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🎯⭐ INTERACTIVE LESSON

Perimeter and Area

Learn step-by-step with interactive practice!

Perimeter and Area - Complete Interactive Lesson

Part 1: Perimeter: The Distance Around

📐 Perimeter and Area

Part 1 of 5 — Perimeter: The Distance Around


Topics in This Part

Section
What Perimeter Means
Perimeter of Rectangles & Squares
Perimeter of Any Polygon

🔑 Key Concept: Perimeter is the total distance around a flat shape — imagine walking along every edge once. You find it by adding up the lengths of all the sides.

What Perimeter Means

If you put a fence around a yard or trim around a picture, you care about the perimeter — the length of the boundary.

To find it, add every side:

P=s1+s2+s3+⋯P = s_1 + s_2 + s_3 + \cdots

Example: A Triangle

A triangle has sides 5 cm5\text{ cm}, 7 cm7\text{ cm}, and 9 cm9\text{ cm}:

P=5+7+9=21 cmP = 5 + 7 + 9 = 21\text{ cm}

💡 Units matter. Perimeter is a length, so the answer keeps the same unit as the sides — cm\text{cm}, m\text{m}, in\text{in}, ft\text{ft} — never squared.

Rectangles and Squares Have Shortcuts

A rectangle has two equal lengths ℓ\ell and two equal widths ww, so instead of adding four numbers you can use:

P=2ℓ+2worP=2(ℓ+w)P = 2\ell + 2w \quad\text{or}\quad P = 2(\ell + w)

A square is a rectangle with all four sides equal to ss:

P=4sP = 4s

ShapeSidesFormulaExample
Rectangleℓ=8, w=3\ell = 8,\ w = 32(ℓ+w)2(\ell+w)2(8+3)=222(8+3)=22
Squares=6s = 64s4s4⋅6=244\cdot 6 = 24

🔑 The shortcuts and "add every side" give the same answer — the formulas just save time.

Concept Check 🎯

Find the Perimeter 🧮

Enter each perimeter (just the number — the unit is shown for you).

1) A square with side 7 cm7\text{ cm}: P= ? cmP = \,?\ \text{cm} 2) A rectangle, ℓ=12 in\ell = 12\text{ in}, w=5 inw = 5\text{ in}: P= ? inP = \,?\ \text{in} 3) A triangle with sides 66, 88, 10 ft10\text{ ft}: P= ? ftP = \,?\ \text{ft}

Working Backward: A Missing Side

If you know the perimeter, you can find a missing side by subtracting the sides you know.

Example

A rectangle has perimeter 30 m30\text{ m} and length 9 m9\text{ m}. Find the width.

2(9)+2w=30  ⇒  18+2w=30  ⇒  2w=12  ⇒  w=6 m2(9) + 2w = 30 \;\Rightarrow\; 18 + 2w = 30 \;\Rightarrow\; 2w = 12 \;\Rightarrow\; w = 6\text{ m}

💡 Perimeter problems are really just addition (going forward) and subtraction/division (working backward). In Part 2 we tackle area — a different kind of measurement.

Work Backward 🧮

1) A square has perimeter 36 cm36\text{ cm}. How long is one side?  ? cm\,?\ \text{cm} 2) A rectangle has perimeter 26 in26\text{ in} and width 4 in4\text{ in}. Find the length.  ? in\,?\ \text{in}

Part 2: Area of Rectangles, Squares & Parallelograms

📐 Perimeter and Area

Part 2 of 5 — Area of Rectangles, Squares & Parallelograms


🔑 The Idea: Area measures the space inside a flat shape — how many unit squares fit. Because it covers a 2-D region, area is always in square units (cm2\text{cm}^2, ft2\text{ft}^2, …).

Area of a Rectangle

Cover a rectangle with a grid of 1×11\times 1 squares. The number that fit is the area:

A=ℓ×w(length×width)A = \ell \times w \quad(\text{length} \times \text{width})

Example: ℓ=8 cm\ell = 8\text{ cm}, w=3 cmw = 3\text{ cm}

A=8×3=24 cm2A = 8 \times 3 = 24\text{ cm}^2

A grid 88 across and 33 down holds exactly 2424 unit squares. ✓

A square is the special case ℓ=w=s\ell = w = s:

A=s×s=s2A = s \times s = s^2

⚠️ Perimeter vs. Area — don't mix them up! For that 8×38\times 3 rectangle, the perimeter is 22 cm22\text{ cm} but the area is 24 cm224\text{ cm}^2. Perimeter is the border; area is the inside.

Perimeter or Area? 🎯

Area of a Parallelogram

Slide a triangle from one end of a parallelogram to the other and it becomes a rectangle. So the area uses the base and the perpendicular height (the straight-up distance between the two parallel sides — not the slanted side):

A=b×hA = b \times h

Example: b=10 mb = 10\text{ m}, h=4 mh = 4\text{ m}

A=10×4=40 m2A = 10 \times 4 = 40\text{ m}^2

⚠️ The height is always perpendicular to the base. If a problem gives you the slanted side length, that is not the height — use the vertical distance.

Pick the Right Formula 🔽

Match each shape to its area formula.

Find the Area 🧮

Enter each area (the unit is shown).

1) Rectangle, ℓ=9 ft\ell = 9\text{ ft}, w=5 ftw = 5\text{ ft}: A= ? ft2A = \,?\ \text{ft}^2 2) Square, side 7 cm7\text{ cm}: A= ? cm2A = \,?\ \text{cm}^2 3) Parallelogram, base 12 m12\text{ m}, height 6 m6\text{ m}: A= ? m2A = \,?\ \text{m}^2

Part 3: Triangles & Trapezoids

📐 Perimeter and Area

Part 3 of 5 — Triangles & Trapezoids


🔑 Why the halves? A triangle is half of a rectangle (or parallelogram). A trapezoid averages its two parallel sides. Both formulas have a 12\dfrac{1}{2} for exactly this reason.

Area of a Triangle

Put two copies of a triangle together and you get a parallelogram with the same base and height. So a triangle is half:

A=12 b hA = \frac{1}{2}\, b \, h

The height is the perpendicular distance from the base to the opposite corner.

Example: b=10 cmb = 10\text{ cm}, h=6 cmh = 6\text{ cm}

A=12(10)(6)=12(60)=30 cm2A = \frac{1}{2}(10)(6) = \frac{1}{2}(60) = 30\text{ cm}^2

💡 Tip: Multiply b×hb \times h first, then take half. 10×6=6010 \times 6 = 60, half of 6060 is 3030.

Concept Check 🎯

Area of a Trapezoid

A trapezoid has two parallel sides — call them b1b_1 and b2b_2. You average them and multiply by the height:

A=12 (b1+b2) hA = \frac{1}{2}\,(b_1 + b_2)\,h

Example: b1=6 inb_1 = 6\text{ in}, b2=10 inb_2 = 10\text{ in}, h=4 inh = 4\text{ in}

A=12(6+10)(4)=12(16)(4)=12(64)=32 in2A = \frac{1}{2}(6 + 10)(4) = \frac{1}{2}(16)(4) = \frac{1}{2}(64) = 32\text{ in}^2

StepWork
Add the parallel sides6+10=166 + 10 = 16
Multiply by height16×4=6416 \times 4 = 64
Take half12×64=32\tfrac{1}{2}\times 64 = 32

🔑 If the two parallel sides were equal, a trapezoid would just be a parallelogram — and the formula would collapse back to b×hb \times h.

Trapezoid, Step by Step 🔽

Find the area of a trapezoid with b1=5 cmb_1 = 5\text{ cm}, b2=9 cmb_2 = 9\text{ cm}, height 6 cm6\text{ cm}.

Triangles & Trapezoids 🧮

Enter each area.

1) Triangle, base 14 ft14\text{ ft}, height 9 ft9\text{ ft}: A= ? ft2A = \,?\ \text{ft}^2 2) Triangle, base 7 cm7\text{ cm}, height 4 cm4\text{ cm}: A= ? cm2A = \,?\ \text{cm}^2 3) Trapezoid, b1=8 mb_1 = 8\text{ m}, b2=12 mb_2 = 12\text{ m}, height 5 m5\text{ m}: A= ? m2A = \,?\ \text{m}^2

Part 4: Circles: Circumference & Area

📐 Perimeter and Area

Part 4 of 5 — Circles: Circumference & Area


🔑 The star of circles is π\pi (pi), about 3.143.14. It's the number you get when you divide any circle's distance-around by its diameter — it never changes.

Radius, Diameter & π\pi

  • The radius rr reaches from the center to the edge.
  • The diameter dd stretches all the way across, through the center.
  • They're related by d=2rd = 2r (the diameter is two radii).

The distance around a circle has a special name — circumference — and two equivalent formulas:

C=2πrorC=πdC = 2\pi r \qquad\text{or}\qquad C = \pi d

Example: radius 5 cm5\text{ cm} (use π≈3.14\pi \approx 3.14)

C=2πr=2(3.14)(5)=31.4 cmC = 2\pi r = 2(3.14)(5) = 31.4\text{ cm}

💡 If you're given the diameter, C=πdC = \pi d is faster. If you're given the radius, use C=2πrC = 2\pi r.

Concept Check 🎯

Area of a Circle

The space inside a circle uses the radius squared:

A=πr2A = \pi r^2

Example: radius 5 cm5\text{ cm} (use π≈3.14\pi \approx 3.14)

A=πr2=3.14×52=3.14×25=78.5 cm2A = \pi r^2 = 3.14 \times 5^2 = 3.14 \times 25 = 78.5\text{ cm}^2

⚠️ Square the radius first, then multiply by π\pi. r2r^2 means r×rr \times r, so 52=255^2 = 25 — not 5×2=105 \times 2 = 10. And if you're given the diameter, cut it in half to get rr before using this formula.

Circle Quantities 🔽

A circle has diameter 12 in12\text{ in}. Use π≈3.14\pi \approx 3.14.

Circle Practice 🧮

Use π≈3.14\pi \approx 3.14. Enter each value as a decimal.

1) Circumference of a circle with radius 3 cm3\text{ cm} (C=2πrC = 2\pi r):  ? cm\,?\ \text{cm} 2) Area of a circle with radius 3 cm3\text{ cm} (A=πr2A = \pi r^2):  ? cm2\,?\ \text{cm}^2 3) Area of a circle with radius 10 m10\text{ m}:  ? m2\,?\ \text{m}^2

Part 5: Composite Figures, Real-World Problems & Mastery Check

📐 Perimeter and Area

Part 5 of 5 — Composite Figures, Real-World Problems & Mastery Check


You now have every basic formula. Real problems often combine shapes or ask "how much fencing / how much paint?" — let's put it all together.

Quick Reference

ShapePerimeter / CircumferenceArea
Rectangle2(ℓ+w)2(\ell + w)ℓ×w\ell \times w
Square4s4ss2s^2
Trianglesum of 3 sides12bh\frac{1}{2}bh
Parallelogramsum of all sidesb×hb \times h
Trapezoidsum of all sides12(b1+b2)h\frac{1}{2}(b_1 + b_2)h
CircleC=2πr=πdC = 2\pi r = \pi dπr2\pi r^2

⚠️ Remember the units: perimeter/circumference use plain units; area uses square units. And in 12bh\frac{1}{2}bh or πr2\pi r^2, always do the multiplication/squaring before the 12\frac{1}{2} or before adding π\pi.

Composite Figures: Split, Then Add

A composite figure is made of simpler shapes glued together. To find its area, break it into pieces, find each area, and add.

Example: An "L" shape

Picture a 10×610\times 6 rectangle with a 4×34\times 3 rectangle removed from one corner. You can either subtract, or split into two rectangles. Subtracting:

A=(10×6)−(4×3)=60−12=48 units2A = (10 \times 6) - (4 \times 3) = 60 - 12 = 48\text{ units}^2

💡 Two strategies: Split-and-add (cut the figure into shapes you know) or subtract (start with a big rectangle and remove the missing chunk). Both give the same area — pick whichever is easier to see.

Real-World Problems 🎯

Composite & Applications 🧮

1) An L-shape: a 10 m×7 m10\text{ m} \times 7\text{ m} rectangle with a 3 m×2 m3\text{ m} \times 2\text{ m} rectangle cut out. Total area = ? m2= \,?\ \text{m}^2 2) A room floor is 15 ft×10 ft15\text{ ft} \times 10\text{ ft}. How many square feet of tile cover it?  ? ft2\,?\ \text{ft}^2 3) A square photo has side 6 in6\text{ in}. How much frame trim goes around it (perimeter)?  ? in\,?\ \text{in}

Exit Quiz ✅

Answer all three to finish the lesson.