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Use VSEPR theory to predict molecular shapes, bond angles, and understand the relationship between electron geometry and molecular geometry.
Learn step-by-step with practice exercises built right in.
VSEPR = Valence Shell Electron Pair Repulsion Theory
Key Principle: Electron pairs (bonding and lone pairs) repel each other and arrange themselves to be as far apart as possible, minimizing repulsion.
Result: Predicts 3D molecular shapes
Developed by: Ronald Gillespie and Ronald Nyholm (1957)
Electron domain: A region of electron density around a central atom
Types of electron domains:
Multiple bonds count as ONE electron domain
Determine the molecular geometry and bond angle for carbon dioxide (CO₂).
Solution:
Given: CO₂ Find: Molecular geometry and bond angle
Step 1: Draw Lewis structure
Total valence electrons: 4 (C) + 2(6) (O) = 16
| Section | Format | Questions | Time | Weight | Calculator |
|---|---|---|---|---|---|
| Multiple Choice | MCQ | 60 | 90 min | 50% | ✅ |
| Free Response (Long) | FRQ | 3 | 69 min | 30% | ✅ |
| Free Response (Short) | FRQ | 4 | 36 min | 20% | ✅ |
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Example: CO₂
Steric Number (SN): Total number of electron domains around central atom
Alternative:
Examples:
CH₄: 4 bonds + 0 lone pairs = SN 4
NH₃: 3 bonds + 1 lone pair = SN 4
H₂O: 2 bonds + 2 lone pairs = SN 4
All have SN = 4, but different molecular shapes!
Definition: Arrangement of ALL electron domains (bonds + lone pairs)
Determined by: Steric number only
Definition: Arrangement of ATOMS only (ignores lone pairs)
Determined by: Steric number AND number of lone pairs
Key distinction: Lone pairs affect geometry but aren't "seen" in molecular shape
Based on steric number:
| SN | Electron Geometry | Bond Angles | Example |
|---|---|---|---|
| 2 | Linear | 180° | CO₂ |
| 3 | Trigonal planar | 120° | BF₃ |
| 4 | Tetrahedral | 109.5° | CH₄ |
| 5 | Trigonal bipyramidal | 90°, 120° | PCl₅ |
| 6 | Octahedral | 90° | SF₆ |
Electron geometry: Linear
| Bonding | Lone Pairs | Molecular Geometry | Bond Angle | Example |
|---|---|---|---|---|
| 2 | 0 | Linear | 180° | CO₂, BeH₂ |
Linear: All atoms in straight line
(180°)
Electron geometry: Trigonal planar
| Bonding | Lone Pairs | Molecular Geometry | Bond Angle | Example |
|---|---|---|---|---|
| 3 | 0 | Trigonal planar | 120° | BF₃, SO₃ |
| 2 | 1 | Bent | <120° (~118°) | SO₂, O₃ |
Trigonal planar: Flat, three atoms around center
with third F above (all in plane)
Bent (from trigonal planar): V-shaped
(with lone pair on S, angle ~119°)
Electron geometry: Tetrahedral
| Bonding | Lone Pairs | Molecular Geometry | Bond Angle | Example |
|---|---|---|---|---|
| 4 | 0 | Tetrahedral | 109.5° | CH₄, CCl₄ |
| 3 | 1 | Trigonal pyramidal | <109.5° (~107°) | NH₃, PCl₃ |
| 2 | 2 | Bent | <109.5° (~104.5°) | H₂O, H₂S |
Tetrahedral: 3D pyramid shape
CH₄: Carbon at center, 4 H atoms at corners of tetrahedron
Trigonal pyramidal: Pyramid with triangular base
NH₃: N at top, 3 H atoms form triangular base (lone pair on top)
Bent (from tetrahedral): V-shaped
H₂O: O at vertex, 2 H atoms, 2 lone pairs (angle 104.5°)
Electron geometry: Trigonal bipyramidal
Two types of positions:
Lone pairs prefer equatorial positions (more space, less repulsion)
| Bonding | Lone Pairs | Molecular Geometry | Bond Angle | Example |
|---|---|---|---|---|
| 5 | 0 | Trigonal bipyramidal | 90°, 120° | PCl₅ |
| 4 | 1 | Seesaw | <90°, <120° | SF₄ |
| 3 | 2 | T-shaped | <90° | ClF₃ |
| 2 | 3 | Linear | 180° | XeF₂ |
Trigonal bipyramidal: Two pyramids joined at base
Seesaw: Like teeter-totter
T-shaped: Like letter T
Linear (from SN 5): Straight line with 3 lone pairs
Electron geometry: Octahedral
All positions are equivalent (all 90° apart)
| Bonding | Lone Pairs | Molecular Geometry | Bond Angle | Example |
|---|---|---|---|---|
| 6 | 0 | Octahedral | 90° | SF₆ |
| 5 | 1 | Square pyramidal | <90° | BrF₅ |
| 4 | 2 | Square planar | 90° | XeF₄ |
Octahedral: 8-sided figure, 6 atoms at corners of octahedron
Square pyramidal: Square base with atom above
Square planar: Flat square (lone pairs above and below)
Repulsion strength: Lone pair-lone pair > Lone pair-bond > Bond-bond
Effect: Lone pairs take up more space than bonding pairs
Result: Bond angles decrease when lone pairs present
CH₄ (no lone pairs): 109.5° (ideal tetrahedral)
NH₃ (1 lone pair): ~107° (slightly compressed)
H₂O (2 lone pairs): ~104.5° (more compressed)
Trend: More lone pairs → smaller bond angles
Step 1: Draw Lewis structure
Step 2: Count electron domains on central atom
Step 3: Determine steric number (SN)
Step 4: Identify electron geometry from SN
Step 5: Count lone pairs
Step 6: Determine molecular geometry
Step 7: Predict bond angles
Step 1: Lewis structure
with lone pair on N
Step 2: Count electron domains
Step 3: Steric number SN = 4
Step 4: Electron geometry SN 4 → Tetrahedral electron geometry
Step 5: Count lone pairs 1 lone pair
Step 6: Molecular geometry SN 4, 1 lone pair → Trigonal pyramidal
Step 7: Bond angles
Molecular polarity depends on:
Nonpolar molecules:
Polar molecules:
Always polar if:
Always nonpolar if:
Examples:
CO₂: O=C=O (linear, symmetrical) → Nonpolar
H₂O: H-O-H (bent due to lone pairs) → Polar
CCl₄: Tetrahedral, all Cl identical → Nonpolar
CHCl₃: Tetrahedral, but H ≠ Cl → Polar
NH₃: Trigonal pyramidal with lone pair → Polar
BF₃: Trigonal planar, all F identical → Nonpolar
For molecules with multiple "central" atoms, analyze each separately:
Example: Ethanol (C₂H₅OH)
| SN | Electron Geometry | 0 LP | 1 LP | 2 LP | 3 LP |
|---|---|---|---|---|---|
| 2 | Linear | Linear (180°) | - | - | - |
| 3 | Trigonal planar | Trig planar (120°) | Bent (<120°) | - | - |
| 4 | Tetrahedral | Tetrahedral (109.5°) | Trig pyramidal (<109.5°) | Bent (<109.5°) | - |
| 5 | Trig bipyramidal | Trig bipyramidal (90°,120°) | Seesaw | T-shaped | Linear (180°) |
| 6 | Octahedral | Octahedral (90°) | Sq pyramidal | Sq planar (90°) | - |
LP = Lone Pairs
Each O has 2 double bonds and 2 lone pairs C has 2 double bonds (no lone pairs)
Step 2: Identify central atom
Central atom: C (carbon)
Step 3: Count electron domains on C
Total electron domains: 2
Remember: Multiple bonds count as ONE domain!
Step 4: Determine steric number
Step 5: Identify electron geometry
SN = 2 → Linear electron geometry
Step 6: Count lone pairs on central atom
C has 0 lone pairs
Step 7: Determine molecular geometry
SN = 2, 0 lone pairs → Linear molecular geometry
Step 8: Predict bond angle
Linear geometry → 180°
Answer:
Verification:
Note: CO₂ is also nonpolar because the two C=O dipoles point in opposite directions and cancel out due to the linear, symmetrical geometry.
Water (H₂O) and methane (CH₄) both have a steric number of 4, yet they have different molecular geometries and bond angles. Explain why.
Solution:
Given: H₂O and CH₄ both have SN = 4 Find: Explain different geometries and bond angles
Step 1: Draw Lewis structures
H₂O (Water):
O has 2 bonding pairs and 2 lone pairs
CH₄ (Methane):
(with 2 more H atoms)
C has 4 bonding pairs and 0 lone pairs
Step 2: Calculate steric numbers
H₂O:
CH₄:
Both have SN = 4 ✓
Step 3: Determine electron geometry
Both have SN = 4 → Tetrahedral electron geometry
Step 4: Determine molecular geometry
H₂O:
CH₄:
Step 5: Explain bond angles
CH₄:
H₂O:
Step 6: Visualize repulsions
Repulsion strength:
H₂O has:
The strong LP-LP and LP-BP repulsions compress the bond angle.
CH₄ has:
Equal repulsions maintain ideal 109.5° angle.
Answer:
Why different despite same SN?
Electron geometry is the same (tetrahedral for both)
Molecular geometry differs due to lone pairs:
Bond angles differ due to lone pair repulsion:
Key principle: Molecular geometry depends on BOTH steric number AND number of lone pairs. Lone pairs are "invisible" in the molecular shape but strongly affect bond angles through greater repulsion.
Summary:
| Property | H₂O | CH₄ |
|---|---|---|
| Steric Number | 4 | 4 |
| Electron Geometry | Tetrahedral | Tetrahedral |
| Lone Pairs | 2 | 0 |
| Molecular Geometry | Bent | Tetrahedral |
| Bond Angle | 104.5° | 109.5° |
Xenon tetrafluoride (XeF₄) is a stable compound. Determine its molecular geometry, predict the bond angles, and explain whether the molecule is polar or nonpolar.
Solution:
Given: XeF₄ (xenon tetrafluoride) Find: Molecular geometry, bond angles, polarity
Step 1: Draw Lewis structure
Count valence electrons:
Skeletal structure: Xe is central
(with 2 more F atoms)
Connect with single bonds: 4 Xe-F bonds = 8 electrons used Remaining: 36 - 8 = 28 electrons
Complete octets of F atoms: Each F needs 6 more electrons (3 lone pairs) 4 F × 6 = 24 electrons Remaining: 28 - 24 = 4 electrons
Place remaining electrons on Xe: 4 electrons = 2 lone pairs on Xe
Lewis structure:
Xe has 4 bonds and 2 lone pairs
Step 2: Count electron domains on Xe
Step 3: Determine steric number
Step 4: Identify electron geometry
SN = 6 → Octahedral electron geometry
Step 5: Count lone pairs
Xe has 2 lone pairs
Step 6: Determine molecular geometry
SN = 6, 2 lone pairs → Square planar
Why square planar?
Step 7: Predict bond angles
F-Xe-F angles:
Ideal octahedral angles: 90°
With 2 lone pairs:
Step 8: Determine polarity
Check bond polarity:
Check molecular symmetry:
Dipole analysis:
Answer:
Molecular geometry: Square planar
Bond angles:
Polarity: Nonpolar
Explanation of polarity: Even though Xe-F bonds are polar, the square planar geometry is perfectly symmetrical. The four bond dipoles point toward the corners of a square and cancel out vectorially. The two lone pairs are positioned opposite each other (above and below the plane), maintaining symmetry.
Additional notes:
Expanded octet: Xe (Period 5) can accommodate 12 electrons (6 electron domains) using d orbitals
Lone pair placement: In octahedral geometry, lone pairs prefer to be 180° apart (trans position) to minimize LP-LP repulsion
Why not other geometries?
Other examples of square planar: ICl₄⁻, BrF₄⁻
Summary:
| Property | Value |
|---|---|
| Steric Number | 6 |
| Electron Geometry | Octahedral |
| Lone Pairs | 2 (opposite positions) |
| Molecular Geometry | Square planar |
| Bond Angles | 90°, 180° |
| Polarity | Nonpolar (symmetrical) |