Flow through a vessel obeys an Ohm's-law analog, Q=ΔP/R, where resistance depends sharply on radius:
R∝r4ηL
Radius dominates: halving r raises resistance 16×. This is why arterioles ("resistance vessels") control BP.
Velocity is slowest in capillaries because total cross-sectional area is largest (v=Q/Atotal) — maximizing exchange time.
Frank–Starling Mechanism & Pressure–Volume Loop
Frank–Starling law: greater end-diastolic volume (preload) → greater stretch → stronger contraction → larger stroke volume. The heart pumps what it receives.
Preload ↑ by venous return; afterload = the pressure the ventricle must overcome (≈ aortic/systemic pressure); contractility ↑ by sympathetic/catecholamines independent of preload.
Capillary Exchange (Starling Forces)
Jv∝(Pc−P
Arteriolar end: hydrostatic pressure dominates → net filtration out.
Venular end: oncotic pressure dominates → net reabsorption in.
Excess filtered fluid returns via the lymphatics. Lymphatic blockage or low plasma albumin → edema.
Cardiovascular 🎯
Worked Examples — Cardiovascular Physiology
<details>
<summary><b>Example 1: Compute cardiac output and mean arterial pressure</b></summary>
Question: HR = 75 bpm, end-diastolic volume = 120 mL, end-systolic volume = 50 mL, total peripheral resistance such that systolic BP = 120 and diastolic = 80 mmHg. Find stroke volume, cardiac output, and mean arterial pressure (MAP).
</details>
<details>
<summary><b>Example 2: Predict the effect of increased afterload</b></summary>
Question: A patient develops aortic stenosis (narrowed aortic valve), raising the pressure the left ventricle must generate to eject blood. In the short term, what happens to stroke volume, and how does the heart compensate long-term?
Solution:
Higher afterload → the ventricle ejects against greater resistance → stroke volume falls acutely (end-systolic volume rises because less blood is ejected).
Frank–Starling: the leftover blood adds to the next preload, partially restoring SV via greater stretch.
Long-term compensation: concentric ventricular hypertrophy (thicker wall) to generate higher pressure — eventually maladaptive, leading to diastolic dysfunction. ✓
High-yield connection: Afterload ↑ → SV ↓; preload ↑ → SV ↑. Distinguish these on pressure–volume loops.
</details>
<details>
<summary><b>Example 3: Reason about capillary fluid movement</b></summary>
Question: At the arteriolar end of a capillary: , , , mmHg. At the venular end (others unchanged). Determine the direction of net fluid movement at each end.
</details>
Key Takeaways — Part 1
CO = HR × SV; BP = CO × TPR
Left ventricle = thickest (systemic pressure)
S1 = AV valves close (lub); S2 = semilunar valves close (dub)
Capillaries = site of gas/nutrient exchange (largest total cross-sectional area)
Part 2: Respiratory System
Organ Systems for the MCAT
Part 2 of 7 — Respiratory System
Gas Exchange
O2:Alveoli→Blood→Tissues
Part 3: Renal & Excretory System
Organ Systems for the MCAT
Part 4 of 7 — Renal System (Kidneys)
Nephron Structure
Glomerulus→PCT→Loop of Henle→DCT→Collecting Duct
Key Functions by Segment
Segment
Function
Key Details
Glomerulus
Part 4: Digestive System
Organ Systems for the MCAT
Part 3 of 7 — Digestive System
GI Tract Order
Mouth → Esophagus → Stomach → Small intestine (duodenum → jejunum → ileum) → Large intestine → Rectum
T regulatory: Suppress immune responses (prevent autoimmunity)
i
)
−
(πc−
πi)
Pc=35
Pi=0
πc=25
πi=0
Pc=15
Solution:
Arteriolar end: net = (35−0)−(25−0)=+10 mmHg → filtration OUT. ✓
Venular end: net = (15−0)−(25−0)=−10 mmHg → reabsorption IN. ✓
Interpretation: Hydrostatic pressure drops along the capillary while oncotic pressure stays roughly constant, so fluid filters out early and is reabsorbed later. Net slight excess is cleared by lymphatics — block them and you get lymphedema.
CO2:Tissues→Blood→Alveoli
Driven by PARTIAL PRESSURE gradients (Fick's law)
Alveoli maximize surface area for diffusion
Fick's Law of Diffusion
Gas flux across the alveolar membrane scales with surface area and partial-pressure gradient, and inversely with membrane thickness:
Vgas∝TA⋅D⋅(P1−P2)
A = surface area (huge in alveoli, ~70 m²); destroyed in emphysema → impaired exchange.
T = membrane thickness; increased by pulmonary edema or fibrosis → impaired diffusion.
(P1−P2) = partial pressure gradient. Alveolar PO2≈100 mmHg vs. venous blood ~40 mmHg drives O₂ in.
Oxygen Transport
98.5% bound to hemoglobin (Hb), 1.5% dissolved in plasma
Each Hb binds 4 O2 molecules
Cooperative binding: Binding of first O2 increases affinity for subsequent O2 (sigmoidal curve)
The Oxygen–Hemoglobin Dissociation Curve (Figure)
The curve plots % Hb saturation (y) vs. PO2 (x) and is sigmoidal due to cooperativity:
PO2 (mmHg)
~% Saturation
Location
100
~98%
Lungs (loading plateau)
40
~75%
Resting venous blood / tissues
26 (P50)
50%
Reference affinity point
20
~35%
Exercising muscle (steep unloading)
The flat upper plateau means modest drops in alveolar PO2 (altitude, mild lung disease) barely lower loading. The steep middle means small PO2 drops in tissue cause large O₂ release — efficient unloading exactly where metabolism is high.
The Bohr Effect (MCAT FAVORITE)
Conditions that RIGHT-shift the curve (raise P50, lower affinity, promote O2 unloading):
Increased CO2 (metabolically active tissue)
Decreased pH (acidic — more CO2/lactic acid)
Increased temperature
Increased 2,3-BPG (chronic hypoxia, high altitude)
Mnemonic: Right shift = Release O2 to tissues. A LEFT shift (↑pH, ↓CO₂, ↓temp, ↓2,3-BPG; also fetal Hb and CO) raises affinity → O₂ held tightly.
CO2 Transport & the Chloride Shift
70% as bicarbonate (HCO3−)
23% bound to Hb (carbaminohemoglobin)
7% dissolved in plasma
In the tissues, CO₂ enters RBCs, and carbonic anhydrase catalyzes:
CO2+H2O⇌H2CO3⇌H++HCO3−
HCO₃⁻ exits the RBC in exchange for Cl⁻ (the chloride shift); H⁺ binds Hb (driving the Bohr effect). In the lungs the entire reaction reverses, expelling CO₂.
Control of Ventilation (Feedback Loop)
The medullary respiratory center sets breathing rate. The dominant stimulus is CO₂/pH, not O₂:
↑PCO2→↑H+ in CSF→central chemoreceptors→↑ventilation→↓PCO2
Central chemoreceptors (medulla) sense CSF pH (a proxy for arterial CO₂) — the primary driver.
Peripheral chemoreceptors (carotid/aortic bodies) sense low PO2 (<60 mmHg), high CO₂, low pH — the backup hypoxic drive.
MCAT note: This ~100 mmHg matches the lung value in the dissociation table. At altitude, Patm falls → PIO falls → drops, triggering the hypoxic ventilatory response.
</details>
<details>
<summary><b>Example 2: Calculate O₂ delivered per minute</b></summary>
Question: Hb = 15 g/dL, each gram of Hb carries 1.34 mL O₂ at full saturation, arterial saturation = 98%, cardiac output = 5 L/min. Approximate O₂ delivery to tissues (ignore dissolved O₂).
Solution:
O₂ content ≈15×1.34×0.98≈19.7 mL O₂ / dL = 197 mL/L.
Interpretation: Anemia (lower Hb) cuts delivery proportionally even with normal saturation — this is why SpO2 alone can mask poor O₂ delivery. The body compensates by raising cardiac output.
</details>
<details>
<summary><b>Example 3: Predict the acid–base effect of hyperventilation</b></summary>
Question: A panicking patient hyperventilates, dropping arterial PCO2 from 40 to 25 mmHg. Using the carbonic anhydrase equilibrium, predict the change in blood pH and the curve shift.
Solution:
CO2+H2O⇌H. Lowering CO₂ pulls the reaction LEFT → fewer H⁺ → (respiratory alkalosis). ✓
High-yield connection: Breathing into a bag re-raises CO₂, restoring pH and curve position. CO₂, not O₂, is the master regulator of ventilation.
</details>
Key Takeaways — Part 2
Gas exchange driven by partial pressure gradients (Fick's law: Vgas∝A(P1−P2)/T)
O2 transport: 98.5% on hemoglobin (cooperative binding, sigmoidal curve)
Bohr effect: right shift = more O2 release (higher CO2, lower pH, higher temp, ↑2,3-BPG)
PBS = Bowman's space hydrostatic pressure (pushes IN, ~15 mmHg)
πGC = glomerular oncotic pressure (pulls IN, ~30 mmHg)
πBS ≈ 0 (essentially protein-free filtrate)
GFR is regulated by adjusting afferent vs. efferent arteriole tone — this is the single most testable renal concept.
Renal Clearance & the Filtration Equation
Cx=PxUx⋅V
where Ux = urine concentration of substance x, V = urine flow rate, Px = plasma concentration.
Inulin is freely filtered, not reabsorbed or secreted → its clearance EQUALS GFR.
PAH (para-aminohippurate) is filtered AND maximally secreted → its clearance estimates renal plasma flow (RPF).
If Cx> GFR → net secretion. If Cx< GFR → net reabsorption.
Countercurrent Multiplier (How Concentrated Urine Is Made)
The thick ascending limb actively pumps Na⁺/K⁺/2Cl⁻ out (impermeable to water), making the medullary interstitium hyperosmotic (up to ~1200 mOsm). The descending limb (water-permeable, solute-impermeable) loses water passively into that gradient. The vasa recta preserve the gradient via countercurrent EXCHANGE. ADH then lets water exit the collecting duct down this gradient → concentrated urine.
Renal System 🎯
Worked Examples — Renal Physiology
<details>
<summary><b>Example 1: Compute net glomerular filtration pressure</b></summary>
Question: Given PGC=55 mmHg, PBS=15 mmHg, πGC=28 mmHg, πBS=0. What is the net filtration pressure, and which direction does fluid move?
Solution:Pnet=(P
Positive → net filtration OUT of the capillary into Bowman's space. ✓
MCAT twist: If a patient develops hypoalbuminemia (low plasma protein, e.g., nephrotic syndrome or liver failure), πGC falls. With πGC=18: mmHg → GFR rises. Conversely, a ureteral stone raises and lowers GFR.
</details>
<details>
<summary><b>Example 2: Calculate renal clearance and classify handling</b></summary>
Question: A substance has plasma concentration Px=2 mg/mL, urine concentration Ux=60 mg/mL, and urine flow rate mL/min. GFR (by inulin) = 120 mL/min. Is this substance secreted, reabsorbed, or neither?
Solution:Cx=Px
Clearance (30) < GFR (120) → the tubule reabsorbs most of the filtered substance. ✓
Interpretation: Filtered load = GFR × Px = 120 × 2 = 240 mg/min. Excreted = Ux × V = 60 mg/min. Reabsorbed = 240 − 60 = 180 mg/min (75% reabsorbed). This is the kind of multi-step data problem the Bio/Biochem section loves.
</details>
<details>
<summary><b>Example 3: Predict the effect of a loop diuretic</b></summary>
Question: Furosemide blocks the Na⁺/K⁺/2Cl⁻ cotransporter in the thick ascending limb. Predict its effect on (a) the medullary osmotic gradient and (b) urine volume.
Solution:
The thick ascending limb normally pumps NaCl into the interstitium to build the medullary gradient.
Blocking the cotransporter → less NaCl deposited → the medullary gradient COLLAPSES.
Without a steep gradient, the collecting duct cannot extract water even when ADH is present.
Result: large volume of dilute urine (powerful diuresis), plus K⁺ wasting (K⁺ no longer recycled). ✓
High-yield connection: This is why loop diuretics are the strongest class — they attack the gradient itself, not just one segment's transport.
Flow: fatty/acidic chyme enters duodenum → secretin + CCK released → pancreas dumps bicarbonate (raises pH to the ~8 optimum for pancreatic enzymes) and enzymes; gallbladder ejects bile → fat emulsified and digested. This is a negative-feedback brake: duodenal contents signal back to slow the stomach until the small intestine catches up.
Absorption
Duodenum: Iron, calcium
Jejunum: Most nutrients (amino acids, sugars, fatty acids)
Ileum: Bile salts (recycled via enterohepatic circulation), vitamin B12
Large intestine: Water, electrolytes
Carbohydrate Absorption Mechanism
Glucose/galactose enter enterocytes via SGLT1 (secondary active transport powered by the Na⁺ gradient from the basolateral Na⁺/K⁺ ATPase), then exit to blood via GLUT2. Fructose enters by facilitated diffusion via GLUT5. This Na⁺-coupled uptake is why oral rehydration therapy pairs glucose with sodium.
Digestive System 🎯
Worked Examples — Digestive Physiology
<details>
<summary><b>Example 1: Predict the response to a fatty meal</b></summary>
Question: A subject eats a high-fat meal. Trace the hormonal cascade and predict the effect on gastric emptying.
Solution:
Fats and amino acids reach the duodenum → I cells release CCK.
MCAT note: Slowed gastric emptying after fat is adaptive — it prevents overwhelming the small intestine's limited digestive/absorptive capacity. Fatty meals therefore "sit heavy."
</details>
<details>
<summary><b>Example 2: Diagnose a malabsorption pattern</b></summary>
Question: A patient has chronic pancreatitis with destroyed exocrine pancreas. Which nutrients are most affected, and what stool finding appears?
Solution:
Loss of pancreatic lipase → triglycerides not digested → fat malabsorption.
Fat-soluble vitamins (A, D, E, K) are also malabsorbed → e.g., vitamin K deficiency → bleeding tendency.
Interpretation: Because the pancreas supplies the major proteases, lipase, and amylase, its failure impairs all three macronutrient classes, but fat malabsorption is the most clinically obvious.
</details>
<details>
<summary><b>Example 3: Reason about Na⁺-coupled glucose uptake</b></summary>
Question: A drug blocks the basolateral Na⁺/K⁺ ATPase in enterocytes. Predict the effect on intestinal glucose absorption via SGLT1.
Solution:
SGLT1 is secondary active transport — it uses the inward Na⁺ gradient to drag glucose into the cell against its gradient.
The Na⁺/K⁺ ATPase pumps Na⁺ out the basolateral side to MAINTAIN that gradient.
Block the pump → intracellular Na⁺ rises → the Na⁺ gradient collapses → SGLT1 can no longer import glucose. ✓
High-yield connection: This is the textbook example of how a primary active pump powers a secondary active transporter — and why oral rehydration solutions combine glucose with sodium to maximize co-transport.
</details>
Key Takeaways — Part 3
Know all digestive enzymes with their sources and substrates
Bile emulsifies fat (liver-made, gallbladder-stored); B12 + bile salts absorbed in ileum
PTH
Raises Ca2+ (bone resorption)
Adrenal cortex
Cortisol, aldosterone, androgens
Stress, Na+/K+, sex
Adrenal medulla
Epinephrine, norepinephrine
Fight-or-flight
Pancreas
Insulin (β), Glucagon (α)
Blood glucose regulation
Hormone Classes & Signaling (Mechanism)
Class
Examples
Solubility
Receptor location
Speed/Duration
Peptide
Insulin, glucagon, ADH, GH
Hydrophilic
Cell-surface (→ cAMP/IP₃ second messengers)
Fast, short
Steroid
Cortisol, aldosterone, sex hormones
Lipophilic
Intracellular/nuclear (→ alter gene transcription)
Slow, long
Amino-acid-derived
T3/T4 (lipophilic), epinephrine (hydrophilic)
Mixed
T3/T4 nuclear; catecholamines surface
Varies
Key principle: lipophilic hormones travel bound to carrier proteins, cross membranes, and change transcription (slow but lasting). Hydrophilic hormones can't cross membranes, so they use surface receptors and second messengers (fast but transient).
The HPA Axis (Three-Level Cascade + Feedback Loop)
Cortisol exerts negative feedback on BOTH the hypothalamus (↓CRH) and pituitary (↓ACTH). The thyroid axis (TRH → TSH → T3/T4) works identically. This feedback logic lets you localize disease:
Negative feedback (default): product inhibits its own production (T3/T4 ⊣ TSH; cortisol ⊣ ACTH).
Positive feedback (rare): oxytocin in labor (contractions → more oxytocin → stronger contractions); the LH surge that triggers ovulation.
Endocrine 🎯
Worked Examples — Endocrine Physiology
<details>
<summary><b>Example 1: Localize a thyroid disorder from lab values</b></summary>
Question: A patient is fatigued and cold-intolerant. Labs: low T3/T4, high TSH. Where is the lesion?
Solution:
Low T3/T4 → hypothyroid symptoms.
With negative feedback intact, low T3/T4 should DISinhibit TSH → TSH rises. The pituitary is responding correctly. ✓
High TSH + low T3/T4 ⇒ the thyroid gland itself cannot respond → primary hypothyroidism (e.g., Hashimoto's or iodine deficiency).
MCAT note: "Tropic hormone HIGH, target hormone LOW" almost always means the END gland failed (primary). Reverse both ⇒ pituitary failure (secondary).
</details>
<details>
<summary><b>Example 2: Predict the hormonal response to fasting</b></summary>
Question: A subject fasts 16 hours. Predict the changes in insulin and glucagon and the metabolic consequence.
Solution:
Falling blood glucose → β cells secrete less insulin, α cells secrete more glucagon. ✓
High glucagon/insulin ratio → hepatic glycogenolysis then gluconeogenesis, plus adipose lipolysis → ketone production.
Result: blood glucose is defended near normal while the body shifts to fat/ketone fuel.
Interpretation: Insulin and glucagon are antagonists; the MCAT cares about the RATIO, not absolute levels. A high insulin/glucagon ratio = storage; low = mobilization.
</details>
<details>
<summary><b>Example 3: Reason through a calcium feedback loop</b></summary>
Question: A patient's parathyroid glands are accidentally removed during thyroid surgery. Predict the change in serum Ca²⁺ and the symptom.
Solution:
No PTH → loss of bone resorption, less renal Ca²⁺ reabsorption, less vitamin-D activation → serum Ca²⁺ falls (hypocalcemia). ✓
High-yield connection: PTH is the dominant minute-to-minute Ca²⁺ regulator. Without it, calcitonin cannot compensate (calcitonin only lowers Ca²⁺), so hypocalcemia results. Hyperparathyroidism does the opposite: bone pain, kidney stones, "stones, bones, groans."
All-or-none: once threshold is reached the spike is fixed in amplitude; stimulus strength is encoded by frequency, not size. The Nernst equation sets each ion's equilibrium potential:
Eion=z61log[ion]in[ion]outmV
EK≈−90 mV and ENa≈+60 mV; resting Vm sits near EK because the membrane is most permeable to K⁺ at rest.
Refractory Periods (Why APs Go One Way)
Absolute refractory period: Na⁺ channels inactivated → no new AP regardless of stimulus. Ensures unidirectional propagation and caps maximum firing rate.
Relative refractory period: some Na⁺ channels recovered, but K⁺ efflux makes threshold harder → only a strong stimulus fires.
Saltatory Conduction
Myelin (Schwann cells in PNS, oligodendrocytes in CNS) insulates axons; APs regenerate only at nodes of Ranvier, "jumping" node to node. This speeds conduction ~10–100×. Multiple sclerosis demyelinates CNS axons → conduction slows or fails.
Synaptic Transmission (Flow)
AP reaches terminal→Ca2+ influx→Vesicle fusion→NT release→Binds receptor
MCAT note: Resting Vm (~−70 mV) sits close to EK because the membrane is most K⁺-permeable at rest. Hyperkalemia (raised external K⁺) makes less negative → resting cells partially depolarize → dangerous cardiac arrhythmias.
</details>
<details>
<summary><b>Example 2: Predict the effect of an acetylcholinesterase inhibitor</b></summary>
Question: An organophosphate pesticide inhibits acetylcholinesterase at the neuromuscular junction. Predict the effect on muscle.
Solution:
Acetylcholinesterase normally clears ACh from the synapse.
Inhibit it → ACh accumulates → receptors are continuously activated → sustained depolarization.
The motor end plate cannot repolarize/reset → depolarizing block → muscle fasciculations then paralysis. ✓
Interpretation: Too much "go" signal is as paralyzing as too little — the channels stay inactivated. This is why nerve-agent poisoning causes the "SLUDGE" cholinergic crisis plus respiratory muscle failure.
</details>
<details>
<summary><b>Example 3: Reason about synaptic summation</b></summary>
Question: A neuron has threshold at −55 mV and rests at −70 mV. A single EPSP depolarizes it by +8 mV; a single IPSP hyperpolarizes by −5 mV. If two EPSPs and one IPSP arrive nearly simultaneously, does the neuron fire?
Solution:
Net change = 2(+8)+1(−5)=+16−5=+11 mV.
New mV. ✓
High-yield connection: This is spatial summation at the axon hillock — the neuron integrates excitatory and inhibitory inputs. One more EPSP (+8) would push it to −51 mV and trigger a spike. Stimulus strength is then coded by firing FREQUENCY, not spike size.
T-cell activation requires two signals: (1) TCR binds the peptide–MHC complex, and (2) a costimulatory signal (e.g., B7–CD28). Signal 1 without signal 2 → anergy (tolerance) — a built-in brake against autoimmunity.
Primary vs. Secondary Response (Figure)
Feature
Primary response (first exposure)
Secondary response (re-exposure)
Lag time
Long (~5–10 days)
Short (1–3 days)
Dominant antibody
IgM first, then IgG
IgG (class-switched, high affinity)
Magnitude
Lower antibody titer
Much higher, faster titer
Basis
Naïve B cells activating
Memory B cells
This memory curve is the entire logic of vaccination: a harmless primary exposure (antigen) generates memory cells so the real pathogen meets a fast, strong secondary response.
Clonal Selection & Antibody Maturation
A vast pre-existing repertoire of B/T cells (generated by V(D)J recombination) means an antigen "selects" the few lymphocytes whose receptors already fit; those clones proliferate. In germinal centers, B cells undergo somatic hypermutation + class switching (IgM → IgG/IgA/IgE), raising affinity and tailoring effector function.
Complement, Opsonization & NK Cells (Innate ↔ Adaptive Bridge)
Opsonization: antibody (IgG) or complement (C3b) coats a pathogen → tags it for phagocytosis ("opsonin = butter for the phagocyte").
NK cells kill cells with absent/low MHC I ("missing self") — many viruses and tumors downregulate MHC I to evade CD8+ T cells, but that very loss flags them for NK killing.
Immune System 🎯
Worked Examples — Immunology Reasoning
<details>
<summary><b>Example 1: Interpret an antibody-titer graph</b></summary>
Question: A graph shows antibody titer vs. time. After the first antigen exposure, IgM rises slowly over ~7 days then falls. After a second exposure weeks later, a much taller, faster curve appears, dominated by IgG. Explain the two curves.
Solution:
First curve = primary response: naïve B cells need time to activate; IgM appears first (slow, low). ✓
Second curve = secondary response: memory B cells respond in 1–3 days with high-affinity, class-switched IgG (fast, tall).
MCAT note: "IgM = recent/first, IgG = past/memory" lets you date an infection from serology: high IgM ⇒ acute; high IgG with low IgM ⇒ prior exposure or vaccination.
</details>
<details>
<summary><b>Example 2: Predict the effect of losing CD4+ T cells (HIV)</b></summary>
Question: HIV destroys CD4+ helper T cells. Predict the impact on both humoral and cell-mediated immunity.
Solution:
CD4+ Th cells provide cytokine "help" that activates B cells AND boosts CD8+ cytotoxic T cells.
Lose CD4+ → B-cell antibody responses weaken AND CD8+ activation falters → both arms collapse. ✓
Result: opportunistic infections and certain cancers (e.g., by reactivated viruses) — defining AIDS.
Interpretation: The helper T cell is the central coordinator; removing it cripples the whole adaptive system, illustrating why CD4 count tracks immune competence.
</details>
<details>
<summary><b>Example 3: Reason about a transfusion / opsonization scenario</b></summary>
Question: A bacterium is coated with IgG and C3b. A macrophage encounters it. What process is occurring, and why is the bacterium cleared faster than an uncoated one?
Solution:
IgG and C3b are opsonins — they coat ("butter") the pathogen surface.
Macrophages bear Fc receptors (for IgG) and complement receptors (for C3b) → they bind the coated bacterium far more avidly.
This opsonization dramatically increases phagocytosis vs. an uncoated cell. ✓
High-yield connection: Opsonization links adaptive (antibody) and innate (complement, phagocyte) immunity. Asplenic patients clear encapsulated bacteria poorly because the spleen is a major site of opsonin-dependent clearance.
</details>
Organ Systems — Complete! ✅
From cardiovascular to immune, organ systems make up the bulk of MCAT biology.
Innate = fast, broad, no memory; adaptive = slow, specific, memory (the basis of vaccination)
MHC I (all nucleated cells) → CD8+; MHC II (APCs) → CD4+; T cells need two signals (or anergy)
Primary response = IgM, slow; secondary = IgG, fast, from memory B cells
NK cells kill "missing self" (low MHC I); opsonization (IgG/C3b) bridges adaptive and innate
Know the key structures, functions, and regulatory mechanisms for each system. Integration between systems (e.g., kidney + endocrine, nervous + cardiovascular) is frequently tested.
0.21
=
713×
0.21≈
150
Alveolar gas equation: PAO2=PIO2−PCO2/R=150−40/0.8=150−50=100 mmHg ✓
2
PAO2
+
+
HCO3−
pH rises
Higher pH + lower CO₂ → LEFT shift of the O₂–Hb curve (reverse Bohr) → Hb holds O₂ more tightly → reduced tissue unloading, contributing to lightheadedness.
GC
−
PBS)−
(πGC−
πBS)=
(55−
15)−
(28−
0)=
40−
28=
+12 mmHg
Pnet=40−18=+22
PBS
V=1
Ux⋅V
=
260×1=
30 mL/min
[K+]out
=
EK
Vm
=
−70+
11=
−59
−59 mV has NOT reached the −55 mV threshold → no action potential.