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🎯⭐ INTERACTIVE LESSON

Integer Exponents

Learn step-by-step with interactive practice!

Integer Exponents - Complete Interactive Lesson

Part 1: ⚡ Integer Exponents

⚡ Integer Exponents

You already know how to work with positive exponents like 232^3 or 545^4. But exponents are even more powerful than that! When we allow the exponent to be any integer — positive, zero, or negative — we unlock a whole new set of tools.

What Are Integer Exponents?

Integer exponents simply means the exponent can be any whole number, including 00 and the negatives:

  • Positive integers: 232^3, 545^4, 10210^2
  • Zero: 505^0, 10010^0, x0x^0
  • Negative integers: 2−32^{-3}, 5−25^{-2}, 10−110^{-1}

The amazing part is that all of them follow the same consistent rules, so once you learn the pattern, you can handle any of them.

Quick Review: Positive Exponents

In the power ana^n:

  • aa is the base — the number being multiplied
  • nn is the exponent — how many times to use the base as a factor

Example: 24=2×2×2×2=162^4 = 2 \times 2 \times 2 \times 2 = 16

🔑 Big Idea: An exponent counts repeated multiplication. Zero and negative exponents extend that idea in a way that keeps every rule working perfectly.

0️⃣ Zero as an Exponent

Rule: Any non-zero number raised to the power 00 equals 11.

a0=1(a≠0)a^0 = 1 \quad (a \neq 0)

Examples:

  • 50=15^0 = 1
  • 100=110^0 = 1
  • 2370=1237^0 = 1
  • (−8)0=1(-8)^0 = 1
  • x0=1x^0 = 1

Why is this true? Use the quotient rule for dividing powers:

  • 5353=125125=1\dfrac{5^3}{5^3} = \dfrac{125}{125} = 1 — any number divided by itself is 11.
  • But the quotient rule also says 5353=53−3=50\dfrac{5^3}{5^3} = 5^{3-3} = 5^0.
  • Since both results must be equal, 50=15^0 = 1.

⚠️ Special note: 000^0 is undefined in mathematics — the zero-exponent rule only works for bases that are not zero.

➖ Negative Exponents

Rule: A negative exponent means take the reciprocal — flip the base to the bottom of a fraction and make the exponent positive.

a−n=1ana^{-n} = \frac{1}{a^n}

Examples:

ExpressionRewrite as a fractionValue
2−32^{-3}123\dfrac{1}{2^3}18\dfrac{1}{8}
5−25^{-2}152\dfrac{1}{5^2}125\dfrac{1}{25}
10−110^{-1}1101\dfrac{1}{10^1}110=0.1\dfrac{1}{10} = 0.1
3−43^{-4}134\dfrac{1}{3^4}181\dfrac{1}{81}

🧠 Watch out: A negative exponent does not make the answer negative! 2−3=182^{-3} = \dfrac{1}{8}, which is a small positive number. The negative sign tells you to flip, not to subtract.

✅ Concept Check

Part 2: 📝 Worked Examples

📝 Worked Examples

Let's evaluate several integer-exponent expressions step by step.

Example 1 — Zero exponent

Evaluate 909^0.

  • Any non-zero base to the power 00 is 11.
  • Answer: 90=19^0 = 1

Example 2 — Negative exponent

Evaluate 4−24^{-2}.

  • Step 1 — Flip: 4−2=1424^{-2} = \dfrac{1}{4^2}
  • Step 2 — Square the base: 42=164^2 = 16
  • Answer: 116\dfrac{1}{16}

Example 3 — Negative exponent with a fraction base

Evaluate (23)−2\left(\dfrac{2}{3}\right)^{-2}.

  • Rule: (ab)−n=(ba)n\left(\dfrac{a}{b}\right)^{-n} = \left(\dfrac{b}{a}\right)^{n} — flip the fraction, then make the exponent positive.
  • Step 1 — Flip the fraction: (32)2\left(\dfrac{3}{2}\right)^{2}
  • Step 2 — Apply the exponent: 3222=94\dfrac{3^2}{2^2} = \dfrac{9}{4}
  • Answer: 94\dfrac{9}{4}

Example 4 — Negative exponent in a denominator

Evaluate 12−3\dfrac{1}{2^{-3}}.

  • Rule: 1a−n=an\dfrac{1}{a^{-n}} = a^{n} — a negative exponent in the denominator jumps to the top and turns positive.
  • 12−3=23=8\dfrac{1}{2^{-3}} = 2^3 = 8
  • Answer: 88

✏️ Your Turn

Evaluate each expression. Type your answer as a whole number or a simple fraction (like 1/16).

Box 1: 70=?7^0 = ? Box 2: 5−2=?5^{-2} = ? Box 3: (14)−1=?\left(\dfrac{1}{4}\right)^{-1} = ?

Part 3: Guided Practice

🎯 Guided Practice

For each one, decide whether the exponent is zero or negative, then evaluate.

🔽 Rewrite Without Negative Exponents

Choose the equivalent form for each expression.

Part 4: 🌍 Where Integer Exponents Show Up

🌍 Where Integer Exponents Show Up

Negative and zero exponents aren't just abstract rules — they describe the real world, especially when measuring very small things.

Tiny measurements 🔬

Scientists describe small lengths using negative powers of 1010:

  • 10−1=110=0.110^{-1} = \dfrac{1}{10} = 0.1 (one tenth)
  • 10−2=1100=0.0110^{-2} = \dfrac{1}{100} = 0.01 (one hundredth)
  • 10−3=11000=0.00110^{-3} = \dfrac{1}{1000} = 0.001 (one thousandth)

A grain of sand is about 10−310^{-3} meters wide, and a virus is about 10−710^{-7} meters wide. Negative exponents let us write these without a long string of zeros.

Combining the laws of exponents

All the exponent rules still work with integer exponents:

RuleFormulaExample
Productam⋅an=am+na^m \cdot a^n = a^{m+n}23⋅2−5=2−2=142^3 \cdot 2^{-5} = 2^{-2} = \dfrac{1}{4}
Quotientaman=am−n\dfrac{a^m}{a^n} = a^{m-n}5255=5−3=1125\dfrac{5^2}{5^5} = 5^{-3} = \dfrac{1}{125}
Power(am)n=amn(a^m)^n = a^{mn}(3−2)3=3−6=1729(3^{-2})^3 = 3^{-6} = \dfrac{1}{729}

🔑 Strategy: First combine exponents using the laws, then handle any negative result by flipping to a fraction at the very end.

✏️ Apply the Rules

Use the laws of exponents, then write each final answer as a whole number or simple fraction (like 1/4).

Box 1: 23⋅2−52^3 \cdot 2^{-5} — first the exponent becomes 2−22^{-2}. What is the final value? Box 2: 6264\dfrac{6^2}{6^4} — simplify and evaluate. Box 3: A bacterium is about 10−610^{-6} meters wide. Written as a fraction 1?\dfrac{1}{?}, what number goes in the blank?

🤔 Apply It

Part 5: Review & Summary

🏆 Review & Summary

You can now work with every integer exponent — positive, zero, and negative. Here is the whole toolkit in one place.

SituationRuleExample
Zero exponenta0=1a^0 = 1 (if a≠0a \neq 0)70=17^0 = 1
Negative exponenta−n=1ana^{-n} = \dfrac{1}{a^n}2−3=182^{-3} = \dfrac{1}{8}
Negative fraction base(ab)−n=(ba)n\left(\dfrac{a}{b}\right)^{-n} = \left(\dfrac{b}{a}\right)^{n}(23)−2=94\left(\dfrac{2}{3}\right)^{-2} = \dfrac{9}{4}
Negative in denominator1a−n=an\dfrac{1}{a^{-n}} = a^{n}12−3=8\dfrac{1}{2^{-3}} = 8
Product ruleam⋅an=am+na^m \cdot a^n = a^{m+n}23⋅2−5=142^3 \cdot 2^{-5} = \dfrac{1}{4}
Quotient ruleaman=am−n\dfrac{a^m}{a^n} = a^{m-n}5255=1125\dfrac{5^2}{5^5} = \dfrac{1}{125}
Power rule(am)n=amn(a^m)^n = a^{mn}(3−2)3=1729(3^{-2})^3 = \dfrac{1}{729}

🔑 Remember the two big ideas:

  1. A zero exponent always gives 11 (for a non-zero base).
  2. A negative exponent means flip, not subtract — the answer stays positive.

Now put it all together in the challenge below!

🎓 Mixed Challenge