Antiderivatives & Indefinite Integrals - Complete Interactive Lesson

Part 1: What is an Antiderivative?

∫ Antiderivatives & Indefinite Integrals

Part 1 of 7 — What is an Antiderivative?

Part	Topic
1	Power Rule for Integration
2	Essential Antiderivative Formulas
3	Initial Value Problems
4	Algebraic Manipulation Before Integrating
5	Inverse Trig Antiderivatives
6	Problem-Solving Workshop
7	Review & Final Assessment

Definition

$\boxed{F'(x) = f(x) \iff \int f(x)\,dx = F(x) + C}$

An antiderivative of $f(x)$ is any function $F(x)$ whose derivative is $f(x)$ .

The indefinite integral $\int f(x)\,dx$ represents the entire FAMILY of antiderivatives.

Key Concept: The " $+C$ " is NOT optional! Since the derivative of any constant is 0, there are infinitely many antiderivatives. For example, $x^2$ , $x^2 + 5$ , and $x^2 - 3$ are ALL antiderivatives of $2x$ .

Notation	Meaning
$\int$	Integral sign ("S" for sum)
$f(x)$	Integrand (the function being integrated)
$dx$	Tells you the variable of integration
$F(x) + C$	General antiderivative (family of functions)

Power Rule for Integration

$\boxed{\int x^n\,dx = \frac{x^{n+1}}{n+1} + C \quad (n \neq -1)}$

Mnemonic: "Add one to the exponent, divide by the new exponent."

This reverses the Power Rule for differentiation. Quick check: $\frac{d}{dx}\left[\frac{x^{n+1}}{n+1}\right] = \frac{(n+1)x^n}{n+1} = x^n$ ✓

Worked Examples

$f(x)$	Rewrite	$\int f(x)\,dx$	Check: $F'(x)$
$x^4$	—	$\frac{x^5}{5} + C$	$\frac{5x^4}{5} = x^4$ ✓
$x^{-3}$	—	$\frac{x^{-2}}{-2} + C = -\frac{1}{2x^2} + C$	$\frac{1}{x^3}$ ✓
$\sqrt{x}$	$x^{1/2}$	$\frac{x^{3/2}}{3/2} + C = \frac{2}{3}x^{3/2} + C$	$\frac{2}{3} \cdot \frac{3}{2} x^{1/2} = \sqrt{x}$ ✓
$\frac{1}{x^4}$	$x^{-4}$	$\frac{x^{-3}}{-3} + C = -\frac{1}{3x^3} + C$	$\frac{1}{x^4}$ ✓
$1$	$x^0$	$x + C$	$1$ ✓

AP Tip: Always CHECK your answer by differentiating! If $F'(x) = f(x)$ , your integral is correct.

The Linearity Property

$\boxed{\int [af(x) + bg(x)]\,dx = a\int f(x)\,dx + b\int g(x)\,dx}$

Example: $\int (3x^2 - 5x + 4)\,dx = 3 \cdot \frac{x^3}{3} - 5 \cdot \frac{x^2}{2} + 4x + C = x^3 - \frac{5x^2}{2} + 4x + C$

Power Rule for Integration 🎯

Special Case: $n = -1$

The Power Rule breaks down when $n = -1$ (division by zero!):

$\int x^{-1}\,dx = \int \frac{1}{x}\,dx = \ln|x| + C$

Key Fact: Absolute value is REQUIRED. $\ln(x)$ is only defined for $x > 0$ , but $\frac{1}{x}$ is defined for all $x \neq 0$ . The absolute value makes the antiderivative valid for negative $x$ too.

Common Mistakes

Mistake	Correct
Forgetting $+C$	Always include $+C$ for indefinite integrals
$\int \frac{1}{x}\,dx = \frac{x^0}{0}$	It's $\ln
$\int 5\,dx = C$	$\int 5\,dx = 5x + C$ (constant × $x$ )
$\int x^{1/2}\,dx = \frac{x^{1/2}}{1/2}$	Must add 1 to exponent FIRST: $\frac{x^{3/2}}{3/2}$

Mixed Power Rule 🎯

Match each integral with its result. 🔍

Compute the coefficient. ✍️

Key Takeaways — Part 1

$\boxed{\int x^n\,dx = \frac{x^{n+1}}{n+1} + C \quad (n \neq -1)}$

Concept	Key Rule
Antiderivative	$F'(x) = f(x)$ means $F$ is an antiderivative of $f$
Indefinite integral	Family of ALL antiderivatives: $F(x) + C$
Power Rule	Add 1 to exponent, divide by new exponent
Exception	$n = -1$ : use $\ln
Linearity	Constants factor out, sums split apart
Check	Always verify by differentiating

Up Next: Part 2 — Essential Antiderivative Formulas (trig, exponential, and more).

Part 2: Essential Antiderivative Formulas

∫ Antiderivatives

Part 2 of 7 — Essential Antiderivative Formulas

The Complete Table

$\boxed{\text{Memorize these — they are the building blocks of ALL integration}}$

Function $f(x)$	Antiderivative $\int f(x)\,dx$	Derivative Check
$x^n$ $(n \neq -1)$	$\frac{x^{n+1}}{n+1} + C$	$\frac{d}{dx}\left[\frac{x^{n+1}}{n+1}\right] = x^n$ ✓
$\frac{1}{x}$	$\ln	x
$e^x$	$e^x + C$	$\frac{d}{dx}[e^x] = e^x$ ✓
$a^x$	$\frac{a^x}{\ln a} + C$	$\frac{d}{dx}\left[\frac{a^x}{\ln a}\right] = a^x$ ✓

Key Fact: $e^x$ is its OWN antiderivative — the only function (up to constants) with this property!

Trigonometric Antiderivatives

Function	Antiderivative	Memory Aid
$\sin x$	$-\cos x + C$	Negative! (sign flips)
$\cos x$	$\sin x + C$	Positive! (no flip)
$\sec^2 x$	$\tan x + C$	Reverse of $\frac{d}{dx}[\tan x]$
$\csc^2 x$	$-\cot x + C$	Negative!
$\sec x \tan x$	$\sec x + C$	Reverse of $\frac{d}{dx}[\sec x]$
$\csc x \cot x$	$-\csc x + C$	Negative!

Pattern: The "co-" functions (cosine, cosecant, cotangent) always get a NEGATIVE sign when integrating.

Inverse Trig Antiderivatives

Function	Antiderivative
$\frac{1}{\sqrt{1-x^2}}$	$\arcsin x + C$
$\frac{1}{1+x^2}$	$\arctan x + C$

AP Tip: These two inverse trig forms appear often on the AP exam. Know them cold!

Essential Antiderivatives 🎯

Linearity of Integration

$\boxed{\int [af(x) + bg(x)]\,dx = a\int f(x)\,dx + b\int g(x)\,dx}$

Worked Examples

Example 1: $\int (5\cos x - 3e^x + \frac{2}{x})\,dx$

$= 5\sin x - 3e^x + 2\ln|x| + C$

Example 2: $\int (\sec^2 x - \csc^2 x)\,dx$

$= \tan x - (-\cot x) + C = \tan x + \cot x + C$

What You CANNOT Do

✗ Wrong	Why
$\int f(x) \cdot g(x)\,dx = \int f\,dx \cdot \int g\,dx$	Products don't split!
$\int \frac{f(x)}{g(x)}\,dx = \frac{\int f\,dx}{\int g\,dx}$	Quotients don't split!
$\int [f(x)]^2\,dx = \frac{[F(x)]^3}{3}$	Composition doesn't work this way!

Key Concept: Integration is LINEAR (constants and sums), but NOT multiplicative. You can only split sums and pull out constants.

Trig & Exponential Integrals 🎯

Match each integral to its result. 🔍

Evaluate the integral. ✍️

Key Takeaways — Part 2

$\boxed{\text{"Co-" functions get a negative: } \int \sin x = -\cos x, \quad \int \csc^2 x = -\cot x}$

Category	Key Formulas
Exponential	$\int e^x\,dx = e^x + C$ ; $\int a^x\,dx = \frac{a^x}{\ln a} + C$
Trig	Memorize all 6; "co-" functions are negative
Inverse trig	$\int \frac{1}{\sqrt{1-x^2}} = \arcsin$ ; $\int \frac{1}{1+x^2} = \arctan$
Linearity	Only sums and constants — NOT products or quotients

Up Next: Part 3 — Initial Value Problems.

Part 3: Trig Antiderivatives

∫ Antiderivatives

Part 3 of 7 — Initial Value Problems (IVPs)

Finding a Specific Antiderivative

An initial condition pins down the exact value of $C$ :

$\boxed{\text{General antiderivative} + \text{initial condition} = \text{particular solution}}$

Step	Action
1	Integrate $f'(x)$ to get $f(x) = F(x) + C$
2	Substitute the initial condition $(x_0, y_0)$
3	Solve for $C$
4	Write the particular solution

Worked Example

Given: $f'(x) = 3x^2 - 4x + 1$ and $f(0) = 5$ . Find $f(x)$ .

Step 1: $f(x) = \int (3x^2 - 4x + 1)\,dx = x^3 - 2x^2 + x + C$

Step 2: $f(0) = 0 - 0 + 0 + C = 5$

Step 3: $C = 5$

$\boxed{f(x) = x^3 - 2x^2 + x + 5}$

Check: $f'(x) = 3x^2 - 4x + 1$ ✓ and $f(0) = 5$ ✓

Position-Velocity-Acceleration

$\boxed{a(t) \xrightarrow{\int} v(t) \xrightarrow{\int} s(t)}$

Each integration introduces a NEW constant, determined by initial conditions.

Quantity	Symbol	Relationship
Acceleration	$a(t)$	Given (or from forces)
Velocity	$v(t)$	$v(t) = \int a(t)\,dt$
Position	$s(t)$	$s(t) = \int v(t)\,dt$

Worked Example: Free Fall

A ball is thrown upward at 64 ft/s from height 80 ft. Find $s(t)$ .

$a(t) = -32$ $ft/s^{2}$ (gravity)

Step 1: $v(t) = \int (-32)\,dt = -32t + C_1$

$v(0) = 64$ → $C_1 = 64$
So $v(t) = -32t + 64$

Step 2: $s(t) = \int (-32t + 64)\,dt = -16t^2 + 64t + C_2$

$s(0) = 80$ → $C_2 = 80$

$\boxed{s(t) = -16t^2 + 64t + 80}$

Key Fact: In free fall, $a = -32$ $ft/s^{2}$ or $a = -9.8$ $m/s^{2}$ . The negative sign means downward. Two initial conditions are needed: $v(0)$ and $s(0)$ .

Initial Value Problems 🎯

Multiple Initial Conditions

When given $f''(x)$ , you need TWO initial conditions (one for each integration):

Integration Level	Introduces	Determined By
$f''(x) \to f'(x)$	$C_1$	$f'(x_0) = v_0$
$f'(x) \to f(x)$	$C_2$	$f(x_1) = y_1$

AP-Style Example

$f''(x) = 12x - 4$ , $f'(1) = 3$ , $f(2) = 10$ . Find $f(x)$ .

First integration: $f'(x) = 6x^2 - 4x + C_1$

$f'(1) = 6 - 4 + C_1 = 3$ → $C_1 = 1$
$f'(x) = 6x^2 - 4x + 1$

Second integration: $f(x) = 2x^3 - 2x^2 + x + C_2$

$f(2) = 16 - 8 + 2 + C_2 = 10$ → $C_2 = 0$

$\boxed{f(x) = 2x^3 - 2x^2 + x}$

AP Tip: When an IVP asks for a SPECIFIC value like $f(3)$ , you can sometimes use the definite integral: $f(3) = f(2) + \int_2^3 f'(x)\,dx$ , which may be faster.

Motion IVPs 🎯

Solve the IVP step by step. 🔍

$f'(x) = 4x - 3$ , $f(2) = 7$

Solve the IVP. ✍️

Key Takeaways — Part 3

$\boxed{f'(x) + \text{initial condition} \xrightarrow{\int} \text{unique } f(x)}$

Concept	Key Rule
IVP	Antiderivative + initial condition → find $C$
Double IVP	$f'' \to f' \to f$ needs TWO conditions
Motion	$a \xrightarrow{\int} v \xrightarrow{\int} s$ , each step needs an IC
Free fall	$a = -32$ $ft/s^{2}$ , $v(t) = -32t + v_0$ , $s(t) = -16t^2 + v_0 t + s_0$
AP shortcut	$f(b) = f(a) + \int_a^b f'(x)\,dx$

Up Next: Part 4 — Algebraic Manipulation Before Integrating.

Part 4: Rewriting Before Integrating

∫ Antiderivatives

Part 4 of 7 — Rewriting Before Integrating

The Strategy

$\boxed{\text{Can't integrate directly?} \to \text{Rewrite algebraically} \to \text{Then integrate}}$

Many integrals look hard but become easy after algebraic manipulation:

Technique	When to Use	Example
Expand products	$(...)(...)$ in integrand	$(x+1)(x-3)$
Split fractions	$\frac{\text{polynomial}}{\text{monomial}}$	$\frac{x^3+2x}{x^2}$
Rewrite radicals	Roots in integrand	$\frac{3}{\sqrt{x}}$
Factor out constants	Coefficient in front	$\int 5x^3\,dx$

Key Concept: You CANNOT integrate products or quotients by integrating top and bottom separately. You must rewrite into a SUM first.

Technique 1: Expand Products

$\int (x+1)(x-3)\,dx = \int (x^2 - 2x - 3)\,dx = \frac{x^3}{3} - x^2 - 3x + C$

$\int x(x^2 + 4)\,dx = \int (x^3 + 4x)\,dx = \frac{x^4}{4} + 2x^2 + C$

Technique 2: Split Fractions

$\int \frac{x^3 + 2x}{x^2}\,dx = \int \left(x + \frac{2}{x}\right)\,dx = \frac{x^2}{2} + 2\ln|x| + C$

$\int \frac{x^2 - 4x + 1}{\sqrt{x}}\,dx = \int (x^{3/2} - 4x^{1/2} + x^{-1/2})\,dx$ $= \frac{2x^{5/2}}{5} - \frac{8x^{3/2}}{3} + 2x^{1/2} + C$

Technique 3: Rewrite Radicals

$\int \frac{3}{\sqrt{x}}\,dx = \int 3x^{-1/2}\,dx = 6\sqrt{x} + C$

$\int \sqrt[3]{x^2}\,dx = \int x^{2/3}\,dx = \frac{x^{5/3}}{5/3} + C = \frac{3}{5}x^{5/3} + C$

AP Tip: Always convert to $x^n$ form before applying the Power Rule. Roots, reciprocals, and radicals are just fractional/negative exponents.

Simplify Then Integrate 🎯

Technique 4: Trig Identities

Sometimes you need a trig identity before integrating:

Integral	Identity Used	Result
$\int \tan^2 x\,dx$	$\tan^2 x = \sec^2 x - 1$	$\tan x - x + C$
$\int \sin^2 x\,dx$	$\sin^2 x = \frac{1-\cos 2x}{2}$	$\frac{x}{2} - \frac{\sin 2x}{4} + C$
$\int \cos^2 x\,dx$	$\cos^2 x = \frac{1+\cos 2x}{2}$	$\frac{x}{2} + \frac{\sin 2x}{4} + C$

Key Fact: $\int \tan x\,dx$ and $\int \sec x\,dx$ require techniques you'll see later ( $u$ -substitution). For now, focus on recognizing when an identity simplifies the integrand.

Decision Flowchart

See This in Integrand	Do This
$(a+b)(c+d)$	FOIL, then integrate terms
$\frac{\text{polynomial}}{x^n}$	Divide each term by $x^n$
$\sqrt[n]{x^m}$	Rewrite as $x^{m/n}$
$\frac{1}{x^n}$	Rewrite as $x^{-n}$
$\tan^2 x$ or $\cot^2 x$	Use Pythagorean identity

Trig & Advanced Rewriting 🎯

Identify the correct rewriting technique. 🔍

Evaluate the integral. ✍️

Key Takeaways — Part 4

$\boxed{\text{Rewrite} \to \text{Integrate term by term} \to \text{Simplify}}$

Technique	Template
Expand products	FOIL or distribute, then integrate each term
Split fractions	Divide each numerator term by denominator
Rewrite radicals	Convert to $x^{m/n}$ , apply Power Rule
Trig identities	$\tan^2 = \sec^2-1$ , double-angle for $\sin^2, \cos^2$
Factor & cancel	$\frac{x^3-1}{x-1} = x^2+x+1$

Up Next: Part 5 — Inverse Trig Antiderivatives.

Part 5: Inverse Trig Antiderivatives

∫ Antiderivatives

Part 5 of 7 — Inverse Trig Antiderivatives

The Two Essential Forms (AB Exam)

$\boxed{\int \frac{1}{\sqrt{a^2 - x^2}}\,dx = \arcsin\left(\frac{x}{a}\right) + C}$

$\boxed{\int \frac{1}{a^2 + x^2}\,dx = \frac{1}{a}\arctan\left(\frac{x}{a}\right) + C}$

Key Fact: The arcsecant formula ( $\int \frac{1}{x\sqrt{x^2-a^2}}$ ) is BC only. AB students need ONLY arcsin and arctan forms.

How to Recognize Them

Pattern in Denominator	Form	Antiderivative
$\sqrt{a^2 - x^2}$ (square root, MINUS)	Arcsin	$\arcsin(x/a)$
$a^2 + x^2$ (no square root, PLUS)	Arctan	$\frac{1}{a}\arctan(x/a)$

Careful with signs: $\sqrt{x^2 - a^2}$ is NOT the arcsin form (notice the minus is flipped!).

Worked Examples

Example 1: $\int \frac{1}{\sqrt{9-x^2}}\,dx$

Here $a^2 = 9$ , so $a = 3$ : $\arcsin\left(\frac{x}{3}\right) + C$

Example 2: $\int \frac{1}{4 + x^2}\,dx$

Here $a^2 = 4$ , so $a = 2$ : $\frac{1}{2}\arctan\left(\frac{x}{2}\right) + C$

Example 3: $\int \frac{3}{\sqrt{1 - 4x^2}}\,dx$

Rewrite: $\frac{3}{\sqrt{1-(2x)^2}}$ . Let $u = 2x$ , $du = 2\,dx$ :

$\frac{3}{2}\int \frac{du}{\sqrt{1-u^2}} = \frac{3}{2}\arcsin(u) + C = \frac{3}{2}\arcsin(2x) + C$

Completing the Square

Sometimes you need to complete the square first:

$\int \frac{1}{x^2 + 6x + 13}\,dx$

$x^2 + 6x + 13 = (x+3)^2 + 4$ . Now it's arctan form!

$= \frac{1}{2}\arctan\left(\frac{x+3}{2}\right) + C$

AP Tip: If the denominator is a quadratic that doesn't factor, try completing the square to reveal an inverse trig form.

Inverse Trig Integrals 🎯

Don't Confuse These!

Integral	Result	Key Clue
$\int \frac{1}{\sqrt{1-x^2}}\,dx$	$\arcsin(x) + C$	Square root + minus
$\int \frac{1}{1+x^2}\,dx$	$\arctan(x) + C$	No square root + plus
$\int \frac{x}{1+x^2}\,dx$	$\frac{1}{2}\ln(1+x^2) + C$	Has $x$ in numerator! (u-sub)
$\int \frac{x}{\sqrt{1-x^2}}\,dx$	$-\sqrt{1-x^2} + C$	Has $x$ in numerator! (u-sub)

Key Concept: The inverse trig forms ONLY work when the numerator is a CONSTANT. If there's an $x$ in the numerator, it's a $u$ -substitution problem instead!

Distinguish the Forms 🎯

Classify each integral. 🔍

Evaluate the definite integral. ✍️

Key Takeaways — Part 5

$\boxed{\frac{1}{\sqrt{a^2-x^2}} \to \arcsin\left(\frac{x}{a}\right) \qquad \frac{1}{a^2+x^2} \to \frac{1}{a}\arctan\left(\frac{x}{a}\right)}$

Concept	Key Rule
Arcsin form	$\sqrt{a^2-x^2}$ in denominator, constant numerator
Arctan form	$a^2+x^2$ in denominator, constant numerator
$x$ in numerator	NOT inverse trig — use $u$ -substitution
Completing square	Reveals hidden inverse trig forms
AB vs BC	AB only needs arcsin and arctan (not arcsec)

Up Next: Part 6 — Problem-Solving Workshop.

Part 6: Mixed Practice

∫ Antiderivatives

Part 6 of 7 — Mixed Practice Workshop

The Real Challenge: Choosing the Right Tool

On the AP Exam, nobody tells you WHICH rule to use. You must:

Look at the integrand's structure
Classify it (power rule? trig? inverse trig? rewrite first?)
Apply the correct formula
Check by differentiating

Decision Flowchart

Ask Yourself	If YES →	Example
Is it a sum/difference?	Split into separate integrals	$\int (x^2 + e^x)\,dx$
Is it $x^n$ ?	Power Rule	$\int x^{-3}\,dx$
Is it $1/x$ ?	$\ln	x
Is it $e^x$ or $a^x$ ?	Exponential rule	$\int 3e^x\,dx$
Is it a trig function?	Trig formula table	$\int \sec^2 x\,dx$
Does it have $\sqrt{a^2 - x^2}$ ?	Arcsin form	$\int \frac{1}{\sqrt{4-x^2}}\,dx$
Does it have $a^2 + x^2$ ?	Arctan form	$\int \frac{1}{9+x^2}\,dx$
Is it a product/fraction?	Can I rewrite algebraically?	$\int \frac{x^2+1}{x}\,dx$

Key Concept: Most "hard" antiderivatives are actually easy formulas in disguise — you just need to rewrite first!

Mixed Worked Examples

Example 1: $\int \left(\frac{3}{x} + 4\cos x - x^5\right)dx$

Split: $3\ln|x| + 4\sin x - \frac{x^6}{6} + C$

Example 2: $\int \frac{x^3 + 2x - 1}{x^2}\,dx$

Rewrite: $\int (x + 2x^{-1} - x^{-2})\,dx = \frac{x^2}{2} + 2\ln|x| + \frac{1}{x} + C$

Example 3: $\int (\sqrt{x} + e^x + \sec x \tan x)\,dx$

$= \frac{2}{3}x^{3/2} + e^x + \sec x + C$

Example 4 (IVP): $f'(x) = 6x^2 - 4x + 1$ , $f(1) = 3$ .

$f(x) = 2x^3 - 2x^2 + x + C$ . $f(1) = 2 - 2 + 1 + C = 3 \Rightarrow C = 2$ .

$f(x) = 2x^3 - 2x^2 + x + 2$

AP Tip: Always verify by differentiating. If $\frac{d}{dx}[\text{your answer}] = \text{integrand}$ , you're correct!

Mixed Antiderivative Problems — Set 1 🎯

Mixed Antiderivative Problems — Set 2 🎯

Common AP Mistakes on Mixed Problems

Mistake	Wrong	Correct
Forgetting $+C$	$\int x\,dx = x^2/2$	$\int x\,dx = x^2/2 + C$
$\int 1/x = x^0/0$	Undefined	$\ln
Missing coefficient	$\int x^{1/2} = x^{3/2}$	$\frac{2}{3}x^{3/2}$
Trig sign errors	$\int \sin x = \sin x$	$\int \sin x = -\cos x$
Not rewriting first	$\int \frac{x+1}{x}$ stuck	$= \int (1 + 1/x)\,dx$
$\int f \cdot g \neq (\int f)(\int g)$	Product of integrals	Must rewrite or use u-sub

Key Fact: The most common FRQ error is forgetting $+C$ on indefinite integrals. On the AP Exam, this can cost you a point!

Identify the technique and compute. 🔍

Solve the IVP. ✍️

Key Takeaways — Part 6

Strategy	When to Use
Split the integral	Sums and differences
Power Rule	Any $x^n$ with $n \neq -1$
$\ln	x
Trig formulas	Recognize the 6 basic forms
Inverse trig	$\sqrt{a^2-x^2}$ or $a^2+x^2$
Rewrite first	Products, fractions, radicals

$\boxed{\text{Step 1: Classify} \to \text{Step 2: Apply} \to \text{Step 3: Verify by differentiating}}$

Up Next: Part 7 — Comprehensive Assessment.

Part 7: Comprehensive Assessment

∫ Antiderivatives — Comprehensive Review

Part 7 of 7 — Final Assessment

Complete Formula Reference

Function	Antiderivative	Notes
$x^n$ $(n \neq -1)$	$\frac{x^{n+1}}{n+1} + C$	Power Rule
$\frac{1}{x}$	$\ln	x
$e^x$	$e^x + C$	—
$\sin x$	$-\cos x + C$	Negative!
$\cos x$	$\sin x + C$	—
$\sec^2 x$	$\tan x + C$	—
$\csc^2 x$	$-\cot x + C$	Negative!
$\sec x \tan x$	$\sec x + C$	—
$\csc x \cot x$	$-\csc x + C$	Negative!
$\frac{1}{\sqrt{a^2-x^2}}$	$\arcsin(x/a) + C$	Inverse trig
$\frac{1}{a^2+x^2}$	$\frac{1}{a}\arctan(x/a) + C$	Inverse trig

Quick-Reference Decision Guide

$\boxed{\text{Read} \to \text{Rewrite (if needed)} \to \text{Recognize the form} \to \text{Apply formula} \to \text{Add } +C}$

Top AP Exam Mistakes — Antiderivatives

#	Mistake	Example	Cost
1	Forgetting $+C$	Writing $x^2/2$ instead of $x^2/2 + C$	1 pt on FRQ
2	Power Rule with $n = -1$	$\int x^{-1} \neq x^0/0$ → it's $\ln	x
3	Missing absolute value	$\ln(x)$ vs $\ln	x
4	Sign errors on trig	$\int \sin x = \cos x$ (forgot negative)	Full credit
5	Coefficient errors	$\int x^{1/2} = x^{3/2}$ (forgot $\times 2/3$ )	Full credit
6	Not verifying IVP	Solving for $C$ but plugging into wrong equation	Full credit

Key Fact: On FRQs, you get a "linkage point" for correctly connecting your antiderivative to the initial condition. Show ALL steps: general solution → plug in IC → solve for $C$ → write particular solution.

Final Assessment — Set 1 🎯

Final Assessment — Set 2 🎯

AP-Style Mixed Classification 🔍

Final Challenge ✍️

Antiderivatives — Complete! ✅

You have mastered:

Skill	Parts Covered
Power Rule & Linearity	Parts 1-2
Trig & Exponential Formulas	Part 2
Initial Value Problems	Parts 3, 6
Rewriting Techniques	Part 4
Inverse Trig Antiderivatives	Part 5
Mixed Problem Strategy	Parts 6-7

AP Exam Checklist

✅ Can I recognize ALL basic antiderivative forms?
✅ Can I rewrite integrands to match known forms?
✅ Do I always include $+C$ for indefinite integrals?
✅ Can I solve IVPs with one or two initial conditions?
✅ Can I distinguish inverse trig from $u$ -sub cases?
✅ Do I verify answers by differentiating?

$\boxed{\text{Integration is the REVERSE of differentiation — always check by differentiating!}}$

Antiderivatives & Indefinite Integrals

Antiderivatives & Indefinite Integrals - Complete Interactive Lesson

Part 1: What is an Antiderivative?

∫ Antiderivatives & Indefinite Integrals

Definition

Power Rule for Integration

Worked Examples

The Linearity Property

Special Case: n=−1n = -1n=−1

Common Mistakes

Key Takeaways — Part 1

Part 2: Essential Antiderivative Formulas

∫ Antiderivatives

The Complete Table

Trigonometric Antiderivatives

Inverse Trig Antiderivatives

Linearity of Integration

Worked Examples

What You CANNOT Do

Key Takeaways — Part 2

Part 3: Trig Antiderivatives

∫ Antiderivatives

Finding a Specific Antiderivative

Worked Example

Position-Velocity-Acceleration

Worked Example: Free Fall

Multiple Initial Conditions

AP-Style Example

Key Takeaways — Part 3

Part 4: Rewriting Before Integrating

∫ Antiderivatives

The Strategy

Technique 1: Expand Products

Technique 2: Split Fractions

Technique 3: Rewrite Radicals

Technique 4: Trig Identities

Decision Flowchart

Key Takeaways — Part 4

Part 5: Inverse Trig Antiderivatives

∫ Antiderivatives

The Two Essential Forms (AB Exam)

How to Recognize Them

Worked Examples

Completing the Square

Don't Confuse These!

Key Takeaways — Part 5

Part 6: Mixed Practice

∫ Antiderivatives

The Real Challenge: Choosing the Right Tool

Decision Flowchart

Mixed Worked Examples

Common AP Mistakes on Mixed Problems

Key Takeaways — Part 6

Part 7: Comprehensive Assessment

∫ Antiderivatives — Comprehensive Review

Complete Formula Reference

Quick-Reference Decision Guide

Top AP Exam Mistakes — Antiderivatives

Antiderivatives — Complete! ✅

AP Exam Checklist

Special Case: $n = -1$