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AP Precalculus FRQ Practice Guide

How to attack free-response questions and earn easy partial credit.

⏱️ ~3-4 hours of focused work📈 AP Precalculus

AP Precalculus has 4 Free Response Questions, each testing a different skill. Knowing the archetype saves time and prevents careless errors.

FRQ Archetype 1: Function Concepts

What it asks: Analyze a polynomial, rational, exponential, or log function. Usually: find domain, zeros, asymptotes, increasing/decreasing intervals, or end behavior. May include graph sketching or interpretation from a graph.

Red flags in the prompt: "justify," "explain," "verify," "support your answer."

Template response

  1. Set up: State what you're finding. "To find vertical asymptotes, I set the denominator equal to zero: x2−4=0⇒x=±2x^2 - 4 = 0 \Rightarrow x = \pm 2."
  2. Check numerator: "At x=2x = 2, the numerator is 8−6=2≠08 - 6 = 2 \neq 0, so x=2x = 2 is a vertical asymptote."
  3. Interpret: "As x→2−x \to 2^-, the numerator approaches a positive value and the denominator approaches zero from below, so f(x)→−∞f(x) \to -\infty."
  4. Conclude: "Therefore, ff has a vertical asymptote at x=2x = 2."

Worked example

Problem: For f(x)=2x2−8x2−4f(x) = \frac{2x^2 - 8}{x^2 - 4}, identify all vertical asymptotes and any holes.

Solution:

  • Factor: f(x)=2(x2−4)x2−4=2(x−2)(x+2)(x−2)(x+2)f(x) = \frac{2(x^2-4)}{x^2-4} = \frac{2(x-2)(x+2)}{(x-2)(x+2)}.
  • Cancel common factors: x=2x = 2 and x=−2x = -2 are removable (holes, not asymptotes).
  • After canceling: f(x)=2f(x) = 2 for x≠±2x \neq \pm 2.
  • Conclusion: No vertical asymptotes; holes at (±2,2)(\pm 2, 2).

⚠️ Trap: Many students forget to check if numerator and denominator share a factor. Always factor completely before setting denominator = 0.

FRQ Archetype 2: Non-Periodic Modeling (Exponential or Logarithmic)

What it asks: A real-world context (population, investment, half-life, pH, decibels). Write the model, interpret parameters, make predictions, or solve for unknown time/quantity.

Red flags: "write an equation," "predict," "how long," "when will."

Template response

  1. Identify the model form: Is this exponential growth/decay (A=a⋅btA = a \cdot b^t) or logarithmic (y=alog⁡b(x)+cy = a\log_b(x) + c)?
  2. Define variables: "Let tt = years since 2020, and P(t)P(t) = population in thousands."
  3. Find parameters: "Initial population: P(0)=500P(0) = 500 (given). Growth rate: 3% per year means b=1.03b = 1.03."
  4. Write the model: P(t)=500⋅1.03tP(t) = 500 \cdot 1.03^t.
  5. Make prediction: "In 2030 (t=10t = 10), P(10)=500⋅1.0310≈671.96P(10) = 500 \cdot 1.03^{10} \approx 671.96 thousand."
  6. Interpret in context: "The population is predicted to be approximately 672,000 in 2030."

Worked example

Problem: A radioactive sample has an initial mass of 100 grams. After 5 years, 60 grams remain. Write an exponential decay model and predict the mass after 12 years.

Solution:

  • Form: M(t)=a⋅btM(t) = a \cdot b^t (or M(t)=aektM(t) = a e^{kt}).
  • Initial condition: M(0)=100⇒a=100M(0) = 100 \Rightarrow a = 100.
  • Use second data point: M(5)=60⇒100b5=60⇒b5=0.6⇒b=0.61/5≈0.8943M(5) = 60 \Rightarrow 100 b^5 = 60 \Rightarrow b^5 = 0.6 \Rightarrow b = 0.6^{1/5} \approx 0.8943.
  • Model: M(t)=100⋅(0.8943)tM(t) = 100 \cdot (0.8943)^t.
  • After 12 years: M(12)=100⋅(0.8943)12≈27.99≈28M(12) = 100 \cdot (0.8943)^{12} \approx 27.99 \approx 28 grams.

FRQ Archetype 3: Sinusoidal Modeling (Periodic Context)

What it asks: Real-world periodic data (temperature cycles, tides, electrical current, seasonal sales). Write f(t)=asin⁡(b(t−c))+df(t) = a\sin(b(t-c)) + d with correct amplitude, period, midline, and phase shift.

Key skill: Extracting parameters from context, not from a table.

Template response

  1. Midline dd: Average of max and min values. "High temp: 85°F, low temp: 55°F. Midline: 85+552=70\frac{85+55}{2} = 70°F."
  2. Amplitude aa: Half the range. "a=85−552=15a = \frac{85-55}{2} = 15."
  3. Period & frequency bb: "The cycle repeats every 12 months, so period = 12. Thus b=2π12=π6b = \frac{2\pi}{12} = \frac{\pi}{6}."
  4. Phase shift cc: "The maximum occurs in July (month 7). For sin⁡\sin, max occurs when b(t−c)=π/2b(t-c) = \pi/2. So π6(7−c)=π2⇒c=7−3=4\frac{\pi}{6}(7-c) = \frac{\pi}{2} \Rightarrow c = 7 - 3 = 4. Thus the shift is 4 months."
  5. Write model: T(t)=15sin⁡(π6(t−4))+70T(t) = 15\sin\left(\frac{\pi}{6}(t-4)\right) + 70, where tt is months since January.

Worked example

Problem: Ocean tides at a beach vary from a low of 2 feet to a high of 8 feet. High tide occurs at noon. The cycle repeats every 12.4 hours. Write a sinusoidal model for the water height h(t)h(t), where tt is hours after midnight.

Solution:

  • Midline: d=8+22=5d = \frac{8+2}{2} = 5 feet.
  • Amplitude: a=8−22=3a = \frac{8-2}{2} = 3 feet.
  • Period: 12.4 hours, so b=2π12.4=5π31b = \frac{2\pi}{12.4} = \frac{5\pi}{31}.
  • Phase shift: High tide (max) at noon (t=12t = 12). For sin⁡\sin, max is at b(t−c)=π/2b(t-c) = \pi/2, so 5π31(12−c)=π2\frac{5\pi}{31}(12-c) = \frac{\pi}{2}. Solve: 12−c=π/2⋅315π=3110=3.1⇒c=8.912 - c = \frac{\pi/2 \cdot 31}{5\pi} = \frac{31}{10} = 3.1 \Rightarrow c = 8.9.
  • Model: h(t)=3sin⁡(5π31(t−8.9))+5h(t) = 3\sin\left(\frac{5\pi}{31}(t - 8.9)\right) + 5.

💡 Key habit: Always check your model at the known max/min. If high tide is at t=12t = 12, verify h(12)=8h(12) = 8.

FRQ Archetype 4: Symbolic Manipulation

What it asks: Solve for a variable, prove an identity, verify a property, or simplify an expression. Often: solve log⁡\log or exponential equations, trig identities, parametric/polar conversions, or matrix systems.

Red flags: "Solve for," "prove," "verify," "show that."

Template response

  1. Show your steps: Write every algebraic move.
  2. State properties used: "By the power rule of logarithms," "using the Pythagorean identity," etc.
  3. Conclude clearly: Box the final answer or state "Therefore, x=…x = \ldots."

Worked example

Problem: Solve ln⁡(x+3)−ln⁡(x−1)=2\ln(x+3) - \ln(x-1) = 2 for xx.

Solution:

  • By the quotient rule for logarithms: ln⁡(x+3x−1)=2\ln\left(\frac{x+3}{x-1}\right) = 2.
  • Exponentiate both sides: x+3x−1=e2\frac{x+3}{x-1} = e^2.
  • Cross-multiply: x+3=e2(x−1)x + 3 = e^2(x-1).
  • Expand: x+3=e2x−e2x + 3 = e^2 x - e^2.
  • Rearrange: 3+e2=e2x−x=x(e2−1)3 + e^2 = e^2 x - x = x(e^2 - 1).
  • Solve: x=3+e2e2−1≈3+7.3897.389−1≈10.3896.389≈1.626x = \frac{3 + e^2}{e^2 - 1} \approx \frac{3 + 7.389}{7.389 - 1} \approx \frac{10.389}{6.389} \approx 1.626.
  • Check domain: x>1x > 1 (so ln⁡(x−1)\ln(x-1) is defined) and x>−3x > -3 (so ln⁡(x+3)\ln(x+3) is defined). x≈1.626x \approx 1.626 satisfies both. ✓

High-yield formulas to memorize for FRQs

TypeFormulaUsage
Sinusoidal formf(t)=asin⁡(b(t−c))+df(t) = a\sin(b(t-c)) + dPeriodic modeling
PeriodT=2πbT = \frac{2\pi}{b}Extract bb from period
Log propertieslog⁡(xy)=log⁡(x)+log⁡(y)\log(xy) = \log(x) + \log(y); log⁡(xn)=nlog⁡(x)\log(x^n) = n\log(x)Solve log equations
Change of baselog⁡b(x)=ln⁡(x)ln⁡(b)\log_b(x) = \frac{\ln(x)}{\ln(b)}Convert between log bases
Exponential formsA=aektA = ae^{kt} and A=abtA = ab^t are equivalent if b=ekb = e^kModel growth/decay

Common FRQ mistakes

⚠️ Mistake 1: Forgetting the phase shift is outside the sine argument. sin⁡(2(t−3))\sin(2(t-3)) has phase shift 3 to the right, not sin⁡(2t−3)\sin(2t - 3).

⚠️ Mistake 2: Forgetting to state your model or define variables. Even if your math is right, if you don't write "Let P(t)=P(t) = population at time tt," you lose communication points.

⚠️ Mistake 3: Confusing cos⁡−1\cos^{-1} with 1/cos⁡1/\cos. Inverse trig is not a reciprocal.

⚠️ Mistake 4: Forgetting domain restrictions when solving trig or log equations. ln⁡(x)\ln(x) is only defined for x>0x > 0; sin⁡−1(x)\sin^{-1}(x) is only defined for −1≤x≤1-1 \leq x \leq 1.

Practice strategy

  • Day 1: Solve one full FRQ from each archetype (untimed, use notes).
  • Day 2: Solve one FRQ from the archetype where you scored lowest (timed, 15–20 min per FRQ).
  • Day 3: Timed full set: all 4 FRQs in 90 minutes.
  • Day 4: Review errors; re-solve problems you missed.

Ready to practice?

Jump to the 1-Month Study Plan for a full FRQ practice calendar, or start with the 3-Day Cram if exam day is near. 🎯


Next: After mastering all 4 archetypes, review the Last-Minute Review for final formulas and common traps.

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