Uniform Circular Motion
Centripetal acceleration and circular motion kinematics
Try the Interactive Version!
Learn step-by-step with practice exercises built right in.
š Uniform Circular Motion
What is Uniform Circular Motion?
Uniform Circular Motion (UCM) occurs when an object moves in a circular path at constant speed.
Key Characteristics
- Speed is constant - the magnitude of velocity doesn't change
- Velocity is NOT constant - the direction is continuously changing
- There MUST be acceleration - changing direction means changing velocity
- Acceleration points toward the center - called centripetal acceleration
š” Critical Insight: Even though speed is constant, there IS acceleration because velocity is a vector (has direction). Changing direction = changing velocity = acceleration!
Centripetal Acceleration
The acceleration that points toward the center of the circular path is called centripetal acceleration (meaning "center-seeking").
Formula
where:
- = centripetal acceleration (m/s²)
- = speed (m/s)
- = radius of circular path (m)
Direction
- Always points toward the center of the circle
- Perpendicular to the velocity vector
- Changes direction as the object moves around the circle
Alternative Form
Using (where is period):
Also, using angular velocity :
Period and Frequency
Period (T)
The period is the time for one complete revolution:
Units: seconds (s)
Frequency (f)
The frequency is the number of revolutions per second:
Units: hertz (Hz) or revolutions per second (rev/s)
Relationship Between v, r, T, and f
Angular Velocity
Angular velocity () measures how fast the angle changes:
Units: radians per second (rad/s)
Relationship to Linear Velocity
This connects the speed along the circular path () to the angular velocity ().
Common Scenarios
Scenario 1: Object on a String
A ball swung in a horizontal circle:
- Tension provides centripetal force
- points toward center
- If string breaks, object flies off tangent to circle (not radially outward!)
Scenario 2: Car Rounding a Curve
A car turning on a flat road:
- Friction provides centripetal force
- Maximum safe speed:
- Radius affects speed: tighter curves require slower speeds
Scenario 3: Satellite in Orbit
A satellite orbiting Earth:
- Gravity provides centripetal force
- at Earth's surface
- Orbital period depends on altitude
ā ļø Common Misconceptions
Misconception 1: "Centrifugal Force"
ā Wrong: There's an outward "centrifugal force" on the object ā Right: There's no outward force. The object wants to move in a straight line (Newton's 1st Law), but centripetal force pulls it inward toward the center. "Centrifugal force" is a fictitious force felt in the rotating reference frame.
Misconception 2: Constant Velocity
ā Wrong: Uniform circular motion has constant velocity ā Right: UCM has constant speed but changing velocity (because direction changes)
Misconception 3: Acceleration and Speed
ā Wrong: If speed is constant, acceleration must be zero ā Right: Acceleration can be perpendicular to velocity, changing direction without changing speed
Misconception 4: Direction After Release
ā Wrong: If the string breaks, the object flies radially outward ā Right: The object flies off tangent to the circle (in the direction of instantaneous velocity)
Problem-Solving Strategy
- Draw a diagram showing the circular path and center
- Identify the radius of the circular path
- Find or calculate the speed (may need to use or )
- Calculate centripetal acceleration:
- Direction: Always toward the center
Key Equations Summary
| Quantity | Formula | Units | |----------|---------|-------| | Centripetal acceleration | | m/s² | | Speed | | m/s | | Period | | s | | Frequency | | Hz | | Angular velocity | | rad/s |
š Important Notes
- Centripetal acceleration exists even though speed is constant
- The acceleration changes direction continuously (always pointing toward center)
- Period and frequency are inversely related:
- For a given radius, higher speed requires greater centripetal acceleration
- All points on a rigid rotating object have the same angular velocity but different linear velocities
š Practice Problems
1Problem 1easy
ā Question:
A car travels around a circular track with a radius of 50 m at a constant speed of 20 m/s. What is the magnitude of the car's centripetal acceleration?
š” Show Solution
Given Information:
- Radius: m
- Speed: m/s
- Motion: uniform circular motion (constant speed)
Find: Centripetal acceleration
Solution:
Use the centripetal acceleration formula:
Substitute the values:
Answer: The centripetal acceleration is 8 m/s² directed toward the center of the circular track.
Note: This acceleration is less than (9.8 m/s²), so friction alone could provide this if the coefficient is sufficient.
2Problem 2medium
ā Question:
A 0.5 kg ball is attached to a 1.2 m string and swung in a horizontal circle, making 2 complete revolutions per second. Calculate: (a) the period, (b) the speed of the ball, and (c) the centripetal acceleration.
š” Show Solution
Given Information:
- Mass: kg
- Radius: m
- Frequency: rev/s = 2 Hz
(a) Find the period :
The period is the time for one revolution:
(b) Find the speed :
Use the relationship between speed, radius, and period:
(c) Find the centripetal acceleration :
Using exact value m/s:
Alternative method using :
Answers:
- (a) Period: 0.5 s
- (b) Speed: 15.1 m/s
- (c) Centripetal acceleration: 189.5 m/s² (toward center)
Note: This is about 19 times the acceleration due to gravity!
3Problem 3hard
ā Question:
A space station rotates to create artificial gravity. If the station has a radius of 100 m and the centripetal acceleration at the outer edge is to equal Earth's gravity (9.8 m/s²), what should be the period of rotation?
š” Show Solution
Given Information:
- Radius: m
- Desired centripetal acceleration: m/s² (to simulate Earth's gravity)
Find: Period
Strategy: We need to work backwards from to find , then use to find .
Step 1: Find the required speed
From , solve for :
Step 2: Find the period
From , solve for :
Alternative Method: Using
Answer: The period of rotation should be approximately 20.1 seconds.
Interpretation: The station completes one rotation about every 20 seconds, creating a centripetal acceleration of m/s² at the outer edge, which would feel like Earth's gravity to people standing on the outer rim.