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Calculate volumes of 3D shapes
Learn step-by-step with practice exercises built right in.
Understanding the volume of curved 3D shapes opens up a world of real-world applications! From soda cans to ice cream cones to basketballs, these formulas help us calculate capacity and make practical decisions.
Volume measures the amount of space inside a 3D shape.
Think of it as:
Units: Cubic units (cm³, in³, m³, ft³)
A cylinder has two circular bases and a curved side (like a soda can).
Formula:
V = πr²h
Where:
Think of it as: Area of base × height
Find the volume of a cylinder with radius 3 cm and height 10 cm. Use π ≈ 3.14.
Use the formula V = πr²h
V = π(3)²(10)
V = π(9)(10)
V = 90π ≈ 90(3.14) = 282.6 cm³
Answer: 90π cm³ or about 282.6 cm³
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Example 1: Find the volume of a cylinder with radius 3 cm and height 10 cm. Use π ≈ 3.14.
Solution: V = πr²h V = π × (3)² × 10 V = π × 9 × 10 V = 90π V ≈ 90 × 3.14 V ≈ 282.6 cm³
Answer: 90π cm³ or approximately 282.6 cm³
Example 2: A cylindrical water tank has diameter 8 ft and height 12 ft. What's the volume?
Solution: Diameter = 8 ft, so radius = 4 ft
V = π(4)²(12) V = π × 16 × 12 V = 192π V ≈ 603.2 ft³
Answer: 192π ft³ or about 603 ft³
A cone has one circular base and comes to a point (apex) at the top.
Formula:
V = (1/3)πr²h
Where:
Key insight: A cone's volume is 1/3 of a cylinder with the same base and height!
Example 1: Find the volume of a cone with radius 5 in and height 9 in.
Solution: V = (1/3)πr²h V = (1/3)π(5)²(9) V = (1/3)π(25)(9) V = (1/3)π(225) V = 75π V ≈ 235.5 in³
Answer: 75π in³ or about 235.5 in³
Example 2: An ice cream cone has radius 2 cm and height 12 cm. How much ice cream fits inside?
Solution: V = (1/3)π(2)²(12) V = (1/3)π(4)(12) V = (1/3)π(48) V = 16π V ≈ 50.24 cm³
Answer: 16π cm³ or about 50 cm³
Example 3: Compare volumes: Cylinder vs. Cone (same base and height)
Cylinder: r = 3, h = 6 V = π(3)²(6) = 54π
Cone: r = 3, h = 6 V = (1/3)π(3)²(6) = 18π
Cone volume = (1/3) × Cylinder volume ✓
A sphere is perfectly round in all directions (like a ball).
Formula:
V = (4/3)πr³
Where:
Example 1: Find the volume of a sphere with radius 6 cm.
Solution: V = (4/3)πr³ V = (4/3)π(6)³ V = (4/3)π(216) V = (4/3) × 216π V = 288π V ≈ 904.3 cm³
Answer: 288π cm³ or about 904 cm³
Example 2: A basketball has diameter 24 cm. What's its volume?
Solution: Diameter = 24 cm, so radius = 12 cm
V = (4/3)π(12)³ V = (4/3)π(1,728) V = (4/3) × 1,728π V = 2,304π V ≈ 7,238.2 cm³
Answer: 2,304π cm³ or about 7,238 cm³
Example 3: A spherical water droplet has radius 0.5 mm. Find its volume.
Solution: V = (4/3)π(0.5)³ V = (4/3)π(0.125) V = (0.5/3)π V ≈ 0.524 mm³
Answer: About 0.52 mm³
Cylinder: V = πr²h
Cone: V = (1/3)πr²h
Sphere: V = (4/3)πr³
Pattern: All use π because they involve circles!
Sometimes you know the volume and need to find a dimension.
Example 1: A cylinder has volume 200π cm³ and height 8 cm. Find the radius.
Solution: V = πr²h 200π = πr²(8) 200π = 8πr²
Divide by 8π: 25 = r² r = 5 cm
Answer: r = 5 cm
Example 2: A sphere has volume 288π in³. Find the radius.
Solution: V = (4/3)πr³ 288π = (4/3)πr³
Multiply by 3/4: (3/4) × 288π = πr³ 216π = πr³
Divide by π: 216 = r³ r = 6 in
Answer: r = 6 in
Cylinders:
Food cans: Calculate how much soup or soda fits
Water tanks: Storage capacity
Pipes: How much water flows through
Cones:
Ice cream cones: How much ice cream fits
Traffic cones: Volume of material
Funnels: Liquid capacity
Spheres:
Sports balls: Air volume inside
Planets: Volume of celestial bodies
Ball bearings: Industrial applications
Water balloons: How much water they hold
Sometimes shapes are combined!
Example: A shape consists of a cylinder topped with a hemisphere (half-sphere). The radius is 4 cm and the cylinder height is 10 cm. Find total volume.
Solution:
Cylinder part: V₁ = πr²h = π(4)²(10) = 160π cm³
Hemisphere part: Full sphere: V = (4/3)π(4)³ = (256/3)π Half sphere: V₂ = (128/3)π cm³
Total: V = 160π + (128/3)π V = (480/3)π + (128/3)π V = (608/3)π V ≈ 637 cm³
Answer: (608/3)π cm³ or about 637 cm³
Volume units must be CUBIC:
Length units → Volume units:
Important conversions:
Example: A cylinder has r = 10 cm and h = 20 cm. Find volume in liters.
Solution: V = π(10)²(20) = 2,000π ≈ 6,283 cm³
Convert to liters: 6,283 cm³ = 6,283 mL = 6.283 liters
Answer: About 6.3 liters
❌ Mistake 1: Using diameter instead of radius
❌ Mistake 2: Forgetting the 1/3 for cones
❌ Mistake 3: Forgetting the 4/3 for spheres
❌ Mistake 4: Wrong units (square instead of cubic)
❌ Mistake 5: Calculation errors with π
❌ Mistake 6: Confusing height with slant height (cones)
Step 1: Identify the shape
Step 2: Write the appropriate formula
Step 3: Identify given information
Step 4: Substitute into formula
Step 5: Calculate step-by-step
Step 6: Include proper units (cubic!)
Step 7: Round appropriately if needed
Cylinder: V = πr²h
Cone: V = (1/3)πr²h
Sphere: V = (4/3)πr³
Remember:
Tip 1: Draw and label
Tip 2: Double-check formulas
Tip 3: Watch for diameter vs. radius
Tip 4: Use calculator wisely
Tip 5: Check reasonableness
Volume formulas for curved shapes:
Cylinder: V = πr²h
Cone: V = (1/3)πr²h
Sphere: V = (4/3)πr³
Key skills:
These formulas are essential for engineering, manufacturing, science, and countless real-world applications!
Find the volume of a cone with radius 4 cm and height 9 cm. Use π ≈ 3.14.
Use the formula V = (1/3)πr²h
V = (1/3)π(4)²(9)
V = (1/3)π(16)(9)
V = (1/3)π(144)
V = 48π ≈ 48(3.14) = 150.72 cm³
Answer: 48π cm³ or about 150.72 cm³
Find the volume of a sphere with radius 6 cm. Use π ≈ 3.14.
Use the formula V = (4/3)πr³
V = (4/3)π(6)³
V = (4/3)π(216)
V = (864/3)π
V = 288π ≈ 288(3.14) = 904.32 cm³
Answer: 288π cm³ or about 904.32 cm³
A cylindrical water tank has volume 1,000π cubic feet and height 10 feet. Find the radius.
Use V = πr²h and solve for r:
1000π = πr²(10)
1000π = 10πr²
100 = r²
r = 10 feet (taking positive root)
Answer: 10 feet
An ice cream cone consists of a cone with radius 3 cm and height 10 cm, topped with a hemisphere (half sphere) of radius 3 cm. Find the total volume. Use π ≈ 3.14.
Volume = Volume of cone + Volume of hemisphere
Cone: V₁ = (1/3)π(3)²(10) = (1/3)π(9)(10) = 30π
Hemisphere: V₂ = (1/2) × (4/3)π(3)³ = (2/3)π(27) = 18π
Total: V = 30π + 18π = 48π ≈ 48(3.14) = 150.72 cm³
Answer: 48π cm³ or about 150.72 cm³