(c) By MVT, since R is continuous on [0,10] and differentiable on (0,10):
R′(c)=10−0R(10)−R(0)=103−4=−0.1 gal/hr² for some c in (0,10).
Table-Based FRQ Quiz 🎯
Over/Underestimate Guide
Method
Overestimate When
Underestimate When
Left Riemann
f decreasing
f increasing
Right Riemann
f increasing
f decreasing
Trapezoidal
f concave up
f concave down
Midpoint
f concave down
f concave up
AP Tip: After computing a Riemann sum, the FRQ often asks “Is this an overestimate or underestimate? Explain.” You MUST state the reason (monotonicity or concavity).
Analyze the table. 🔍
Compute the trapezoidal sum. ✍️
Key Takeaways — Part 3
Table FRQs require Riemann sums, trapezoidal rule, and MVT/IVT
Watch for unequal subintervals — use actual Δxi
Over/underestimate depends on monotonicity (Riemann) or concavity (trapezoidal)
Estimate derivatives with difference quotients from nearest table values
What You Can Read from Each Graph
Given Graph of
You Can Determine
f
Values f(a), zeros, positive/negative regions
f′
Where f is increasing/decreasing, local extrema
f′′
Concavity and inflection points of f
f′
∫ab (area under )
Reading f′ Graph ↔ Properties of f
Feature of f′ Graph
Meaning for f
f′(x)>0
f is increasing
f′(x)<0
f is decreasing
f′ crosses x-axis from + to −
f has local maximum
f′ crosses x-axis from − to +
f has local minimum
f′ is increasing
f is concave up
f′ is decreasing
f is concave down
f′ has a local extremum
f has inflection point
Key Fact: When given graph of f′, compute ∫f′dx to find net change of f. Use geometric area formulas (triangles, semicircles).
Worked Example — Graph of f′
Suppose f′ is piecewise linear on [0,8]:
f′(0)=2, f′(2)=0, f′(5)=−3, f′(8)=0
(a) On what intervals is f increasing?
f′>0 on (0,2) → f increasing on [0,2].
(b) Local max of f at x=?
f′ changes from + to − at x=2 → local max.
(c)f(0)=5. Find f(2).
f(2)=f(0)+∫02f′(x)dx=5+ area of triangle =5+21(2)(2)=7.
(d) Inflection point of f?
f′ has a local min at x=5 → f′′ changes sign → inflection point at x=5.
Graph-Based FRQ Quiz 🎯
Geometric Area Formulas for Graphs
Shape
Formula
Rectangle
base×height
Triangle
21×base×height
Semicircle
21πr2
Trapezoid
21(b1+b
AP Tip: Areas below the x-axis count as NEGATIVE when computing ∫f′dx.
Analyze the graph of f′. 🔍
Compute from the graph. ✍️
Key Takeaways — Part 4
Graph of f′: above x-axis → f increasing; below → f decreasing
f′ sign change at zero → local extremum of f
f′ local extremum → inflection point of f
Use geometric area formulas; below-axis area is negative
At each point (x,y), draw a short segment with slope dxdy(x,y)
Slope Value
Segment
dxdy=0
Horizontal
dxdy>0
Slants up-right
dxdy<0
Slants down-right
dxdy undefined
Vertical or no segment
Separation of Variables Steps
Step
Action
Example: dxdy=xy
1
Separate
ydy=xdx
2
Integrate
$\ln
3
Solve for y
y=Aex2/2
4
Apply IC
y(0)=3⟹A=3
Key Fact: On AP FRQs, always include the constant of integration and solve for it using the initial condition. Forgetting +C loses a point.
Worked Example — DE FRQ
dxdy=y2x, y(0)=4.
(a) Slope at (1,2): dxdy=22(1)=1.
(b) Solve:
ydy=2xdx⟹2y2=x2+C
y(0)=4: 216=0+C⟹C=8
y2=2x2+16⟹y=2x2+16 (positive since y(0)=4>0)
(c)y(2)=8+16=24=26
Differential Equation FRQ Quiz 🎯
Common DE Mistakes on FRQs
Mistake
Why It Costs Points
Forgetting +C
Lose 1 point even if rest is correct
Not separating correctly
Cannot integrate an unseparated DE
Wrong sign on $\ln
y
Not checking domain
y>0 vs y<0 affects $
Slope field: wrong direction
Double-check sign at each point
Euler’s Method (Calculator FRQ)
When asked to approximate y(x1) using Euler’s method with step size h:
yn+1=yn
Example:dxdy=x+y, y, .
y(0.5)=1+0.5(0+1)=1.5
y(1)=1.5+0.5(0.5+1.5)=1.5+1=2.5
Classify the DE approach. 🔍
Solve the IVP. ✍️
Key Takeaways — Part 5
DE FRQs: slope fields, separation of variables, initial conditions
Always include +C and solve for it using the IC
Solution curves follow the slope field segments
Euler’s method: yn+1=yn+h⋅f(xn,yn)
−
g(x)]dx
Volume — Disk (about x-axis)
π∫ab[f(x)]2dx
Volume — Washer (about x-axis)
π∫ab([R(x)]2−[r(x)]2)dx
Volume — Known cross-sections
∫abA(x)dx
Cross-Section Shapes
Shape
Area Formula
Square
A=s2 where s=f(x)−g(x)
Semicircle
A=8π[f(x)−g(x)]
Equilateral triangle
A=43
Isosceles right triangle
A=21[f(x)−g(x)]
Key Fact: Cross-section problems always say “perpendicular to the x-axis (or y-axis).” The side length equals the distance between curves.
Worked Example — Area & Volume FRQ
Region R is bounded by y=x2 and y=2x for 0≤x≤2.
(a) Area of R:
A=∫02(2x−x2)dx=[x2−3x3]024−38=34
(b) Volume when R is revolved about the x-axis (washer):
V=π∫02[(2x)2−(x2)2]dx=π∫02(4x2−x4)dx
=π[34x3−5x5]02=π(332−532)=1564π
(c) Volume with square cross-sections perpendicular to x-axis:
V=∫02(2x−x2)2dx
Area & Volume FRQ Quiz 🎯
Revolution About Non-Standard Axes
Axis of Revolution
Outer Radius R
Inner Radius r
x-axis (y=0)
f(x)
g(x)
y=k (above curves)
k−g(x)
k−f(x
y=k (below curves)
f(x)−k
g(x)−k
AP Tip: Draw the axis of revolution and each curve. Measure radii as distances, always positive.
Set up the integral. 🔍
Compute the area. ✍️
Key Takeaways — Part 6
Area: ∫[top−bottom]dx or ∫[right−left]dy
Disk/washer: remember the π factor
Cross-sections: match the shape formula; no π for squares/triangles
Non-standard axes: adjust radii by the distance to the axis
f′(a)=limh→0hf(a+h)−f(a)
Definition of derivative
(fg)′=f′g+fg′
Product rule
[f(g(x))]′=f′(g(x))g′(x)
Chain rule
∫abf′(x)dx=f(b)−f(a)
Net change / FTC 2
dxd∫ag(x)f(t)dt=f(g(x))g′(x)
FTC 1 + chain
favg=b−a1∫abf
Average value
A=∫[top−bottom]dx
Area between curves
V=π∫[R2−r2]dx
Washer volume
Mixed Practice — Set 1 🎯
Mixed Practice — Set 2 📝
FRQ strategy identification. 🔍
Final computation. ✍️
Completion Checklist
Part
Topic
Status
1
FRQ Structure & Core Skills
✅
2
Rate & Accumulation FRQs
✅
3
Table-Based FRQs
✅
4
Graph-Based FRQs
✅
5
Differential Equation FRQs
✅
6
Area & Volume FRQs
✅
7
Full Practice FRQ Set
✅
You’ve completed the Free-Response Strategies unit! You’re ready for the FRQ section. 🎉
Final Reminders
Show ALL work on every FRQ part
Include units whenever the problem involves a physical quantity
Name theorems explicitly (IVT, MVT, EVT)
“Set up but do not evaluate” = write the integral and STOP