Known series โ six essential Maclaurin series
- Function representation โ building new series from old
- DE connections โ coefficient matching for series solutions
Key Fact: Power series questions appear in 5+ MC questions and at least 1 FRQ on every BC exam. This is arguably the most important BC-specific topic.
Up Next: Taylor & Maclaurin Series โ the general construction formula.
n
/
n
| โxn/n2 | 1 | โ1/n2 conv. | โ(โ1)n/n2 conv. | [โ1,1] |
| โxn | 1 | โ1 div. | โ(โ1)n div. | (โ1,1) |
| โn!xn | 0 | N/A | N/A | {0} |
| โxn/n! | โ | N/A | N/A | (โโ,โ) |
n
(โ1)n+1xn
โ
+
1
(โ1)nx2n+1
โ
n
โ
xn
=
โ(anโ+
bnโ)xn
Multiplication by xk: xkโanโxn=โanโxn+k (radius unchanged) min(R1โ,R2โ)
| Multiplication by polynomial | Same R |
1โx/2
1
โ
=
23โโn=0โโ(2xโ)n=
โn=0โโ2n+13xnโ
2
=
0
โ
โ
n!x2nโ
=
1+
x2+
2x4โ+
6x6โ+
โฏ
2n
/
n
!
โซ0xโ=โn=0โโ(2n+1)n!(โ1)nx2n+1โ
=
1/6
n=0
โ
โ
โ
n!f(n)(c)โ
(
x
โ
c
)n
โน
anโ
=
n!f(n)(c)โ
โ