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Physics: Mechanics - Interactive Lesson | Study Mondo
Physics: Mechanics - Complete Interactive Lesson Part 1: Kinematics & Motion Physics: Mechanics for the MCAT
Part 1 of 7 โ Kinematics
The Big 5 Kinematic Equations
v = v 0 + a t v = v_0 + at v = v 0 โ + a t
ฮ x = v 0 t + 1 2 a t 2 \Delta x = v_0 t + \tfrac{1}{2}at^2 ฮ x = v 0 โ t + 2 1 โ a t
v 2 = v 0 2 + 2 a ฮ x v^2 = v_0^2 + 2a\Delta x v 2 = v 0 2 โ + 2 a ฮ x
ฮ x = 1 2 ( v 0 + v ) t \Delta x = \tfrac{1}{2}(v_0 + v)t ฮ x = 2 1 โ ( v 0 โ + v )
ฮ x = v t โ 1 2 a t 2 \Delta x = vt - \tfrac{1}{2}at^2 ฮ x = v t โ 2 1 โ a t 2
Projectile Motion
Horizontal: a x = 0 a_x = 0 a x โ = 0 , v x = v 0 cos โก ฮธ = constant v_x = v_0\cos\theta = \text{constant} v x โ =
MCAT Tip: Free Fall
All objects fall at the same rate regardless of mass (ignoring air resistance). g โ 10 โ
โ m/s 2 g \approx 10\;\text{m/s}^2 g โ 10 m/s 2 for quick calculations on the MCAT.
Relative Motion Shortcut
In one-dimensional motion, use relative velocity directly:
v A / B = v A โ v B v_{A/B} = v_A - v_B v A / B โ = v A โ โ v
This simplifies chase and meeting-time questions.
Key Takeaways โ Part 1
Use g โ 10 โ
โ m/s 2 g \approx 10\;\text{m/s}^2 g โ 10 m/s 2 for MCAT calculations
Projectile motion: separate into x (constant velocity) and y (constant acceleration)
Complementary angles give same range; 45ยฐ gives maximum range
Relative velocity questions are often one subtraction when set up correctly.
Part 2: Forces & Newtons Laws Physics: Mechanics for the MCAT
Part 2 of 7 โ Newton's Laws & Forces
Newton's Three Laws
Inertia : An object at rest stays at rest; an object in motion stays in motion (unless acted on by a net force)
F = m a F = ma F = ma : Net force equals mass times acceleration
Action-Reaction : Every force has an equal and opposite force (on a DIFFERENT object!)
Common MCAT Forces
Force Formula Direction Weight W = m g W = mg W =
Part 3: Work, Energy & Power Physics: Mechanics for the MCAT
Part 3 of 7 โ Work, Energy & Power
Work-Energy Theorem
W n e t = ฮ K E = 1 2 m v 2 โ 1 2 m v 0 2 W_{net} = \Delta KE = \frac{1}{2}mv^2 - \frac{1}{2}mv_0^2 W n e t โ = ฮ K E =
Part 4: Momentum & Collisions Physics: Mechanics for the MCAT
Part 4 of 7 โ Momentum & Collisions
Linear Momentum
p โ = m v โ \vec{p} = m\vec{v} p โ = m v
Part 5: Fluids & Pressure Physics: Mechanics for the MCAT
Part 5 of 7 โ Fluids (ULTRA HIGH YIELD)
Density & Pressure
ฯ = m V P = F A \rho = \frac{m}{V} \qquad P = \frac{F}{A} ฯ = V m โ P =
Part 6: Waves & Sound Physics: Mechanics for the MCAT
Part 6 of 7 โ Torque, Equilibrium & Simple Machines
Torque
ฯ = r F sin โก ฮธ \tau = rF\sin\theta ฯ = r F sin ฮธ
r r r = distance from pivot (lever arm)
Counterclockwise = positive (by convention)
Equilibrium Conditions
For static equilibrium: โ F = 0 \sum F = 0 โ F AND
Part 7: Review & MCAT Practice Physics: Mechanics for the MCAT
Part 7 of 7 โ Waves & Sound
Wave Properties
v = f ฮป T = 1 f v = f\lambda \qquad T = \frac{1}{f} v = f ฮป T = f 1 โ
Transverse : oscillation perpendicular to propagation (light, string waves)
2
t
v
0 โ
cos
ฮธ
=
constant
Vertical: a y = โ g = โ 9.8 โ
โ m/s 2 a_y = -g = -9.8\;\text{m/s}^2 a y โ = โ g = โ 9.8 m/s 2 Time to reach max height: t = v 0 sin โก ฮธ g t = \frac{v_0\sin\theta}{g} t = g v 0 โ s i n ฮธ โ Range: R = v 0 2 sin โก ( 2 ฮธ ) g R = \frac{v_0^2\sin(2\theta)}{g} R = g v 0 2 โ s i n ( 2 ฮธ ) โ (max at 45ยฐ) B
โ
m
g
Normal N N N (variable)Perpendicular to surface
Friction (static) f s โค ฮผ s N f_s \le \mu_s N f s โ โค ฮผ s โ N Opposes potential motion
Friction (kinetic) f k = ฮผ k N f_k = \mu_k N f k โ = ฮผ k โ N Opposes actual motion
Tension T T T (variable)Along the string
Spring F = โ k x F = -kx F = โ k x Restoring (toward equilibrium)
Inclined Plane (MCAT FAVORITE)
Component along plane: m g sin โก ฮธ mg\sin\theta m g sin ฮธ
Component perpendicular: m g cos โก ฮธ mg\cos\theta m g cos ฮธ (= Normal force if no other vertical forces)
Friction on incline: f = ฮผ m g cos โก ฮธ f = \mu mg\cos\theta f = ฮผ m g cos ฮธ
Force-Analysis Workflow
Isolate one object.
Draw every real force (weight, normal, tension, friction, applied).
Choose axes along likely motion.
Write โ F = m a \sum F = ma โ F = ma per axis.
Forces & Newton's Laws ๐ฏ
Key Takeaways โ Part 2
F n e t = m a F_{net} = ma F n e t โ = ma : always draw a free body diagram first!
Incline: m g sin โก ฮธ mg\sin\theta m g sin ฮธ along the plane, m g cos โก ฮธ mg\cos\theta m g cos ฮธ perpendicular
Elevator problems: apparent weight = m ( g ยฑ a ) m(g \pm a) m ( g ยฑ a )
Static friction is a maximum (f s โค ฮผ s N f_s \le \mu_s N f s โ โค ฮผ s โ N ); kinetic friction is exact (f k = ฮผ k N f_k = \mu_k N f )
If speed is constant, net force is zero even if multiple forces are present.
2 1
โ
m
v 2
โ
2 1 โ m v 0 2 โ
W = F d cos โก ฮธ W = Fd\cos\theta W = F d cos ฮธ
Conservation of Energy K E i + P E i = K E f + P E f ( ifย noย non-conservativeย forces ) KE_i + PE_i = KE_f + PE_f \quad (\text{if no non-conservative forces}) K E i โ + P E i โ = K E f โ + P E f โ ( ifย noย non-conservativeย forces )
Kinetic energy: K E = 1 2 m v 2 KE = \frac{1}{2}mv^2 K E = 2 1 โ m v 2
Gravitational PE: P E = m g h PE = mgh PE = m g h
Spring PE: P E = 1 2 k x 2 PE = \frac{1}{2}kx^2 PE = 2 1 โ k x 2
Power P = W t = F v P = \frac{W}{t} = Fv P = t W โ = F v
Conservative vs Nonconservative Forces
Conservative (gravity, springs): path-independent work; mechanical energy conserved.
Nonconservative (friction, drag): convert mechanical energy to thermal/internal energy.
When friction is present, include nonconservative work in the energy equation.
Key Takeaways โ Part 3
W = F d cos โก ฮธ W = Fd\cos\theta W = F d cos ฮธ : only the component of force parallel to displacement does work
Conservation of energy: K E + P E = constant KE + PE = \text{constant} K E + PE = constant (no friction/air resistance)
v = 2 g h v = \sqrt{2gh} v = 2 g h โ for an object dropped from height h h h โ memorize this shortcut
Power = Work/time = Force ร \times ร velocity
Friction does negative work and reduces mechanical energy.
Impulse-Momentum Theorem J โ = F โ ฮ t = ฮ p โ \vec{J} = \vec{F}\Delta t = \Delta\vec{p} J = F ฮ t = ฮ p โ
Conservation of Momentum m 1 v 1 i + m 2 v 2 i = m 1 v 1 f + m 2 v 2 f m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f} m 1 โ v 1 i โ + m 2 โ v 2 i โ = m 1 โ v 1 f โ + m 2 โ v 2 f โ
Always conserved in the absence of external forces!
Collision Types Type Momentum Kinetic Energy Elastic Conserved Conserved Inelastic Conserved NOT conserved (some lost to heat/deformation) Perfectly inelastic Conserved Maximum KE loss (objects stick together)
For perfectly inelastic: m 1 v 1 + m 2 v 2 = ( m 1 + m 2 ) v f m_1v_1 + m_2v_2 = (m_1 + m_2)v_f m 1 โ v 1 โ + m 2 โ v 2 โ = ( m 1 โ + m 2 โ ) v f โ
Why Increasing Collision Time Matters From J = F ฮ t = ฮ p J = F\Delta t = \Delta p J = F ฮ t = ฮ p , for fixed momentum change, increasing ฮ t \Delta t ฮ t lowers average force.
This principle explains airbags, padded helmets, and crumple zones.
Key Takeaways โ Part 4
Momentum is ALWAYS conserved in collisions (absent external forces)
KE is ONLY conserved in elastic collisions
Perfectly inelastic = objects stick together = maximum KE loss
Impulse (F ฮ t F\Delta t F ฮ t ) = change in momentum โ explains why airbags work (increase ฮ t \Delta t ฮ t )
A
F
โ
Hydrostatic Pressure P = P 0 + ฯ g h P = P_0 + \rho g h P = P 0 โ + ฯ g h
where P 0 P_0 P 0 โ = atmospheric pressure (1 atm = 101,325 Pa)
Pascal's Principle Pressure applied to a confined fluid is transmitted equally: F 1 A 1 = F 2 A 2 \frac{F_1}{A_1} = \frac{F_2}{A_2} A 1 โ F 1 โ โ = A 2 โ F 2 โ โ
Archimedes' Principle (Buoyancy) F b = ฯ f l u i d โ
V d i s p l a c e d โ
g F_b = \rho_{fluid} \cdot V_{displaced} \cdot g F b โ = ฯ f l u i d โ โ
V d i s pl a ce d โ โ
g
Object floats if ฯ o b j e c t < ฯ f l u i d \rho_{object} < \rho_{fluid} ฯ o bj ec t โ < ฯ f l u i d โ
Bernoulli's Equation (Conservation of Energy for Fluids) P 1 + 1 2 ฯ v 1 2 + ฯ g h 1 = P 2 + 1 2 ฯ v 2 2 + ฯ g h 2 P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2 P 1 โ + 2 1 โ ฯ v 1 2 โ + ฯ g h 1 โ = P 2 โ + 2 1 โ ฯ v 2 2 โ + ฯ g h 2 โ
Continuity Equation A 1 v 1 = A 2 v 2 A_1 v_1 = A_2 v_2 A 1 โ v 1 โ = A 2 โ v 2 โ
Narrower pipe โ faster flow โ lower pressure (Venturi effect)
Flow Rate Volume flow rate Q = A v Q = Av Q = A v helps connect continuity to units (m3 ^3 3 /s) and physiology passages about blood flow.
Key Takeaways โ Part 5
Bernoulli: faster flow โ lower pressure (explains aneurysms, airplane lift)
Continuity: A 1 v 1 = A 2 v 2 A_1v_1 = A_2v_2 A 1 โ v 1 โ = A 2 โ v 2 โ (incompressible fluid)
Buoyancy: object floats when ฯ o b j e c t < ฯ f l u i d \rho_{object} < \rho_{fluid} ฯ o bj ec t โ < ฯ f l u i d โ
Hydrostatic pressure increases with depth: P = P 0 + ฯ g h P = P_0 + \rho gh P = P 0 โ + ฯ g h
=
0
โ ฯ = 0 \sum \tau = 0 โ ฯ = 0
Center of Mass x c m = โ m i x i โ m i x_{cm} = \frac{\sum m_i x_i}{\sum m_i} x c m โ = โ m i โ โ m i โ x i โ โ
Simple Machines
Lever : F 1 d 1 = F 2 d 2 F_1 d_1 = F_2 d_2 F 1 โ d 1 โ = F 2 โ d 2 โ (mechanical advantage)
Pulley : redirects force; compound pulleys multiply force
Inclined plane : reduces force needed but increases distance
Key Principle : Machines reduce force but NEVER reduce work (W = F d W = Fd W = F d is constant).
Pivot Choice Strategy Choose a pivot that eliminates unknown forces (often a support point) so torque equations simplify quickly.
Torque & Equilibrium ๐ฏ
Key Takeaways โ Part 6
Torque = r F sin โก ฮธ rF\sin\theta r F sin ฮธ ; maximum when force is perpendicular to lever arm
Equilibrium: โ F = 0 \sum F = 0 โ F = 0 AND โ ฯ = 0 \sum \tau = 0 โ ฯ = 0 (choose any pivot point!)
Simple machines trade force for distance; work is conserved
MCAT loves beam/seesaw problems โ practice them!
Longitudinal : oscillation parallel to propagation (sound)
Sound
Speed in air: โ 340 โ
โ m/s \approx 340\;\text{m/s} โ 340 m/s (faster in denser media)
Intensity : I = P 4 ฯ r 2 I = \frac{P}{4\pi r^2} I = 4 ฯ r 2 P โ (inverse square law)
Decibels : ฮฒ = 10 log โก ( I / I 0 ) \beta = 10\log(I/I_0) ฮฒ = 10 log ( I / I 0 โ ) where I 0 = 10 โ 12 โ
โ W/m 2 I_0 = 10^{-12}\;\text{W/m}^2 I
Every 10 dB increase = 10ร intensity
Doppler Effect f โฒ = f v ยฑ v o b s e r v e r v โ v s o u r c e f' = f\frac{v \pm v_{observer}}{v \mp v_{source}} f โฒ = f v โ v so u rce โ v ยฑ v o b ser v er โ โ
Source approaching โ higher frequency (pitch)
Source receding โ lower frequency
Standing Waves
Both ends fixed : ฮป n = 2 L n \lambda_n = \frac{2L}{n} ฮป n โ = n 2 L โ , f n = n v 2 L f_n = n\frac{v}{2L} f n โ = n 2 L v โ
One end open : ฮป n = 4 L n \lambda_n = \frac{4L}{n} ฮป n โ = n 4 L โ (odd harmonics only: n = 1 , 3 , 5... n = 1, 3, 5... )
For a fixed source frequency, wavelength changes with medium because ฮป = v / f \lambda = v/f ฮป = v / f and wave speed depends on medium properties.
Physics Mechanics โ Complete! โ
Key formulas: v = f ฮป v = f\lambda v = f ฮป , Doppler effect, inverse square law for intensity. Sound travels faster in denser media (opposite of light!). Standing wave harmonics depend on boundary conditions.
k
โ
=
ฮผ k โ N
0
โ
=
1 0 โ 12 W/m 2
n =
1 , 3 , 5...