Direct and Inverse Variation
Relationships between varying quantities
Direct and Inverse Variation
What is Direct Variation?
Direct variation: As one variable increases, the other increases proportionally.
Formula: y = kx
Where:
- k = constant of variation (constant of proportionality)
- k ≠ 0
- Relationship is linear through origin
Key phrase: "y varies directly as x"
Example 1: Distance varies directly with time (at constant speed)
If speed = 50 mph (this is k): d = 50t
Travel 2 hours: d = 50(2) = 100 miles Travel 5 hours: d = 50(5) = 250 miles
Example 2: Cost varies directly with pounds
If apples cost 2 dollars per pound (k = 2): C = 2p
Buy 3 pounds: C = 2(3) = 6 dollars Buy 7 pounds: C = 2(7) = 14 dollars
Characteristics of Direct Variation
1. Passes through origin (0, 0)
When x = 0, y = k(0) = 0
2. Constant ratio y/x = k
Example: y = 3x
x = 1 → y = 3 → ratio: 3/1 = 3 x = 2 → y = 6 → ratio: 6/2 = 3 x = 4 → y = 12 → ratio: 12/4 = 3
The ratio is always k!
3. Graph is a straight line through origin
Slope = k
4. As x doubles, y doubles
If y = 5x: x = 2 → y = 10 x = 4 (doubled) → y = 20 (doubled)
Finding the Constant k
Given one pair of values (x, y)
Step 1: Use y = kx Step 2: Substitute known values Step 3: Solve for k Step 4: Write equation
Example 1: y varies directly as x. When x = 4, y = 12
12 = k(4) k = 3
Equation: y = 3x
Example 2: y varies directly as x. When x = 5, y = 30
30 = k(5) k = 6
Equation: y = 6x
Example 3: Distance d varies directly with time t. When t = 3, d = 165
165 = k(3) k = 55
Equation: d = 55t (speed is 55 mph)
Using Direct Variation to Solve Problems
Example 1: y varies directly as x. If y = 15 when x = 3, find y when x = 7
Step 1: Find k 15 = k(3) k = 5
Step 2: Use k to find new y y = 5(7) = 35
Example 2: The cost C of bananas varies directly with weight w. If 2 pounds cost 3 dollars, find the cost of 5 pounds
Find k: 3 = k(2) k = 1.5
Find new cost: C = 1.5(5) = 7.50 dollars
Example 3: Earnings E vary directly with hours h worked. If you earn 120 dollars for 8 hours, how much for 12 hours?
Find k: 120 = k(8) k = 15 (hourly wage)
For 12 hours: E = 15(12) = 180 dollars
What is Inverse Variation?
Inverse variation: As one variable increases, the other decreases proportionally.
Formula: y = k/x or xy = k
Where:
- k = constant of variation
- k ≠ 0
- Relationship is hyperbola (curve)
Key phrase: "y varies inversely as x"
Example 1: Time varies inversely with speed
To travel 120 miles (k = 120): t = 120/r
At 30 mph: t = 120/30 = 4 hours At 60 mph: t = 120/60 = 2 hours Faster speed → less time!
Example 2: Workers and time to complete job
To paint house requiring 24 worker-hours (k = 24): t = 24/w
1 worker: t = 24 hours 2 workers: t = 12 hours 4 workers: t = 6 hours
More workers → less time!
Characteristics of Inverse Variation
1. Product xy is constant
xy = k (always the same)
2. Does NOT pass through origin
Cannot have x = 0 (division by zero!)
3. Graph is a hyperbola
Two curves in opposite quadrants
4. As x increases, y decreases
Example: y = 12/x
x = 1 → y = 12 x = 2 → y = 6 (x doubled, y halved) x = 3 → y = 4 x = 4 → y = 3 (x doubled again, y halved again)
5. Asymptotes at x = 0 and y = 0
Graph approaches but never touches axes
Finding k for Inverse Variation
Given one pair (x, y)
Use: k = xy
Example 1: y varies inversely as x. When x = 3, y = 8
k = 3 × 8 = 24
Equation: y = 24/x or xy = 24
Example 2: y varies inversely as x. When x = 6, y = 2
k = 6 × 2 = 12
Equation: y = 12/x
Example 3: Time t varies inversely with speed r. When r = 40, t = 5
k = 40 × 5 = 200
Equation: t = 200/r (200-mile trip)
Using Inverse Variation to Solve Problems
Example 1: y varies inversely as x. If y = 6 when x = 4, find y when x = 8
Find k: k = 4 × 6 = 24
Find new y: y = 24/8 = 3
Example 2: Time to complete a job varies inversely with workers. 3 workers take 8 hours. How long for 6 workers?
Find k: k = 3 × 8 = 24 worker-hours
Find new time: t = 24/6 = 4 hours
Example 3: Pressure and volume inversely related (Boyle's Law). When volume is 20 liters, pressure is 5 atmospheres. Find pressure at 10 liters.
Find k: k = 20 × 5 = 100
Find new pressure: P = 100/10 = 10 atmospheres
Direct vs. Inverse Variation Comparison
Direct Variation (y = kx):
- Both increase together
- Both decrease together
- Ratio y/x is constant
- Graph: line through origin
- Example: More hours → more pay
Inverse Variation (y = k/x):
- One increases, other decreases
- Product xy is constant
- Graph: hyperbola
- Example: More speed → less time
How to identify:
"Varies directly" or "proportional to" → y = kx
"Varies inversely" or "inversely proportional" → y = k/x
Joint Variation
One variable varies directly as the product of two or more variables
Formula: z = kxy
Example: Area of rectangle varies jointly as length and width
A = lw (here k = 1)
If l = 5 and w = 3: A = 15 If l = 10 and w = 3: A = 30 (length doubled, area doubled)
Example 2: Volume of cylinder varies jointly as radius squared and height
V = πr²h (k = π)
Combined Variation
Mix of direct and inverse variation
Formula: z = kx/y
z varies directly as x and inversely as y
Example: Speed varies directly as distance and inversely as time
s = d/t (k = 1)
More distance → more speed (direct) More time → less speed (inverse)
Example 2: z = kxy/w
z varies jointly as x and y, and inversely as w
Given: When x = 2, y = 3, w = 6, z = 4
Find k: 4 = k(2)(3)/6 4 = k k = 4
Equation: z = 4xy/w
Real-World Applications of Direct Variation
1. Wages: Pay varies directly with hours worked E = rh (r = hourly rate)
2. Distance: Distance varies directly with time (constant speed) d = rt
3. Spring stretch: Force varies directly with distance stretched (Hooke's Law) F = kx
4. Currency exchange: Dollars vary directly with euros d = ke
5. Perimeter and side: Perimeter of square varies directly with side P = 4s (k = 4)
6. Cost and quantity: Total cost varies directly with items purchased C = px (p = price per item)
Real-World Applications of Inverse Variation
1. Travel time: Time varies inversely with speed t = d/r (d = distance is constant)
2. Work completion: Time varies inversely with workers t = k/w (k = total worker-hours)
3. Gas law (Boyle's): Pressure varies inversely with volume (constant temperature) P = k/V
4. Brightness: Light intensity varies inversely with distance squared I = k/d²
5. Gear ratios: Speed varies inversely with number of teeth s = k/n
6. Seesaw balance: Weight varies inversely with distance from fulcrum w₁d₁ = w₂d₂
Recognizing Variation from Tables
Direct Variation Test: Check if y/x is constant
x | y | y/x 1 | 3 | 3 2 | 6 | 3 3 | 9 | 3 4 | 12 | 3
Constant ratio → Direct variation! (y = 3x)
Inverse Variation Test: Check if xy is constant
x | y | xy 1 | 12 | 12 2 | 6 | 12 3 | 4 | 12 4 | 3 | 12
Constant product → Inverse variation! (y = 12/x)
Neither:
x | y | y/x | xy 1 | 5 | 5 | 5 2 | 8 | 4 | 16 3 | 11 | 3.67 | 33
Neither constant → Not direct or inverse variation
Graphing Variation
Direct Variation (y = kx):
- Straight line
- Passes through (0, 0)
- Slope = k
- If k > 0: line rises left to right
- If k < 0: line falls left to right
Inverse Variation (y = k/x):
- Hyperbola (two curves)
- If k > 0: curves in quadrants I and III
- If k < 0: curves in quadrants II and IV
- Never touches axes (asymptotes)
- Symmetric about origin
Common Mistakes to Avoid
-
Confusing direct and inverse Direct: y = kx (multiply) Inverse: y = k/x (divide)
-
Forgetting to find k first Always find k before solving for new values!
-
Using wrong formula Read carefully: "directly" vs "inversely"
-
Arithmetic errors with fractions Be careful with division in inverse variation
-
Thinking direct variation has y-intercept Must pass through origin! (0, 0)
-
Not checking units Ensure units make sense in context
Problem-Solving Strategy
For Direct Variation:
- Write y = kx
- Substitute known pair to find k
- Write equation with k value
- Use equation to find unknown
For Inverse Variation:
- Write y = k/x or xy = k
- Substitute known pair to find k
- Write equation with k value
- Use equation to find unknown
Identifying type:
- "Varies directly" or "proportional" → y = kx
- "Varies inversely" or "inversely proportional" → y = k/x
- Check if y/x constant (direct) or xy constant (inverse)
Quick Reference
Direct Variation:
- Formula: y = kx
- Graph: line through origin
- Test: y/x = k (constant ratio)
- As x ↑, y ↑
Inverse Variation:
- Formula: y = k/x or xy = k
- Graph: hyperbola
- Test: xy = k (constant product)
- As x ↑, y ↓
Finding k:
- Direct: k = y/x
- Inverse: k = xy
Joint: z = kxy (varies jointly as x and y)
Combined: z = kx/y (direct in x, inverse in y)
Practice Tips
- Always identify variation type first
- Find k before finding other values
- Check if answer makes sense (direct: both increase, inverse: opposite)
- Practice with real-world contexts
- Graph to visualize relationships
- Use tables to test for variation type
- Remember formulas: y = kx vs y = k/x
- Master fraction operations for inverse variation
- Verify by checking if ratio or product is constant
- Apply to physics, chemistry, economics problems
- Don't confuse with linear equations (direct variation is special case)
- Understand the meaning of k in each context
- Practice converting word problems to equations
Understanding variation helps you model real-world relationships mathematically. These concepts appear throughout science, economics, and engineering!
📚 Practice Problems
1Problem 1easy
❓ Question:
If y varies directly with x, and y = 12 when x = 3, find y when x = 7.
💡 Show Solution
Step 1: Write the direct variation equation: y = kx (where k is the constant of variation)
Step 2: Find k using the given values: 12 = k(3) k = 12/3 k = 4
Step 3: Write the specific equation: y = 4x
Step 4: Find y when x = 7: y = 4(7) y = 28
Step 5: Verify with original: When x = 3: y = 4(3) = 12 ✓
Answer: y = 28
2Problem 2easy
❓ Question:
varies directly with , and when . Find the constant of variation.
💡 Show Solution
For direct variation:
Substitute the given values:
Divide by 4:
Answer: The constant of variation is
3Problem 3easy
❓ Question:
If y varies inversely with x, and y = 8 when x = 2, find y when x = 4.
💡 Show Solution
Step 1: Write the inverse variation equation: y = k/x (where k is the constant of variation)
Step 2: Find k using the given values: 8 = k/2 k = 8 × 2 k = 16
Step 3: Write the specific equation: y = 16/x
Step 4: Find y when x = 4: y = 16/4 y = 4
Step 5: Verify with original: When x = 2: y = 16/2 = 8 ✓
Step 6: Note the inverse relationship: When x doubled (2 to 4), y halved (8 to 4)
Answer: y = 4
4Problem 4medium
❓ Question:
varies directly with , and when . Find when .
💡 Show Solution
Step 1: Find
Step 2: Write the equation
Step 3: Find when
Answer:
5Problem 5medium
❓ Question:
The distance d traveled at constant speed varies directly with time t. If d = 120 miles when t = 2 hours, how far will you travel in 5 hours?
💡 Show Solution
Step 1: Identify the type of variation: Direct variation: d = kt
Step 2: Find the constant k (this represents speed): 120 = k(2) k = 120/2 k = 60 miles per hour
Step 3: Write the equation: d = 60t
Step 4: Find d when t = 5: d = 60(5) d = 300 miles
Step 5: Interpret: The constant k = 60 is the speed in mph. This makes sense: distance = speed × time
Answer: 300 miles
6Problem 6medium
❓ Question:
The time t it takes to complete a job varies inversely with the number of workers n. If 4 workers can complete the job in 6 hours, how long will it take 8 workers?
💡 Show Solution
Step 1: Identify inverse variation: More workers → less time (inverse relationship) t = k/n
Step 2: Find k using given information: 6 = k/4 k = 6 × 4 k = 24
Step 3: Interpret k: k = 24 represents the total "worker-hours" needed (4 workers × 6 hours = 24 worker-hours)
Step 4: Write the equation: t = 24/n
Step 5: Find t when n = 8: t = 24/8 t = 3 hours
Step 6: Verify the relationship: 4 workers × 6 hours = 24 worker-hours 8 workers × 3 hours = 24 worker-hours ✓
Answer: 3 hours
7Problem 7hard
❓ Question:
varies inversely with , and when . Find when .
💡 Show Solution
Step 1: Find using
Step 2: Write the equation
Step 3: Find when
Note: When doubled from 4 to 8, was halved from 6 to 3 ✓
Answer:
8Problem 8hard
❓ Question:
The volume V of a gas varies directly with temperature T and inversely with pressure P. If V = 30 when T = 300 and P = 2, find V when T = 450 and P = 3.
💡 Show Solution
Step 1: Write the joint variation equation: V varies directly with T and inversely with P V = kT/P
Step 2: Find k using given values: 30 = k(300)/2 30 = 150k k = 30/150 k = 1/5 or 0.2
Step 3: Write the complete equation: V = 0.2T/P or V = T/(5P)
Step 4: Find V when T = 450 and P = 3: V = 0.2(450)/3 V = 90/3 V = 30
Step 5: Alternative method using T/5P: V = 450/(5×3) V = 450/15 V = 30
Step 6: Verify with original values: V = 0.2(300)/2 = 60/2 = 30 ✓
Step 7: Analyze the change: Temperature increased by factor of 1.5 (300 to 450) Pressure increased by factor of 1.5 (2 to 3) These changes cancelled out, so V stayed at 30
Answer: V = 30
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