Volume of Cylinders, Cones, and Spheres
Calculate volumes of 3D shapes
Volume of Cylinders, Cones, and Spheres
Understanding the volume of curved 3D shapes opens up a world of real-world applications! From soda cans to ice cream cones to basketballs, these formulas help us calculate capacity and make practical decisions.
Review: What Is Volume?
Volume measures the amount of space inside a 3D shape.
Think of it as:
- How much liquid it can hold
- How many unit cubes fit inside
- The capacity of the shape
Units: Cubic units (cm³, in³, m³, ft³)
Volume of a Cylinder
A cylinder has two circular bases and a curved side (like a soda can).
Formula:
V = πr²h
Where:
- r = radius of the circular base
- h = height of the cylinder
- π ≈ 3.14 or use calculator's π button
Think of it as: Area of base × height
- Base area = πr²
- Multiply by height: πr² × h = πr²h
Example 1: Find the volume of a cylinder with radius 3 cm and height 10 cm. Use π ≈ 3.14.
Solution: V = πr²h V = π × (3)² × 10 V = π × 9 × 10 V = 90π V ≈ 90 × 3.14 V ≈ 282.6 cm³
Answer: 90π cm³ or approximately 282.6 cm³
Example 2: A cylindrical water tank has diameter 8 ft and height 12 ft. What's the volume?
Solution: Diameter = 8 ft, so radius = 4 ft
V = π(4)²(12) V = π × 16 × 12 V = 192π V ≈ 603.2 ft³
Answer: 192π ft³ or about 603 ft³
Volume of a Cone
A cone has one circular base and comes to a point (apex) at the top.
Formula:
V = (1/3)πr²h
Where:
- r = radius of the circular base
- h = height (perpendicular from base to apex)
- π ≈ 3.14
Key insight: A cone's volume is 1/3 of a cylinder with the same base and height!
Example 1: Find the volume of a cone with radius 5 in and height 9 in.
Solution: V = (1/3)πr²h V = (1/3)π(5)²(9) V = (1/3)π(25)(9) V = (1/3)π(225) V = 75π V ≈ 235.5 in³
Answer: 75π in³ or about 235.5 in³
Example 2: An ice cream cone has radius 2 cm and height 12 cm. How much ice cream fits inside?
Solution: V = (1/3)π(2)²(12) V = (1/3)π(4)(12) V = (1/3)π(48) V = 16π V ≈ 50.24 cm³
Answer: 16π cm³ or about 50 cm³
Example 3: Compare volumes: Cylinder vs. Cone (same base and height)
Cylinder: r = 3, h = 6 V = π(3)²(6) = 54π
Cone: r = 3, h = 6 V = (1/3)π(3)²(6) = 18π
Cone volume = (1/3) × Cylinder volume ✓
Volume of a Sphere
A sphere is perfectly round in all directions (like a ball).
Formula:
V = (4/3)πr³
Where:
- r = radius of the sphere
- π ≈ 3.14
Example 1: Find the volume of a sphere with radius 6 cm.
Solution: V = (4/3)πr³ V = (4/3)π(6)³ V = (4/3)π(216) V = (4/3) × 216π V = 288π V ≈ 904.3 cm³
Answer: 288π cm³ or about 904 cm³
Example 2: A basketball has diameter 24 cm. What's its volume?
Solution: Diameter = 24 cm, so radius = 12 cm
V = (4/3)π(12)³ V = (4/3)π(1,728) V = (4/3) × 1,728π V = 2,304π V ≈ 7,238.2 cm³
Answer: 2,304π cm³ or about 7,238 cm³
Example 3: A spherical water droplet has radius 0.5 mm. Find its volume.
Solution: V = (4/3)π(0.5)³ V = (4/3)π(0.125) V = (0.5/3)π V ≈ 0.524 mm³
Answer: About 0.52 mm³
Comparing the Three Formulas
Cylinder: V = πr²h
- "Pi r squared h"
- Base area × height
Cone: V = (1/3)πr²h
- "One-third pi r squared h"
- 1/3 of cylinder volume
Sphere: V = (4/3)πr³
- "Four-thirds pi r cubed"
- Only depends on radius
Pattern: All use π because they involve circles!
Finding Unknown Dimensions
Sometimes you know the volume and need to find a dimension.
Example 1: A cylinder has volume 200π cm³ and height 8 cm. Find the radius.
Solution: V = πr²h 200π = πr²(8) 200π = 8πr²
Divide by 8π: 25 = r² r = 5 cm
Answer: r = 5 cm
Example 2: A sphere has volume 288π in³. Find the radius.
Solution: V = (4/3)πr³ 288π = (4/3)πr³
Multiply by 3/4: (3/4) × 288π = πr³ 216π = πr³
Divide by π: 216 = r³ r = 6 in
Answer: r = 6 in
Real-World Applications
Cylinders:
Food cans: Calculate how much soup or soda fits
- Soda can: r ≈ 3 cm, h ≈ 12 cm
- V ≈ 339 cm³ (about 339 mL)
Water tanks: Storage capacity
- Tank: r = 5 ft, h = 10 ft
- V ≈ 785 ft³
Pipes: How much water flows through
- Pipe: r = 2 in, length = 100 in
- V ≈ 1,256 in³
Cones:
Ice cream cones: How much ice cream fits
- Waffle cone: r = 3 cm, h = 10 cm
- V ≈ 94 cm³
Traffic cones: Volume of material
- Orange cone: r = 6 in, h = 18 in
- V ≈ 678 in³
Funnels: Liquid capacity
Spheres:
Sports balls: Air volume inside
- Basketball: r ≈ 12 cm
- V ≈ 7,238 cm³
Planets: Volume of celestial bodies
- Earth radius ≈ 6,371 km
- V ≈ 1.08 × 10¹² km³
Ball bearings: Industrial applications
Water balloons: How much water they hold
Composite Shapes
Sometimes shapes are combined!
Example: A shape consists of a cylinder topped with a hemisphere (half-sphere). The radius is 4 cm and the cylinder height is 10 cm. Find total volume.
Solution:
Cylinder part: V₁ = πr²h = π(4)²(10) = 160π cm³
Hemisphere part: Full sphere: V = (4/3)π(4)³ = (256/3)π Half sphere: V₂ = (128/3)π cm³
Total: V = 160π + (128/3)π V = (480/3)π + (128/3)π V = (608/3)π V ≈ 637 cm³
Answer: (608/3)π cm³ or about 637 cm³
Units and Conversions
Volume units must be CUBIC:
Length units → Volume units:
- cm → cm³
- m → m³
- ft → ft³
- in → in³
Important conversions:
- 1 m³ = 1,000,000 cm³
- 1 ft³ = 1,728 in³
- 1 cm³ = 1 mL (milliliter)
- 1 m³ = 1,000 liters
Example: A cylinder has r = 10 cm and h = 20 cm. Find volume in liters.
Solution: V = π(10)²(20) = 2,000π ≈ 6,283 cm³
Convert to liters: 6,283 cm³ = 6,283 mL = 6.283 liters
Answer: About 6.3 liters
Common Mistakes to Avoid
❌ Mistake 1: Using diameter instead of radius
- Wrong: V = π(10)²h when diameter = 10
- Right: r = 5, so V = π(5)²h
❌ Mistake 2: Forgetting the 1/3 for cones
- Wrong: Cone V = πr²h
- Right: Cone V = (1/3)πr²h
❌ Mistake 3: Forgetting the 4/3 for spheres
- Wrong: V = πr³
- Right: V = (4/3)πr³
❌ Mistake 4: Wrong units (square instead of cubic)
- Wrong: Volume = 50 cm²
- Right: Volume = 50 cm³
❌ Mistake 5: Calculation errors with π
- Use calculator's π button for accuracy
- Or use 3.14 as approximation
❌ Mistake 6: Confusing height with slant height (cones)
- Use perpendicular height, not slant
Problem-Solving Strategy
Step 1: Identify the shape
- Cylinder? Cone? Sphere? Combination?
Step 2: Write the appropriate formula
Step 3: Identify given information
- Radius or diameter?
- Height?
- Convert diameter to radius if needed
Step 4: Substitute into formula
Step 5: Calculate step-by-step
- Handle fractions carefully
- Keep π in answer or use 3.14
Step 6: Include proper units (cubic!)
Step 7: Round appropriately if needed
Quick Reference
Cylinder: V = πr²h
Cone: V = (1/3)πr²h
Sphere: V = (4/3)πr³
Remember:
- All use radius (r), not diameter
- Cone = 1/3 of cylinder
- Units must be cubic (cm³, m³, etc.)
- Diameter = 2 × radius
Practice Tips
Tip 1: Draw and label
- Sketch the shape
- Mark radius, height, diameter
- Check which you're given
Tip 2: Double-check formulas
- Cylinder has h
- Cone has 1/3
- Sphere has 4/3 and r³
Tip 3: Watch for diameter vs. radius
- Always convert diameter to radius!
- r = d/2
Tip 4: Use calculator wisely
- π button for best accuracy
- Or use 3.14 for approximation
Tip 5: Check reasonableness
- Cone should be 1/3 of cylinder
- Larger radius = much larger volume (squared or cubed!)
Summary
Volume formulas for curved shapes:
Cylinder: V = πr²h
- Two circular bases
- Straight sides
- Applications: cans, tanks, pipes
Cone: V = (1/3)πr²h
- One circular base
- Comes to a point
- 1/3 of cylinder volume
- Applications: ice cream cones, funnels
Sphere: V = (4/3)πr³
- Perfectly round
- Only depends on radius
- Applications: balls, planets, bubbles
Key skills:
- Identify the correct formula
- Convert diameter to radius
- Calculate accurately with π
- Use proper cubic units
These formulas are essential for engineering, manufacturing, science, and countless real-world applications!
📚 Practice Problems
1Problem 1easy
❓ Question:
Find the volume of a cylinder with radius 3 cm and height 10 cm. Use π ≈ 3.14.
💡 Show Solution
Use the formula V = πr²h
V = π(3)²(10)
V = π(9)(10)
V = 90π ≈ 90(3.14) = 282.6 cm³
Answer: 90π cm³ or about 282.6 cm³
2Problem 2easy
❓ Question:
Find the volume of a cone with radius 4 cm and height 9 cm. Use π ≈ 3.14.
💡 Show Solution
Use the formula V = (1/3)πr²h
V = (1/3)π(4)²(9)
V = (1/3)π(16)(9)
V = (1/3)π(144)
V = 48π ≈ 48(3.14) = 150.72 cm³
Answer: 48π cm³ or about 150.72 cm³
3Problem 3medium
❓ Question:
Find the volume of a sphere with radius 6 cm. Use π ≈ 3.14.
💡 Show Solution
Use the formula V = (4/3)πr³
V = (4/3)π(6)³
V = (4/3)π(216)
V = (864/3)π
V = 288π ≈ 288(3.14) = 904.32 cm³
Answer: 288π cm³ or about 904.32 cm³
4Problem 4medium
❓ Question:
A cylindrical water tank has volume 1,000π cubic feet and height 10 feet. Find the radius.
💡 Show Solution
Use V = πr²h and solve for r:
1000π = πr²(10)
1000π = 10πr²
100 = r²
r = 10 feet (taking positive root)
Answer: 10 feet
5Problem 5hard
❓ Question:
An ice cream cone consists of a cone with radius 3 cm and height 10 cm, topped with a hemisphere (half sphere) of radius 3 cm. Find the total volume. Use π ≈ 3.14.
💡 Show Solution
Volume = Volume of cone + Volume of hemisphere
Cone: V₁ = (1/3)π(3)²(10) = (1/3)π(9)(10) = 30π
Hemisphere: V₂ = (1/2) × (4/3)π(3)³ = (2/3)π(27) = 18π
Total: V = 30π + 18π = 48π ≈ 48(3.14) = 150.72 cm³
Answer: 48π cm³ or about 150.72 cm³
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