Part 1 of 5 — Quantum Numbers & Electron Configuration
Atomic structure is tested in virtually every MCAT general chemistry passage. Questions focus on quantum number rules, electron configurations, and predicting properties from position on the periodic table.
The Four Quantum Numbers
Every electron in an atom is described by a unique set of four quantum numbers:
Aufbau Principle: Fill lowest-energy orbitals first.
Order: 1s,2s,2p,3s,3p,4s,3d,4p,5s,
Writing Electron Configurations — Examples
Carbon (Z=6):1s22s22p
Iron (Z=26):[Ar]3d64s2
Noble-gas shorthand: write the preceding noble gas in brackets, then continue.
Fe²⁺: Remove electrons from the outermost shell first (4s before 3d). Fe2+:[Ar]3d6
Fe³⁺:[Ar]3d5
Note: 3d5 is a half-filled subshell — extra stability.
Exceptions to Aufbau
Two common MCAT exceptions:
Chromium (Z=24): Expected [Ar]3d44s2; Actual — half-filled is stabilized.
Quantum Numbers & Configuration — Check Your Understanding 🎯
Worked Example: Identifying an Element from Configuration
A neutral atom has the electron configuration [Ne]3s23p4.
Step 1 — Count total electrons:
Ne has 10 electrons. Add 3s more → .
Configuration Application Questions 🎯
Key Takeaways — Part 1
ℓ ranges from 0 to n−1;mℓ ranges from to . Impossible combos are a common MCAT trap.
Part 2: Periodic Trends
Atomic Structure & Periodic Trends
Part 2 of 5 — Periodic Trends: Atomic Radius, Ionization Energy & Electronegativity
Periodic trends follow directly from effective nuclear charge (Zeff) — the net positive charge an outer electron "feels" after inner electrons partially shield it.
Ze
Part 3: Spectra, PES & Bohr Model
Atomic Structure & Periodic Trends
Part 3 of 5 — Emission Spectra, Photoelectron Spectroscopy & the Bohr Model
These topics appear frequently in MCAT passages because they connect quantum mechanics to experimental data. You won't need to derive the equations — but you must interpret graphs and predict relative values.
The Bohr Model (Hydrogen-Like Atoms)
Bohr proposed that electrons orbit the nucleus only at specific, quantized energy levels.
Energy of Level n in Hydrogen:
En
Part 4: Nuclear Chemistry & Half-Life
Atomic Structure & Periodic Trends
Part 4 of 5 — Nuclear Chemistry: Radioactive Decay & Half-Life
Nuclear chemistry is a distinct but related MCAT topic. You need to recognize decay types, balance nuclear equations, and calculate remaining quantity using half-life.
Types of Radioactive Decay
Type
Symbol
Change in A
Change in Z
What's emitted
Alpha decay
α
Part 5: Mixed MCAT Review
Atomic Structure & Periodic Trends
Part 5 of 5 — Mixed MCAT Review: Passage-Style Practice
This final part uses integrated questions that combine quantum numbers, periodic trends, spectra, and nuclear chemistry — exactly as the MCAT mixes topics within a single passage.
Quick-Reference Summary
Quantum Number Rules
n: positive integer ≥1
ℓ: 0 to
−21
Electron spin
→
d
ℓ=3→f
4
d
,
5
p
,
…
Pauli Exclusion Principle: No two electrons in the same atom can have identical quantum numbers. Each orbital holds at most 2 electrons with opposite spins.
Hund's Rule: Within a subshell, place one electron in each orbital before pairing. All singly-occupied orbitals have the same spin (maximizes multiplicity).
2
[Ar]3d54s1
3d
Copper (Z=29): Expected [Ar]3d94s2; Actual [Ar]3d104s1 — fully-filled 3d is stabilized.
2
3
p4
=
6
16 total electrons
Step 2 — Identify the element: Z=16 is sulfur (S).
Step 3 — Determine unpaired electrons:
The 3p4 configuration: by Hund's rule, fill each of the 3 p-orbitals with one electron first → 3p: ↑↓ ↑ ↑ → 2 unpaired electrons.
Step 4 — Common ion:
S typically gains 2 electrons to form S2−, achieving the [Ar] configuration (3p6).
MCAT Trap: 4s vs. 3d Removal Order
Students often think 3d electrons (lower n) are removed before 4s when forming cations. This is wrong. The outermost shell electrons are always removed first (highest n). Once the 4s electrons are gone, the 3d orbitals become lower in energy than 4s due to reduced shielding.
−ℓ
+ℓ
Aufbau order:1s,2s,2p,3s,3p,4s,3d,4p… Note 4s fills before 3d.
Hund's rule: maximize unpaired electrons within a subshell.
Cr (3d54s1) and Cu (3d104s1): exceptions due to stability of half-filled and fully-filled d subshells.
Isoelectronic species share the same electron configuration; differ in nuclear charge.
ff
=
Z−
σ
where Z = atomic number, σ = shielding constant (approximately equal to the number of inner-shell electrons).
Atomic Radius
Trend: ↑ down a group, ↓ across a period (left to right).
Factor
Effect
More electron shells (down a group)
Increases radius
Higher Zeff same shell (across period)
Pulls electrons closer, decreases radius
Cation vs. anion radius:
Cations are smaller than the neutral atom (fewer electrons, same or similar Zeff, electrons pulled closer).
Anions are larger than the neutral atom (more electrons → more electron-electron repulsion, expanded cloud).
Isoelectronic series (all 10 electrons): N3−>O2−>F−>Ne>Na+>Mg2+>Al3+
As Z increases across the series, same electron count is pulled harder → smaller radius.
Ionization Energy (IE)
Energy required to remove one electron from a gaseous atom: X(g)→X+(g)+e−
Trend: ↓ down a group, ↑ across a period — opposite of atomic radius.
Successive ionization energies: Each successive IE is larger (removing from a more positive ion). A large jump between IEn and IEn+1 means you crossed into a core shell.
Example — Sodium (Z=11, config [Ne]3s1):
IE1≈496 kJ/mol (remove 3s1, easy)
IE2≈4,562 kJ/mol (must break into the filled Ne core → huge jump)
This is how the MCAT can ask you to identify an element's group from a table of successive IEs.
Exceptions to the across-period IE trend:
Group IIA → Group IIIA:IE drops slightly (e.g., Mg>Al) because Al removes a 3p electron, which is shielded by the 3s pair.
Group VA → Group VIA:IE drops slightly (e.g., P>S) because S has a paired 3p electron with extra repulsion, making it easier to remove.
Electronegativity
Tendency to attract bonding electrons. Measured by the Pauling scale.
Trend: Increases across a period, decreases down a group. Most electronegative: F (3.98) Least electronegative (among metals): Cs/Fr
Electronegativity difference predicts bond type:
ΔEN<0.5: nonpolar covalent
0.5≤ΔEN<1.7: polar covalent
ΔEN≥1.7: ionic character
Electron Affinity (EA)
Energy change when a gaseous atom gains one electron: X(g)+e−→X−(g)
Generally becomes more negative (more exothermic) across a period and up a group.
Exceptions:
Group IIA (filled s subshell) and Group VA (half-filled p subshell) have near-zero or positive EA — extra stability makes electron gain unfavorable.
Noble gases have positive EA (no tendency to gain electrons).
Periodic Trends — Check Your Understanding 🎯
Trend Summary Table
Property
Across Period (→)
Down Group (↓)
Reason
Atomic radius
Decreases
Increases
Zeff vs. more shells
1st Ionization Energy
Increases*
Decreases
Harder to remove e⁻ from higher Zeff; farther e⁻ easier to remove
Electronegativity
Increases
Decreases
Same logic as IE
Electron Affinity
More negative*
Less negative
Higher Zeff attracts added e⁻ more
Metallic character
Decreases
Increases
Inversely related to IE
*With minor exceptions as discussed above.
Worked Example: Predicting Properties
Question: Without looking at a table, which has a higher first ionization energy — O or F?
Reasoning: Both are in Period 2. F is one position to the right of O, so it has a higher Zeff. However, O (3p4 analogy: 2p, paired electron) vs F () — F has no extra pairing repulsion disadvantage in removing one electron. F has higher AND no extra repulsion penalty → . ✓ (confirmed: kJ/mol; kJ/mol)
Electronegativity & Special Cases 🎯
Key Takeaways — Part 2
Zeff is the engine behind all periodic trends. Higher Zeff → smaller radius, higher IE, higher EN.
Atomic radius: largest at bottom-left (Cs), smallest at top-right (He/F among main-group).
IE exceptions: Group IIA > Group IIIA; Group VA > Group VIA — memorize the explanations.
Isoelectronic series: size decreases as Z increases (same electrons, more protons).
Cations are smaller, anions are larger than their neutral atoms.
EA exceptions: Group IIA and Group VA have near-zero/positive EA due to subshell stability.
On the MCAT, successive IE data is a reliable way to identify an element's group.
=
−n213.6 eV=
−n22.18×10−18 J
Negative sign: electron is bound to the nucleus (energy =0 at n=∞, ionized).
Ground state:n=1, most negative energy, most stable.
Excited state:n>1; higher energy (less negative).
Energy of a Photon Emitted During a Transition:
ΔE=Efinal−Einitial=−13.6(nf21−n
For a downward transition (ni>nf): ΔE<0, photon is emitted.
For an upward transition (nf>ni): ΔE>0, photon is absorbed.
Ephoton=hν=λhc
where h=6.626×10−34 J·s, c=3.0×108 m/s.
Spectral Series in Hydrogen
Series
Final level nf
Region
Lyman
1
Ultraviolet
Balmer
2
Visible (some UV)
Paschen
3
Infrared
MCAT rule: The largest energy photon in a series is the transition from n=∞ (ionization) to nf. The smallest energy photon is the adjacent transition (n=nf+1 to n=nf).
Photoelectron Spectroscopy (PES)
PES bombards a sample with high-energy photons (UV or X-ray). Electrons are ejected, and their kinetic energy is measured.
KE=hν−BE
where BE = binding energy (energy needed to remove the electron from that subshell).
Interpreting a PES Spectrum
X-axis: Binding energy (increases left to right, or right to left depending on convention — read the axis label!)
Y-axis: Relative number of electrons (peak area/height)
Each peak corresponds to one subshell
Core electrons (inner subshells) have higher binding energy than valence electrons
Peak relative height ∝ number of electrons in that subshell
Example — Sodium (Na, [Ne]3s1):
Peaks at high BE: 1s (2 electrons), 2s (2 electrons), 2p (6 electrons)
Peak at low BE: 3s (1 electron)
The 3s peak is half the height of 2s or 1s (only 1 electron vs. 2)
The 2p peak is 3× the height of 2s (6 electrons vs. 2)
Emission Spectra & Bohr Model 🎯
Wave-Particle Duality & de Broglie Wavelength
Louis de Broglie proposed that matter has wave-like properties. For a particle with momentum p=mv:
λ=mvh
MCAT implication: Electrons (small mass) have observable wavelengths. Macroscopic objects have negligible wavelengths.
You cannot simultaneously know both position and momentum exactly. This is why quantum mechanics uses probability orbitals (regions where electrons are likely to be) rather than fixed orbits.
Worked Example: Photon Energy
Calculate the energy and wavelength of a photon emitted during the n=3→n=1 transition in hydrogen.
ΔE=13.6(121
Convert to joules: 12.09×1.602×10−19=1.94×10−18 J
λ=Ehc=
This is ultraviolet (Lyman series, nf=1).
PES Interpretation & Wave-Particle Duality 🎯
Key Takeaways — Part 3
Bohr model:En=−13.6/n2 eV for H. Downward transitions emit photons; upward absorb.
PES peaks: lowest BE = valence electrons (outermost); highest BE = core electrons (1s).
Peak area ∝ number of electrons in that subshell. Use it to identify elements.
de Broglie:λ=h/(mv); electrons have measurable wavelengths; macroscopic objects do not.
Heisenberg: Position and momentum cannot both be known exactly — basis for orbital (probability cloud) model.
−4
−2
24He nucleus
Beta-minus decay
β−
0
+1
Electron + antineutrino
Beta-plus (positron)
β+
0
−1
Positron + neutrino
Gamma
γ
0
0
High-energy photon
Electron capture
EC
0
−1
X-ray photon emitted
where A = mass number (protons + neutrons), Z = atomic number (protons).
Alpha decay example:92238U→90234Th+24He
Beta-minus decay example: A neutron converts to a proton.
614C→714N+−10e+νˉ
Conservation Laws in Nuclear Reactions
Mass number (A) is conserved: sum of A on left = sum on right.
Atomic number (Z) is conserved: sum of Z on left = sum on right.
Charge is conserved.
These laws let you identify unknown products:
Example:90234Th undergoes beta-minus decay. What is the product?
A: 234=234+0 ✓ (unchanged)
Z: 90=(Zproduct)+(−1) → Zproduct=91
Z=91 is Protactinium (Pa): 91234Pa
Half-Life
The half-life t1/2 is the time for half of a radioactive sample to decay.
N(t)=N0(21)t/t1/2=N0e−λt
where λ=ln2/t1/2 is the decay constant.
MCAT shortcut: Work in units of half-lives.
Number of half-lives
Fraction remaining
Percent remaining
0
1
100%
1
1/2
50%
2
1/4
25%
3
1/8
12.5%
4
1/16
6.25%
Worked Example:
A 40 g sample of 131I (t1/2=8 days) remains after 32 days. How much is left?
32÷8=4 half-lives.
Remaining=40×(1/2)4=40/16=2.5 g
Binding Energy & Mass Defect
The nucleus is lighter than the sum of its individual protons and neutrons. This mass defectΔm is the mass converted to energy that holds the nucleus together.
E=Δm⋅c2(Einstein’s equation)
Binding energy per nucleon is maximized around iron-56 (56Fe) — this is the most stable nucleus. Elements heavier than Fe release energy by fission; lighter elements release energy by fusion.
Nuclear Decay & Balancing 🎯
Half-Life Applications in Medicine
Nuclear medicine relies on radioactive isotopes with appropriate half-lives:
99mTc (t1/2=6 h): Most common medical imaging isotope. Short half-life minimizes patient radiation dose. Emits gamma rays detected by SPECT scanners.
131I (t1/2=8 d): Treats thyroid cancer and hyperthyroidism. Iodine concentrates in the thyroid gland; beta emission destroys tissue locally.
18F (t1/2=110 min): Used in PET scanning (positron emission). Short half-life means it must be made on-site at a cyclotron.
Radiocarbon Dating
14C (t1/2=5,730 years) is used to date organic materials up to ~50,000 years old. Living organisms maintain a constant ratio of through metabolism. After death, decays. Measuring the remaining ratio gives the age.
MCAT Worked Problem:
A wood sample contains 12.5% of its original 14C. How old is the sample? (t1/2=5,730 years)