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Part 1: Definition & Convergence
Infinite Sequences
Part 1 of 7 โ Definition & Convergence
A sequence is an ordered list of numbers: a1โ,a2โ,a3โ,โฆ
Formally, a sequence is a function a:NโR written as {anโ}.
Convergence
nโโlimโanโ=
If no finite limit exists, the sequence diverges.
Examples
| Sequence anโ | limnโโโa |
|---|
Key Fact: A sequence converges if and only if its terms approach a single finite number.
Computing Limits of Sequences
Technique 1: Direct substitution (polynomial/rational)
anโ=n2โ5 (divide by highest power of )
Summary
- Sequence: ordered list {anโ}
- Converges if limnโโโa (finite)
Part 2: Bounded & Monotonic Sequences
Infinite Sequences โ Monotone & Bounded Sequences
Part 2 of 7 โ Monotonicity, Bounds, and the Monotone Convergence Theorem
Definitions
| Property | Meaning |
|---|
| Increasing | an+1โโฅanโ for all |
Part 3: Geometric & Recursive Sequences
Infinite Sequences โ Recursive Sequences & Special Limits
Part 3 of 7 โ Recursion and Important Limits
Recursive Sequences
A recursive sequence defines an+1โ in terms of previous terms:
a
Part 4: Growth Rate Hierarchy
Infinite Sequences โ Sequences vs. Series
Part 4 of 7 โ The Bridge to Series
Sequence vs. Series
| Concept | Symbol | Question |
|---|
| Sequence | {anโ} | Does a? |
Part 5: Sequences vs. Series
Infinite Sequences โ Telescoping & p-Series
Part 5 of 7 โ Special Series Types
Telescoping Series
A telescoping series has partial sums where most terms cancel:
โn=
Part 6: Practice Workshop
Infinite Sequences โ Workshop
Part 6 of 7 โ Problem-Solving Workshop
Mixed problems covering sequence convergence, series basics, and special types.
Workshop Overview
| Problem Type | Key Technique |
|---|
| Sequence limit | Growth hierarchy, L'Hรดpital's |
| Recursive sequence | Solve L=f(L) |
| Telescoping sum | Partial fractions, cancellation |
| Series classification | Geometric, p-series, th term test |
Part 7: Final Assessment
Infinite Sequences โ Comprehensive Review
Part 7 of 7 โ Full Topic Review
Master Reference
| Topic | Key Result |
|---|
| Sequence convergence | limanโ=L (finite) |
| Monotone Convergence | Monotone + Bounded Convergent |
L
โน
theย sequenceย convergesย toย
L
โ
n
โ
| 1/n | 0 | Yes |
| (โ1)n | DNE | No (oscillates) |
| n2 | โ | No (unbounded) |
| (1+1/n)n | e | Yes |
| 3+1/n2 | 3 | Yes |
3n2+1
โ
โ
13โ=
3
Technique 2: Squeeze Theorem
0โคnsinnโโคn1โโ0, so nsinnโโ0.
Technique 3: L'Hรดpital's via continuous extension
If f(x) is continuous and limxโโโf(x)=L, then limnโโโf(n)=L.
anโ=nlnnโ:limxโโโxlnxโ=LโHlim11/xโ=0
Technique 4: Root/ratio for exponential behavior
anโ=nnn!โโ0 (factorial grows slower than exponential of n)
nโ
=
L
Techniques: direct comparison, squeeze theorem, L'Hรดpital's, growth rate orderingGrowth rate hierarchy: lnnโชnpโชanโชn!โชnn
Next: Part 2 โ Monotone sequences and boundedness.
| Decreasing | an+1โโคanโ for all n |
| Monotone | Either increasing or decreasing |
| Bounded above | โM:anโโคM for all n |
| Bounded below | โm:anโโฅm for all n |
| Bounded | Both bounded above and below |
Monotone Convergence Theorem
Monotoneย +ย BoundedโนConvergentโ
This is one of the most powerful tools for proving convergence without finding the limit.
Key Fact: An increasing sequence that is bounded above must converge. A decreasing sequence that is bounded below must converge.
Testing Monotonicity
Method 1: Difference test
an+1โโanโ>0โน increasing; <0โน decreasing.
Method 2: Ratio test (for positive sequences)
an+1โ/anโ>1โน increasing; decreasing.
Method 3: Derivative test
If anโ=f(n) and fโฒ(x)> for , then is increasing.
Example
anโ=n+1nโ. Is it monotone? Bounded?
an+1โโ
So {anโ} is increasing. Also anโ<1 for all (bounded above). By MCT, it converges. Indeed, .
Summary
- Monotone: always increasing or always decreasing
- Test with: difference, ratio, or derivative
- Monotone Convergence Theorem: Monotone + Bounded โน Convergent
- This theorem proves existence of a limit without finding it
Next: Part 3 โ Recursive sequences and special limits.
n+1
โ
=
f(anโ),a1โ=
given
To find the limit (if it converges), assume limanโ=L and solve:
Example
a1โ=1, an+1โ=2+anโโ.
If L exists: L=2+LโโนL2=2+LโนL2โLโ2=0โนL=2 (since L>0).
Must also verify convergence: show the sequence is increasing and bounded above by 2.
Important Limits to Know
| Limit | Value | Why |
|---|
| limannpโ (a>1) | 0 | Exponential beats polynomial |
| limn!anโ | 0 | Factorial beats exponential |
| limnq(lnn)pโ () |
| limn1/n | 1 | Apply ln: |
| limnnn!โ | 0 | beats factorial |
| lim(1+1/n)n | e | Definition of e |
| limrn ($ | r | <1$) |
Growth Rate Hierarchy
lnnโชnpโชanโชn!โช
Each function on the left grows infinitely slower than the one on its right.
Summary
- Recursive sequences: find limit by solving L=f(L)
- Must separately verify convergence (monotone + bounded)
- Growth hierarchy: lnnโชnpโชanโชn!โชnn
- Key limit: (1+k/n)nโek
Next: Part 4 โ Sequences and series connection.
n
โ
โ
L
| Series | โanโ | Does โn=1โโanโ converge? |
A series is the sum of a sequence. The partial sums form a new sequence:
SNโ=โn=1Nโanโ=a1โ+a2โ+โฏ+aNโ
n=1โโโanโ=NโโlimโSNโโ
Key Fact: A series converges if and only if the sequence of partial sums converges.
The nth Term Test (Divergence Test)
Ifย nโโlimโanโ๎ =0,ย thenย โanโย diverges.โ
Contrapositive: If โanโ converges, then anโโ0.
CAUTION: anโโ0 does NOT guarantee convergence!
The harmonic series โ1/n has anโ=1/nโ0 but diverges.
Geometric Series
โn=0โโrn=
| โฃrโฃ | Behavior |
|-------|----------|
| โฃrโฃ<1 | Converges to 1โr |
| | Diverges |
Summary
- Series = sum of a sequence: โanโ=limSNโ
- nth Term Test: if anโ๎ โ0, series diverges
- anโโ0 does NOT guarantee convergence
- Geometric series: converges iff โฃrโฃ<1, sum =1โraโ
Next: Part 5 โ Telescoping and p-series.
1
โ
โ
(n1โโn+11โ)
=
limNโโโ(1โN+11โ)=
1
How to recognize: Partial fractions often reveal telescoping structure.
n=1โโโnp1โย convergesย ifย andย onlyย ifย p>1โ
| Series | p | Converges? |
|---|
| โ1/n | 1 | No (harmonic) |
| โ1/n2 | 2 | Yes (=ฯ2/6) |
| โ1/nโ | 1/2 | No |
| โ1/n3 | 3 | Yes |
AP Tip: The p-series test and geometric series test are the most fundamental โ many other tests compare to these.
Telescoping Example
Find โn=1โโn(n+2)1โ.
Step 1. Partial fractions: n(n+2)1โ=2
Step 2. Write partial sums:
SNโ=2
Most terms telescope! Surviving terms:
SNโ=21โ
โn=1โโn(n+2)
Summary
- Telescoping series: write partial sums, identify cancellation
- p-series: โ1/np converges iff p>1
- The harmonic series (p=1) is the critical boundary case
- Partial fractions often reveal hidden telescoping
Next: Part 6 โ Problem-Solving Workshop.
n
Problem Set
Problem 1. Does โn=1โโn2+1n2โ converge?
anโ=n2+1n. by the th term test.
Problem 2. Find โn=0โโ5n3.
Geometric: a=3, r=1/5. Sum =.
Problem 3. Classify โn=1โโnฯ.
p-series with p=ฯโ3.14>1. Converges.
Workshop Summary
- nth term test: quick divergence check (anโ๎ โ0)
- Geometric and p-series are the fundamental comparison targets
- Growth hierarchy for sequence limits: lnnโชnpโชanโชn!
- Always check convergence before finding a sum
Next: Part 7 โ Comprehensive Review.
โน
| Recursive sequences | Solve L=f(L) for the limit |
| nth Term Test | anโ๎ โ0โนโanโ diverges |
| Geometric series | โarn=1โraโ if $ |
| p-series | โ1/np converges iff p>1 |
| Telescoping | Use partial fractions, find limSNโ |
| Growth hierarchy | lnnโชnpโชanโชn!โชnn |
AP Tip: The AP BC exam tests sequences primarily through series. Understanding sequence convergence is the foundation for all series work.
Common Pitfalls
-
"anโโ0 so โanโ converges" โ FALSE. The harmonic series is the classic counterexample.
-
Confusing the sequence {anโ} with the series โanโ โ one asks about the terms, the other about the sum.
-
Forgetting to verify convergence of recursive sequences โ solving L=f(L) only finds CANDIDATES for the limit.
-
Incorrect geometric series formula โ remember โn=0โโarn= starts at . If starting at : .
-
p-series boundary โ p=1 (harmonic series) DIVERGES. Need p>1 (strictly).
Topic Complete!
You've mastered infinite sequences and the bridge to series:
- Sequence convergence (limits, monotonicity, boundedness)
- Recursive sequences and special limits
- Geometric series, p-series, and telescoping series
- The nth term test and its limitations
n=1โโโanโ=Nโโlimโ
Up next: Infinite Series โ convergence tests (comparison, integral, ratio, root).
<1โน
0
anโ
=
n+2n+1โโ
n+1nโ=
(n+2)(n+1)(n+1)2โn(n+2)โ=
(n+2)(n+1)1โ>
0
n
limanโ=1 q>0
| Polynomial beats logarithm |
n
lnn
โ
โ
0
nn
nn
โ
1โr
1
โ
ifย
โฃ
r
โฃ
<
1
1
โ
โฃrโฃโฅ1
1
โ
(n1โโn+21โ)
1
โ
[(1โ31โ)+(21โโ41โ)+(31โโ51โ)+โฏ]
(1+21โโN+11โโN+21โ)
1
โ
=
21โ(23โ)=
43โ
2
โ
โ
1๎ =
0
Diverges
โ
1โ1/5
3
โ
=
4/53โ=
415โ
1
โ
1โr
a
โ
1โrarโ
SNโ
โ
a
rn
=
1โraโ
(
โฃ
r
โฃ
<
1
)
โ