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🎯⭐ INTERACTIVE LESSON

Logarithmic Functions

Learn step-by-step with interactive practice!

Logarithmic Functions - Complete Interactive Lesson

Part 1: Introduction to Logarithms

📖 Logarithmic Functions — Definition & Inverse Relation

Part 1 of 7

A logarithm answers: "What exponent do I need?"

log⁡bx=y  ⟺  by=x\boxed{\log_b x = y \iff b^y = x}

"log⁡\log base bb of xx equals yy" means "bb raised to yy gives xx."

The Three Standard Bases

NotationNameBaseCalculator Key
log⁡x\log xCommon log1010LOG
ln⁡x\ln xNatural loge≈2.718e \approx 2.718LN
log⁡bx\log_b xGeneral logbbUse change of base

Quick Conversion Examples

Exponential FormLogarithmic Form
25=322^5 = 32log⁡232=5\log_2 32 = 5
103=100010^3 = 1000log⁡1000=3\log 1000 = 3
e1=ee^1 = eln⁡e=1\ln e = 1
50=15^0 = 1log⁡51=0\log_5 1 = 0
3−2=193^{-2} = \frac{1}{9}log⁡319=−2\log_3 \frac{1}{9} = -2

🔄 Logs and Exponentials Are Inverses

If f(x)=bxf(x) = b^x, then f−1(x)=log⁡bxf^{-1}(x) = \log_b x.

Inverse Properties — they undo each other:

log⁡b(bx)=xandblog⁡bx=x\boxed{\log_b(b^x) = x \quad \text{and} \quad b^{\log_b x} = x}

ExpressionSimplifies ToWhy
log⁡2(27)\log_2(2^7)77Log undoes the exponential
10log⁡5010^{\log 50}5050Exponential undoes the log
ln⁡(e−3)\ln(e^{-3})−3-3ln⁡\ln undoes exe^x
eln⁡12e^{\ln 12}1212exe^x undoes ln⁡\ln

Graphical Connection

The graph of y=log⁡bxy = \log_b x is the reflection of y=bxy = b^x over the line y=xy = x.

Featurey=bxy = b^x (with b>1b > 1)y=log⁡bxy = \log_b x
Domain(−∞,∞)(-\infty, \infty)(0,∞)(0, \infty)
Range(0,∞)(0, \infty)(−∞,∞)(-\infty, \infty)
Asymptotey=0y = 0 (horizontal)x=0x = 0 (vertical)
Passes through(0,1)(0, 1)(1,0)(1, 0)
Another point(1,b)(1, b)(b,1)(b, 1)

📝 Worked Example: Converting & Evaluating

Evaluate log⁡464\log_4 64 without a calculator.

Step 1: Rewrite as an equation: log⁡464=x\log_4 64 = x means 4x=644^x = 64

Step 2: Express both sides as powers of 44:

  • 41=44^1 = 4
  • 42=164^2 = 16
  • 43=644^3 = 64 ✔

log⁡464=3\boxed{\log_4 64 = 3}

Pattern for Evaluating Logs Mentally

StepAction
1Set log⁡bx=?\log_b x = ? → rewrite as b?=xb^? = x
2Find common base or multiply repeatedly
3Match exponents

Key Values to Memorize

| log⁡b1=0\log_b 1 = 0 | Because b0=1b^0 = 1 for any base | | log⁡bb=1\log_b b = 1 | Because b1=bb^1 = b | | log⁡bbn=n\log_b b^n = n | Inverse property |

Concept Check 🎯

Evaluate These Logs 🧮

1) log⁡5125=\log_5 125 = ? (e.g., log⁡264\log_2 64: since 26=642^6 = 64, the answer is 66)

2) log⁡100.001=\log_{10} 0.001 = ? (e.g., log⁡100.01\log_{10} 0.01: since 10−2=0.0110^{-2} = 0.01, the answer is −2-2)

3) ln⁡(e5)=\ln(e^5) = ? (e.g., ln⁡(e−2)\ln(e^{-2}): by inverse property, the answer is −2-2)

Log Fundamentals 🔽

Exit Quiz ✅

Part 2: Properties of Logarithms

📐 Logarithmic Functions — Core Log Properties

Part 2 of 7

Log properties turn multiplication, division, and exponentiation into addition, subtraction, and scalar multiplication.

The Three Fundamental Properties

PropertyRuleDirection
Product Rulelog⁡b(xy)=log⁡bx+log⁡by\log_b(xy) = \log_b x + \log_b yMultiplication → Addition
Quotient Rulelog⁡b(xy)=log⁡bx−log⁡by\log_b\left(\frac{x}{y}\right) = \log_b x - \log_b yDivision → Subtraction
Power Rulelog⁡b(xk)=k⋅log⁡bx\log_b(x^k) = k \cdot \log_b xExponent → Coefficient

⚠️ Critical restriction: These rules only apply to products, quotients, and powers inside the log. There is no rule for log⁡(x+y)\log(x + y) or log⁡(x−y)\log(x - y).

🔓 Expanding Logarithmic Expressions

"Expanding" means using the rules left-to-right to break a single log into simpler pieces.

Worked Example 1

Expand log⁡3(x2yz4)\log_3\left(\frac{x^2 y}{z^4}\right)

StepActionResult
1Quotient rulelog⁡3(x2y)−log⁡3(z4)\log_3(x^2 y) - \log_3(z^4)
2Product rule on first termlog⁡3(x2)+log⁡3y−log⁡3(z4)\log_3(x^2) + \log_3 y - \log_3(z^4)
3Power rule on each2log⁡3x+log⁡3y−4log⁡3z2\log_3 x + \log_3 y - 4\log_3 z

log⁡3(x2yz4)=2log⁡3x+log⁡3y−4log⁡3z\boxed{\log_3\left(\frac{x^2 y}{z^4}\right) = 2\log_3 x + \log_3 y - 4\log_3 z}

Order of Operations for Expanding

  1. Quotient rule first (handle the fraction)
  2. Product rule next (break up any remaining products)
  3. Power rule last (pull exponents out front)

🔒 Condensing Logarithmic Expressions

"Condensing" means running the rules right-to-left to combine multiple logs into one.

Worked Example 2

Condense 3ln⁡a−12ln⁡b+ln⁡c3\ln a - \frac{1}{2}\ln b + \ln c

StepActionResult
1Power rule (reverse)ln⁡a3−ln⁡b1/2+ln⁡c\ln a^3 - \ln b^{1/2} + \ln c
2Combine ++ terms (product)ln⁡(a3c)−ln⁡(b)\ln(a^3 c) - \ln(\sqrt{b})
3Quotient rule (reverse)ln⁡(a3cb)\ln\left(\frac{a^3 c}{\sqrt{b}}\right)

3ln⁡a−12ln⁡b+ln⁡c=ln⁡(a3cb)\boxed{3\ln a - \frac{1}{2}\ln b + \ln c = \ln\left(\frac{a^3 c}{\sqrt{b}}\right)}

Why Condensing Matters

  • Solving equations requires one log on each side
  • Condensing to a single log lets you drop the log and solve the argument

🚫 Common Errors to Avoid

❌ Wrong✅ CorrectWhy
log⁡(x+y)=log⁡x+log⁡y\log(x + y) = \log x + \log yNo simplification existsLog of a sum ≠ sum of logs
log⁡(x−y)=log⁡x−log⁡y\log(x - y) = \log x - \log yNo simplification existsLog of a difference ≠ difference of logs
(log⁡x)2=2log⁡x(\log x)^2 = 2\log x(log⁡x)2(\log x)^2 stays as isSquaring the output ≠ power rule
log⁡xlog⁡y=log⁡xy\frac{\log x}{\log y} = \log\frac{x}{y}log⁡xlog⁡y=log⁡yx\frac{\log x}{\log y} = \log_y xDividing logs = change of base, NOT quotient rule

Quick Memory Aid

The rules work for operations inside the log argument:

  • Inside multiplication → product rule
  • Inside division → quotient rule
  • Inside exponent → power rule

If it's addition or subtraction inside, stop — no rule applies.

Properties Quiz 🎯

Expand & Condense 🧮

1) Expand: log⁡2(8x5)\log_2(8x^5). What is the coefficient of log⁡2x\log_2 x? (e.g., in log⁡3(y4)=4log⁡3y\log_3(y^4) = 4\log_3 y, the coefficient is 44)

2) Condense: log⁡4+log⁡25\log 4 + \log 25. What is the single number inside the resulting log⁡\log? (e.g., log⁡3+log⁡7=log⁡21\log 3 + \log 7 = \log 21, so the number is 2121)

3) Given log⁡b2=0.5\log_b 2 = 0.5 and log⁡b3=0.8\log_b 3 = 0.8. Find log⁡b12\log_b 12, writing your answer as a decimal. (e.g., if log⁡b5=1.2\log_b 5 = 1.2 and log⁡b2=0.5\log_b 2 = 0.5, then log⁡b10=1.2+0.5=1.7\log_b 10 = 1.2 + 0.5 = 1.7)

Rule Identification 🔽

Exit Quiz ✅

Part 3: Solving Logarithmic Equations

📈 Logarithmic Functions — Transformations & Graphs

Part 3 of 7

The general transformed logarithmic function:

g(x)=a⋅log⁡b(x−h)+k\boxed{g(x) = a \cdot \log_b(x - h) + k}

Parameter Effects

ParameterEffectExample
aaVertical stretch ($a
hhHorizontal shift: right if h>0h>0, left if h<0h<0h=3h = 3: shift right 3
kkVertical shift: up if k>0k>0, down if k<0k<0k=−1k = -1: shift down 1
bbBase controls steepness: larger bb = less steepb=10b = 10 vs b=2b = 2

📊 The Parent Function y=log⁡bxy = \log_b x

Key Points of y=log⁡2xy = \log_2 x (parent)

xxy=log⁡2xy = \log_2 x
14\frac{1}{4}−2-2
12\frac{1}{2}−1-1
1100
2211
4422
8833

Features of Every Parent Log Function

FeatureValue
Domain(0,∞)(0, \infty)
Range(−∞,∞)(-\infty, \infty)
xx-intercept(1,0)(1, 0) — always
Vertical asymptotex=0x = 0
Increasing/decreasingIncreasing if b>1b > 1; decreasing if 0<b<10 < b < 1

🔄 Applying Transformations Step by Step

Worked Example

Graph g(x)=−2log⁡3(x+1)+4g(x) = -2\log_3(x + 1) + 4 and identify all key features.

Start from the parent y=log⁡3xy = \log_3 x and track the anchor point (1,0)(1, 0):

StepTransformationAnchor PointVA
Parenty=log⁡3xy = \log_3 x(1,0)(1, 0)x=0x = 0
1. Replace xx with x+1x+1Shift left 11(0,0)(0, 0)x=−1x = -1
2. Multiply by −2-2Reflect & stretch(0,0)(0, 0)x=−1x = -1
3. Add 44Shift up 44(0,4)(0, 4)x=−1x = -1

Key Features of g(x)=−2log⁡3(x+1)+4g(x) = -2\log_3(x + 1) + 4

FeatureValue
Domain(−1,∞)(-1, \infty)
Range(−∞,∞)(-\infty, \infty)
VAx=−1x = -1
New "anchor"(0,4)(0, 4)
BehaviorDecreasing (because a=−2<0a = -2 < 0)

Quick Rules for Domain & VA

Domain of log⁡b(x−h):x>hVA at x=h\boxed{\text{Domain of } \log_b(x - h): \quad x > h \quad \text{VA at } x = h}

🎯 Finding the xx-Intercept Algebraically

Set g(x)=0g(x) = 0 and solve:

−2log⁡3(x+1)+4=0-2\log_3(x + 1) + 4 = 0

log⁡3(x+1)=2\log_3(x + 1) = 2

x+1=32=9x + 1 = 3^2 = 9

x=8x = 8

xx-intercept: (8,0)(8, 0) ✔

General Method

For g(x)=alog⁡b(x−h)+kg(x) = a\log_b(x-h)+k, set g=0g = 0:

log⁡b(x−h)=−ka  ⟹  x=b−k/a+h\log_b(x - h) = -\frac{k}{a} \implies x = b^{-k/a} + h

Finding the yy-Intercept

Set x=0x = 0: only exists if 00 is in the domain (i.e., h<0h < 0).

g(0)=alog⁡b(0−h)+k=alog⁡b(−h)+kg(0) = a\log_b(0 - h) + k = a\log_b(-h) + k

Transformation Quiz 🎯

Graph Analysis 🧮

1) Find the xx-intercept of f(x)=log⁡2(x−3)−4f(x) = \log_2(x - 3) - 4. Set f=0f = 0, solve for xx. (e.g., for log⁡3(x−1)−2=0\log_3(x-1) - 2 = 0: log⁡3(x−1)=2\log_3(x-1) = 2, x−1=9x-1 = 9, x=10x = 10)

2) The domain of g(x)=ln⁡(2x+6)g(x) = \ln(2x + 6) is x>x > what value? (e.g., for ln⁡(3x+9)\ln(3x + 9): set 3x+9>03x + 9 > 0, so x>−3x > -3)

3) If h(x)=5log⁡(x)−10h(x) = 5\log(x) - 10, find h(100)h(100). (e.g., 3log⁡(1000)−6=3(3)−6=33\log(1000) - 6 = 3(3) - 6 = 3)

Transformation Identification 🔽

Exit Quiz ✅

Part 4: Change of Base

🔍 Logarithmic Functions — Solving Log Equations

Part 4 of 7

The Two Core Strategies

StrategyWhen to UseKey Move
Rewrite as exponentialSingle log on one sidelog⁡b(stuff)=c  ⟹  stuff=bc\log_b(\text{stuff}) = c \implies \text{stuff} = b^c
Condense then convertMultiple logsCombine into one log, then convert

⚠️ Always check solutions! Every candidate must make all original log arguments positive.

📝 Type 1: Single Log = Number

Worked Example 1

Solve log⁡3(2x+1)=4\log_3(2x + 1) = 4

StepActionResult
1Convert to exponential2x+1=34=812x + 1 = 3^4 = 81
2Solve linear equation2x=802x = 80
3Isolate xxx=40x = 40
4Check: log⁡3(2(40)+1)\log_3(2(40)+1)=log⁡3(81)=4= \log_3(81) = 4 ✔

x=40\boxed{x = 40}

Worked Example 2

Solve ln⁡(x−3)=2\ln(x - 3) = 2

x−3=e2  ⟹  x=e2+3≈10.389x - 3 = e^2 \implies x = e^2 + 3 \approx 10.389

Check: x−3=e2>0x - 3 = e^2 > 0 ✔

📝 Type 2: Log = Log (One-to-One Property)

If log⁡bA=log⁡bB\log_b A = \log_b B, then A=BA = B (as long as both arguments are positive).

Worked Example 3

Solve log⁡2(x+5)=log⁡2(3x−1)\log_2(x + 5) = \log_2(3x - 1)

x+5=3x−1x + 5 = 3x - 1

6=2x  ⟹  x=36 = 2x \implies x = 3

Check: log⁡2(3+5)=log⁡2(8)=3\log_2(3+5) = \log_2(8) = 3 and log⁡2(3(3)−1)=log⁡2(8)=3\log_2(3(3)-1) = \log_2(8) = 3 ✔

📝 Type 3: Multiple Logs — Condense First

Worked Example 4: Extraneous Solution Alert!

Solve log⁡(x)+log⁡(x−3)=1\log(x) + \log(x - 3) = 1

StepActionResult
1Product rulelog⁡[x(x−3)]=1\log[x(x-3)] = 1
2Convert to exponentialx(x−3)=101=10x(x-3) = 10^1 = 10
3Expandx2−3x−10=0x^2 - 3x - 10 = 0
4Factor(x−5)(x+2)=0(x-5)(x+2) = 0
5Candidatesx=5x = 5 or x=−2x = -2

Domain check — both original arguments must be positive:

  • x=5x = 5: log⁡(5)\log(5) ✔ and log⁡(5−3)=log⁡(2)\log(5-3) = \log(2) ✔ → valid
  • x=−2x = -2: log⁡(−2)\log(-2) ❌ → extraneous, reject

x=5\boxed{x = 5}

⚠️ Why Extraneous Solutions Appear

When you condense logs, you may expand the domain. The product x(x−3)x(x-3) can be positive even when the individual factors aren't both positive. Always check each original log argument separately.

Solving Strategies Quiz 🎯

Solve for xx 🧮

1) log⁡4(3x)=2\log_4(3x) = 2. Find xx. (e.g., log⁡3(2x)=3\log_3(2x) = 3: 2x=272x = 27, x=13.5x = 13.5)

2) log⁡(x)+log⁡(5)=3\log(x) + \log(5) = 3. Find xx. (e.g., log⁡(x)+log⁡(2)=2\log(x) + \log(2) = 2: log⁡(2x)=2\log(2x) = 2, 2x=1002x = 100, x=50x = 50)

3) 2ln⁡(x)=ln⁡(25)2\ln(x) = \ln(25). Find xx. (e.g., 2ln⁡(x)=ln⁡(9)2\ln(x) = \ln(9): ln⁡(x2)=ln⁡(9)\ln(x^2) = \ln(9), x2=9x^2 = 9, x=3x = 3)

Strategy Selection 🔽

Exit Quiz ✅

Part 5: Logarithmic Models

🔀 Logarithmic Functions — Change of Base & Calculator Fluency

Part 5 of 7

Calculators only have LOG (log⁡10\log_{10}) and LN (ln⁡\ln) keys. To evaluate any other base, use the Change of Base Formula:

log⁡bx=log⁡xlog⁡b=ln⁡xln⁡b\boxed{\log_b x = \frac{\log x}{\log b} = \frac{\ln x}{\ln b}}

Why It Works

Starting from log⁡bx=y\log_b x = y:

by=x  ⟹  ln⁡(by)=ln⁡x  ⟹  yln⁡b=ln⁡x  ⟹  y=ln⁡xln⁡bb^y = x \implies \ln(b^y) = \ln x \implies y \ln b = \ln x \implies y = \frac{\ln x}{\ln b}

🧮 Evaluating with Change of Base

Example 1: log⁡750\log_7 50

log⁡750=ln⁡50ln⁡7=3.9121.946≈2.011\log_7 50 = \frac{\ln 50}{\ln 7} = \frac{3.912}{1.946} \approx 2.011

Sanity check: 72=49≈507^2 = 49 \approx 50 ✔ (answer should be slightly above 22)

Example 2: log⁡3100\log_3 100

log⁡3100=log⁡100log⁡3=20.477≈4.192\log_3 100 = \frac{\log 100}{\log 3} = \frac{2}{0.477} \approx 4.192

Sanity check: 34=813^4 = 81 and 35=2433^5 = 243, so answer is between 44 and 55 ✔

Quick Reference for Common Calculations

ExpressionCalculator EntryResult
log⁡210\log_2 10ln⁡(10)/ln⁡(2)\ln(10)/\ln(2)≈3.322\approx 3.322
log⁡530\log_5 30ln⁡(30)/ln⁡(5)\ln(30)/\ln(5)≈2.113\approx 2.113
log⁡81000\log_8 1000log⁡(1000)/log⁡(8)\log(1000)/\log(8)≈3.322\approx 3.322
log⁡0.53\log_{0.5} 3ln⁡(3)/ln⁡(0.5)\ln(3)/\ln(0.5)≈−1.585\approx -1.585

🔗 Useful Relationships from Change of Base

Reciprocal Property

log⁡ba=1log⁡ab\boxed{\log_b a = \frac{1}{\log_a b}}

Example: log⁡28=3\log_2 8 = 3 and log⁡82=13\log_8 2 = \frac{1}{3}. Product: 3×13=13 \times \frac{1}{3} = 1 ✔

Converting Between Bases

To convert log⁡ax\log_a x into log⁡bx\log_b x:

log⁡ax=log⁡bxlog⁡ba\log_a x = \frac{\log_b x}{\log_b a}

Change of Base in Equations

Solve log⁡2x=log⁡35\log_2 x = \log_3 5

Convert right side: log⁡35=ln⁡5ln⁡3≈1.465\log_3 5 = \frac{\ln 5}{\ln 3} \approx 1.465

So log⁡2x=1.465  ⟹  x=21.465≈2.760\log_2 x = 1.465 \implies x = 2^{1.465} \approx 2.760

📊 Graphing Any Log with Change of Base

To graph y=log⁡bxy = \log_b x on a calculator, enter:

y=ln⁡xln⁡by = \frac{\ln x}{\ln b}

Base Comparison Table

Basey=log⁡b(10)y = \log_b(10)Growth RateSteepness
b=2b = 23.3223.322FastestSteepest
b=eb = e2.3032.303MiddleMedium
b=10b = 101.0001.000SlowerFlatter
b=100b = 1000.5000.500SlowestFlattest

Key insight: Larger base = slower growth = flatter curve. All pass through (1,0)(1, 0).

Change of Base Quiz 🎯

Calculator Practice 🧮

1) Evaluate log⁡232\log_2 32 using change of base: log⁡32log⁡2\frac{\log 32}{\log 2}. (e.g., log⁡327=log⁡27log⁡3=1.4310.477=3\log_3 27 = \frac{\log 27}{\log 3} = \frac{1.431}{0.477} = 3)

2) If log⁡47≈1.404\log_4 7 \approx 1.404, find log⁡74\log_7 4 to three decimal places. (e.g., if log⁡35≈1.465\log_3 5 \approx 1.465, then log⁡53=1/1.465≈0.683\log_5 3 = 1/1.465 \approx 0.683)

3) Evaluate log⁡927\log_9 27 exactly. Hint: write both as powers of 33. (e.g., log⁡832\log_8 32: 8=238 = 2^3, 32=2532 = 2^5, so answer is 53\frac{5}{3})

Base Fluency 🔽

Exit Quiz ✅

Part 6: Problem-Solving Workshop

🌍 Logarithmic Functions — Modeling with Logs

Part 6 of 7

Logarithmic scales appear throughout science. They compress enormous ranges into manageable numbers.

Real-World Log Scales

ScaleFormulaWhat It Measures
pHpH=−log⁡[H+]\text{pH} = -\log[H^+]Acidity (hydrogen ion concentration)
DecibelsdB=10log⁡(II0)dB = 10\log\left(\frac{I}{I_0}\right)Sound intensity
RichterM=log⁡(AA0)M = \log\left(\frac{A}{A_0}\right)Earthquake magnitude
Stellar magnitudem=−2.5log⁡(FF0)m = -2.5\log\left(\frac{F}{F_0}\right)Star brightness

Key pattern: All involve log⁡(ratio)\log(\text{ratio}) — they measure how many times larger one quantity is than a reference.

🧪 pH Scale

pH=−log⁡[H+]\boxed{\text{pH} = -\log[H^+]}

Worked Example 1

Orange juice has [H+]=3.2×10−4[H^+] = 3.2 \times 10^{-4} M. Find its pH.

pH=−log⁡(3.2×10−4)\text{pH} = -\log(3.2 \times 10^{-4})

=−(log⁡3.2+log⁡10−4)= -(\log 3.2 + \log 10^{-4})

=−(0.505+(−4))=−(0.505−4)=3.495= -(0.505 + (-4)) = -(0.505 - 4) = 3.495

pH≈3.5\boxed{\text{pH} \approx 3.5}

Worked Example 2 (Reverse)

A solution has pH =8.3= 8.3. Find [H+][H^+].

−log⁡[H+]=8.3  ⟹  log⁡[H+]=−8.3  ⟹  [H+]=10−8.3≈5.01×10−9-\log[H^+] = 8.3 \implies \log[H^+] = -8.3 \implies [H^+] = 10^{-8.3} \approx 5.01 \times 10^{-9} M

pH Comparison

ChangepH drops by[H+][H^+] multiplied by
11 unit111010
22 units22100100
33 units331,0001{,}000

A pH drop of 11 means 10×10\times more acidic — that's the power of the log scale!

🔊 Decibel Scale

dB=10log⁡(II0)\boxed{dB = 10\log\left(\frac{I}{I_0}\right)}

where I0=10−12 W/m2I_0 = 10^{-12}\text{ W/m}^2 (threshold of hearing).

Worked Example 3

A rock concert has intensity I=10−2 W/m2I = 10^{-2}\text{ W/m}^2. Find the decibel level.

dB=10log⁡(10−210−12)=10log⁡(1010)=10⋅10=100 dBdB = 10\log\left(\frac{10^{-2}}{10^{-12}}\right) = 10\log(10^{10}) = 10 \cdot 10 = 100\text{ dB}

Common Sound Levels

SoundIntensity (W/m2)(W/m^{2})Decibels
Whisper10−1010^{-10}2020 dB
Conversation10−610^{-6}6060 dB
Rock concert10−210^{-2}100100 dB
Jet engine10110^{1}130130 dB

Comparing Two Sounds

If sound A is 10 dB10\text{ dB} louder than sound B, then A has 10×10\times the intensity.

20 dB20\text{ dB} louder → 100×100\times intensity. 30 dB30\text{ dB} louder → 1,000×1{,}000\times intensity.

🌋 Richter Scale & Comparing Magnitudes

M=log⁡(AA0)\boxed{M = \log\left(\frac{A}{A_0}\right)}

Comparing Two Earthquakes

How many times stronger is a magnitude 77 earthquake than a magnitude 55?

Each unit on the Richter scale represents 10×10\times the amplitude.

Difference: 7−5=27 - 5 = 2 units → 102=100×10^2 = 100\times the amplitude

But energy scales by ≈31.6×\approx 31.6\times per unit:

22 units → 31.62≈1,000×31.6^2 \approx 1{,}000\times the energy

Summary Table

Magnitude DifferenceAmplitude RatioEnergy Ratio
1110×10\times≈31.6×\approx 31.6\times
22100×100\times≈1,000×\approx 1{,}000\times
331,000×1{,}000\times≈31,600×\approx 31{,}600\times

Log Models Quiz 🎯

Applied Calculations 🧮

1) Find the pH of a solution with [H+]=10−9[H^+] = 10^{-9} M. (e.g., [H+]=10−4[H^+] = 10^{-4}: pH =−log⁡(10−4)=4= -\log(10^{-4}) = 4)

2) A sound has intensity I=10−5 W/m2I = 10^{-5}\text{ W/m}^2. Find its decibel level. Use I0=10−12I_0 = 10^{-12}. (e.g., I=10−8I = 10^{-8}: dB=10log⁡(10−8/10−12)=10⋅4=40dB = 10\log(10^{-8}/10^{-12}) = 10 \cdot 4 = 40)

3) How many times more intense is a 80 dB80\text{ dB} sound than a 50 dB50\text{ dB} sound? (e.g., 70 dB70\text{ dB} vs 40 dB40\text{ dB}: difference 30 dB=103=1000×30\text{ dB} = 10^3 = 1000\times)

Scale Identification 🔽

Exit Quiz ✅

Part 7: Review & Applications

🏆 Logarithmic Functions — Full Synthesis

Part 7 of 7 — Putting It All Together

Your Complete Log Toolkit

Concept (Part)Key Idea
Definition & Inverse (1)log⁡bx=y  ⟺  by=x\log_b x = y \iff b^y = x; domain (0,∞)(0, \infty)
Properties (2)Product, quotient, power rules for expanding/condensing
Transformations (3)g(x)=alog⁡b(x−h)+kg(x) = a\log_b(x-h)+k; VA at x=hx = h
Solving Equations (4)Convert → solve → check for extraneous
Change of Base (5)log⁡bx=ln⁡xln⁡b\log_b x = \frac{\ln x}{\ln b}
Modeling (6)pH, decibels, Richter — all use log⁡(ratio)\log(\text{ratio})

📋 Multi-Step Problem Walkthrough

A bacteria population is modeled by P(t)=500e0.2tP(t) = 500e^{0.2t}.

(a) When does the population reach 10,00010{,}000? (b) What is the doubling time? (c) Express the model in the form P(t)=500⋅btP(t) = 500 \cdot b^t and find the percent growth rate.

Part (a): When P=10,000P = 10{,}000?

500e0.2t=10000500e^{0.2t} = 10000

e0.2t=20e^{0.2t} = 20

0.2t=ln⁡20≈2.9960.2t = \ln 20 \approx 2.996

t≈14.98≈15t \approx 14.98 \approx 15 time units

Part (b): Doubling time

500e0.2t=1000  ⟹  e0.2t=2500e^{0.2t} = 1000 \implies e^{0.2t} = 2

t=ln⁡20.2=0.6930.2≈3.47t = \frac{\ln 2}{0.2} = \frac{0.693}{0.2} \approx 3.47 time units

Part (c): Convert to P=500⋅btP = 500 \cdot b^t

e0.2t=(e0.2)t≈(1.2214)te^{0.2t} = (e^{0.2})^t \approx (1.2214)^t

So b≈1.2214b \approx 1.2214, meaning ≈22.14%\approx 22.14\% growth per time unit.

🗺️ Problem-Type Decision Map

If the Problem Says...StrategyFirst Move
"Evaluate log⁡b(number)\log_b(\text{number})"DefinitionRewrite as b?=numberb^? = \text{number}
"Expand/simplify log⁡(expression)\log(\text{expression})"Properties (P2)Apply product/quotient/power rules
"Graph f(x)=alog⁡(x−h)+kf(x) = a\log(x-h)+k"Transformations (P3)ID shifts, VA, anchor point
"Solve log⁡(stuff)=stuff\log(\text{stuff}) = \text{stuff}"Equation solving (P4)Condense logs → convert to exponential
"Compute log⁡bx\log_b x to a decimal"Change of base (P5)=ln⁡x/ln⁡b= \ln x / \ln b
"Find the pH / dB / magnitude"Modeling (P6)Plug into the log-scale formula
"When does the population reach...?"Log + exponentialIsolate exponential → take ln⁡\ln

Connecting Logs to Exponentials

Almost every "when does it reach" problem follows this pattern:

abt=c  ⟹  bt=ca  ⟹  t=ln⁡(c/a)ln⁡bab^t = c \implies b^t = \frac{c}{a} \implies t = \frac{\ln(c/a)}{\ln b}

Synthesis Quiz 🎯

Multi-Skill Drill 🧮

1) An investment grows as A=2000e0.06tA = 2000e^{0.06t}. How many years to reach $6,000? Round to one decimal. (e.g., 1000e0.05t=30001000e^{0.05t} = 3000: t=ln⁡30.05=1.0990.05=22.0t = \frac{\ln 3}{0.05} = \frac{1.099}{0.05} = 22.0 years)

2) Condense: 2log⁡x−12log⁡y2\log x - \frac{1}{2}\log y. Write the coefficient on yy when the expression equals log⁡(xayb)\log\left(\frac{x^a}{y^b}\right). What is bb as a fraction? (e.g., 3log⁡x−2log⁡y=log⁡(x3/y2)3\log x - 2\log y = \log(x^3/y^2), so b=2b = 2)

3) An earthquake of magnitude 44 vs magnitude 77: the stronger one has how many times the amplitude? (e.g., magnitude 33 vs 55: difference 22, ratio =102=100= 10^2 = 100)

Concept Connection 🔽

Final Exit Quiz — Logarithmic Functions ✅