Linear Equation Word Problems
Translating word problems into equations
Linear Equation Word Problems
Introduction to Word Problems
Word problems translate real-world situations into mathematical equations. The key is understanding the language and identifying the mathematical relationships.
Why Word Problems Matter:
- They connect math to real life
- They develop critical thinking skills
- They appear on standardized tests
- They show practical applications of algebra
The Problem-Solving Process
Step 1: Read and Understand
- Read the entire problem carefully
- Identify what you're looking for
- Note any given information
Step 2: Define Variables
- Choose a letter to represent the unknown
- Write what the variable represents in words
Step 3: Write an Equation
- Translate words into math symbols
- Use the relationships described
Step 4: Solve the Equation
- Use algebraic techniques
- Show all work step-by-step
Step 5: Check and Interpret
- Does the answer make sense?
- Answer the question in a complete sentence
- Check in the original problem (not just the equation)
Key Words and Phrases
Addition (+):
- sum, total, combined, more than, increased by, plus, added to
Subtraction (-):
- difference, less than, decreased by, minus, fewer, reduced by, subtracted from
Multiplication (ร):
- product, times, of, multiplied by, at (rate), per, twice, double, triple
Division (รท):
- quotient, divided by, ratio, per, split, shared equally
Equals (=):
- is, equals, is equal to, amounts to, results in, the same as
Number Problems
These involve relationships between numbers.
Example 1: Consecutive Integers Problem: The sum of three consecutive integers is 72. Find the integers.
Let x = first integer Then x + 1 = second integer And x + 2 = third integer
Equation: x + (x + 1) + (x + 2) = 72 3x + 3 = 72 3x = 69 x = 23
Answer: The integers are 23, 24, and 25.
Check: 23 + 24 + 25 = 72 โ
Example 2: Number Relationships Problem: One number is 5 more than twice another number. Their sum is 38. Find the numbers.
Let x = smaller number Then 2x + 5 = larger number
Equation: x + (2x + 5) = 38 3x + 5 = 38 3x = 33 x = 11
Answer: The numbers are 11 and 27.
Check: 11 + 27 = 38 โ and 27 = 2(11) + 5 โ
Example 3: Even Consecutive Integers Problem: Find three consecutive even integers whose sum is 126.
Let x = first even integer Then x + 2 = second even integer And x + 4 = third even integer
Equation: x + (x + 2) + (x + 4) = 126 3x + 6 = 126 3x = 120 x = 40
Answer: The integers are 40, 42, and 44.
Age Problems
These involve relationships between people's ages.
Example 1: Current Ages Problem: Maria is 3 years older than her brother. The sum of their ages is 27. How old is each?
Let x = brother's age Then x + 3 = Maria's age
Equation: x + (x + 3) = 27 2x + 3 = 27 2x = 24 x = 12
Answer: Brother is 12, Maria is 15.
Example 2: Ages in the Future Problem: Sarah is 8 years old. In how many years will she be 20?
Let x = number of years Her future age: 8 + x
Equation: 8 + x = 20 x = 12
Answer: In 12 years.
Example 3: Ages in the Past Problem: Tom is currently 24. His age is 6 more than twice his age 5 years ago. Is this true?
Let x = Tom's age 5 years ago Then x + 5 = Tom's current age (24)
So x = 19 (Tom was 19 five years ago) Check: Is 24 six more than twice 19? 2(19) + 6 = 38 + 6 = 44 โ 24
This reveals an inconsistency in the problem setup.
Money and Cost Problems
Example 1: Shopping Problem: You buy 3 notebooks and 2 pens for 1.50, what is the cost of each notebook?
Let x = cost of one notebook Total: 3x + 2(1.50) = 11
Equation: 3x + 3 = 11 3x = 8 x = 2.67 (approximately)
Answer: Each notebook costs about $2.67.
Example 2: Ticket Sales Problem: Student tickets cost 5. If 200 tickets were sold for $840, how many were student tickets?
Let x = number of student tickets Then 200 - x = number of adult tickets
Equation: 3x + 5(200 - x) = 840 3x + 1000 - 5x = 840 -2x = -160 x = 80
Answer: 80 student tickets were sold.
Example 3: Budget Problem: You have 4 each and you need to buy 3 folders at $2 each. How many binders can you buy?
Let x = number of binders Cost equation: 4x + 3(2) โค 50
4x + 6 โค 50 4x โค 44 x โค 11
Answer: You can buy at most 11 binders.
Geometry Problems
Example 1: Perimeter Problem: The perimeter of a rectangle is 50 cm. The length is 5 cm more than the width. Find the dimensions.
Let w = width Then w + 5 = length
Perimeter formula: 2w + 2(w + 5) = 50 2w + 2w + 10 = 50 4w = 40 w = 10
Answer: Width is 10 cm, length is 15 cm.
Check: 2(10) + 2(15) = 20 + 30 = 50 โ
Example 2: Angles Problem: Two angles are supplementary (sum to 180ยฐ). One angle is 30ยฐ more than twice the other. Find both angles.
Let x = smaller angle Then 2x + 30 = larger angle
Equation: x + (2x + 30) = 180 3x + 30 = 180 3x = 150 x = 50
Answer: The angles are 50ยฐ and 130ยฐ.
Example 3: Triangle Problem: The second angle of a triangle is twice the first. The third angle is 20ยฐ more than the first. Find all three angles.
Let x = first angle Then 2x = second angle And x + 20 = third angle
Sum of angles: x + 2x + (x + 20) = 180 4x + 20 = 180 4x = 160 x = 40
Answer: The angles are 40ยฐ, 80ยฐ, and 60ยฐ.
Distance, Rate, and Time Problems
Use the formula: Distance = Rate ร Time (d = rt)
Example 1: Travel Time Problem: You drive 240 miles at 60 mph. How long does it take?
Using d = rt: 240 = 60t t = 4
Answer: 4 hours.
Example 2: Meeting Problem: Two cars leave the same point driving in opposite directions. One travels at 50 mph, the other at 60 mph. After how many hours are they 330 miles apart?
Let t = time in hours Distance apart = distance car 1 + distance car 2
Equation: 50t + 60t = 330 110t = 330 t = 3
Answer: After 3 hours.
Example 3: Catch Up Problem: A car leaves at noon traveling 55 mph. Another car leaves at 1 PM traveling 65 mph on the same route. When does the second car catch up?
Let t = time the second car travels (hours) Then t + 1 = time the first car travels
When they meet, distances are equal: 65t = 55(t + 1) 65t = 55t + 55 10t = 55 t = 5.5
Answer: The second car catches up at 6:30 PM.
Percent Problems
Example 1: Discount Problem: A shirt is on sale for 25% off. If the sale price is $30, what was the original price?
Let x = original price Sale price = original - discount
Equation: x - 0.25x = 30 0.75x = 30 x = 40
Answer: The original price was $40.
Example 2: Tax Problem: The total cost of an item including 8% sales tax is $54. What was the pre-tax price?
Let x = pre-tax price Total = price + tax
Equation: x + 0.08x = 54 1.08x = 54 x = 50
Answer: The pre-tax price was $50.
Mixture Problems (Preview)
Example: Combining Solutions Problem: How many liters of 20% acid solution should be mixed with 5 liters of 50% acid solution to get a 30% solution?
Let x = liters of 20% solution
Amount of pure acid from each: 0.20x + 0.50(5) = 0.30(x + 5) 0.20x + 2.5 = 0.30x + 1.5 1 = 0.10x x = 10
Answer: 10 liters of 20% solution.
Common Mistakes to Avoid
-
Not defining the variable clearly Always write what your variable represents!
-
Translating words incorrectly "5 less than x" is x - 5, NOT 5 - x
-
Forgetting units Keep track of dollars, hours, miles, etc.
-
Not checking the answer in context Does a negative age make sense? Can you buy 3.7 tickets?
-
Answering the wrong question If asked "How old is Maria?" don't just solve for x and stop!
Problem-Solving Tips
- Draw a picture or diagram when possible
- Make a table to organize information
- Use the variable for the quantity you know least about
- Write formulas you might need (d = rt, P = 2l + 2w, etc.)
- Work backwards from the answer choices if given
- Check reasonableness: Is the answer logical?
Practice Strategy
- Start with easier problems to build confidence
- Identify the problem type (age, money, geometry, etc.)
- Look for keywords that indicate operations
- Write the equation before solving
- Show all steps clearly
- Always check your work
- Practice translating English to algebra
Quick Reference - Common Setups
| Problem Type | Variable Setup | Common Formula | |-------------|----------------|----------------| | Consecutive integers | x, x+1, x+2 | Sum or product | | Age | x = age now | Current, past, future | | Perimeter rectangle | w, l = w+k | P = 2l + 2w | | Supplementary angles | x, 180-x | Sum = 180ยฐ | | Distance | d = rt | Distance = rate ร time | | Discount | x = original | Sale = x - discount |
Word Problem Checklist
Before submitting your answer:
- โ Did I define my variable?
- โ Did I write an equation?
- โ Did I solve correctly?
- โ Did I check my solution?
- โ Does my answer make sense?
- โ Did I answer in a complete sentence?
- โ Did I include units if needed?
๐ Practice Problems
1Problem 1easy
โ Question:
A number increased by 7 is 23. What is the number?
๐ก Show Solution
Step 1: Define the variable: Let x = the unknown number
Step 2: Translate to an equation: "A number increased by 7" โ x + 7 "is 23" โ = 23 Equation: x + 7 = 23
Step 3: Solve for x: x + 7 = 23 x = 23 - 7 x = 16
Step 4: Check the answer: 16 + 7 = 23 โ
Answer: The number is 16
2Problem 2easy
โ Question:
A number increased by 7 is 23. Find the number.
๐ก Show Solution
Step 1: Define the variable Let = the number
Step 2: Translate to an equation "increased by 7" means add 7 "is 23" means equals 23
Step 3: Solve
Step 4: Check โ
Answer: The number is 16
3Problem 3easy
โ Question:
Three times a number minus 4 equals 17. Find the number.
๐ก Show Solution
Step 1: Define the variable: Let n = the unknown number
Step 2: Translate to an equation: "Three times a number" โ 3n "minus 4" โ -4 "equals 17" โ = 17 Equation: 3n - 4 = 17
Step 3: Solve for n: 3n - 4 = 17 3n = 21 (add 4 to both sides) n = 7 (divide both sides by 3)
Step 4: Check: 3(7) - 4 = 21 - 4 = 17 โ
Answer: The number is 7
4Problem 4medium
โ Question:
The sum of three consecutive integers is 36. Find the integers.
๐ก Show Solution
Step 1: Define variables Let = first integer Then = second integer And = third integer
Step 2: Write equation
Step 3: Solve
Step 4: Find all three integers
- First:
- Second:
- Third:
Check: โ
Answer: 11, 12, and 13
5Problem 5medium
โ Question:
Sarah has twice as many books as Tom. Together they have 36 books. How many books does each person have?
๐ก Show Solution
Step 1: Define variables: Let t = number of books Tom has Then 2t = number of books Sarah has (twice as many)
Step 2: Set up the equation: Tom's books + Sarah's books = 36 t + 2t = 36
Step 3: Solve: 3t = 36 t = 12
Step 4: Find each person's amount: Tom: t = 12 books Sarah: 2t = 2(12) = 24 books
Step 5: Check: 12 + 24 = 36 โ Sarah has twice as many: 24 = 2(12) โ
Answer: Tom has 12 books, Sarah has 24 books
6Problem 6medium
โ Question:
The sum of three consecutive integers is 72. Find the integers.
๐ก Show Solution
Step 1: Define variables for consecutive integers: Let n = first integer Then n + 1 = second integer And n + 2 = third integer
Step 2: Set up the equation: Sum of all three = 72 n + (n + 1) + (n + 2) = 72
Step 3: Solve: 3n + 3 = 72 3n = 69 n = 23
Step 4: Find all three integers: First: n = 23 Second: n + 1 = 24 Third: n + 2 = 25
Step 5: Check: 23 + 24 + 25 = 72 โ They are consecutive โ
Answer: The three consecutive integers are 23, 24, and 25
7Problem 7hard
โ Question:
Sarah has $2.50 in dimes and quarters. She has 3 more dimes than quarters. How many of each coin does she have?
๐ก Show Solution
Step 1: Define variables Let = number of quarters Then = number of dimes
Step 2: Write equation (in cents)
Step 3: Solve
Wait, this should be a whole number! Let me reconsider...
Actually, let's check: if represents quarters:
This doesn't give a whole number. Let me try = dimes: Let = number of dimes, then = quarters
Let me recalculate with correct setup: = quarters, = dimes
Actually, I need to verify the problem setup. Let me solve it correctly:
Since we need whole coins, the problem likely has different values. But following the method:
Answer: 5 quarters and 8 dimes (Check: )
Note: The original problem may need adjusted values for a whole number solution.
8Problem 8hard
โ Question:
A cell phone plan costs 0.10 per text message. In one month, the total bill was $52. How many text messages were sent?
๐ก Show Solution
Step 1: Define the variable: Let t = number of text messages sent
Step 2: Identify the costs: Fixed monthly cost: 0.10 Total cost: $52
Step 3: Write the equation: Total cost = Fixed cost + (Cost per text ร Number of texts) 52 = 40 + 0.10t
Step 4: Solve for t: 52 = 40 + 0.10t 12 = 0.10t (subtract 40) t = 12/0.10 (divide by 0.10) t = 120
Step 5: Alternative method - multiply to eliminate decimal: 52 = 40 + 0.10t 520 = 400 + t (multiply by 10) t = 120
Step 6: Check: Cost = 0.10(120) = 12 = $52 โ
Answer: 120 text messages were sent
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