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🎯⭐ INTERACTIVE LESSON

Infinite Limits and Vertical Asymptotes

Learn step-by-step with interactive practice!

Infinite Limits and Vertical Asymptotes - Complete Interactive Lesson

Part 1: Notation and Meaning

📈 Infinite Limits — When Functions Blow Up

Part 1 of 4 — Notation and meaning


Topics in This Part

Section
What "lim⁡=∞\lim = \infty" Really Means
🔑 Infinite Limits vs. Limits at Infinity
Notation and Conventions

🔑 Why this matters: Infinite limits describe vertical asymptotes — a key feature of any rational function.

💡 What "lim⁡x→af(x)=+∞\lim_{x \to a} f(x) = +\infty" Means

As xx approaches aa, the values of f(x)f(x) grow without bound (positive direction).

This is not saying the limit exists in the usual sense — ∞\infty isn't a real number. It's a description of how the limit fails to be a finite number.

Same for −∞-\infty: f(x)f(x) decreases without bound.

💡 In AP language, we sometimes say "the limit equals +∞+\infty" and sometimes say "the limit DNE (and the function →+∞\to +\infty)". Both are accepted on the exam.

⚖️ Infinite Limits vs. Limits at Infinity

Two different concepts, similar names — don't confuse them.

TypeNotationMeans
Limit at infinitylim⁡x→∞f(x)\lim_{x \to \infty} f(x)Behavior as xx goes to ∞\infty — describes horizontal asymptotes
Infinite limitlim⁡x→af(x)=∞\lim_{x \to a} f(x) = \inftyBehavior near a finite aa where ff blows up — describes vertical asymptotes

Quick test: is ∞\infty in the target (under the lim) or in the value (after the equal sign)?

  • Under the lim → limit at infinity (horizontal asymptote idea).
  • After the equal sign → infinite limit (vertical asymptote idea).

📝 Notation and Conventions

NotationMeaning
lim⁡x→a+f(x)=+∞\lim_{x \to a^+} f(x) = +\inftyApproaching aa from the right, ff shoots up
lim⁡x→a+f(x)=−∞\lim_{x \to a^+} f(x) = -\inftyApproaching aa from the right, ff shoots down
lim⁡x→a−f(x)=+∞\lim_{x \to a^-} f(x) = +\inftyApproaching from the left, ff shoots up
lim⁡x→af(x)=+∞\lim_{x \to a} f(x) = +\inftyBoth sides go to +∞+\infty

⚠️ If the two sides go to opposite infinities (e.g., left →−∞\to -\infty, right →+∞\to +\infty), the two-sided limit DNE. We do not say it equals ∞\infty in that case.

Notation Check 🎯

Identify 🧮

For f(x)=1(x−5)2f(x) = \dfrac{1}{(x - 5)^2}:

1) lim⁡x→5+f(x)=?\lim_{x \to 5^+} f(x) = ? (use infinity, -infinity, DNE, or a number)

2) lim⁡x→5−f(x)=?\lim_{x \to 5^-} f(x) = ?

3) lim⁡x→5f(x)=?\lim_{x \to 5} f(x) = ?

Part 2: Diagnosing Infinite Limits

🔍 Diagnosing Infinite Limits

Part 2 of 4 — The "nonzero / zero" pattern


Topics in This Part

Section
🔑 The Nonzero-Over-Zero Test
Sign Analysis on Each Side
Worked Examples

🔑 Why this matters: Recognizing the c/0c/0 pattern (nonzero cc) tells you immediately you have a vertical asymptote — and a sign analysis tells you which infinity.

🔑 The Nonzero-Over-Zero Test

For lim⁡x→ap(x)q(x)\lim_{x \to a} \dfrac{p(x)}{q(x)}:

Direct substitution givesConclusion
Number LLLimit is LL ✅
0/00/0Indeterminate — factor/rationalize
Nonzero / 0Vertical asymptote at x=ax = a — limit is ±∞\pm\infty or DNE

The key is: if the denominator is approaching 0 but the numerator is approaching a nonzero number, the magnitude blows up.

💡 The next question is just which sign of infinity each side gives.

➕➖ Sign Analysis

Once you know "nonzero / zero," determine the sign of the result on each side of aa:

  1. Numerator sign: plug aa into p(x)p(x) — get the sign (positive or negative).
  2. Denominator sign as x→a+x \to a^+: is q(x)q(x) slightly positive or slightly negative?
  3. Denominator sign as x→a−x \to a^-: same question.
  4. Combine: like signs → +∞+\infty, opposite signs → −∞-\infty.

Worked example. lim⁡x→2+1x−2\lim_{x \to 2^+} \dfrac{1}{x - 2}.

  • Numerator: 1>01 > 0.
  • For xx slightly bigger than 2: x−2x - 2 is small positive.
  • ++=+\dfrac{+}{+} = +. So →+∞\to +\infty.

For lim⁡x→2−1x−2\lim_{x \to 2^-} \dfrac{1}{x - 2}: x−2x - 2 slightly negative, so +−=−\dfrac{+}{-} = -, →−∞\to -\infty.

Sides disagree → two-sided limit DNE.

📝 Worked Examples

LimitNumerator at aaDenominator on each sideResult
lim⁡x→3+xx−3\lim_{x \to 3^+} \dfrac{x}{x - 3}+3+3small +++∞+\infty
lim⁡x→3−xx−3\lim_{x \to 3^-} \dfrac{x}{x - 3}+3+3small −-−∞-\infty
lim⁡x→0+−1x\lim_{x \to 0^+} \dfrac{-1}{x}−1-1small ++−∞-\infty
lim⁡x→0−−1x\lim_{x \to 0^-} \dfrac{-1}{x}−1-1small −-+∞+\infty
lim⁡x→11(x−1)2\lim_{x \to 1} \dfrac{1}{(x-1)^2}+1+1small ++ on both sides (squared)+∞+\infty on both sides; two-sided =+∞= +\infty

Diagnose 🎯

Sign Analysis 🔽

Part 3: Vertical Asymptotes

📍 Vertical Asymptotes

Part 3 of 4 — Where do they live?


Topics in This Part

Section
Definition
🔑 Where to Find Them
Holes vs. Asymptotes (the 0/00/0 vs. nonzero/0 distinction)

🔑 Why this matters: Vertical asymptotes are a graph feature; understanding them connects limits to function behavior.

📐 Definition

The vertical line x=ax = a is a vertical asymptote of ff if at least one of the following holds:

lim⁡x→a+f(x)=±∞orlim⁡x→a−f(x)=±∞\lim_{x \to a^+} f(x) = \pm\infty \quad \text{or} \quad \lim_{x \to a^-} f(x) = \pm\infty.

In other words: the function shoots off to ±∞\pm\infty as xx approaches aa from at least one side.

💡 You don't need both sides to agree. A one-sided infinite limit is enough.

🔍 Where to Find Vertical Asymptotes

For a rational function p(x)q(x)\dfrac{p(x)}{q(x)}:

  1. Find zeros of q(x)q(x) — these are the candidate asymptotes.
  2. For each zero aa, check the numerator p(a)p(a):
    • p(a)≠0p(a) \ne 0 → vertical asymptote at x=ax = a.
    • p(a)=0p(a) = 0 → it's a 0/00/0 situation. Could be a hole (removable) or a vertical asymptote, depending on multiplicities.

Worked example. f(x)=x+1x2−4=x+1(x−2)(x+2)f(x) = \dfrac{x + 1}{x^2 - 4} = \dfrac{x + 1}{(x - 2)(x + 2)}.

  • Denominator zeros: x=2x = 2 and x=−2x = -2.
  • Numerator at x=2x = 2: 3≠03 \ne 0 → asymptote at x=2x = 2.
  • Numerator at x=−2x = -2: −1≠0-1 \ne 0 → asymptote at x=−2x = -2.
  • Two vertical asymptotes.

🕳️ Holes vs. Asymptotes

If both p(a)=0p(a) = 0 and q(a)=0q(a) = 0, factor to figure out which it is.

Example 1 — hole. f(x)=x2−1x−1=(x−1)(x+1)x−1=x+1f(x) = \dfrac{x^2 - 1}{x - 1} = \dfrac{(x-1)(x+1)}{x - 1} = x + 1 for x≠1x \ne 1. The factor cancels exactly. There's a hole at x=1x = 1, no asymptote. The limit there equals 22.

Example 2 — asymptote. f(x)=x−1(x−1)2=1x−1f(x) = \dfrac{x - 1}{(x - 1)^2} = \dfrac{1}{x - 1}. After cancelling, the denominator still has a remaining (x−1)(x - 1), so there's an asymptote.

💡 Rule: count multiplicities. If the denominator's power of (x−a)(x - a) is greater than the numerator's, you have an asymptote. Otherwise, a hole (or no issue).

Identify Asymptotes 🎯

Count Asymptotes 🧮

How many vertical asymptotes does each function have?

1) f(x)=1x2−9f(x) = \dfrac{1}{x^2 - 9} → ?

2) g(x)=x−1x2−1g(x) = \dfrac{x - 1}{x^2 - 1} → ? (think about cancellation)

3) h(x)=x+2(x−1)(x−5)h(x) = \dfrac{x + 2}{(x - 1)(x - 5)} → ?

Part 4: Asymptotes Beyond Rationals

🌐 Asymptotes Beyond Rationals

Part 4 of 4 — Logs, tangent, and reading from a graph


Topics in This Part

Section
ln⁡x\ln x at x=0x = 0
tan⁡x\tan x at x=π/2+kπx = \pi/2 + k\pi
Reading Asymptotes from a Graph

🔑 Why this matters: Vertical asymptotes appear in many functions, not just rationals.

📉 Natural Log at x=0x = 0

The function ln⁡x\ln x is defined for x>0x > 0 and:

lim⁡x→0+ln⁡x=−∞\lim_{x \to 0^+} \ln x = -\infty

So x=0x = 0 is a vertical asymptote of ln⁡x\ln x — but only on the right side (the function isn't defined for x≤0x \le 0).

Same for log⁡bx\log_b x with any base b>1b > 1.

📐 Tangent's Asymptotes

tan⁡x=sin⁡xcos⁡x\tan x = \dfrac{\sin x}{\cos x} has vertical asymptotes wherever cos⁡x=0\cos x = 0, i.e., at:

x=π2+kπ(k∈Z)x = \frac{\pi}{2} + k\pi \quad (k \in \mathbb{Z})

At each one, the left and right limits go to opposite infinities.

ValueLeft limitRight limit
x=π/2x = \pi/2+∞+\infty−∞-\infty
x=3π/2x = 3\pi/2+∞+\infty−∞-\infty

💡 The pattern repeats with period π\pi.

👁️ Reading Asymptotes from a Graph

A vertical asymptote appears as a vertical "cliff" on the graph: the curve rockets up or down as it approaches a vertical line x=ax = a.

Visual signs:

  • The curve rises (or falls) without bound near x=ax = a.
  • A vertical dashed line is often drawn at x=ax = a in textbook plots.
  • The function is undefined at x=ax = a.

⚠️ Don't confuse a hole (single missing point) with an asymptote (unbounded behavior). Holes look normal locally, just with one point missing; asymptotes show the function blowing up.

Apply the Ideas 🎯

Exit Check ✅