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๐ŸŽฏโญ INTERACTIVE LESSON

Arithmetic and Geometric Sequences

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Arithmetic and Geometric Sequences - Complete Interactive Lesson

Part 1: Sequences & the Common Difference

๐Ÿ”ข Arithmetic & Geometric Sequences

Part 1 of 5 โ€” Sequences & the Common Difference


Topics in This Part

Section
What Is a Sequence?
Arithmetic Sequences
Finding the Common Difference

๐Ÿ”‘ Key Concept: A sequence is an ordered list of numbers. The numbers are called terms. The whole lesson is about spotting the pattern that gets you from one term to the next โ€” and writing a rule for it.

What Is a Sequence?

A sequence is just a list of numbers in a set order:

2,โ€…โ€Š5,โ€…โ€Š8,โ€…โ€Š11,โ€…โ€Š14,โ€…โ€Šโ€ฆ2,\; 5,\; 8,\; 11,\; 14,\; \dots

We name the terms with subscripts:

TermSymbolValue
1st terma1a_122
2nd terma2a_255
3rd terma3a_388
nnth termana_n?

The little number is the position (or index). So a4=11a_4 = 11 means "the 4th term is 1111."

๐Ÿ’ก The "โ€ฆ\dots" means the pattern keeps going forever. A sequence can be finite (it stops) or infinite (it never ends).

Arithmetic Sequences

In an arithmetic sequence, you get the next term by adding the same number every time. That fixed number is the common difference, written dd.

2,โ€…โ€Š5,โ€…โ€Š8,โ€…โ€Š11,โ€…โ€Š14,โ€…โ€Šโ€ฆd=+32,\; 5,\; 8,\; 11,\; 14,\; \dots \qquad d = +3

To find dd, subtract any term from the one after it:

d=a2โˆ’a1=5โˆ’2=3d = a_2 - a_1 = 5 - 2 = 3

It must be the same gap every time, or the sequence is not arithmetic.

SequenceDifference between termsArithmetic?
4,7,10,134, 7, 10, 13+3,+3,+3+3, +3, +3โœ… yes, d=3d=3
20,17,14,1120, 17, 14, 11โˆ’3,โˆ’3,โˆ’3-3, -3, -3โœ… yes, d=โˆ’3d=-3
1,2,4,81, 2, 4, 8+1,+2,+4+1, +2, +4โŒ no (gap changes)

๐Ÿ”‘ Key Idea: Arithmetic = repeated addition of a constant dd. If dd is negative, the terms go down.

Concept Check ๐ŸŽฏ

Find the Common Difference ๐Ÿงฎ

For each arithmetic sequence, find dd by computing a2โˆ’a1a_2 - a_1. (Negative answers are fine.)

1) 6,10,14,18,โ€ฆd=โ€‰?6, 10, 14, 18, \dots \quad d = \,? 2) 30,24,18,12,โ€ฆd=โ€‰?30, 24, 18, 12, \dots \quad d = \,? 3) โˆ’7,โˆ’4,โˆ’1,2,โ€ฆd=โ€‰?-7, -4, -1, 2, \dots \quad d = \,?

Predicting the Next Term

Once you know dd, the next term is just current term +โ€‰d+\, d:

an+1=an+da_{n+1} = a_n + d

This is called a recursive rule โ€” it tells you how to get the next term from the one you have.

Example: 4,11,18,25,โ€ฆ4, 11, 18, 25, \dots has d=7d = 7. The next term is 25+7=3225 + 7 = 32.

โš ๏ธ Recursion is great for the next term, but slow for far-away terms. To jump straight to the 100th term without listing all of them, we need a direct formula โ€” that's Part 2.

Extend the Pattern ๐Ÿ”ฝ

The arithmetic sequence is 4,11,18,25,โ€ฆ4, 11, 18, 25, \dots. Fill in each blank using an+1=an+da_{n+1} = a_n + d.

Part 2: The Explicit Formula for Arithmetic Sequences

๐Ÿ”ข Arithmetic & Geometric Sequences

Part 2 of 5 โ€” The Explicit Formula for Arithmetic Sequences


๐Ÿ”‘ The Idea: Instead of adding dd over and over, the explicit formula lets you plug in a position nn and get the term ana_n directly โ€” even the 500th term.

The Explicit (nth-Term) Formula

For an arithmetic sequence with first term a1a_1 and common difference dd:

โ€‰an=a1+(nโˆ’1)โ€‰dโ€‰\boxed{\,a_n = a_1 + (n - 1)\,d\,}

Why (nโˆ’1)(n-1)? To reach the nnth term, you start at a1a_1 and add dd a total of (nโˆ’1)(n-1) times โ€” because there are nโˆ’1n-1 gaps between nn terms.

TermBuilt from a1a_1Adds of dd
a1a_1a1a_100 times
a2a_2a1+da_1 + d11 time
a3a_3a1+2da_1 + 2d22 times
ana_na1+(nโˆ’1)da_1 + (n-1)dnโˆ’1n-1 times

๐Ÿ’ก The number of steps is always one less than the term number. That single "โˆ’1-1" is the most common place students slip.

Worked Example

Find the 10th term of 3,7,11,15,โ€ฆ3, 7, 11, 15, \dots

First, identify the pieces: a1=3a_1 = 3 and d=7โˆ’3=4d = 7 - 3 = 4.

Plug into an=a1+(nโˆ’1)da_n = a_1 + (n-1)d with n=10n = 10:

a10=3+(10โˆ’1)(4)=3+(9)(4)=3+36=39a_{10} = 3 + (10 - 1)(4) = 3 + (9)(4) = 3 + 36 = 39

โœ… Check: Count up โ€” 3,7,11,15,19,23,27,31,35,393, 7, 11, 15, 19, 23, 27, 31, 35, 39. The 10th term is indeed 3939. โœ“

Building the Rule

You can also write the whole formula for this sequence by simplifying:

an=3+(nโˆ’1)(4)=3+4nโˆ’4=4nโˆ’1a_n = 3 + (n-1)(4) = 3 + 4n - 4 = 4n - 1

Now any term is one step away: a20=4(20)โˆ’1=79a_{20} = 4(20) - 1 = 79.

Build the Formula ๐Ÿ”ฝ

You're writing the explicit formula for the arithmetic sequence 5,8,11,14,โ€ฆ5, 8, 11, 14, \dots. Fill in each piece.

Find the Term ๐Ÿงฎ

Use an=a1+(nโˆ’1)da_n = a_1 + (n-1)d for each.

1) a1=2,โ€…โ€Šd=5a_1 = 2,\; d = 5. Find a8=โ€‰?a_8 = \,? 2) 4,9,14,19,โ€ฆ4, 9, 14, 19, \dots Find the 12th term, a12=โ€‰?a_{12} = \,? 3) a1=50,โ€…โ€Šd=โˆ’3a_1 = 50,\; d = -3. Find a10=โ€‰?a_{10} = \,?

Working Backwards ๐ŸŽฏ

Part 3: Geometric Sequences & the Common Ratio

๐Ÿ”ข Arithmetic & Geometric Sequences

Part 3 of 5 โ€” Geometric Sequences & the Common Ratio


๐Ÿ”‘ New Pattern: Arithmetic sequences add the same number. Geometric sequences multiply by the same number every time. That multiplier is the common ratio, rr.

Geometric Sequences

In a geometric sequence, each term is the previous term times a fixed number rr:

2,โ€…โ€Š6,โ€…โ€Š18,โ€…โ€Š54,โ€…โ€Š162,โ€…โ€Šโ€ฆr=ร—32,\; 6,\; 18,\; 54,\; 162,\; \dots \qquad r = \times 3

To find the common ratio, divide any term by the one before it:

r=a2a1=62=3r = \frac{a_2}{a_1} = \frac{6}{2} = 3

It must be the same ratio every step:

SequenceRatio between termsGeometric?
5,10,20,405, 10, 20, 40ร—2\times 2 eachโœ… yes, r=2r=2
81,27,9,381, 27, 9, 3ร—13\times \frac{1}{3} eachโœ… yes, r=13r=\frac{1}{3}
2,4,6,82, 4, 6, 8ร—2,ร—1.5,โ€ฆ\times 2, \times 1.5, \dotsโŒ no (it's arithmetic)

๐Ÿ”‘ Key Idea: Geometric = repeated multiplication by a constant rr. If 0<r<10 < r < 1, the terms shrink; if r>1r > 1, they grow fast.

Find the Common Ratio ๐Ÿงฎ

Find rr by computing a2a1\dfrac{a_2}{a_1}. (Fractions like 1/21/2 are fine.)

1) 3,12,48,192,โ€ฆr=โ€‰?3, 12, 48, 192, \dots \quad r = \,? 2) 7,14,28,56,โ€ฆr=โ€‰?7, 14, 28, 56, \dots \quad r = \,? 3) 80,40,20,10,โ€ฆr=โ€‰?80, 40, 20, 10, \dots \quad r = \,? (fraction or decimal)

The Explicit Formula for Geometric Sequences

For a geometric sequence with first term a1a_1 and common ratio rr:

โ€‰an=a1โ‹…rโ€‰nโˆ’1โ€‰\boxed{\,a_n = a_1 \cdot r^{\,n-1}\,}

Just like arithmetic, the exponent is (nโˆ’1)(n-1) โ€” because reaching the nnth term takes nโˆ’1n-1 multiplications.

Worked Example

Find the 5th term of 2,6,18,โ€ฆ2, 6, 18, \dots

Here a1=2a_1 = 2 and r=62=3r = \frac{6}{2} = 3. With n=5n = 5:

a5=2โ‹…3โ€‰5โˆ’1=2โ‹…34=2โ‹…81=162a_5 = 2 \cdot 3^{\,5-1} = 2 \cdot 3^4 = 2 \cdot 81 = 162

โœ… Check: 2,6,18,54,1622, 6, 18, 54, 162 โ€” the 5th term is 162162. โœ“

Concept Check ๐ŸŽฏ

Find the Term ๐Ÿงฎ

Use an=a1โ‹…rโ€‰nโˆ’1a_n = a_1 \cdot r^{\,n-1}.

1) a1=3,โ€…โ€Šr=2a_1 = 3,\; r = 2. Find a6=โ€‰?a_6 = \,? 2) 1,5,25,125,โ€ฆ1, 5, 25, 125, \dots Find a4=โ€‰?a_4 = \,? 3) a1=4,โ€…โ€Šr=3a_1 = 4,\; r = 3. Find a4=โ€‰?a_4 = \,?

Part 4: Telling Them Apart & Real-World Models

๐Ÿ”ข Arithmetic & Geometric Sequences

Part 4 of 5 โ€” Telling Them Apart & Real-World Models


๐Ÿ”‘ The Big Question: Given a sequence, is it arithmetic, geometric, or neither? Then: how do sequences model real situations like savings, populations, and bouncing balls?

Arithmetic vs. Geometric

The fastest test: look at how you get from one term to the next.

ArithmeticGeometric
Operationadd ddmultiply by rr
Find the ratesubtract: a2โˆ’a1a_2 - a_1divide: a2รทa1a_2 \div a_1
Formulaan=a1+(nโˆ’1)da_n = a_1 + (n-1)dan=a1โ‹…rโ€‰nโˆ’1a_n = a_1 \cdot r^{\,n-1}
Graph shapestraight linecurve (exponential)
Example3,7,11,153, 7, 11, 153,6,12,243, 6, 12, 24

๐Ÿ’ก Quick test: Compute both the difference and the ratio of the first two pairs. If the difference is constant โ†’ arithmetic. If the ratio is constant โ†’ geometric. If neither is constant โ†’ it's neither.

Classify Each Sequence ๐Ÿ”ฝ

Decide whether each sequence is arithmetic, geometric, or neither.

Sequences in the Real World

Arithmetic models describe steady, repeated adding:

You save $50 in a jar, then add $15 every week. Week nn has an=50+(nโˆ’1)(15)a_n = 50 + (n-1)(15) dollars.

Geometric models describe repeated multiplying (percent growth/decay):

A bacteria colony of 200200 doubles every hour. After nn hours there are an=200โ‹…2โ€‰na_n = 200 \cdot 2^{\,n} cells. (Here we use the exponent nn because "after 1 hour" already means one doubling.)

โš ๏ธ Watch the starting point. "Doubles every hour starting at 200" can be written as a sequence 200,400,800,โ€ฆ200, 400, 800, \dots where a1=200,r=2a_1 = 200, r = 2, giving an=200โ‹…2nโˆ’1a_n = 200\cdot 2^{n-1} for the nnth term in the list. Read carefully whether nn counts terms or hours.

Application Check ๐ŸŽฏ

Model It ๐Ÿงฎ

1) You start with $50 and add $15 each week: an=50+(nโˆ’1)(15)a_n = 50 + (n-1)(15). How many dollars after week 6 (a6a_6)? โ€‰?\,? 2) A colony starts at 200200 and doubles each hour: the list is 200,400,800,โ€ฆ200, 400, 800, \dots with an=200โ‹…2โ€‰nโˆ’1a_n = 200\cdot 2^{\,n-1}. How many cells is the 4th term (a4a_4)? โ€‰?\,?

Part 5: Mixed Practice & Mastery Check

๐Ÿ”ข Arithmetic & Geometric Sequences

Part 5 of 5 โ€” Mixed Practice & Mastery Check


You can now (1) find dd and rr, (2) use both explicit formulas, (3) tell the two types apart, and (4) model real situations. Let's put it all together.

Quick Reference

GoalArithmeticGeometric
Get the next term+โ€‰d+\,dร—โ€‰r\times\, r
Find the rated=a2โˆ’a1d = a_2 - a_1r=a2รทa1r = a_2 \div a_1
nnth terman=a1+(nโˆ’1)da_n = a_1 + (n-1)dan=a1โ‹…rโ€‰nโˆ’1a_n = a_1 \cdot r^{\,n-1}
Behaviourconstant difference (line)constant ratio (curve)

โš ๏ธ Top traps: use (nโˆ’1)(n-1), not nn, in both formulas; subtract for dd but divide for rr; and for geometric terms, apply the exponent before multiplying by a1a_1.

Mixed Practice ๐Ÿ”ฝ

Pull the right tool for each problem.

Mixed Drill ๐Ÿงฎ

1) Arithmetic: a1=9,โ€…โ€Šd=6a_1 = 9,\; d = 6. Find a7=โ€‰?a_7 = \,? 2) Geometric: a1=2,โ€…โ€Šr=5a_1 = 2,\; r = 5. Find a4=โ€‰?a_4 = \,? 3) Arithmetic sequence 11,8,5,2,โ€ฆ11, 8, 5, 2, \dots Find a9=โ€‰?a_9 = \,?

Mixed Practice ๐ŸŽฏ

Exit Quiz โœ…

Answer all three to finish the lesson.