🎯⭐ INTERACTIVE LESSON

Integration Applications

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Integration Applications - Complete Interactive Lesson

Part 1: Average Value of a Function

Integration Applications

Part 1 of 7 — Area Between Curves (Advanced)

Area Between Two Curves

A=intabf(x)g(x),dxA = int_a^b |f(x) - g(x)|,dx

When f(x)geqg(x)f(x) geq g(x) on [a,b][a,b]:

A=intab[f(x)g(x)],dxA = int_a^b [f(x) - g(x)],dx

When Curves Cross

Split the integral at intersection points!

Worked Example

Area between y=x2y = x^2 and y=xy = x on [0,1][0, 1]:

Intersection: x2=ximpliesx=0,1x^2 = x implies x = 0, 1.

On [0,1][0,1]: xgeqx2x geq x^2.

A = int_0^1 (x - x^2),dx = left[ rac{x^2}{2} - rac{x^3}{3} ight]_0^1 = rac{1}{2} - rac{1}{3} = rac{1}{6}

Area Between Curves 🎯

Key Takeaways — Part 1

  1. Always determine which curve is on top
  2. Find intersection points to set limits
  3. Split integral if curves cross within the interval

Part 2: Mean Value Theorem for Integrals

Integration Applications

Part 2 of 7 — Cross-Sectional Volumes

Volume with Known Cross Sections

V=intabA(x),dxV = int_a^b A(x),dx

where A(x)A(x) is the area of the cross section at position xx.

Common Cross Sections

If the base is between y=f(x)y = f(x) and y=g(x)y = g(x), the side length is s=f(x)g(x)s = f(x) - g(x).

ShapeArea Formula
Squares2s^2
Semicircle rac{pi}{8}s^2
Equilateral triangle rac{sqrt{3}}{4}s^2
Isosceles right triangle rac{1}{2}s^2

Cross Sections 🎯

Base is the region between y=xy = \sqrt{x} and y=0y = 0 from x=0x = 0 to x=4x = 4. Cross sections perpendicular to xx-axis are squares.

Key Takeaways — Part 2

  1. Volume = A(x)dx\int A(x)\,dx where A(x)A(x) = cross-section area
  2. The side length of the cross section comes from the curve

Part 3: Net Change Theorem

Integration Applications

Part 3 of 7 — Volumes: Disk and Washer Methods

Disk Method (rotation about x-axis)

V=piintab[f(x)]2,dxV = piint_a^b [f(x)]^2,dx

Washer Method

ight),dx$$ $R$ = outer radius, $r$ = inner radius. ### Rotation About Other Lines If rotating about $y = k$: - radius = $|f(x) - k|$

Disk & Washer 🎯

Key Takeaways — Part 3

  1. Disk: πr2\pi r^2 — one function
  2. Washer: π(R2r2)\pi(R^2 - r^2) — two functions
  3. Adjust radii when rotating about lines other than axes

Part 4: Physical Applications

Integration Applications

Part 4 of 7 — Riemann Sums and Trapezoidal Rule

Left, Right, and Midpoint Sums

Ln=sumi=0n1f(xi),DeltaxqquadRn=sumi=1nf(xi),DeltaxL_n = sum_{i=0}^{n-1} f(x_i),Delta x qquad R_n = sum_{i=1}^{n} f(x_i),Delta x

Trapezoidal Rule

T_n = rac{Delta x}{2}[f(x_0) + 2f(x_1) + 2f(x_2) + cdots + 2f(x_{n-1}) + f(x_n)]

Over/Underestimates

MethodIncreasing ffDecreasing ff
LeftUnderOver
RightOverUnder
TrapOver (concave up)Under (concave down)

Numerical Integration 🎯

Given: x=0,1,2,3x = 0, 1, 2, 3 with f(0)=1,f(1)=3,f(2)=2,f(3)=5f(0) = 1, f(1) = 3, f(2) = 2, f(3) = 5.

Key Takeaways — Part 4

  1. Trapezoidal rule averages left and right sums
  2. Know which methods overestimate vs underestimate

Part 5: Economics Applications

Integration Applications

Part 5 of 7 — Rate Problems & Net Change

The Net Change Theorem

intabf(x),dx=f(b)f(a)int_a^b f'(x),dx = f(b) - f(a)

Common Contexts

  • Water flow: intR(t),dtint R(t),dt = total water
  • Population: intP(t),dtint P'(t),dt = net change in population
  • Cost: intC(x),dxint C'(x),dx = total cost change
  • Velocity: intv(t),dtint v(t),dt = displacement

Rate Problems 🎯

Water flows into a tank at R(t)=10+sin(t)R(t) = 10 + \sin(t) gal/min.

Key Takeaways — Part 5

  1. Integrating a rate gives total accumulation
  2. Include units in your answer on the AP exam

Part 6: Problem-Solving Workshop

Integration Applications

Part 6 of 7 — Practice Workshop

Mixed Integration Applications 🎯

Workshop Complete!

Part 7: Review & Applications

Integration Applications — Review

Part 7 of 7 — Final Assessment

Final Assessment 🎯

Integration Applications — Complete! ✅