Skip to content Geometric Distribution - Interactive Lesson | Study MondoGeometric Distribution - Complete Interactive Lesson
Part 1: Binomial Setting
๐ฐ Binomial & Geometric Distributions
Part 1 of 7 โ The Binomial Setting
BINS Criteria
A random variable X is binomial if:
| Letter | Condition |
|---|
| B | Binary outcomes (success/failure) |
| I | Independent trials |
| N | Fixed Number of trials (n) |
| S | Same probability of success (p) each trial |
Binomial Distribution: XsimB(n,p)
P(X=k)=binomnkpk(1โp)
where binomnk=fracn!k!(nโk)!
Mean and Standard Deviation
mu=npqquadsigma=sqrtnp(1โ
Example: 20 free throws, p=0.8
- mu=20(0.8)=16
- sigma
Binomial Basics ๐งฎ
A basketball player makes 75% of free throws. She shoots 12.
1) Expected number of makes?
2) Standard deviation? (round to 2 decimal places)
3) P(X=12)? (round to 4 decimal places)
Part 2: Binomial Probabilities
๐ข Binomial Calculations
Part 2 of 7 โ Computing Binomial Probabilities
Using the Formula
P(X=k)=binomnkpk
Part 3: Binomial Mean & Std Dev
๐ฏ Geometric Distribution
Part 3 of 7 โ Waiting for First Success
Geometric Setting
- Binary outcomes (success/failure)
- Independent trials
- Same probability p each trial
- Count trials until first success
Geometric Distribution: XsimG(p)
Part 4: Geometric Setting
๐ Normal Approximation to Binomial
Part 4 of 7 โ When n is Large
When to Use Normal Approximation
The binomial distribution B(n,p) is approximately normal when:
Part 5: Geometric Probabilities
๐ Binomial vs Geometric
Part 5 of 7 โ Choosing the Right Model
Side-by-Side Comparison
| Feature | Binomial | Geometric |
|---|
| Counts | Successes in n trials | Trials until 1st success |
| Fixed | Number of trials n | Probability p |
|
Part 6: Problem-Solving Workshop
๐ Problem-Solving Workshop
Part 6 of 7 โ AP-Style Practice
AP Free-Response Strategy
When the AP exam gives a binomial/geometric scenario:
- State the distribution and parameters: โXsimB(n,p)โ or โXsimG(p)โ
- conditions (BINS for binomial)
Part 7: Mixed Review
๐ Review & Applications
Part 7 of 7 โ Comprehensive Review
Key Formulas
| Distribution | PMF | Mean | SD |
|---|
| Binomial B(n,p) | binomn |
nโk
p
)
=
sqrt20(0.8)(0.2)=
sqrt3.2
approx1.789
(
1
โ
p)nโk
Cumulative Probabilities
- P(Xleqk): use
binomcdf(n, p, k) on calculator
- P(Xgeqk)=1โP(Xleqkโ1)
- P(aleqXleqb)=P(Xleqb)โ
Worked Example
XsimB(5,0.4). Find P(Xgeq3).
P(Xgeq3)=P(3)+P(4)+P(5)
=binom53(0.4)3(0.6)2+binom54(0.4)4(0.6)1+binom55(0.4)5
=10(0.064)(0.36)+5(0.0256)(0.6)+1(0.01024)
=0.2304+0.0768+0.01024=0.3174
Binomial Calculation ๐งฎ
XsimB(4,0.5).
1) P(X=2)=? (as a fraction, e.g., 3/8)
2) P(Xleq1)=? (as a fraction)
3) P(Xgeq3)=? (as a fraction)
P(X=k)=(1โp)kโ1p
where k=1,2,3,ldots (first success on trial k)
Mean and Standard Deviation
mu=frac1pqquadsigma=fracsqrt1โpp
Example: Rolling a die until getting a 6 (p=1/6):
- Expected number of rolls: mu=6
- This means on average youโll need 6 rolls
Geometric Practice ๐งฎ
A quality inspector finds defective items with probability p=0.1.
1) Expected inspections until first defect?
2) P(textfirstdefecton3rditem)? (as a decimal)
3) P(Xleq3)? (probability within first 3, as a decimal)
np
geq10
quad
textAND
quadn(1โ
p)
geq10
This is the Large Counts Condition.
Use: XdotsimN(np,sqrtnp(1โp))
Worked Example
XsimB(200,0.35)
Check: np=70geq10 โ, n(1โp)=130geq10 โ
mu=70, sigma=sqrt200(0.35)(0.65)=sqrt45.5approx6.745
P(Xgeq80)approxPleft(Zgeqfrac80โ706.745right)=P(Zgeq1.48)approx0.0694
Normal Approximation ๐งฎ
XsimB(400,0.6)
1) mu=?
2) sigma=? (round to 2 decimals)
3) z-score for X=260? (round to 2 decimals)
n
| Values | 0,1,2,ldots,n | 1,2,3,ldots |
| Formula | binomnkpk(1โp)nโk | (1โp)kโ1p |
Decision Flowchart
- Are there binary outcomes with constant p? โ If no, neither
- Is n fixed? โ Yes: Binomial. No: continue
- Counting trials until first success? โ Yes: Geometric
Model Identification ๐งฎ
1) Flipping a coin until heads: Binomial or Geometric?
2) Number of heads in 50 flips: Binomial or Geometric?
3) For scenario 2: E(X)=?
Verify
Calculate using the formula or calculatorInterpret in context with proper probability languageMixed Practice ๐งฎ
10% of products are defective. A sample of 20 is inspected.
1) P(textexactly2defective)=? (round to 4 decimals)
2) Expected number defective?
3) If inspecting one at a time, expected items until first defect?
k
pk
(
1
โ
p)nโk
| sqrtnp(1โp) |
| Geometric G(p) | (1โp)kโ1p | 1/p | fracsqrt1โpp |
Normal Approximation Conditions
npgeq10 AND n(1โp)geq10
Common AP Mistakes
- Using geometric when n is fixed (should be binomial)
- Forgetting binomnk in binomial formula
- Starting geometric at k=0 instead of k=1
Final Challenge ๐งฎ
XsimB(100,0.3)
1) muXโ=?
2) sigmaXโ=? (round to 2 decimals)
3) Using normal approximation, P(X>35)approx? (Standard normal: P(Z>1.09))
P(X
leqaโ
1)
a
pp
ro
x
0.138